Factoring Polynomials

42 soru

Soru 21Soru →

Consider the polynomial 8x2−10x−38x^2 - 10x - 3. When this expression is factored completely into the form (4x+a)(2x−b)(4x + a)(2x - b), where aa and bb are positive integers, what are the corresponding values for aa and bb?

Aşağıdaki boşlukları doldurun

The value of aa is and the value of bb is .
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Cevap

The value of a is 1 and the value of b is 3.
By applying the AC method, the quadratic 8x2−10x−38x^2 - 10x - 3 can be rewritten as 8x2−12x+2x−38x^2 - 12x + 2x - 3 and factored by grouping into 4x(2x−3)+1(2x−3)=(4x+1)(2x−3)4x(2x - 3) + 1(2x - 3) = (4x + 1)(2x - 3). Aligning this with (4x+a)(2x−b)(4x + a)(2x - b) directly shows that a=1a = 1 and b=3b = 3.

Adım Adım Çözüm

1
Identify the type of polynomial and the appropriate factoring method.
The polynomial 8x2−10x−38x^2 - 10x - 3 is a non-monic quadratic trinomial (where the leading coefficient is not 1). We can use the ac-method.
The ac-method involves finding two numbers that multiply to the product of the leading coefficient and the constant term, and add to the middle coefficient.
2
Calculate the ac product and find the target sum.
The product is a×c=8×(−3)=−24a \times c = 8 \times (-3) = -24. The target sum is the middle coefficient, which is −10-10.
These values are required to split the middle term for factoring by grouping.
3
Find two integers that multiply to -24 and add to -10.
The numbers −12-12 and 22 meet these conditions, since (−12)×2=−24(-12) \times 2 = -24 and (−12)+2=−10(-12) + 2 = -10.
This allows us to rewrite the middle term −10x-10x without changing the value of the polynomial.
4
Rewrite the middle term and factor by grouping.
8x2−12x+2x−38x^2 - 12x + 2x - 3. Grouping the terms yields (8x2−12x)+(2x−3)(8x^2 - 12x) + (2x - 3). Factoring out the greatest common factor from each group gives 4x(2x−3)+1(2x−3)4x(2x - 3) + 1(2x - 3).
Grouping transforms the four-term expression into a format where a common binomial factor can be extracted.
5
Factor out the common binomial factor and determine the final values.
Factoring out (2x−3)(2x - 3) leaves (4x+1)(2x−3)(4x + 1)(2x - 3). Comparing this to the given form (4x+a)(2x−b)(4x + a)(2x - b) reveals that a=1a = 1 and b=3b = 3.
Matching the derived factorization with the required format identifies the specific constants requested by the problem.

Anahtar Kavram

Factoring non-monic quadratic trinomials using the AC method and grouping.
Soru 22Soru →

Find the completely factored form of the given polynomial:

−12x2+30x+72-12x^2 + 30x + 72

Which of the following options shows the correct factorization?

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Cevap: −6(2x+3)(x−4)-6(2x + 3)(x - 4)

Cevap

The completely factored form is −6(2x+3)(x−4)-6(2x + 3)(x - 4).
The polynomial requires factoring out the Greatest Common Factor (GCF) of -6, which leaves the trinomial 2x2−5x−122x^2 - 5x - 12. Factoring this trinomial yields the binomials (2x+3)(2x + 3) and (x−4)(x - 4). Multiplying these by the GCF gives the fully factored expression.

Adım Adım Çözüm

1
Identify and factor out the Greatest Common Factor (GCF) from all terms in the polynomial −12x2+30x+72-12x^2 + 30x + 72.
The GCF is -6. Factoring this out gives: −6(2x2−5x−12)-6(2x^2 - 5x - 12).
Factoring out a negative GCF makes the leading coefficient of the trinomial positive, which simplifies the subsequent factoring steps.
2
Factor the remaining quadratic trinomial 2x2−5x−122x^2 - 5x - 12 by finding two integers that multiply to (2×−12)=−24(2 \times -12) = -24 and add to the middle coefficient −5-5.
The two integers are -8 and 3.
These integers will be used to split the middle term to factor by grouping.
3
Rewrite the trinomial by splitting the middle term using the integers found, then factor by grouping.
2x2−8x+3x−12=2x(x−4)+3(x−4)=(2x+3)(x−4)2x^2 - 8x + 3x - 12 = 2x(x - 4) + 3(x - 4) = (2x + 3)(x - 4).
Grouping allows us to factor out common binomials to find the factored form of the trinomial.
4
Combine the GCF with the factored binomials to write the final completely factored expression.
−6(2x+3)(x−4)-6(2x + 3)(x - 4)
A completely factored polynomial must include all extracted common factors alongside the irreducible binomial components.

Anahtar Kavram

Factoring polynomials using a Greatest Common Factor (GCF) and factoring non-monic trinomials.
Soru 23Soru →

Which of the following expressions is equivalent to 6x2−15x−366x^2 - 15x - 36 and is factored completely?

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Cevap: 3(2x+3)(x−4)3(2x + 3)(x - 4)

Cevap

The completely factored expression is 3(2x+3)(x−4)3(2x + 3)(x - 4).
The correct answer identifies the GCF of 3 and correctly factors the remaining quadratic 2x2−5x−122x^2 - 5x - 12 into (2x+3)(x−4)(2x + 3)(x - 4). Expanding this result confirms it equals 6x2−15x−366x^2 - 15x - 36 and no further factors can be extracted.

Adım Adım Çözüm

1
Identify and factor out the greatest common factor (GCF) from all three terms.
3(2x2−5x−12)3(2x^2 - 5x - 12)
The coefficients 6, -15, and -36 are all divisible by 3.
2
Find two numbers that multiply to acac (where a=2a=2 and c=−12c=-12, so 2×−12=−242 \times -12 = -24) and add to the middle coefficient (b=−5b=-5).
The numbers are −8-8 and 33.
(−8)×3=−24(-8) \times 3 = -24 and (−8)+3=−5(-8) + 3 = -5.
3
Rewrite the trinomial by splitting the middle term using these two numbers.
3(2x2−8x+3x−12)3(2x^2 - 8x + 3x - 12)
This sets up the polynomial for factoring by grouping.
4
Factor the trinomial by grouping.
3[2x(x−4)+3(x−4)]=3(2x+3)(x−4)3[2x(x - 4) + 3(x - 4)] = 3(2x + 3)(x - 4)
Factoring out (x−4)(x - 4) from both groups provides the final completely factored form.

Anahtar Kavram

Factoring out a GCF followed by factoring a non-monic trinomial.
Soru 24Soru →

Which of the following represents the completely factored form of the algebraic expression 30v3−35v2−15v30v^3 - 35v^2 - 15v?

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Cevap: 5v(3v+1)(2v−3)5v(3v + 1)(2v - 3)

Cevap

The completely factored form is 5v(3v+1)(2v−3)5v(3v + 1)(2v - 3).
The correct answer accurately extracts the Greatest Common Factor of 5v from the original expression, leaving the non-monic trinomial 6v^2 - 7v - 3. Factoring this remaining trinomial by grouping correctly yields the binomials (3v + 1) and (2v - 3). Expanding these prime factors back confirms they produce the exact original expression.

Adım Adım Çözüm

1
Identify and factor out the greatest common factor (GCF) from all three terms in the polynomial 30v3−35v2−15v30v^3 - 35v^2 - 15v.
5v(6v2−7v−3)5v(6v^2 - 7v - 3)
Factoring out the GCF simplifies the remaining polynomial and is a necessary first step for complete factorization.
2
Analyze the remaining quadratic trinomial 6v2−7v−36v^2 - 7v - 3 to factor it by grouping. Find two numbers that multiply to a×ca \times c (6×−3=−186 \times -3 = -18) and add to bb (−7-7).
The two numbers are −9-9 and 22.
These numbers allow us to split the middle term (−7v-7v) into two separate terms to enable factoring by grouping.
3
Rewrite the trinomial by splitting the middle term using the numbers found, then factor by grouping.
6v2−9v+2v−3=3v(2v−3)+1(2v−3)=(3v+1)(2v−3)6v^2 - 9v + 2v - 3 = 3v(2v - 3) + 1(2v - 3) = (3v + 1)(2v - 3)
Grouping the terms reveals the common binomial factor of (2v−3)(2v - 3).
4
Combine the GCF extracted in step 1 with the binomial factors found in step 3.
5v(3v+1)(2v−3)5v(3v + 1)(2v - 3)
This represents the original expression as a product of its simplest irreducible factors.

Anahtar Kavram

Factoring a polynomial by first extracting the greatest common factor (GCF), followed by factoring a non-monic quadratic trinomial using grouping.
Soru 25Soru →

Decompose the quadratic trinomial 6x2−11x−106x^2 - 11x - 10 into a product of two binomial factors structured as (ax−b)(cx+d)(ax - b)(cx + d). Assume all parameters (aa, bb, cc, and dd) are strictly positive integers. To ensure a unique arrangement, the leading coefficient aa must be strictly less than cc. Provide the values of the four parameters.

Aşağıdaki boşlukları doldurun

a=a = , b=b = , c=c = , and d=d = .
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Cevap

The parameters are a=2a = 2, b=5b = 5, c=3c = 3, and d=2d = 2.
Factoring the polynomial 6x2−11x−106x^2 - 11x - 10 using the AC method produces (2x−5)(3x+2)(2x - 5)(3x + 2). Matching these two factors against the template (ax−b)(cx+d)(ax - b)(cx + d) under the rule that a<ca < c (since 2<32 < 3) perfectly determines the positive integers as a=2a = 2, b=5b = 5, c=3c = 3, and d=2d = 2.

Adım Adım Çözüm

1
Identify the factoring technique for a non-monic quadratic trinomial in the form Ax2+Bx+CAx^2 + Bx + C.
The AC method (factoring by grouping) is required because the leading coefficient A=6A = 6 is greater than 1.
Directly finding factors of the constant CC that sum to BB only works when A=1A = 1.
2
Multiply the leading coefficient AA by the constant term CC.
6×(−10)=−606 \times (-10) = -60.
This establishes the target product needed to properly split the middle term for grouping.
3
Find two integers that multiply to −60-60 and add to the middle coefficient B=−11B = -11.
The correct pair of integers is −15-15 and 44.
(−15)×4=−60(-15) \times 4 = -60 and −15+4=−11-15 + 4 = -11.
4
Rewrite the middle term using these two integers and factor the resulting four-term expression by grouping.
6x2−15x+4x−10=3x(2x−5)+2(2x−5)=(2x−5)(3x+2)6x^2 - 15x + 4x - 10 = 3x(2x - 5) + 2(2x - 5) = (2x - 5)(3x + 2).
Grouping the first two terms and the last two terms reveals a common binomial factor of (2x−5)(2x - 5).
5
Match the factored expression to the required template (ax−b)(cx+d)(ax - b)(cx + d) while adhering to the condition a<ca < c.
The factors are (2x−5)(2x - 5) and (3x+2)(3x + 2). Since 2<32 < 3, (ax−b)(ax - b) corresponds exactly to (2x−5)(2x - 5), yielding a=2a=2 and b=5b=5. Consequently, (cx+d)(cx + d) corresponds to (3x+2)(3x + 2), yielding c=3c=3 and d=2d=2.
This guarantees a unique, correctly-ordered set of strictly positive parameters.

Anahtar Kavram

Factoring non-monic quadratic trinomials via grouping
Soru 26Soru →

Complete the factorization of the perfect square trinomial below by filling in the missing number.

Aşağıdaki boşlukları doldurun

$x^2 + 14x + 49 = (x + )^2$
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Cevap

7
A perfect square trinomial takes the general form x2+2bx+b2=(x+b)2x^2 + 2bx + b^2 = (x + b)^2. In the given expression x2+14x+49x^2 + 14x + 49, the constant term is 4949, which is 727^2. The middle term is 14x14x, which is equal to 2×7×x2 \times 7 \times x. Therefore, the expression factors directly as (x+7)2(x + 7)^2, meaning the missing number in the blank is 7.

Adım Adım Çözüm

1
Recognize the polynomial form
The expression x2+14x+49x^2 + 14x + 49 matches the structure of a perfect square trinomial: a2+2ab+b2a^2 + 2ab + b^2.
The first term is a perfect square (x2x^2), and the last term is a perfect square (49=7249 = 7^2).
2
Verify the middle term
Checking the middle term: 2×x×7=14x2 \times x \times 7 = 14x. This matches the middle term of the given expression.
Confirming the middle term proves the expression can be factored exactly as (a+b)2(a + b)^2.
3
Determine the missing value
The expression factors as (x+7)2(x + 7)^2.
Using the formula (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2 where a=xa = x and b=7b = 7.

Anahtar Kavram

Factoring perfect square trinomials
Soru 27Soru →

An engineer needs to simplify a calculation involving the volume of a component, modeled by the polynomial 4y3+12y2−72y4y^3 + 12y^2 - 72y. What is the fully factored equivalent of this polynomial?

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Cevap: 4y(y+6)(y−3)4y(y + 6)(y - 3)

Cevap

4y(y+6)(y−3)4y(y + 6)(y - 3)
To fully factor the given expression, first extract the greatest common factor (GCF). All terms share a common factor of 4y4y, yielding 4y(y2+3y−18)4y(y^2 + 3y - 18). Next, factor the resulting quadratic trinomial y2+3y−18y^2 + 3y - 18. The two numbers that multiply to −18-18 and sum to 33 are 66 and −3-3. This gives the binomial factors (y+6)(y + 6) and (y−3)(y - 3). Combining these with the GCF results in the completely factored form 4y(y+6)(y−3)4y(y + 6)(y - 3).

Adım Adım Çözüm

1
Identify and extract the greatest common factor (GCF) from all terms in the polynomial 4y3+12y2−72y4y^3 + 12y^2 - 72y.
4y(y2+3y−18)4y(y^2 + 3y - 18)
Factoring out the GCF simplifies the remaining polynomial, making it easier to factor completely.
2
Factor the remaining quadratic trinomial y2+3y−18y^2 + 3y - 18 by finding two integers that multiply to −18-18 and add to 33.
(y+6)(y−3)(y + 6)(y - 3)
The integers 66 and −3-3 satisfy both conditions: 6×(−3)=−186 \times (-3) = -18 and 6+(−3)=36 + (-3) = 3.
3
Combine the GCF with the factored binomials to state the final expression.
4y(y+6)(y−3)4y(y + 6)(y - 3)
This represents the original polynomial decomposed entirely into its lowest degree factors.

Anahtar Kavram

Factoring Polynomials with a GCF
Tahmini Süre:1m 0s
Soru 28Soru →

Pair each algebraic expression with its completely factored equivalent.

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Öğeler

4y2−16y4y^2 - 16y
y2−16y^2 - 16
y2−8y+16y^2 - 8y + 16
4y+164y + 16

Eşleşmeler

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Cevap

The correct pairings are: 4y2−16y4y^2 - 16y matches with 4y(y−4)4y(y - 4); y2−16y^2 - 16 matches with (y−4)(y+4)(y - 4)(y + 4); y2−8y+16y^2 - 8y + 16 matches with (y−4)2(y - 4)^2; and 4y+164y + 16 matches with 4(y+4)4(y + 4).
Each polynomial requires a distinct factoring method. Identifying the correct structure—such as GCF, difference of squares, or perfect square trinomial—leads directly to the completely factored form.

Adım Adım Çözüm

1
Factor 4y2−16y4y^2 - 16y
4y(y−4)4y(y - 4)
The terms share a greatest common factor of 4y4y.
2
Factor y2−16y^2 - 16
(y−4)(y+4)(y - 4)(y + 4)
It follows the difference of squares pattern a2−b2=(a−b)(a+b)a^2 - b^2 = (a - b)(a + b).
3
Factor y2−8y+16y^2 - 8y + 16
(y−4)2(y - 4)^2
It is a perfect square trinomial, as (−4)×(−4)=16(-4) \times (-4) = 16 and (−4)+(−4)=−8(-4) + (-4) = -8.
4
Factor 4y+164y + 16
4(y+4)4(y + 4)
The terms share a greatest common factor of 44.

Anahtar Kavram

Factoring polynomials using greatest common factors, difference of squares, and perfect square trinomial patterns.
Soru 29Soru →

Match each polynomial expression to its completely factored form.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

x2−16x^2 - 16
x2+6x+8x^2 + 6x + 8
2x2−12x+182x^2 - 12x + 18
3x2−5x−23x^2 - 5x - 2

Eşleşmeler

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Cevap

The correct matches pair each polynomial with its mathematically equivalent fully factored expression.
Each polynomial requires identifying its specific factoring archetype: the difference of two squares, a standard quadratic trinomial, GCF extraction followed by recognizing a perfect square trinomial, or factoring a non-monic trinomial.

Adım Adım Çözüm

1
Analyze the binomial x2−16x^2 - 16.
Matches to (x−4)(x+4)(x - 4)(x + 4).
It represents a difference of perfect squares.
2
Analyze the trinomial x2+6x+8x^2 + 6x + 8.
Matches to (x+2)(x+4)(x + 2)(x + 4).
The constants 2 and 4 have a product of 8 and a sum of 6.
3
Analyze the polynomial 2x2−12x+182x^2 - 12x + 18.
Matches to 2(x−3)22(x - 3)^2.
Factoring out the common factor of 2 leaves x2−6x+9x^2 - 6x + 9, which is the square of (x−3)(x - 3).
4
Analyze the polynomial 3x2−5x−23x^2 - 5x - 2.
Matches to (3x+1)(x−2)(3x + 1)(x - 2).
Multiplying the binomials (3x+1)(3x + 1) and (x−2)(x - 2) confirms it expands to the original expression.

Anahtar Kavram

Factoring different archetypes of polynomials, including the difference of squares, monic trinomials, non-monic trinomials, and extracting the Greatest Common Factor (GCF).
Soru 30Soru →

To optimize a packaging design, a technician models the surface area using the algebraic expression 18xy2−24xy−10x18xy^2 - 24xy - 10x. What is the fully factored equivalent of this expression?

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Cevap: 2x(3y−5)(3y+1)2x(3y - 5)(3y + 1)

Cevap

The fully factored equivalent is 2x(3y−5)(3y+1)2x(3y - 5)(3y + 1).
The expression is fully factored by first extracting the greatest common factor of 2x2x, resulting in 2x(9y2−12y−5)2x(9y^2 - 12y - 5). Then, using the ac-method, the remaining non-monic quadratic trinomial is factored into (3y−5)(3y+1)(3y - 5)(3y + 1), yielding the final correct product.

Adım Adım Çözüm

1
Identify and extract the greatest common factor (GCF) from all three terms.
2x(9y2−12y−5)2x(9y^2 - 12y - 5)
Extracting the GCF simplifies the polynomial and prepares the remaining quadratic trinomial for factoring.
2
Identify the components of the remaining quadratic trinomial ay2+by+cay^2 + by + c.
Here, a=9a = 9, b=−12b = -12, and c=−5c = -5.
This establishes the values needed to use the ac-method for factoring non-monic quadratics.
3
Find two numbers that multiply to acac and add to bb.
ac=9×−5=−45ac = 9 \times -5 = -45. The two numbers that multiply to −45-45 and add to −12-12 are −15-15 and 33.
These numbers allow the middle term to be split, enabling factoring by grouping.
4
Rewrite the middle term and factor the trinomial by grouping.
9y2−15y+3y−5=3y(3y−5)+1(3y−5)=(3y−5)(3y+1)9y^2 - 15y + 3y - 5 = 3y(3y - 5) + 1(3y - 5) = (3y - 5)(3y + 1)
This completes the factorization of the trinomial portion of the expression.
5
Combine the originally extracted GCF with the factored binomials.
2x(3y−5)(3y+1)2x(3y - 5)(3y + 1)
This yields the complete and fully factored form of the original polynomial.

Anahtar Kavram

Factoring Polynomials with a GCF
Soru 31Soru →

A rectangular garden has an area given by the expression 4n2−4n−244n^2 - 4n - 24. Which of the following represents the completely factored form of this area expression?

Cevabı ve açıklamayı göster

Cevap: 4(n−3)(n+2)4(n - 3)(n + 2)

Cevap

The completely factored form is 4(n−3)(n+2)4(n - 3)(n + 2).
To factor the expression completely, first remove the greatest common factor of 4 from all terms, which gives 4(n2−n−6)4(n^2 - n - 6). Then, factor the trinomial inside the parentheses. We need two numbers that multiply to -6 and add to -1, which are -3 and 2. This gives the completely factored form 4(n−3)(n+2)4(n - 3)(n + 2).

Adım Adım Çözüm

1
Identify and factor out the greatest common factor (GCF) from all terms in the polynomial 4n2−4n−244n^2 - 4n - 24.
4(n2−n−6)4(n^2 - n - 6)
Factoring out the GCF simplifies the polynomial and is the required first step for complete factorization.
2
Factor the remaining quadratic trinomial n2−n−6n^2 - n - 6 by finding two numbers that multiply to -6 and add to -1.
The numbers are -3 and 2, yielding (n−3)(n+2)(n - 3)(n + 2).
This breaks down the trinomial into its constituent binomial factors.
3
Combine the GCF and the binomial factors to write the final expression.
4(n−3)(n+2)4(n - 3)(n + 2)
This represents the full, completely factored form of the original area expression.

Anahtar Kavram

Factoring out a GCF followed by factoring a quadratic trinomial
Soru 32Soru →

Which of the following expressions represents the completely factored form of the polynomial 3k3−15k2−42k3k^3 - 15k^2 - 42k?

Cevabı ve açıklamayı göster

Cevap: 3k(k−7)(k+2)3k(k - 7)(k + 2)

Cevap

The completely factored form is 3k(k−7)(k+2)3k(k - 7)(k + 2).
The polynomial is completely factored by first extracting the Greatest Common Factor, 3k3k, which simplifies the expression to 3k(k2−5k−14)3k(k^2 - 5k - 14). Next, the remaining trinomial is factored by finding two numbers that multiply to −14-14 and add to −5-5. These numbers are −7-7 and 22. Combining these gives the final fully factored form of 3k(k−7)(k+2)3k(k - 7)(k + 2).

Adım Adım Çözüm

1
Identify and factor out the Greatest Common Factor (GCF) from all three terms of the polynomial.
The GCF of 3k33k^3, −15k2-15k^2, and −42k-42k is 3k3k. Factoring this out leaves 3k(k2−5k−14)3k(k^2 - 5k - 14).
Factoring out the GCF simplifies the remaining polynomial and is the required first step for complete factorization.
2
Factor the remaining quadratic trinomial, k2−5k−14k^2 - 5k - 14.
Find two integers that multiply to −14-14 (the constant term) and add to −5-5 (the coefficient of the middle term). These integers are −7-7 and 22. This yields the binomial factors (k−7)(k - 7) and (k+2)(k + 2).
These binomials represent the linear factors of the quadratic expression.
3
Combine the GCF and the binomial factors to write the fully factored expression.
3k(k−7)(k+2)3k(k - 7)(k + 2)
This represents the original polynomial as a product of its simplest prime factors.

Anahtar Kavram

Factoring polynomials by first extracting the Greatest Common Factor (GCF) and then factoring the resulting quadratic trinomial.
Tahmini Süre:1m 0s
Soru 33Soru →

The algebraic expression 5x2+35x5x^2 + 35x can be completely factored into the form 5x(x+c)5x(x + c). What is the value of the constant cc?

Cevabı ve açıklamayı göster

Cevap: 7; +7; seven; Seven

Cevap

7
By extracting the greatest common factor of 5x5x from 5x2+35x5x^2 + 35x, we divide both terms by 5x5x. This leaves (x+7)(x + 7) inside the parentheses. Comparing this to the given structure 5x(x+c)5x(x + c), it is clear that cc must be 7.

Adım Adım Çözüm

1
Identify the greatest common factor (GCF) of the terms 5x25x^2 and 35x35x.
The GCF is 5x5x.
Both terms are divisible by 5 and share a minimum of one xx.
2
Divide each term of the original expression by the GCF to find the binomial factor.
5x25x=x\frac{5x^2}{5x} = x and 35x5x=7\frac{35x}{5x} = 7.
Factoring out the GCF is the reverse of distributing it.
3
Write the factored form and compare it to the given form 5x(x+c)5x(x + c).
The factored form is 5x(x+7)5x(x + 7). Therefore, comparing it to 5x(x+c)5x(x + c), c=7c = 7.
Matching corresponding terms reveals the value of the unknown constant.

Anahtar Kavram

Factoring the Greatest Common Factor (GCF)
Soru 34Soru →

When the polynomial 5x2−205x^2 - 20 is factored completely into the form k(x−c)(x+c)k(x - c)(x + c), where kk and cc are positive integers, what is the value of the sum k+ck + c?

Cevabı ve açıklamayı göster

Cevap: 7; seven

Cevap

7
The polynomial 5x2−205x^2 - 20 can be factored completely by first pulling out the greatest common factor, 55, leaving 5(x2−4)5(x^2 - 4). The expression inside the parentheses is a difference of squares and factors into (x−2)(x+2)(x - 2)(x + 2). This makes the completely factored form 5(x−2)(x+2)5(x - 2)(x + 2). Comparing this to the form k(x−c)(x+c)k(x - c)(x + c), we see that k=5k = 5 and c=2c = 2. Their sum is 5+2=75 + 2 = 7.

Adım Adım Çözüm

1
Factor out the greatest common factor (GCF) from the polynomial.
5x2−20=5(x2−4)5x^2 - 20 = 5(x^2 - 4)
Both terms share a common numerical factor of 55. Factoring it out simplifies the remaining polynomial.
2
Factor the remaining binomial as a difference of squares.
5(x2−4)=5(x−2)(x+2)5(x^2 - 4) = 5(x - 2)(x + 2)
The binomial x2−4x^2 - 4 follows the pattern a2−b2=(a−b)(a+b)a^2 - b^2 = (a - b)(a + b), where a=xa = x and b=2b = 2.
3
Identify the values of kk and cc from the given form.
k=5k = 5 and c=2c = 2
By matching 5(x−2)(x+2)5(x - 2)(x + 2) to the target form k(x−c)(x+c)k(x - c)(x + c), the constant multiplier is 55 and the positive integer in the binomial is 22.
4
Calculate the sum of kk and cc.
5+2=75 + 2 = 7
The question asks for the final value of the sum k+ck + c.

Anahtar Kavram

Factoring polynomials using the greatest common factor and the difference of squares.
Soru 35Soru →

To determine the critical points of a trajectory, a physicist needs to fully factor the quadratic expression 4x2−8x−604x^2 - 8x - 60. What is the completely factored equivalent of this expression?

Cevabı ve açıklamayı göster

Cevap: 4(x−5)(x+3)4(x - 5)(x + 3)

Cevap

The completely factored form of the expression is 4(x−5)(x+3)4(x - 5)(x + 3).
The correct answer is found by first extracting the Greatest Common Factor (GCF), which is 44, leaving 4(x2−2x−15)4(x^2 - 2x - 15). Then, the inner trinomial x2−2x−15x^2 - 2x - 15 is factored into (x−5)(x+3)(x - 5)(x + 3) because −5-5 and 33 multiply to −15-15 and add to −2-2. Combining these gives the fully factored form 4(x−5)(x+3)4(x - 5)(x + 3).

Adım Adım Çözüm

1
Identify and factor out the Greatest Common Factor (GCF) from all terms in the expression 4x2−8x−604x^2 - 8x - 60.
The GCF of 44, −8-8, and −60-60 is 44. Factoring it out yields 4(x2−2x−15)4(x^2 - 2x - 15).
Extracting the GCF first simplifies the remaining polynomial, making the trinomial easier to factor.
2
Factor the remaining quadratic trinomial x2−2x−15x^2 - 2x - 15 by finding two numbers that multiply to the constant term (−15-15) and add to the middle term's coefficient (−2-2).
The numbers are −5-5 and 33, so the trinomial factors to (x−5)(x+3)(x - 5)(x + 3).
Expanding (x−5)(x+3)(x - 5)(x + 3) gives x2+3x−5x−15x^2 + 3x - 5x - 15, which simplifies back to x2−2x−15x^2 - 2x - 15.
3
Combine the GCF and the factored binomials to write the completely factored form.
4(x−5)(x+3)4(x - 5)(x + 3)
This represents the original expression broken down into its prime polynomial factors.

Anahtar Kavram

Factoring polynomials by first extracting the Greatest Common Factor (GCF) and then factoring the resulting quadratic trinomial.
Tahmini Süre:1m 0s
Soru 36Soru →

Complete the factored form of the polynomial by finding the missing values.

Aşağıdaki boşlukları doldurun

The polynomial 6x2−6x−726x^2 - 6x - 72 can be factored completely into the form 6(x−a)(x+b)6(x - a)(x + b). The missing positive integers are a=a = and b=b = .
Cevabı ve açıklamayı göster

Cevap

The missing values are a = 4 and b = 3. The completely factored form is 6(x - 4)(x + 3).
To factor the polynomial 6x2−6x−726x^2 - 6x - 72 completely, we first factor out the greatest common factor (GCF), which is 66. This leaves us with the expression 6(x2−x−12)6(x^2 - x - 12). Next, we factor the quadratic trinomial x2−x−12x^2 - x - 12. We need to find two integers that multiply to give −12-12 and add up to −1-1. Those integers are −4-4 and 33. This means the trinomial factors as (x−4)(x+3)(x - 4)(x + 3). Combining these, the complete factorization is 6(x−4)(x+3)6(x - 4)(x + 3). By comparing this result to the given format 6(x−a)(x+b)6(x - a)(x + b), we can see that the first missing value is a=4a = 4 and the second missing value is b=3b = 3.

Adım Adım Çözüm

1
Identify and factor out the greatest common factor (GCF) from the polynomial.
The GCF of the terms 6x26x^2, −6x-6x, and −72-72 is 66. Factoring this out gives: 6(x2−x−12)6(x^2 - x - 12).
Factoring out the GCF simplifies the remaining quadratic expression, making it easier to factor into binomials.
2
Factor the remaining quadratic trinomial x2−x−12x^2 - x - 12.
We look for two numbers that multiply to −12-12 and add up to −1-1 (the coefficient of the middle term). These numbers are −4-4 and 33. Thus, x2−x−12x^2 - x - 12 factors to (x−4)(x+3)(x - 4)(x + 3).
A monic quadratic trinomial x2+px+qx^2 + px + q factors into (x+m)(x+n)(x + m)(x + n) where m×n=qm \times n = q and m+n=pm + n = p.
3
Write the complete factorization and match it to the given format.
The completely factored expression is 6(x−4)(x+3)6(x - 4)(x + 3). Matching this to the given form 6(x−a)(x+b)6(x - a)(x + b), we determine that a=4a = 4 and b=3b = 3.
This directly identifies the specific positive integers required to complete the given algebraic expression.

Anahtar Kavram

Factoring out a Greatest Common Factor (GCF) followed by factoring a standard quadratic trinomial.
Soru 37Soru →

During an algebra calculation, an engineer needs to rewrite the expression 2x2+7x−152x^2 + 7x - 15 in its completely factored form. Which of the following is equivalent to this expression?

Cevabı ve açıklamayı göster

Cevap: (2x−3)(x+5)(2x - 3)(x + 5)

Cevap

The correct factorization is (2x−3)(x+5)(2x - 3)(x + 5).
The correct answer is mathematically equivalent to the original polynomial. Expanding it using the FOIL method confirms this: (2x)(x)+(2x)(5)+(−3)(x)+(−3)(5)=2x2+10x−3x−15=2x2+7x−15(2x)(x) + (2x)(5) + (-3)(x) + (-3)(5) = 2x^2 + 10x - 3x - 15 = 2x^2 + 7x - 15.

Adım Adım Çözüm

1
Identify the coefficients of the quadratic expression ax2+bx+cax^2 + bx + c.
a=2a = 2, b=7b = 7, and c=−15c = -15.
Identifying these values is required to determine the target product and sum for factoring by grouping.
2
Find two numbers that multiply to a×ca \times c and add up to bb.
The numbers are 1010 and −3-3 because 10×(−3)=−3010 \times (-3) = -30 and 10+(−3)=710 + (-3) = 7.
These specific numbers allow us to logically split the middle term of the polynomial.
3
Rewrite the middle term 7x7x using these two numbers and factor the polynomial by grouping.
2x2+10x−3x−15=2x(x+5)−3(x+5)=(2x−3)(x+5)2x^2 + 10x - 3x - 15 = 2x(x + 5) - 3(x + 5) = (2x - 3)(x + 5).
Extracting the greatest common factor from each pair reveals the common binomial factor, completing the factorization.

Anahtar Kavram

Factoring non-monic quadratic trinomials by grouping
Soru 38Soru →

Match each polynomial expression with its completely factored algebraic form.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

9x2−16y29x^2 - 16y^2
x2−8x+15x^2 - 8x + 15
3x2+12x−363x^2 + 12x - 36
2x2+5x−122x^2 + 5x - 12

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

The expressions correctly match their completely factored forms by applying the rules for difference of squares, perfect trinomials, extracting a greatest common factor, and factoring by grouping.
Each polynomial must be analyzed to find its unique factors. Recognizing perfect squares, extracting common factors first, and finding the correct binomial number pairs based on sum and product rules lead to the correct matches.

Adım Adım Çözüm

1
Identify the structure of each polynomial to determine the correct factoring technique.
Categorize the expressions into difference of squares, monic trinomials, GCF + trinomial, and non-monic trinomials.
Applying the correct initial technique is essential to fully factoring the polynomial.
2
Apply the corresponding factoring method to break down the polynomial into its most basic prime factors.
Each expression is rewritten as a product of binomials and, if applicable, a constant scalar.
This verifies that the polynomial is factored completely, revealing the correct match.

Anahtar Kavram

Factoring Polynomials
Soru 39Soru →

To analyze the zeroes of a mathematical function, the algebraic expression 3x3+6x2−9x3x^3 + 6x^2 - 9x must be written as a product of its simplest linear factors. Which of the following represents the completely factored equivalent of this expression?

Cevabı ve açıklamayı göster

Cevap: 3x(x+3)(x−1)3x(x + 3)(x - 1)

Cevap

The completely factored equivalent is 3x(x+3)(x−1)3x(x + 3)(x - 1).
The correct answer successfully extracts the greatest common factor, 3x3x, leaving the quadratic trinomial x2+2x−3x^2 + 2x - 3. This trinomial factors correctly into (x+3)(x−1)(x + 3)(x - 1) because 33 and −1-1 multiply to −3-3 and add to positive 22.

Adım Adım Çözüm

1
Identify and extract the Greatest Common Factor (GCF) from all three terms in the expression 3x3+6x2−9x3x^3 + 6x^2 - 9x.
3x(x2+2x−3)3x(x^2 + 2x - 3)
Factoring out the GCF simplifies the remaining polynomial, making it possible to factor the quadratic trinomial.
2
Find two integers that multiply to the constant term (−3-3) and add to the middle coefficient (22).
The correct integers are 33 and −1-1.
These values are needed to factor the quadratic trinomial x2+2x−3x^2 + 2x - 3 into two binomials.
3
Rewrite the trinomial as a product of two binomials and combine it with the previously extracted GCF.
3x(x+3)(x−1)3x(x + 3)(x - 1)
This provides the final, completely factored form of the original algebraic expression.

Anahtar Kavram

Factoring Polynomials via GCF and Trinomial Methods
Soru 40Soru →

An architect is designing a rectangular layout where the area is represented by the algebraic expression 4y2+12y−404y^2 + 12y - 40. To determine the possible dimensions of the layout in terms of yy, the architect needs to rewrite this expression in its completely factored form. Which of the following represents the completely factored expression?

Cevabı ve açıklamayı göster

Cevap: 4(y+5)(y−2)4(y + 5)(y - 2)

Cevap

The completely factored expression is 4(y+5)(y−2)4(y + 5)(y - 2).
The correct answer completely factors out the GCF of 4 from all terms and correctly factors the remaining trinomial y2+3y−10y^2 + 3y - 10 into (y+5)(y−2)(y + 5)(y - 2).

Adım Adım Çözüm

1
Identify and extract the greatest common factor (GCF) from all terms in the expression 4y2+12y−404y^2 + 12y - 40.
4(y2+3y−10)4(y^2 + 3y - 10)
Factoring out the GCF simplifies the polynomial and makes the remaining trinomial easier to factor.
2
Find two integers that multiply to the constant term (-10) and add to the coefficient of the middle term (3).
The correct integers are 5 and -2.
These integers are required to construct the binomial factors of the simplified trinomial y2+3y−10y^2 + 3y - 10.
3
Write the trinomial as a product of two binomials using the integers found, and combine them with the GCF.
4(y+5)(y−2)4(y + 5)(y - 2)
This represents the original expression fully broken down into its prime polynomial factors.

Anahtar Kavram

Factoring Polynomials by Extracting the GCF and Grouping
ÖncekiSayfa 2 / 3Sonraki
Factoring Polynomials Alıştırma Soruları — Armed Services Vocational Aptitude Battery (ASVAB) — Sayfa 2 | Examkin