A network administrator is inspecting a host connected to a Cisco switch. The host network interface has a hardware MAC address of `5254.0012.3456`. Assuming IPv6 stateless autoconfiguration uses the standard IEEE EUI-64 format, what is the resulting 64-bit interface identifier?
Cevap: 5054:00ff:fe12:3456 / 5054:00FF:FE12:3456 / 5054:ff:fe12:3456 / 5054:FF:FE12:3456
Cevap
5054:00ff:fe12:3456
To derive the EUI-64 interface identifier from MAC address `5254.0012.3456`:
1. Split the MAC address: `52:54:00` and `12:34:56`.
2. Insert `FFFE` in the middle: `5254:00FF:FE12:3456`.
3. Invert the 7th bit of the first byte: `0x52` (`0101 0010` in binary) becomes `0x50` (`0101 0000` in binary).
Combining these operations yields the final 64-bit interface identifier `5054:00ff:fe12:3456`.
1. Split the MAC address: `52:54:00` and `12:34:56`.
2. Insert `FFFE` in the middle: `5254:00FF:FE12:3456`.
3. Invert the 7th bit of the first byte: `0x52` (`0101 0010` in binary) becomes `0x50` (`0101 0000` in binary).
Combining these operations yields the final 64-bit interface identifier `5054:00ff:fe12:3456`.
Adım Adım Çözüm
Anahtar Kavram
EUI-64 Interface Identifier Derivation