A network administrator is verifying the IPv6 dynamic address configuration on a host interface. The host interface has a burned-in MAC address of `0012.7F34.5678`. Which two statements correctly describe the process and result of generating the interface identifier and IPv6 address using standard EUI-64?
- The hexadecimal string `FFFE` is inserted into the middle of the 48-bit MAC address to expand it to 64 bits.Cevap
- The resulting 64-bit interface identifier for the host is `0212:7fff:fe34:5678`.Cevap
- CThe hexadecimal string `FFFF` is inserted into the middle of the MAC address to form the 64-bit interface identifier.
- DThe first byte of the MAC address remains `00` in the interface identifier because it is a globally unique burned-in address.
Cevap
The correct statements are that FFFE is inserted into the midpoint of the 48-bit MAC address and that the resulting 64-bit interface identifier is 0212:7fff:fe34:5678.
Generating an IPv6 EUI-64 interface identifier requires two key transformations on a 48-bit MAC address: inserting the hexadecimal value FFFE between the OUI and the vendor-assigned payload (the middle 16 bits) and inverting the 7th bit (Universal/Local bit) of the first byte. For MAC address 0012.7F34.5678, inserting FFFE produces 0012:7FFF:FE34:5678, and flipping the 7th bit converts the first byte from 00 to 02, producing 0212:7fff:fe34:5678.
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Anahtar Kavram
IPv6 EUI-64 Interface Identifier Derivation