Soru

Zorluk: ZorInequalities, Absolute Values, and Number Ranges in Data Sufficiency

If aa and bb are non-zero real numbers, is ab>a+b|a - b| > |a + b|?

(1) a+2b<a2b|a + 2b| < |a - 2b|
(2) a1<b1|a - 1| < |b - 1|

Which of the following choices correctly describes the sufficiency of the statements?

  1. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.Cevap
  2. B
    Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
  3. C
    BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
  4. D
    EACH statement ALONE is sufficient.
  5. E
    Statements (1) and (2) TOGETHER are NOT sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
The option stating that Statement (1) ALONE is sufficient, but Statement (2) alone is not sufficient is correct. Squaring both sides of the question stem inequality ab>a+b|a - b| > |a + b| yields a22ab+b2>a2+2ab+b2a^2 - 2ab + b^2 > a^2 + 2ab + b^2, which simplifies directly to ab<0ab < 0. Statement (1) states a+2b<a2b|a + 2b| < |a - 2b|. Squaring both sides yields a2+4ab+4b2<a24ab+4b2a^2 + 4ab + 4b^2 < a^2 - 4ab + 4b^2, which simplifies to 8ab<08ab < 0, or ab<0ab < 0. This gives a definitive YES to the question, so Statement (1) is sufficient. Statement (2) compares the distances of aa and bb from 1 on the number line. Choosing a=0.5a = 0.5 and b=2b = -2 satisfies 0.51<21|0.5 - 1| < |-2 - 1| and gives ab=1<0ab = -1 < 0 (YES), whereas choosing a=0.5a = 0.5 and b=3b = 3 satisfies 0.51<31|0.5 - 1| < |3 - 1| and gives ab=1.5>0ab = 1.5 > 0 (NO). Thus, Statement (2) is insufficient.

Adım Adım Çözüm

1
Rephrase the question stem target using absolute value properties.
Since both sides of ab>a+b|a - b| > |a + b| are non-negative, square both sides: (ab)2>(a+b)2    a22ab+b2>a2+2ab+b2    2ab>2ab    4ab<0    ab<0(a - b)^2 > (a + b)^2 \implies a^2 - 2ab + b^2 > a^2 + 2ab + b^2 \implies -2ab > 2ab \implies 4ab < 0 \implies ab < 0. Thus, the question asks: 'Is ab<0ab < 0?' (Do aa and bb have opposite signs?)
Simplifying the target inequality converts an absolute value relationship into a clear sign constraint on the product abab.
2
Evaluate Statement (1): a+2b<a2b|a + 2b| < |a - 2b|.
Square both sides: (a+2b)2<(a2b)2    a2+4ab+4b2<a24ab+4b2    4ab<4ab    8ab<0    ab<0(a + 2b)^2 < (a - 2b)^2 \implies a^2 + 4ab + 4b^2 < a^2 - 4ab + 4b^2 \implies 4ab < -4ab \implies 8ab < 0 \implies ab < 0. This provides a definitive YES to the question 'Is ab<0ab < 0?'
Statement (1) uniquely guarantees that aa and bb have opposite signs, making Statement (1) ALONE sufficient.
3
Evaluate Statement (2): a1<b1|a - 1| < |b - 1|.
Test numbers: Case 1: If a=0.5a = 0.5 and b=2b = -2, then 0.51=0.5|0.5 - 1| = 0.5 and 21=3|-2 - 1| = 3. Since 0.5<30.5 < 3, Statement (2) holds, and ab=(0.5)(2)=1<0ab = (0.5)(-2) = -1 < 0 (YES). Case 2: If a=0.5a = 0.5 and b=3b = 3, then 0.51=0.5|0.5 - 1| = 0.5 and 31=2|3 - 1| = 2. Since 0.5<20.5 < 2, Statement (2) holds, and ab=(0.5)(3)=1.5>0ab = (0.5)(3) = 1.5 > 0 (NO).
Because Statement (2) permits both ab<0ab < 0 and ab>0ab > 0, it cannot determine whether ab<0ab < 0. Statement (2) ALONE is insufficient.

Anahtar Kavram

Properties of Absolute Value Inequalities and Rephrased Data Sufficiency Targets
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