Single Event Probability

18 soru

Soru 1Soru →

During a land navigation exercise, an instructor maps out 150 possible waypoint coordinates. Of these waypoints, 45 are located in dense forest, 35 are in open terrain, 50 are near water features, and the remaining waypoints are on elevated ridges. If a cadet is randomly assigned one waypoint coordinate, what is the probability that it is located on an elevated ridge? (Express your answer as a simplified fraction)

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Cevap: 2/15; 2 / 15

Cevap

2/15
The correct probability is found by dividing the number of ridge waypoints (20) by the total number of waypoints (150). Simplifying the fraction 20/150 yields 2/15.

Adım Adım Çözüm

1
Determine the total number of possible outcomes.
Total waypoints = 150.
The denominator for a single event probability calculation is the total number of items in the set.
2
Calculate the number of favorable outcomes (elevated ridge waypoints).
150 - (45 + 35 + 50) = 150 - 130 = 20 waypoints on elevated ridges.
You must subtract the sum of all known waypoint categories from the total to find the unknown remainder.
3
Set up the probability ratio and simplify the fraction.
20 / 150 simplifies to 2 / 15.
Probability is the number of favorable outcomes divided by total outcomes. ASVAB format requires fractions to be reduced to their lowest terms.

Anahtar Kavram

Single Event Probability
Soru 2Soru →

An aviation squadron has a total of 3030 crew members available for assignment. The squadron consists of 1212 pilots, 1010 mechanics, 55 medics, and 33 navigators. If one crew member is randomly selected to lead a safety briefing, what is the probability that the selected member is NOT a mechanic?

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Cevap: 23\frac{2}{3}

Cevap

The correct probability is 23\frac{2}{3}.
The correct answer is found by identifying the total number of crew members who are not mechanics (30−10=2030 - 10 = 20) and dividing this by the total number of crew members (3030). This forms the fraction 2030\frac{20}{30}, which simplifies to 23\frac{2}{3}.

Adım Adım Çözüm

1
Identify the total number of possible outcomes.
Total crew members = 3030.
The denominator for a single event probability is the total population from which the selection is made.
2
Determine the number of favorable outcomes (crew members who are NOT mechanics).
30−10=2030 - 10 = 20 crew members.
The probability of a complementary event ('NOT' an event) can be found by subtracting the specific group from the total.
3
Calculate the probability as a ratio and simplify the fraction.
Probability = 2030=23\frac{20}{30} = \frac{2}{3}.
Probability is the number of favorable outcomes over the total outcomes, expressed in its simplest form.

Anahtar Kavram

Probability of a Complementary Event
Soru 3Soru →

An armory has a total of 5050 training rifles on a rack. Exactly 1515 of these rifles are equipped with laser sights. If a recruit is randomly issued one of these training rifles, what is the probability, expressed as a decimal, that they receive a rifle with a laser sight?

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Cevap: 0.3

Cevap

0.3
The probability of a single event is calculated by dividing the number of specific desired outcomes by the total number of possible outcomes. In this scenario, there are 15 rifles with laser sights out of a total of 50 rifles in the armory. Therefore, the probability is 15/50. To express this as a decimal, you can simplify the fraction by dividing the numerator and denominator by 5 to get 3/10, which easily converts to 0.3.

Adım Adım Çözüm

1
Determine the total number of possible outcomes.
50
This is the total number of training rifles available on the rack.
2
Determine the number of favorable outcomes.
15
This is the number of training rifles equipped with laser sights, which represents the target event.
3
Calculate the probability by dividing the favorable outcomes by the total possible outcomes.
15 / 50 = 3 / 10 = 0.3
The basic formula for single event probability is the ratio of target outcomes to total outcomes.

Anahtar Kavram

Single Event Probability
Soru 4Soru →

A deck of flashcards used for language training contains 5050 cards. There are 1515 vocabulary cards, 2525 grammar cards, and 1010 phrase cards. If a student randomly selects one card from the deck to study, what is the probability that it is a vocabulary card?

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Cevap: 310\frac{3}{10}

Cevap

310\frac{3}{10}
The correct answer is found by dividing the number of vocabulary cards by the total number of cards in the deck. There are 1515 vocabulary cards out of 5050 total cards. The fraction 1550\frac{15}{50} simplifies to 310\frac{3}{10} when both the numerator and denominator are divided by their greatest common factor, 55.

Adım Adım Çözüm

1
Identify the total number of possible outcomes.
Total cards = 5050
The denominator of a probability fraction is the total number of items in the set.
2
Identify the number of favorable outcomes.
Vocabulary cards = 1515
The question asks specifically for the probability of drawing a vocabulary card.
3
Set up the probability fraction and simplify.
1550=310\frac{15}{50} = \frac{3}{10}
Probability is the ratio of favorable outcomes to total outcomes, and fractions should be reduced to their simplest form.

Anahtar Kavram

Calculating single event probability as the ratio of favorable outcomes to the total number of possible outcomes.
Soru 5Soru →

A box contains a mixture of red, blue, and green tokens. There are exactly 1616 red tokens in the box. The probability of randomly selecting a red token is 25\frac{2}{5}. If there are 1414 blue tokens in the box, what is the probability of randomly selecting a green token on a single draw?

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Cevap: 14\frac{1}{4}

Cevap

The probability of randomly selecting a green token is 14\frac{1}{4}.
To find the probability of drawing a green token, you must first know the total number of tokens. Because the 1616 red tokens make up 25\frac{2}{5} of the total, the total number of tokens is 16÷25=4016 \div \frac{2}{5} = 40. The box contains 1616 red and 1414 blue tokens, accounting for 3030 tokens. This leaves 1010 green tokens (40−3040 - 30). The probability of selecting a green token is the number of green tokens divided by the total number of tokens: 1040\frac{10}{40}, which reduces to 14\frac{1}{4}.

Adım Adım Çözüm

1
Determine the total number of tokens in the box.
Total tokens = 4040
Since 1616 red tokens represent a probability of 25\frac{2}{5}, we can find the total by dividing the part by its fraction: 16÷25=16×52=4016 \div \frac{2}{5} = 16 \times \frac{5}{2} = 40.
2
Calculate the number of green tokens.
Green tokens = 1010
Subtract the known red and blue tokens from the total: 40−16 (red)−14 (blue)=10 green tokens40 - 16 \text{ (red)} - 14 \text{ (blue)} = 10 \text{ green tokens}.
3
Calculate the probability of drawing a green token.
Probability = 14\frac{1}{4}
Probability is the number of favorable outcomes divided by total outcomes: 1040\frac{10}{40}, which simplifies to 14\frac{1}{4}.

Anahtar Kavram

Single Event Probability and Total Outcomes
Soru 6Soru →

A maintenance kit contains 1212 metric wrenches, 1515 standard wrenches, 99 screwdrivers, and an unknown number of pliers. If the probability of randomly selecting a screwdriver from the entire kit is 16\frac{1}{6}, what is the probability of randomly selecting a standard wrench? Express your answer as a fraction in simplest form.

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Cevap: 5/18;518;5/185/18; \frac{5}{18}; 5 / 18

Cevap

5/18
By using the given probability of selecting a screwdriver (1/6) and the known count of screwdrivers (9), we determine that the total number of items in the kit is 54 (because 9 is 1/6 of 54). The probability of randomly selecting a standard wrench is then the number of standard wrenches (15) divided by the total (54). Simplifying the fraction 15/54 by dividing both numbers by 3 yields 5/18.

Adım Adım Çözüm

1
Set up an equation to find the total number of items in the kit.
9Total=16\frac{9}{\text{Total}} = \frac{1}{6}
The probability of an event is the number of favorable outcomes divided by the total number of possible outcomes. Here, we know the probability and the exact count of screwdrivers.
2
Solve for the total number of items.
\text{Total} = 9 \times 6 = 54
Cross-multiplying isolates the total variable, revealing there are 54 items in the entire kit.
3
Calculate the probability of selecting a standard wrench.
Probability=1554\text{Probability} = \frac{15}{54}
There are 15 standard wrenches out of the 54 total items calculated.
4
Simplify the fraction.
1554=518\frac{15}{54} = \frac{5}{18}
Both 15 and 54 are divisible by 3. Dividing the numerator and denominator by 3 gives the simplest form.

Anahtar Kavram

Calculating probabilities by determining the total sample size from a known probability.
Soru 7Soru →

A military supply depot receives a shipment of 400400 uniform jackets. Of these jackets, 25%25\% are size Small, 38\frac{3}{8} are size Medium, and the remaining jackets are divided equally between size Large and size Extra-Large. If a quartermaster randomly selects one jacket from the entire shipment, what is the probability that it is a size Extra-Large jacket?

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Cevap: 316\frac{3}{16}

Cevap

316\frac{3}{16}
The probability of a single event is the number of favorable outcomes divided by the total number of possible outcomes. First, determine the number of Extra-Large jackets. There are 100100 Small jackets (25%25\% of 400400) and 150150 Medium jackets (38\frac{3}{8} of 400400). This leaves 150150 jackets (400−100−150=150400 - 100 - 150 = 150). Since these remaining jackets are divided equally between Large and Extra-Large, there are exactly 7575 Extra-Large jackets. The probability of randomly selecting an Extra-Large jacket is the number of Extra-Large jackets (7575) over the total number of jackets (400400). Simplifying the fraction 75400\frac{75}{400} by dividing the numerator and denominator by 2525 yields 316\frac{3}{16}.

Adım Adım Çözüm

1
Calculate the number of Small jackets in the shipment.
25%25\% of 400400 is 100100 jackets.
To find the remaining jackets, you first need to determine the exact counts of the known sizes.
2
Calculate the number of Medium jackets in the shipment.
38\frac{3}{8} of 400=3×50=150400 = 3 \times 50 = 150 jackets.
Converting the fraction to an exact count is required to subtract from the total.
3
Determine the number of jackets remaining for the Large and Extra-Large sizes.
400−(100+150)=400−250=150400 - (100 + 150) = 400 - 250 = 150 remaining jackets.
Subtracting the known sizes from the total gives the combined count of the remaining two sizes.
4
Calculate the number of Extra-Large jackets.
150÷2=75150 \div 2 = 75 Extra-Large jackets.
The problem states the remaining jackets are divided equally between the final two sizes.
5
Calculate the probability of selecting an Extra-Large jacket.
Probability =75400= \frac{75}{400}.
Single event probability is the number of favorable outcomes divided by the total number of possible outcomes.
6
Simplify the probability fraction.
75400=316\frac{75}{400} = \frac{3}{16}.
Standardized tests require probability fractions to be in simplest form.

Anahtar Kavram

Single Event Probability
Soru 8Soru →

An armory stores a mixture of lithium, alkaline, and nickel-metal hydride (NiMH) batteries. The probability of randomly selecting a lithium battery from the storage is 25\frac{2}{5}. If there are exactly 4848 lithium batteries in the armory, what is the total number of batteries stored?

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Cevap: 120120

Cevap

The total number of batteries stored is 120.
The correct answer is found by setting up the proportion derived from the probability definition: 2/5 = 48/x. Cross-multiplying gives 2x = 240, and dividing by 2 results in 120 total batteries.

Adım Adım Çözüm

1
Set up the probability formula using the given information.
Probability=Number of LithiumTotal Batteries\text{Probability} = \frac{\text{Number of Lithium}}{\text{Total Batteries}}, so 25=48x\frac{2}{5} = \frac{48}{x}, where xx is the total number of batteries.
Single event probability is the ratio of favorable outcomes to the total number of possible outcomes.
2
Solve the proportion for xx by cross-multiplying.
2x=5×482x = 5 \times 48
Cross-multiplying allows us to solve an equation with fractions and isolate the variable terms.
3
Simplify the equation and isolate xx.
2x=2402x = 240, so x=2402=120x = \frac{240}{2} = 120.
Dividing both sides by 2 isolates the variable, revealing the total number of batteries.

Anahtar Kavram

Calculating the total number of outcomes given the probability of a single event and the number of favorable outcomes.
Soru 9Soru →

A quartermaster is organizing a drawer of 6060 uniform patches. The drawer contains 1515 rank insignia patches, 2121 unit patches, and the remaining patches are flag patches. If one patch is randomly selected from the drawer, what is the probability of selecting a flag patch? Express your answer as a decimal.

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Cevap: 0.4

Cevap

0.4
The probability is found by dividing the number of flag patches (2424) by the total number of patches (6060). The fraction 2460\frac{24}{60} simplifies to 25\frac{2}{5}, which is 0.40.4 when expressed as a decimal.

Adım Adım Çözüm

1
Calculate the number of flag patches in the drawer.
60−(15+21)=60−36=2460 - (15 + 21) = 60 - 36 = 24 flag patches.
To determine the probability, the exact number of the desired item (flag patches) must first be known.
2
Set up the probability fraction.
2460\frac{24}{60}
The probability of a single event is the number of favorable outcomes divided by the total number of possible outcomes.
3
Convert the fraction to a decimal.
2460=25=0.4\frac{24}{60} = \frac{2}{5} = 0.4
The question explicitly specifies that the final answer must be expressed as a decimal.

Anahtar Kavram

Single Event Probability
Soru 10Soru →

A motor pool inventory shows that 14\frac{1}{4} of the vehicles are heavy trucks, 13\frac{1}{3} are light tactical vehicles, and the remaining vehicles are armored personnel carriers. If a vehicle is randomly selected for an inspection, what is the probability that it is an armored personnel carrier?

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Cevap: 512\frac{5}{12}

Cevap

512\frac{5}{12}
The total probability of all mutually exclusive events must sum to 1. First, find the combined probability of heavy trucks and light tactical vehicles by using a common denominator of 12: 14\frac{1}{4} becomes 312\frac{3}{12} and 13\frac{1}{3} becomes 412\frac{4}{12}. Their sum is 712\frac{7}{12}. Since the remaining vehicles are armored personnel carriers, subtract this sum from the total probability of 1 (or 1212\frac{12}{12}). The result is 512\frac{5}{12}.

Adım Adım Çözüm

1
Find the combined probability of selecting a heavy truck or a light tactical vehicle.
14+13\frac{1}{4} + \frac{1}{3}
To determine the portion of the fleet that is not armored personnel carriers, the given fractions must be added.
2
Add the fractions by finding a common denominator.
312+412=712\frac{3}{12} + \frac{4}{12} = \frac{7}{12}
Fractions must have the same denominator (12) before their numerators can be added.
3
Subtract the combined fraction from 1 (the total probability).
1−712=1212−712=5121 - \frac{7}{12} = \frac{12}{12} - \frac{7}{12} = \frac{5}{12}
The sum of probabilities for all possible events must equal exactly 1. The remainder represents the armored personnel carriers.

Anahtar Kavram

Single Event Probability from Complementary Events
Tahmini Süre:1m 0s
Soru 11Soru →

An electrician's toolbox contains 88 red wire connectors, 1414 blue wire connectors, and 1010 green wire connectors. If the electrician randomly selects one connector without looking, what is the probability that it is NOT a blue connector?

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Cevap: 916\frac{9}{16}

Cevap

916\frac{9}{16}
The probability of an event is calculated by dividing the number of favorable outcomes by the total number of possible outcomes. There are 32 total connectors in the toolbox. The number of connectors that are NOT blue is 18 (8 red + 10 green). Therefore, the probability is 18/32, which simplifies to 9/16.

Adım Adım Çözüm

1
Calculate the total number of wire connectors in the toolbox.
8+14+10=328 + 14 + 10 = 32 total connectors.
The denominator of a probability fraction represents the total number of possible outcomes.
2
Determine the number of favorable outcomes (connectors that are NOT blue).
88 (red) +10+ 10 (green) =18= 18 connectors that are not blue. Alternatively, 3232 (total) −14- 14 (blue) =18= 18.
The question asks for the probability of selecting a connector that is NOT blue.
3
Set up the probability fraction and simplify.
1832=18÷232÷2=916\frac{18}{32} = \frac{18 \div 2}{32 \div 2} = \frac{9}{16}
Probability is favorable outcomes over total outcomes, and must always be expressed in simplest form.

Anahtar Kavram

Single Event Probability
Soru 12Soru →

A supply sergeant is organizing a crate of 150150 signal flares. The crate contains 5050 red flares, 4040 green flares, 3636 yellow flares, and the remaining flares are white. If a recruit randomly selects one flare from the crate without looking, what is the probability that they select a white flare? Express your answer as a decimal.

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Cevap: 0.16

Cevap

0.16
The correct probability is found by first determining the number of white flares (150−126=24150 - 126 = 24), and then dividing that number by the total number of flares to find the probability of a single event (24÷150=0.1624 \div 150 = 0.16).

Adım Adım Çözüm

1
Calculate the total number of red, green, and yellow flares.
50+40+36=12650 + 40 + 36 = 126
This is required to find out how many flares are in the known color categories.
2
Calculate the number of white flares.
150−126=24150 - 126 = 24
Subtracting the other flares from the total gives the remaining white flares.
3
Calculate the probability of selecting a white flare.
24150\frac{24}{150}
Probability is the number of favorable outcomes (white flares) divided by the total number of possible outcomes (total flares).
4
Convert the fraction to a decimal.
24150=425=0.16\frac{24}{150} = \frac{4}{25} = 0.16
The question specifically asks for the answer to be expressed as a decimal.

Anahtar Kavram

Single Event Probability
Tahmini Süre:1m 0s
Soru 13Soru →

A dining facility manager is planning a special event and will randomly select one pie from a large frozen delivery. According to the shipping manifest, 13\frac{1}{3} of the pies are apple, 14\frac{1}{4} are cherry, 15\frac{1}{5} are blueberry, and the rest are pecan. What is the probability that the randomly selected pie is a pecan pie?

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Cevap: 1360\frac{13}{60}

Cevap

The probability of selecting a pecan pie is 1360\frac{13}{60}.
The sum of the probabilities of all possible outcomes in this scenario must equal 1. By finding a common denominator (60), we determine that apple, cherry, and blueberry pies account for 4760\frac{47}{60} of the delivery. The remaining fraction, 1360\frac{13}{60}, represents the probability of selecting a pecan pie.

Adım Adım Çözüm

1
Find a common denominator to add the fractions of the known pie types (13\frac{1}{3}, 14\frac{1}{4}, and 15\frac{1}{5}).
The least common multiple of 3, 4, and 5 is 60.
Fractions must have the same denominator before they can be added.
2
Convert each fraction to an equivalent fraction with a denominator of 60.
13=2060\frac{1}{3} = \frac{20}{60}, 14=1560\frac{1}{4} = \frac{15}{60}, and 15=1260\frac{1}{5} = \frac{12}{60}.
This allows for straight addition of the numerators.
3
Add the equivalent fractions to find the total portion of apple, cherry, and blueberry pies.
2060+1560+1260=4760\frac{20}{60} + \frac{15}{60} + \frac{12}{60} = \frac{47}{60}.
This sum represents all the pies in the delivery that are NOT pecan.
4
Subtract this sum from 1 (the whole delivery) to find the probability of selecting a pecan pie.
1−4760=6060−4760=13601 - \frac{47}{60} = \frac{60}{60} - \frac{47}{60} = \frac{13}{60}.
The sum of all possible mutually exclusive outcomes must equal 1.

Anahtar Kavram

Single Event Probability and Fraction Operations
Soru 14Soru →

A logistics officer is inspecting a shipment of 120120 combat helmets. The shipment contains 4545 large helmets, 3535 medium helmets, 2424 small helmets, and the remaining helmets are extra-large. If the officer randomly selects one helmet for quality control, what is the probability that it is an extra-large helmet? Express your answer as a fraction in simplest form.

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Cevap: 2/15; 2 / 15

Cevap

2/15
The correct answer is derived by first finding the number of extra-large helmets. Subtracting the known sizes from the total yields 120−104=16120 - 104 = 16 extra-large helmets. The probability of selecting an extra-large helmet is the ratio of extra-large helmets to the total inventory, which is 16120\frac{16}{120}. Simplifying this fraction by dividing both the numerator and the denominator by their greatest common divisor (88) yields the final probability of 215\frac{2}{15}.

Adım Adım Çözüm

1
Calculate the total number of known helmets.
45+35+24=10445 + 35 + 24 = 104
To find the number of extra-large helmets, we first need to determine how many helmets belong to the other given size categories.
2
Determine the number of extra-large helmets.
120−104=16120 - 104 = 16
Subtracting the sum of the known sizes from the total number of helmets gives the remaining count, which represents the extra-large helmets.
3
Set up the probability fraction.
16120\frac{16}{120}
The probability of a single event is the number of favorable outcomes (1616 extra-large helmets) divided by the total number of possible outcomes (120120 total helmets).
4
Simplify the fraction.
215\frac{2}{15}
Divide the numerator and denominator by their greatest common divisor, which is 88 (16÷8=216 \div 8 = 2 and 120÷8=15120 \div 8 = 15).

Anahtar Kavram

Single Event Probability
Soru 15Soru →

A communications specialist is inventorying a batch of hand-held radios. The batch contains 1818 VHF radios, 1212 UHF radios, and 2020 dual-band radios. If one radio is randomly selected for a quality check, what is the probability that it is a VHF radio? Express your answer as a simplified fraction.

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Cevap: 9/25;9/25;9259/25; 9 / 25; \frac{9}{25}

Cevap

9/25
The probability of an event is the number of favorable outcomes divided by the total number of possible outcomes. There are 1818 VHF radios and a total of 5050 radios (18+12+2018 + 12 + 20). The probability is 1850\frac{18}{50}, which simplifies to 925\frac{9}{25} by dividing both the numerator and the denominator by 22.

Adım Adım Çözüm

1
Calculate the total number of radios in the batch.
18+12+20=5018 + 12 + 20 = 50
The denominator of a probability fraction represents the total number of possible outcomes.
2
Identify the number of favorable outcomes.
1818 VHF radios
The numerator of a probability fraction represents the number of favorable outcomes.
3
Set up the probability ratio and simplify.
1850=925\frac{18}{50} = \frac{9}{25}
Probability is the ratio of favorable outcomes to total outcomes, and the question asks for a simplified fraction.

Anahtar Kavram

Single event probability is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.
Soru 16Soru →

An intelligence analyst has a container of map pins used for marking locations on a briefing board. The container holds 2424 red pins, 1616 blue pins, and 1010 green pins. If the analyst randomly selects one pin from the container, what is the probability that it is a blue pin?

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Cevap: 825\frac{8}{25}

Cevap

The probability of selecting a blue pin is 825\frac{8}{25}.
The probability of a single event is found by dividing the number of favorable outcomes by the total number of outcomes. There are 1616 blue pins (favorable outcomes) and a total of 5050 pins (24+16+1024 + 16 + 10). This creates the fraction 1650\frac{16}{50}, which simplifies to 825\frac{8}{25} when both numbers are divided by 22.

Adım Adım Çözüm

1
Determine the total number of possible outcomes.
24 (red)+16 (blue)+10 (green)=50 total pins24 \text{ (red)} + 16 \text{ (blue)} + 10 \text{ (green)} = 50 \text{ total pins}
The denominator of a probability fraction must represent all possible items that can be selected.
2
Identify the number of favorable outcomes.
16 blue pins16 \text{ blue pins}
The numerator must represent the specific event being asked for (selecting a blue pin).
3
Set up the probability fraction and simplify.
1650=16÷250÷2=825\frac{16}{50} = \frac{16 \div 2}{50 \div 2} = \frac{8}{25}
Fractions must always be reduced to their simplest form by dividing both the numerator and denominator by their greatest common factor.

Anahtar Kavram

Single Event Probability
Soru 17Soru →

A motor pool has a fleet of 4040 vehicles available for dispatch. The fleet consists of 2525 HMMWVs, 1010 transport trucks, and 55 tactical ambulances. If a dispatcher selects one vehicle at random for a surprise inspection, what is the probability, expressed as a fraction in simplest form, that the selected vehicle is a tactical ambulance?

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Cevap: 1/8; 1 / 8

Cevap

1/8
The probability of an event is found by dividing the number of favorable outcomes by the total number of possible outcomes. There are 5 tactical ambulances out of a total 40 vehicles. The resulting fraction is 5/40, which simplifies to 1/8 by dividing both the numerator and the denominator by 5.

Adım Adım Çözüm

1
Identify the total number of possible outcomes.
The total number of vehicles in the motor pool is 4040.
The denominator of a single event probability fraction represents the total number of items in the population.
2
Identify the number of favorable outcomes.
There are 55 tactical ambulances.
The numerator represents the count of the specific target items being selected.
3
Set up the probability ratio and simplify the fraction.
The initial ratio is 540\frac{5}{40}. Dividing both the numerator and denominator by 55 yields 18\frac{1}{8}.
Probability is the ratio of favorable outcomes to total outcomes, and the question requires the answer in simplest fraction form.

Anahtar Kavram

Single Event Probability
Soru 18Soru →

A supply room bin contains a mixture of 3030 electronic components. There are 1212 resistors, 1010 capacitors, and 88 inductors. If a technician randomly selects one component from the bin, what is the probability that the selected component is an inductor?

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Cevap: 415\frac{4}{15}

Cevap

The probability of selecting an inductor is 415\frac{4}{15}.
The correct probability is found by dividing the number of inductors (88) by the total number of components (3030). This gives the fraction 830\frac{8}{30}, which simplifies to 415\frac{4}{15} by dividing both the numerator and the denominator by their greatest common factor, 22.

Adım Adım Çözüm

1
Identify the total number of possible outcomes.
Total components = 3030
The denominator for single event probability is always the total number of items available.
2
Identify the number of favorable outcomes.
Number of inductors = 88
The numerator represents the specific event being measured (selecting an inductor).
3
Set up the probability fraction and simplify.
Probability = 830=415\frac{8}{30} = \frac{4}{15}
Probability is favorable outcomes over total outcomes, and the resulting fraction must be reduced to its simplest form.

Anahtar Kavram

Single Event Probability is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.
Single Event Probability Alıştırma Soruları — Armed Services Vocational Aptitude Battery (ASVAB) | Examkin