Examkin

Soru

Zorluk: ZorIPv4 Addressing and Subnetting

A network engineer is subnetting the parent address block 192.168.45.0/24192.168.45.0/24 to provision subnets for a regional office. Each subnet must support a minimum of 5050 usable host interfaces while minimizing address wastage. If subnets are assigned sequentially starting from the lowest network address, what is the broadcast address of the third subnet?

  1. 192.168.45.191192.168.45.191Cevap
  2. B
    192.168.45.190192.168.45.190
  3. C
    192.168.45.127192.168.45.127
  4. D
    192.168.45.95192.168.45.95

Cevap

The broadcast address of the third usable subnet is 192.168.45.191192.168.45.191.
To support 50 host interfaces, 6 host bits (26−2=622^6 - 2 = 62 usable addresses) are necessary, yielding a /26/26 mask (block size of 64). The sequential subnets are 192.168.45.0/26192.168.45.0/26 (Subnet 1), 192.168.45.64/26192.168.45.64/26 (Subnet 2), and 192.168.45.128/26192.168.45.128/26 (Subnet 3). The broadcast address of Subnet 3 is the highest address in its range, 192.168.45.191192.168.45.191.

Adım Adım Çözüm

1
Determine the required host bits and prefix length.
Using the formula 2n−2≥502^n - 2 \ge 50, n=6n = 6 host bits are needed because 26−2=62≥502^6 - 2 = 62 \ge 50. The prefix length is 32−6=/2632 - 6 = /26.
Choosing 5 host bits (/27/27) yields only 25−2=302^5 - 2 = 30 usable hosts, which is insufficient.
2
Calculate the subnet block size (increment).
The block size is 26=642^6 = 64 addresses.
A /26/26 prefix leaves 6 host bits in the fourth octet, causing subnet boundaries to increment by 64.
3
List sequential subnet ranges to identify the third subnet.
Subnet 1: 192.168.45.0/26192.168.45.0/26 (192.168.45.0192.168.45.0 - 192.168.45.63192.168.45.63)
Subnet 2: 192.168.45.64/26192.168.45.64/26 (192.168.45.64192.168.45.64 - 192.168.45.127192.168.45.127)
Subnet 3: 192.168.45.128/26192.168.45.128/26 (192.168.45.128192.168.45.128 - 192.168.45.191192.168.45.191)
Subnets are allocated sequentially starting from 192.168.45.0192.168.45.0.
4
Identify the broadcast address of the third subnet.
The network address is 192.168.45.128192.168.45.128, and the broadcast address (the last address in the block) is 192.168.45.191192.168.45.191.
The broadcast address precedes the next subnet's network address (192.168.45.192−1=192.168.45.191192.168.45.192 - 1 = 192.168.45.191).

Anahtar Kavram

IPv4 VLSM Subnetting and Broadcast Address Calculation
Bu soruyu puanla

Konular

IPv4 Addressing and Subnetting

Bu konudan daha fazla soru