Inequalities, Absolute Values, and Number Ranges in Data Sufficiency

32 soru

Soru 1Soru →

If xx is a real number, is ∣x2−4∣<5|x^2 - 4| < 5?

(1) ∣x−1∣<2|x - 1| < 2
(2) ∣x+1∣<3|x + 1| < 3

Which of the following choices correctly describes the sufficiency of the statements?

Cevabı ve açıklamayı göster

Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Rephrasing the question target ∣x2−4∣<5|x^2 - 4| < 5 gives −5<x2−4<5  ⟹  −1<x2<9-5 < x^2 - 4 < 5 \implies -1 < x^2 < 9. Since x2≥0x^2 \ge 0 for all real numbers, the condition reduces to x2<9x^2 < 9, or −3<x<3-3 < x < 3.

Statement (1) states ∣x−1∣<2|x - 1| < 2, which translates to −2<x−1<2  ⟹  −1<x<3-2 < x - 1 < 2 \implies -1 < x < 3. Any number xx in (−1,3)(-1, 3) automatically satisfies −3<x<3-3 < x < 3, giving a definitive 'Yes'. Hence, Statement (1) alone is sufficient.

Statement (2) states ∣x+1∣<3|x + 1| < 3, which translates to −3<x+1<3  ⟹  −4<x<2-3 < x + 1 < 3 \implies -4 < x < 2. If x=0x = 0, xx is in (−3,3)(-3, 3) ('Yes'); if x=−3.5x = -3.5, xx is not in (−3,3)(-3, 3) ('No'). Because both 'Yes' and 'No' are possible, Statement (2) alone is not sufficient.

Therefore, the statement indicating that Statement (1) alone is sufficient, but Statement (2) alone is not sufficient, is the correct choice.

Adım Adım Çözüm

1
Rephrase the target question stem algebraically.
The target inequality ∣x2−4∣<5|x^2 - 4| < 5 is equivalent to −5<x2−4<5-5 < x^2 - 4 < 5. Adding 4 yields −1<x2<9-1 < x^2 < 9. Since x2≥0x^2 \ge 0 for all real numbers, −1<x2-1 < x^2 is always true. Thus, the target question simplifies to whether x2<9x^2 < 9, which means −3<x<3-3 < x < 3.
Simplifying the question stem simplifies evaluating the statement ranges.
2
Evaluate Statement (1): ∣x−1∣<2|x - 1| < 2.
Expanding the absolute value gives −2<x−1<2-2 < x - 1 < 2, which simplifies to −1<x<3-1 < x < 3. Every value of xx in the interval (−1,3)(-1, 3) is strictly inside (−3,3)(-3, 3). Thus, Statement (1) guarantees a definitive 'Yes'.
Since Statement (1) provides a single definitive answer ('Yes'), Statement (1) alone is sufficient.
3
Evaluate Statement (2): ∣x+1∣<3|x + 1| < 3.
Expanding the absolute value gives −3<x+1<3-3 < x + 1 < 3, which simplifies to −4<x<2-4 < x < 2. If x=0x = 0, then −3<0<3-3 < 0 < 3 is true ('Yes'). If x=−3.5x = -3.5, then ∣(−3.5)2−4∣=∣12.25−4∣=8.25<5|(-3.5)^2 - 4| = |12.25 - 4| = 8.25 < 5 is false ('No').
Since Statement (2) allows both 'Yes' and 'No' answers, Statement (2) alone is not sufficient.

Anahtar Kavram

Rephrasing absolute value inequality bounds in Data Sufficiency questions
Soru 2Soru →

If xx is a real number, is x>0x > 0?

(1) ∣x∣=5|x| = 5
(2) x+3>5x + 3 > 5

Cevabı ve açıklamayı göster

Cevap: Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

Cevap

Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
The choice stating that Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient, is correct because Statement (1) yields two possible values for xx (55 and −5-5), resulting in both 'Yes' and 'No' answers. In contrast, Statement (2) simplifies to x>2x > 2, which guarantees that x>0x > 0 with a definitive 'Yes'.

Adım Adım Çözüm

1
Rephrase the target question
The target asks whether xx lies to the right of 00 on the real number line (a Yes/No question).
Establishing clear sufficiency criteria requires identifying what yields a definitive 'Yes' or definitive 'No'.
2
Evaluate Statement (1): ∣x∣=5|x| = 5
xx can be 55 or −5-5. If x=5x = 5, the answer is Yes (5>05 > 0). If x=−5x = -5, the answer is No (−5≯0-5 \ngtr 0).
Since Statement (1) allows both a 'Yes' and a 'No' response, it is NOT sufficient.
3
Evaluate Statement (2): x+3>5x + 3 > 5
Subtracting 33 from both sides gives x>2x > 2. Any number strictly greater than 22 is automatically greater than 00.
Statement (2) provides a definitive 'Yes' answer to the question x>0x > 0, so Statement (2) ALONE is sufficient.

Anahtar Kavram

Absolute Value Definition and Single-Variable Inequality Simplification in Data Sufficiency
Soru 3Soru →

If xx is a real number, is x>0x > 0?

(1) ∣x∣=−x|x| = -x
(2) x+∣x∣>0x + |x| > 0

Which of the following choices correctly describes the sufficiency of the statements?

Cevabı ve açıklamayı göster

Cevap: EACH statement ALONE is sufficient.

Cevap

EACH statement ALONE is sufficient.
The option stating that each statement alone is sufficient is correct. Statement (1) shows that x≤0x \le 0, which gives a definitive 'No' to whether x>0x > 0. Statement (2) shows that x>0x > 0, which gives a definitive 'Yes' to whether x>0x > 0. Because both statements yield a clear, conclusive answer independently, each statement alone is sufficient.

Adım Adım Çözüm

1
Analyze Statement (1): ∣x∣=−x|x| = -x
By definition of absolute value, ∣x∣=−x|x| = -x holds true if and only if x≤0x \le 0.
If x≤0x \le 0, then xx is not strictly positive, so the answer to 'Is x>0x > 0?' is a definitive 'No'.
2
Evaluate sufficiency of Statement (1)
Statement (1) provides a definitive 'No' answer to the question stem.
In Data Sufficiency, a statement that consistently yields a definitive 'No' is sufficient.
3
Analyze Statement (2): x+∣x∣>0x + |x| > 0
If x≤0x \le 0, then ∣x∣=−x|x| = -x, so x+∣x∣=x−x=0x + |x| = x - x = 0, which is not greater than 00. If x>0x > 0, then ∣x∣=x|x| = x, so x+∣x∣=2x>0x + |x| = 2x > 0.
The inequality x+∣x∣>0x + |x| > 0 is satisfied if and only if x>0x > 0.
4
Evaluate sufficiency of Statement (2)
Statement (2) provides a definitive 'Yes' answer to the question stem.
Since Statement (2) guarantees x>0x > 0, it is sufficient on its own.
5
Combine evaluations
Each statement alone provides a definitive answer to the question stem.
Therefore, EACH statement ALONE is sufficient.

Anahtar Kavram

Absolute Value Definition and Yes/No Data Sufficiency Decision Logic
Tahmini Süre:1m 0s
Soru 4Soru →

If xx and yy are real numbers, is ∣x−y∣<∣x+y∣|x - y| < |x + y|?

(1) x3y>0x^3 y > 0
(2) ∣x∣<y|x| < y

Cevabı ve açıklamayı göster

Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Rephrasing the stem by squaring both non-negative sides reveals that ∣x−y∣<∣x+y∣|x - y| < |x + y| is strictly equivalent to xy>0xy > 0. Statement (1) specifies x3y>0x^3 y > 0. Because x3x^3 and xx always have the same sign, x3y>0x^3 y > 0 means xx and yy share the same sign, which guarantees xy>0xy > 0. Thus, Statement (1) alone provides a definitive 'Yes'. Statement (2) states ∣x∣<y|x| < y, which forces y>0y > 0 but allows xx to be either positive or negative, so xyxy can be either positive or negative. Therefore, Statement (1) alone is sufficient, but Statement (2) alone is not sufficient.

Adım Adım Çözüm

1
Rephrase the question stem by squaring both sides of the inequality.
Since both ∣x−y∣|x - y| and ∣x+y∣|x + y| are non-negative, ∣x−y∣<∣x+y∣  ⟺  (x−y)2<(x+y)2  ⟺  x2−2xy+y2<x2+2xy+y2  ⟺  0<4xy  ⟺  xy>0|x - y| < |x + y| \iff (x - y)^2 < (x + y)^2 \iff x^2 - 2xy + y^2 < x^2 + 2xy + y^2 \iff 0 < 4xy \iff xy > 0. The question asks whether xx and yy have the same sign (and neither is zero).
Simplifying absolute value inequalities before analyzing statements prevents misinterpretation.
2
Evaluate Statement (1): x3y>0x^3 y > 0.
Since x3x^3 always has the exact same algebraic sign as xx for all real numbers, x3y>0  ⟹  xy>0x^3 y > 0 \implies xy > 0. This yields a definitive 'Yes' to the rephrased question.
Statement (1) alone provides enough information to answer the target question conclusively.
3
Evaluate Statement (2): ∣x∣<y|x| < y.
Since ∣x∣≥0|x| \ge 0, this implies y>0y > 0. However, xx can be positive (e.g., x=2,y=3  ⟹  xy=6>0x=2, y=3 \implies xy=6 > 0, Yes) or negative (e.g., x=−2,y=3  ⟹  xy=−6<0x=-2, y=3 \implies xy=-6 < 0, No).
Because Statement (2) allows both 'Yes' and 'No' answers, it is not sufficient.

Anahtar Kavram

Rephrasing absolute value inequalities and analyzing product sign constraints in Data Sufficiency
Soru 5Soru →

If xx is a real number, is ∣x−3∣<5|x - 3| < 5?

(1) 1<x<61 < x < 6
(2) x>0x > 0

Which of the following describes the sufficiency of the statements?

Cevabı ve açıklamayı göster

Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
The correct choice is the option stating that Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. Rephrasing ∣x−3∣<5|x - 3| < 5 yields −2<x<8-2 < x < 8. Statement (1) restricts xx to (1,6)(1, 6), which is completely inside (−2,8)(-2, 8), guaranteeing a 'Yes' answer. Statement (2) allows values like x=2x = 2 ('Yes') and x=10x = 10 ('No'), so it is not sufficient.

Adım Adım Çözüm

1
Rephrase the target inequality from the stem.
The absolute value inequality ∣x−3∣<5|x - 3| < 5 is equivalent to −5<x−3<5-5 < x - 3 < 5. Adding 3 to all parts gives −2<x<8-2 < x < 8. The question asks: 'Is xx strictly between −2-2 and 88?'
Simplifying the stem into a clear range for xx makes evaluating sufficiency straightforward.
2
Evaluate Statement (1): 1<x<61 < x < 6.
Every number in the interval (1,6)(1, 6) is strictly between −2-2 and 88. Thus, the answer to 'Is −2<x<8-2 < x < 8?' is a definitive 'Yes'. Statement (1) alone is sufficient.
Since the entire set of allowed values under statement (1) is a subset of (−2,8)(-2, 8), statement (1) provides a conclusive answer.
3
Evaluate Statement (2): x>0x > 0.
If x=2x = 2, then −2<2<8-2 < 2 < 8 is True (Yes). However, if x=10x = 10, then −2<10<8-2 < 10 < 8 is False (No). Because both 'Yes' and 'No' are possible, Statement (2) alone is not sufficient.
A statement is insufficient if it permits values that produce conflicting answers to the target question.

Anahtar Kavram

Absolute Value Inequalities and Range Containment in Data Sufficiency
Soru 6Soru →

If kk is a real number, is ∣k∣<4|k| < 4?

(1) k>−3k > -3
(2) k<3k < 3

Which of the following describes the sufficiency of the statements?

Cevabı ve açıklamayı göster

Cevap: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Cevap

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
Rephrasing ∣k∣<4|k| < 4 gives −4<k<4-4 < k < 4. Neither statement alone provides both an upper and lower bound. However, combining Statement (1) (k>−3k > -3) and Statement (2) (k<3k < 3) establishes −3<k<3-3 < k < 3. Because the interval (−3,3)(-3, 3) is entirely contained inside (−4,4)(-4, 4), any value of kk satisfying both statements guarantees ∣k∣<4|k| < 4. Thus, both statements together are sufficient.

Adım Adım Çözüm

1
Rephrase the question stem target
The target inequality ∣k∣<4|k| < 4 is equivalent to −4<k<4-4 < k < 4. The question asks whether kk lies strictly inside the range (−4,4)(-4, 4).
Simplifying an absolute value inequality into a compound inequality clarifies the exact target range.
2
Evaluate Statement (1) independently
Statement (1) specifies k>−3k > -3. If k=0k = 0, then ∣0∣=0<4|0| = 0 < 4 (Yes). If k=5k = 5, then ∣5∣=5≮4|5| = 5 \not< 4 (No).
Since Statement (1) yields both 'Yes' and 'No' answers, it is insufficient.
3
Evaluate Statement (2) independently
Statement (2) specifies k<3k < 3. If k=0k = 0, then ∣0∣=0<4|0| = 0 < 4 (Yes). If k=−5k = -5, then ∣−5∣=5≮4|-5| = 5 \not< 4 (No).
Since Statement (2) yields both 'Yes' and 'No' answers, it is insufficient.
4
Evaluate Statements (1) and (2) combined
Combining k>−3k > -3 and k<3k < 3 gives −3<k<3-3 < k < 3. Any value of kk in (−3,3)(-3, 3) automatically falls within (−4,4)(-4, 4), yielding a definitive 'Yes' to ∣k∣<4|k| < 4.
The interval (−3,3)(-3, 3) is a complete subset of (−4,4)(-4, 4), making the combined information sufficient.

Anahtar Kavram

Absolute Value Range Simplification and Subset Verification in Data Sufficiency
Soru 7Soru →

If xx and yy are real numbers such that x≠0x \neq 0, is ∣x∣<y|x| < y?

(1) x2<y2x^2 < y^2
(2) y>0y > 0

Which of the following correctly describes the sufficiency of the statements?

Cevabı ve açıklamayı göster

Cevap: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Cevap

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
Combining both statements is sufficient. Statement (1) establishes that ∣x∣<∣y∣|x| < |y| because taking the square root of x2<y2x^2 < y^2 yields absolute values. Statement (2) specifies y>0y > 0, meaning ∣y∣=y|y| = y. Substituting yy for ∣y∣|y| gives ∣x∣<y|x| < y, which conclusively answers the question stem with 'Yes'.

Adım Adım Çözüm

1
Rephrase the target question
The target question asks whether ∣x∣<y|x| < y. Since ∣x∣≥0|x| \ge 0 for all real numbers xx, a necessary condition for ∣x∣<y|x| < y to be true is y>0y > 0.
Simplifying absolute value conditions clarifies what values of variables are required.
2
Evaluate Statement (1): x2<y2x^2 < y^2
Taking the principal square root of both sides gives x2<y2\sqrt{x^2} < \sqrt{y^2}, which simplifies to ∣x∣<∣y∣|x| < |y|.
The square root of a squared real number is its absolute value.
3
Test sufficiency of Statement (1) alone
If x=1x = 1 and y=2y = 2, then 12<221^2 < 2^2 is true, and ∣1∣<2|1| < 2 (Yes). If x=1x = 1 and y=−2y = -2, then 12<(−2)21^2 < (-2)^2 is true, but ∣1∣<−2|1| < -2 is false (No). Since both Yes and No are possible, Statement (1) alone is NOT sufficient.
Knowing ∣x∣<∣y∣|x| < |y| does not determine the sign of yy.
4
Evaluate Statement (2): y>0y > 0
Statement (2) gives no information about xx. For example, if y=5y = 5 and x=2x = 2, ∣2∣<5|2| < 5 (Yes). If y=5y = 5 and x=10x = 10, ∣10∣<5|10| < 5 is false (No). Thus Statement (2) alone is NOT sufficient.
No bound on xx is provided.
5
Evaluate Statements (1) and (2) together
From Statement (1), ∣x∣<∣y∣|x| < |y|. From Statement (2), y>0y > 0, which implies ∣y∣=y|y| = y. Substituting ∣y∣=y|y| = y into ∣x∣<∣y∣|x| < |y| gives ∣x∣<y|x| < y. This definitively answers 'Yes' to the question stem.
Combining the magnitude inequality with the sign constraint produces a unique, definitive Yes answer.

Anahtar Kavram

Absolute Value Inequalities and Number Ranges in Data Sufficiency
Soru 8Soru →

If xx is a real number, is ∣x−2∣<3|x - 2| < 3?

(1) x2−4x+3<0x^2 - 4x + 3 < 0
(2) ∣x∣<4|x| < 4

Which of the options correctly describes the sufficiency of the statements?

Cevabı ve açıklamayı göster

Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
The correct answer specifies that Statement (1) alone is sufficient while Statement (2) alone is not. Rephrasing the question stem shows that ∣x−2∣<3|x - 2| < 3 is equivalent to −1<x<5-1 < x < 5. Statement (1) yields 1<x<31 < x < 3, which lies entirely inside (−1,5)(-1, 5), guaranteeing a 'Yes' answer. Statement (2) yields −4<x<4-4 < x < 4, which allows values outside (−1,5)(-1, 5) (such as x=−2x = -2, giving 'No') as well as values inside (such as x=0x = 0, giving 'Yes'), so it is not sufficient.

Adım Adım Çözüm

1
Rephrase the target question stem algebraically.
The inequality ∣x−2∣<3|x - 2| < 3 is equivalent to −3<x−2<3-3 < x - 2 < 3, which simplifies to −1<x<5-1 < x < 5. The question asks: Is xx strictly between −1-1 and 55?
Simplifying the target inequality establishes the exact boundary values needed for evaluation.
2
Evaluate Statement (1): x2−4x+3<0x^2 - 4x + 3 < 0.
Factoring the quadratic gives (x−1)(x−3)<0(x - 1)(x - 3) < 0, which holds when 1<x<31 < x < 3.
Since the interval (1,3)(1, 3) is entirely contained within the target range (−1,5)(-1, 5), every value of xx satisfying Statement (1) results in a definitive 'Yes' to the question. Thus, Statement (1) is sufficient.
3
Evaluate Statement (2): ∣x∣<4|x| < 4.
This absolute value inequality simplifies to −4<x<4-4 < x < 4.
If x=0x = 0, then −1<0<5-1 < 0 < 5 is True ('Yes'). If x=−2x = -2, then −1<−2<5-1 < -2 < 5 is False ('No'). Because Statement (2) allows both 'Yes' and 'No' outcomes, Statement (2) is not sufficient.

Anahtar Kavram

Inequalities, Absolute Values, and Number Ranges in Data Sufficiency
Soru 9Soru →

If aa and bb are non-zero real numbers, is ∣a+b∣<∣a∣+∣b∣|a + b| < |a| + |b|?

(1) a3b2<0a^3 b^2 < 0
(2) ∣a−b∣>∣a+b∣|a - b| > |a + b|

Which of the following describes the sufficiency of the statements?

Cevabı ve açıklamayı göster

Cevap: Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

Cevap

Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
The correct response identifies that statement (2) alone provides enough information to answer the question, whereas statement (1) does not. Rephrasing the stem ∣a+b∣<∣a∣+∣b∣|a + b| < |a| + |b| reveals it is true if and only if aa and bb have opposite signs (ab<0ab < 0). Statement (1) only confirms that a<0a < 0, leaving the sign of bb unknown. Statement (2) can be squared to yield ab<0ab < 0, which conclusively answers the question with a 'Yes'.

Adım Adım Çözüm

1
Rephrase the question stem
The inequality ∣a+b∣<∣a∣+∣b∣|a + b| < |a| + |b| holds if and only if aa and bb have opposite signs (i.e., ab<0ab < 0). If aa and bb have the same sign or if either is zero, ∣a+b∣=∣a∣+∣b∣|a + b| = |a| + |b|. Thus, the target question is: 'Is ab<0ab < 0?'
Simplifying absolute value properties reduces the stem to a straightforward sign comparison.
2
Evaluate Statement (1): a3b2<0a^3 b^2 < 0
Since b≠0b \neq 0, b2>0b^2 > 0 for all real numbers. Thus, a3b2<0a^3 b^2 < 0 implies a3<0a^3 < 0, which means a<0a < 0. However, bb can be either positive or negative. If b>0b > 0, then ab<0ab < 0 (YES). If b<0b < 0, then ab>0ab > 0 (NO).
Since statement (1) allows both a YES and a NO answer, Statement (1) ALONE is NOT sufficient.
3
Evaluate Statement (2): ∣a−b∣>∣a+b∣|a - b| > |a + b|
Square both sides (valid since both sides are non-negative): (a−b)2>(a+b)2  ⟹  a2−2ab+b2>a2+2ab+b2  ⟹  −2ab>2ab  ⟹  4ab<0  ⟹  ab<0(a - b)^2 > (a + b)^2 \implies a^2 - 2ab + b^2 > a^2 + 2ab + b^2 \implies -2ab > 2ab \implies 4ab < 0 \implies ab < 0.
Statement (2) directly proves that ab<0ab < 0, yielding a definitive YES to the question stem. Thus, Statement (2) ALONE is SUFFICIENT.

Anahtar Kavram

Absolute Value Distance and Sign Properties
Soru 10Soru →

If mm and nn are real numbers such that mn≠0mn \neq 0, is ∣m+n∣m>1\frac{|m + n|}{m} > 1?

(1) m<0m < 0

(2) n>2∣m∣n > 2|m|

Cevabı ve açıklamayı göster

Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
The option stating that Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient is correct. For Statement (1), since m<0m < 0 and the absolute value ∣m+n∣|m + n| is always non-negative, the quotient ∣m+n∣m\frac{|m + n|}{m} is non-positive (≤0\le 0). Therefore, it can never be greater than 1, giving a definitive 'No' to the question stem, which makes Statement (1) sufficient. For Statement (2), mm can be positive (yielding a 'Yes') or negative (yielding a 'No'), making Statement (2) insufficient.

Adım Adım Çözüm

1
Analyze the target question stem and constraints.
The absolute value ∣m+n∣|m + n| is always non-negative (∣m+n∣≥0|m + n| \ge 0). The target asks whether ∣m+n∣m>1\frac{|m + n|}{m} > 1.
Establishing the properties of the numerator and denominator helps simplify the condition.
2
Evaluate Statement (1): m<0m < 0.
Since ∣m+n∣≥0|m + n| \ge 0 and m<0m < 0, dividing a non-negative number by a negative number yields a result that is less than or equal to 0 (∣m+n∣m≤0\frac{|m + n|}{m} \le 0). Thus, the expression can never be greater than 1, yielding a definitive 'No'.
A definitive 'No' answer means Statement (1) alone IS SUFFICIENT.
3
Evaluate Statement (2): n>2∣m∣n > 2|m|.
Since 2∣m∣>02|m| > 0, nn must be positive. Test cases for mm:
- Case 2a: If m=1m = 1, then n>2n > 2. Let n=3n = 3. Then ∣1+3∣1=4>1\frac{|1 + 3|}{1} = 4 > 1 (Answer: YES).
- Case 2b: If m=−1m = -1, then n>2(1)=2n > 2(1) = 2. Let n=3n = 3. Then ∣−1+3∣−1=2−1=−2≯1\frac{|-1 + 3|}{-1} = \frac{2}{-1} = -2 \ngtr 1 (Answer: NO).
Since both 'Yes' and 'No' are possible, Statement (2) alone is NOT SUFFICIENT.
Testing cases with positive and negative values of mm shows that Statement (2) does not yield a unique answer.

Anahtar Kavram

Data Sufficiency Yes/No Decision Logic with Signed Denominator and Absolute Value Properties
Tahmini Süre:2m 0s
Soru 11Soru →

If rr and ss are real numbers, is r∣s∣<s∣r∣r|s| < s|r|?

(1) rs<0rs < 0
(2) r+s>∣r−s∣r + s > |r - s|

Which of the following options correctly describes the sufficiency of the statements?

Cevabı ve açıklamayı göster

Cevap: Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

Cevap

Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
The choice stating that Statement (2) ALONE is sufficient while Statement (1) alone is not sufficient is correct. Rephrased, r∣s∣<s∣r∣r|s| < s|r| is true only when r<0r < 0 and s>0s > 0. Statement (1) allows rr to be positive while ss is negative, yielding a 'No', as well as rr negative while ss is positive, yielding a 'Yes', so it is insufficient. Statement (2) simplifies algebraically to rs>0rs > 0 and r+s>0r + s > 0, which guarantees both numbers are positive. When both numbers are positive, r∣s∣<s∣r∣r|s| < s|r| reduces to rs<rsrs < rs, which is false. Because Statement (2) yields a definitive 'No', it is sufficient on its own.

Adım Adım Çözüm

1
Rephrase the question stem target
The inequality r∣s∣<s∣r∣r|s| < s|r| holds if and only if r<0r < 0 and s>0s > 0.
If rr and ss have the same sign or either is zero, r∣s∣=s∣r∣r|s| = s|r|, making the strict inequality false. If r>0r > 0 and s<0s < 0, r∣s∣=−rsr|s| = -rs and s∣r∣=−rss|r| = -rs, making both sides equal. Only when r<0r < 0 and s>0s > 0 does r∣s∣=rs<0r|s| = rs < 0 and s∣r∣=−rs>0s|r| = -rs > 0, which makes the inequality true.
2
Evaluate Statement (1): rs<0rs < 0
Statement (1) is NOT sufficient.
This condition means rr and ss have opposite signs. Case 1: If r=−2r = -2 and s=3s = 3, then r<0r < 0 and s>0s > 0, so the answer is YES. Case 2: If r=3r = 3 and s=−2s = -2, then r>0r > 0 and s<0s < 0, so the answer is NO. Since both YES and NO are possible, Statement (1) is insufficient.
3
Evaluate Statement (2): r+s>∣r−s∣r + s > |r - s|
Statement (2) ALONE is sufficient.
Since ∣r−s∣≥0|r - s| \ge 0, we have r+s>0r + s > 0. Squaring both positive sides gives (r+s)2>(r−s)2  ⟹  r2+2rs+s2>r2−2rs+s2  ⟹  4rs>0  ⟹  rs>0(r + s)^2 > (r - s)^2 \implies r^2 + 2rs + s^2 > r^2 - 2rs + s^2 \implies 4rs > 0 \implies rs > 0. Since rs>0rs > 0 and r+s>0r + s > 0, both rr and ss must be positive. If r>0r > 0 and s>0s > 0, then r∣s∣=rsr|s| = rs and s∣r∣=rss|r| = rs, so r∣s∣<s∣r∣r|s| < s|r| simplifies to rs<rsrs < rs, which is FALSE. This gives a definitive NO to the question, making Statement (2) sufficient.

Anahtar Kavram

Data Sufficiency Yes/No Decision Logic with Absolute Value Inequalities
Soru 12Soru →

If pp and qq are non-zero real numbers, is ∣p+q∣>∣p−q∣|p + q| > |p - q|?

(1) ∣p+2q∣<∣p−2q∣|p + 2q| < |p - 2q|
(2) p−q>0p - q > 0

Cevabı ve açıklamayı göster

Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
The correct response identifies Statement (1) as sufficient and Statement (2) as insufficient. Rephrasing the question stem by squaring both sides of ∣p+q∣>∣p−q∣|p + q| > |p - q| yields 4pq>04pq > 0, or pq>0pq > 0. Statement (1) expands and simplifies to 8pq<08pq < 0, meaning pq<0pq < 0. This provides a definitive 'No' answer to the question 'Is pq>0pq > 0?', which constitutes full sufficiency. Statement (2) merely tells us p>qp > q, which permits pp and qq to both be positive (pq>0pq > 0) or to have opposite signs (pq<0pq < 0), rendering Statement (2) insufficient.

Adım Adım Çözüm

1
Rephrase the question stem target geometrically or algebraically.
Squaring both non-negative sides of ∣p+q∣>∣p−q∣|p + q| > |p - q| gives (p+q)2>(p−q)2  ⟹  p2+2pq+q2>p2−2pq+q2  ⟹  4pq>0  ⟹  pq>0(p + q)^2 > (p - q)^2 \implies p^2 + 2pq + q^2 > p^2 - 2pq + q^2 \implies 4pq > 0 \implies pq > 0. The question asks: Is pq>0pq > 0?
Simplifying the question stem simplifies evaluation of both statements by focusing on whether pp and qq have the same sign.
2
Evaluate Statement (1): ∣p+2q∣<∣p−2q∣|p + 2q| < |p - 2q|.
Squaring both non-negative sides gives (p+2q)2<(p−2q)2  ⟹  p2+4pq+4q2<p2−4pq+4q2  ⟹  8pq<0  ⟹  pq<0(p + 2q)^2 < (p - 2q)^2 \implies p^2 + 4pq + 4q^2 < p^2 - 4pq + 4q^2 \implies 8pq < 0 \implies pq < 0.
Since pq<0pq < 0, we can answer the rephrased target question ('Is pq>0pq > 0?') with a definitive 'NO'. In Data Sufficiency, a definitive 'No' means the statement is sufficient.
3
Evaluate Statement (2): p−q>0p - q > 0.
If p=3p = 3 and q=1q = 1, then p−q=2>0p - q = 2 > 0 and pq=3>0pq = 3 > 0 (Yes). If p=1p = 1 and q=−2q = -2, then p−q=3>0p - q = 3 > 0 and pq=−2<0pq = -2 < 0 (No).
Because Statement (2) allows both 'Yes' and 'No' outcomes, it is not sufficient.

Anahtar Kavram

Rephrasing absolute value distance inequalities and recognizing that a definitive 'No' response in Yes/No Data Sufficiency constitutes sufficiency.
Soru 13Soru →

If kk is a real number, is ∣k2−4∣<3k|k^2 - 4| < 3k?

(1) k2−5k+4<0k^2 - 5k + 4 < 0
(2) ∣k−1∣<2|k - 1| < 2

Which statement(s) provide sufficient information to determine whether the inequality holds?

Cevabı ve açıklamayı göster

Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
The stem inequality ∣k2−4∣<3k|k^2 - 4| < 3k simplifies to 1<k<41 < k < 4. Statement (1) directly yields 1<k<41 < k < 4, providing a definitive Yes answer. Statement (2) yields −1<k<3-1 < k < 3, which includes values inside (1,4)(1, 4) such as k=2k = 2 (Yes) and values outside (1,4)(1, 4) such as k=0.5k = 0.5 (No), making Statement (2) insufficient.

Adım Adım Çözüm

1
Rephrase the target question stem algebraically.
The target inequality ∣k2−4∣<3k|k^2 - 4| < 3k requires 3k>03k > 0 (so k>0k > 0) and translates to −3k<k2−4<3k-3k < k^2 - 4 < 3k. Solving k2−4<3kk^2 - 4 < 3k yields (k−4)(k+1)<0  ⟹  −1<k<4(k - 4)(k + 1) < 0 \implies -1 < k < 4. Solving −3k<k2−4-3k < k^2 - 4 for k>0k > 0 yields k2+3k−4>0  ⟹  (k+4)(k−1)>0  ⟹  k>1k^2 + 3k - 4 > 0 \implies (k + 4)(k - 1) > 0 \implies k > 1. Combining these gives the rephrased question: 'Is 1<k<41 < k < 4?'
Simplifying the question stem before evaluating the statements prevents misinterpretation of absolute value boundary conditions.
2
Evaluate Statement (1): k2−5k+4<0k^2 - 5k + 4 < 0.
Factoring the quadratic gives (k−1)(k−4)<0(k - 1)(k - 4) < 0, which means 1<k<41 < k < 4.
Since Statement (1) guarantees that kk lies strictly between 11 and 44, the answer to the rephrased question is a definitive Yes. Statement (1) ALONE is sufficient.
3
Evaluate Statement (2): ∣k−1∣<2|k - 1| < 2.
Removing the absolute value gives −2<k−1<2-2 < k - 1 < 2, or −1<k<3-1 < k < 3.
If k=2k = 2, then 1<2<41 < 2 < 4, giving a Yes answer. If k=0.5k = 0.5, then 0.50.5 is in (−1,3)(-1, 3) but not in (1,4)(1, 4), giving a No answer (since ∣0.52−4∣=3.75>3(0.5)=1.5|0.5^2 - 4| = 3.75 > 3(0.5) = 1.5). Because Statement (2) allows both Yes and No outcomes, it is NOT sufficient.

Anahtar Kavram

Absolute Value Inequalities and Question Stem Rephrasing

Alternatif Yöntem

Instead of solving the quadratic inequality −3k<k2−4<3k-3k < k^2 - 4 < 3k algebraically, test the boundary points k=1k = 1 and k=4k = 4 in ∣k2−4∣=3k|k^2 - 4| = 3k: at k=1k = 1, ∣1−4∣=3=3(1)|1 - 4| = 3 = 3(1); at k=4k = 4, ∣16−4∣=12=3(4)|16 - 4| = 12 = 3(4). Since 3k3k grows linearly while k2−4k^2 - 4 grows quadratically, the inequality holds strictly between these two positive roots 1<k<41 < k < 4.
Tahmini Süre:2m 0s
Soru 14Soru →

If xx is a real number, is ∣x−3∣+∣x+2∣≤7|x - 3| + |x + 2| \le 7?

(1) x2−2x−8≤0x^2 - 2x - 8 \le 0
(2) x(x−5)≤0x(x - 5) \le 0

Cevabı ve açıklamayı göster

Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Rephrasing the question target ∣x−3∣+∣x+2∣≤7|x - 3| + |x + 2| \le 7 shows that it is satisfied if and only if −3≤x≤4-3 \le x \le 4. Statement (1) yields the interval [−2,4][-2, 4], which is completely contained within [−3,4][-3, 4], guaranteeing a definitive 'Yes'. Statement (2) yields [0,5][0, 5], which includes values like 4.54.5 that result in a 'No'. Thus, Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Adım Adım Çözüm

1
Rephrase the question stem inequality ∣x−3∣+∣x+2∣≤7|x - 3| + |x + 2| \le 7.
The target inequality simplifies to −3≤x≤4-3 \le x \le 4.
Interpret ∣x−3∣+∣x+2∣|x - 3| + |x + 2| as the sum of distances from xx to 33 and −2-2 on the real number line. The distance between −2-2 and 33 is 55. For −2≤x≤3-2 \le x \le 3, the sum of distances is constantly 5≤75 \le 7. For x>3x > 3, the sum is 2x−1≤7  ⟹  x≤42x - 1 \le 7 \implies x \le 4. For x<−2x < -2, the sum is 1−2x≤7  ⟹  x≥−31 - 2x \le 7 \implies x \ge -3. Thus, the inequality holds if and only if x∈[−3,4]x \in [-3, 4].
2
Evaluate Statement (1): x2−2x−8≤0x^2 - 2x - 8 \le 0.
Statement (1) gives −2≤x≤4-2 \le x \le 4.
Factoring gives (x−4)(x+2)≤0(x - 4)(x + 2) \le 0, which holds when x∈[−2,4]x \in [-2, 4]. Since [−2,4]⊆[−3,4][-2, 4] \subseteq [-3, 4], every value of xx satisfying Statement (1) guarantees that ∣x−3∣+∣x+2∣≤7|x - 3| + |x + 2| \le 7 is true. This yields a definitive 'Yes'. Statement (1) alone is sufficient.
3
Evaluate Statement (2): x(x−5)≤0x(x - 5) \le 0.
Statement (2) gives 0≤x≤50 \le x \le 5.
The solution set is x∈[0,5]x \in [0, 5]. If x=1x = 1, −3≤1≤4-3 \le 1 \le 4 is true (Yes). If x=4.5x = 4.5, ∣4.5−3∣+∣4.5+2∣=1.5+6.5=8≤7|4.5 - 3| + |4.5 + 2| = 1.5 + 6.5 = 8 \le 7 is false (No). Since Statement (2) allows both 'Yes' and 'No' outcomes, Statement (2) alone is not sufficient.

Anahtar Kavram

Question stem rephrasing for distance-based absolute values and set-inclusion sufficiency evaluation
Soru 15Soru →

If xx is a real number, is ∣x−3∣<2x|x - 3| < 2x?

(1) x2−4x+3>0x^2 - 4x + 3 > 0
(2) ∣x−2∣<1|x - 2| < 1

Which of the following choices correctly describes the sufficiency of the statements?

Cevabı ve açıklamayı göster

Cevap: Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

Cevap

Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
Rephrasing the stem ∣x−3∣<2x|x - 3| < 2x shows it is equivalent to asking whether x>1x > 1. Statement (2) restricts xx to the range 1<x<31 < x < 3, where every value of xx satisfies x>1x > 1, providing a definitive YES answer. Statement (1) permits x<1x < 1 (giving a NO) and x>3x > 3 (giving a YES), making Statement (1) insufficient.

Adım Adım Çözüm

1
Rephrase the target question stem algebraically.
The target inequality is ∣x−3∣<2x|x - 3| < 2x. Since absolute values are non-negative (∣x−3∣≥0|x - 3| \ge 0), 2x2x must be strictly positive, so x>0x > 0.
- If x≥3x \ge 3, ∣x−3∣=x−3<2x  ⟹  x>−3|x - 3| = x - 3 < 2x \implies x > -3, which holds for all x≥3x \ge 3.
- If 0<x<30 < x < 3, ∣x−3∣=3−x<2x  ⟹  3x>3  ⟹  x>1|x - 3| = 3 - x < 2x \implies 3x > 3 \implies x > 1.
Thus, the inequality ∣x−3∣<2x|x - 3| < 2x holds if and only if x>1x > 1. The target question simplifies to: 'Is x>1x > 1?'
Simplifying the question stem before analyzing statements prevents misinterpreting the range of valid solutions.
2
Evaluate Statement (1): x2−4x+3>0x^2 - 4x + 3 > 0.
Factoring the quadratic yields (x−1)(x−3)>0(x - 1)(x - 3) > 0, so x<1x < 1 or x>3x > 3.
- If x=0x = 0 (which is <1< 1), ∣0−3∣=3|0 - 3| = 3 and 2(0)=02(0) = 0. Is 3<03 < 0? NO.
- If x=4x = 4 (which is >3> 3), ∣4−3∣=1|4 - 3| = 1 and 2(4)=82(4) = 8. Is 1<81 < 8? YES.
Since Statement (1) allows for both YES and NO outcomes, it is NOT sufficient.
Testing specific values from the disjoint solution set demonstrates that a single definitive answer cannot be reached.
3
Evaluate Statement (2): ∣x−2∣<1|x - 2| < 1.
Solving the absolute value inequality gives −1<x−2<1  ⟹  1<x<3-1 < x - 2 < 1 \implies 1 < x < 3.
For every value of xx in the interval (1,3)(1, 3), xx is strictly greater than 11. Therefore, the answer to 'Is x>1x > 1?' is a definitive YES for all possible values of xx in this statement.
A statement is sufficient if every allowed value of xx yields a consistent YES answer to the rephrased question stem.

Anahtar Kavram

Question Stem Rephrasing for Absolute Value Inequalities
Tahmini Süre:2m 0s
Soru 16Soru →

If xx is a real number, is x2<4x^2 < 4?

(1) ∣x−1∣<2|x - 1| < 2
(2) ∣x+1∣<3|x + 1| < 3

Cevabı ve açıklamayı göster

Cevap: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Cevap

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
Rephrasing the target question x2<4x^2 < 4 shows that we need to determine if −2<x<2-2 < x < 2. Statement (1) gives −1<x<3-1 < x < 3, which allows values outside (−2,2)(-2, 2) like x=2.5x = 2.5, so it is insufficient alone. Statement (2) gives −4<x<2-4 < x < 2, which allows values outside (−2,2)(-2, 2) like x=−3x = -3, so it is insufficient alone. Taking the intersection of both statements gives −1<x<2-1 < x < 2. Since every number in (−1,2)(-1, 2) satisfies −2<x<2-2 < x < 2, the combined statements definitively answer YES.

Adım Adım Çözüm

1
Rephrase the target question
The target question asking whether x2<4x^2 < 4 is equivalent to asking whether −2<x<2-2 < x < 2.
Taking the square root of both sides of x2<4x^2 < 4 yields ∣x∣<2|x| < 2, which expands to −2<x<2-2 < x < 2.
2
Evaluate Statement (1) independently
Statement (1) states ∣x−1∣<2|x - 1| < 2, which expands to −2<x−1<2-2 < x - 1 < 2, or −1<x<3-1 < x < 3.
If x=0x = 0, then −1<0<3-1 < 0 < 3 is true and 02<40^2 < 4 (Yes). If x=2.5x = 2.5, then −1<2.5<3-1 < 2.5 < 3 is true, but 2.52=6.25≮42.5^2 = 6.25 \not< 4 (No). Because we get both Yes and No answers, Statement (1) alone is insufficient.
3
Evaluate Statement (2) independently
Statement (2) states ∣x+1∣<3|x + 1| < 3, which expands to −3<x+1<3-3 < x + 1 < 3, or −4<x<2-4 < x < 2.
If x=0x = 0, then −4<0<2-4 < 0 < 2 is true and 02<40^2 < 4 (Yes). If x=−3x = -3, then −4<−3<2-4 < -3 < 2 is true, but (−3)2=9≮4(-3)^2 = 9 \not< 4 (No). Because we get both Yes and No answers, Statement (2) alone is insufficient.
4
Evaluate Statements (1) and (2) together
Combining −1<x<3-1 < x < 3 and −4<x<2-4 < x < 2 requires xx to satisfy both inequalities simultaneously, yielding the intersection −1<x<2-1 < x < 2.
Every value of xx in the interval (−1,2)(-1, 2) lies strictly inside the required target interval (−2,2)(-2, 2). Thus, x2<4x^2 < 4 is definitively YES. Both statements together are sufficient.

Anahtar Kavram

Inequality range intersection and absolute value distance expansion in Data Sufficiency
Tahmini Süre:2m 0s
Soru 17Soru →

If mm and nn are non-zero real numbers, is ∣m+n∣m>1\frac{|m + n|}{m} > 1?

(1) m<−∣n∣m < -|n|
(2) mn>0mn > 0 and ∣m+n∣=m+n|m + n| = m + n

Cevabı ve açıklamayı göster

Cevap: EACH statement ALONE is sufficient.

Cevap

EACH statement ALONE is sufficient.
The correct choice is that EACH statement ALONE is sufficient. Statement (1) restricts mm to negative values, guaranteeing that the numerator is non-negative while the denominator is negative, so the ratio can never exceed 1 (yielding a definitive 'No'). Statement (2) forces both mm and nn to be strictly positive, which simplifies the ratio to 1+nm>11 + \frac{n}{m} > 1 (yielding a definitive 'Yes'). Since each statement provides a definitive answer independently, each statement alone is sufficient.

Adım Adım Çözüm

1
Analyze the question stem target ∣m+n∣m>1\frac{|m + n|}{m} > 1.
Since absolute value ∣m+n∣|m + n| is always non-negative (∣m+n∣≥0|m + n| \ge 0), if m<0m < 0, the ratio ∣m+n∣m≤0\frac{|m + n|}{m} \le 0, which can never be greater than 1. Thus, if m<0m < 0, the answer is a definitive 'No'. If m>0m > 0, the expression simplifies to ∣m+n∣>m|m + n| > m.
Establishing the behavior of the expression based on the sign of mm simplifies statement evaluation.
2
Evaluate Statement (1): m<−∣n∣m < -|n|.
Since n≠0n \neq 0, ∣n∣>0|n| > 0, which implies −∣n∣<0-|n| < 0. Therefore, m<0m < 0. Because m<0m < 0 and ∣m+n∣≥0|m + n| \ge 0, the fraction ∣m+n∣m\frac{|m + n|}{m} is non-positive (≤0\le 0). Thus, ∣m+n∣m\frac{|m + n|}{m} cannot be greater than 1, yielding a definitive 'No'. Statement (1) ALONE is sufficient.
A statement that yields a definitive 'No' to a Yes/No Data Sufficiency question is sufficient.
3
Evaluate Statement (2): mn>0mn > 0 and ∣m+n∣=m+n|m + n| = m + n.
From mn>0mn > 0, mm and nn must have the same sign (both positive or both negative). The condition ∣m+n∣=m+n|m + n| = m + n requires m+n≥0m + n \ge 0. If both mm and nn were negative, m+nm + n would be negative, contradicting ∣m+n∣≥0|m + n| \ge 0. Hence, both mm and nn must be positive (m>0m > 0 and n>0n > 0). Substituting into the expression: ∣m+n∣m=m+nm=1+nm\frac{|m + n|}{m} = \frac{m + n}{m} = 1 + \frac{n}{m}. Since n>0n > 0 and m>0m > 0, nm>0\frac{n}{m} > 0, so 1+nm>11 + \frac{n}{m} > 1. This yields a definitive 'Yes'. Statement (2) ALONE is sufficient.
Determining that mm and nn must both be positive allows exact evaluation of the inequality.

Anahtar Kavram

Data Sufficiency logic for Yes/No questions involving absolute value properties and variable sign analysis.
Soru 18Soru →

If xx is a real number, is ∣2x−3∣≤5|2x - 3| \le 5?

(1) ∣x−1∣≤2|x - 1| \le 2
(2) x2−3x−4≤0x^2 - 3x - 4 \le 0

Cevabı ve açıklamayı göster

Cevap: EACH statement ALONE is sufficient.

Cevap

EACH statement ALONE is sufficient.
Rephrasing the target inequality ∣2x−3∣≤5|2x - 3| \le 5 gives −1≤x≤4-1 \le x \le 4. Statement (1) yields −1≤x≤3-1 \le x \le 3, which is completely contained within [−1,4][-1, 4] and therefore guarantees a definitive 'Yes'. Statement (2) yields −1≤x≤4-1 \le x \le 4, which matches the condition directly and also gives a definitive 'Yes'. Hence, each statement alone is sufficient.

Adım Adım Çözüm

1
Rephrase the question stem target inequality algebraically.
−5≤2x−3≤5  ⟹  −2≤2x≤8  ⟹  −1≤x≤4-5 \le 2x - 3 \le 5 \implies -2 \le 2x \le 8 \implies -1 \le x \le 4. Target Question: Is −1≤x≤4-1 \le x \le 4?
Simplifying the question stem converts an absolute value inequality into a clear number range for xx.
2
Evaluate Statement (1): ∣x−1∣≤2|x - 1| \le 2.
−2≤x−1≤2  ⟹  −1≤x≤3-2 \le x - 1 \le 2 \implies -1 \le x \le 3. Since every value in [−1,3][-1, 3] is also in [−1,4][-1, 4], the answer to 'Is −1≤x≤4-1 \le x \le 4?' is a definitive YES.
If a statement's allowed range is a subset of the target range, it guarantees a definitive 'Yes' answer.
3
Evaluate Statement (2): x2−3x−4≤0x^2 - 3x - 4 \le 0.
Factor the quadratic: (x−4)(x+1)≤0  ⟹  −1≤x≤4(x - 4)(x + 1) \le 0 \implies -1 \le x \le 4. This matches the target range exactly, yielding a definitive YES.
Matching the target inequality range provides a definitive 'Yes' answer.

Anahtar Kavram

Data Sufficiency Yes/No decision logic for absolute value range constraints and subset range implications.
Tahmini Süre:1m 30s
Soru 19Soru →

If aa and bb are non-zero real numbers, is ∣a−b∣>∣a+b∣|a - b| > |a + b|?

(1) ∣a+2b∣<∣a−2b∣|a + 2b| < |a - 2b|
(2) ∣a−1∣<∣b−1∣|a - 1| < |b - 1|

Which of the following choices correctly describes the sufficiency of the statements?

Cevabı ve açıklamayı göster

Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
The option stating that Statement (1) ALONE is sufficient, but Statement (2) alone is not sufficient is correct. Squaring both sides of the question stem inequality ∣a−b∣>∣a+b∣|a - b| > |a + b| yields a2−2ab+b2>a2+2ab+b2a^2 - 2ab + b^2 > a^2 + 2ab + b^2, which simplifies directly to ab<0ab < 0. Statement (1) states ∣a+2b∣<∣a−2b∣|a + 2b| < |a - 2b|. Squaring both sides yields a2+4ab+4b2<a2−4ab+4b2a^2 + 4ab + 4b^2 < a^2 - 4ab + 4b^2, which simplifies to 8ab<08ab < 0, or ab<0ab < 0. This gives a definitive YES to the question, so Statement (1) is sufficient. Statement (2) compares the distances of aa and bb from 1 on the number line. Choosing a=0.5a = 0.5 and b=−2b = -2 satisfies ∣0.5−1∣<∣−2−1∣|0.5 - 1| < |-2 - 1| and gives ab=−1<0ab = -1 < 0 (YES), whereas choosing a=0.5a = 0.5 and b=3b = 3 satisfies ∣0.5−1∣<∣3−1∣|0.5 - 1| < |3 - 1| and gives ab=1.5>0ab = 1.5 > 0 (NO). Thus, Statement (2) is insufficient.

Adım Adım Çözüm

1
Rephrase the question stem target using absolute value properties.
Since both sides of ∣a−b∣>∣a+b∣|a - b| > |a + b| are non-negative, square both sides: (a−b)2>(a+b)2  ⟹  a2−2ab+b2>a2+2ab+b2  ⟹  −2ab>2ab  ⟹  4ab<0  ⟹  ab<0(a - b)^2 > (a + b)^2 \implies a^2 - 2ab + b^2 > a^2 + 2ab + b^2 \implies -2ab > 2ab \implies 4ab < 0 \implies ab < 0. Thus, the question asks: 'Is ab<0ab < 0?' (Do aa and bb have opposite signs?)
Simplifying the target inequality converts an absolute value relationship into a clear sign constraint on the product abab.
2
Evaluate Statement (1): ∣a+2b∣<∣a−2b∣|a + 2b| < |a - 2b|.
Square both sides: (a+2b)2<(a−2b)2  ⟹  a2+4ab+4b2<a2−4ab+4b2  ⟹  4ab<−4ab  ⟹  8ab<0  ⟹  ab<0(a + 2b)^2 < (a - 2b)^2 \implies a^2 + 4ab + 4b^2 < a^2 - 4ab + 4b^2 \implies 4ab < -4ab \implies 8ab < 0 \implies ab < 0. This provides a definitive YES to the question 'Is ab<0ab < 0?'
Statement (1) uniquely guarantees that aa and bb have opposite signs, making Statement (1) ALONE sufficient.
3
Evaluate Statement (2): ∣a−1∣<∣b−1∣|a - 1| < |b - 1|.
Test numbers: Case 1: If a=0.5a = 0.5 and b=−2b = -2, then ∣0.5−1∣=0.5|0.5 - 1| = 0.5 and ∣−2−1∣=3|-2 - 1| = 3. Since 0.5<30.5 < 3, Statement (2) holds, and ab=(0.5)(−2)=−1<0ab = (0.5)(-2) = -1 < 0 (YES). Case 2: If a=0.5a = 0.5 and b=3b = 3, then ∣0.5−1∣=0.5|0.5 - 1| = 0.5 and ∣3−1∣=2|3 - 1| = 2. Since 0.5<20.5 < 2, Statement (2) holds, and ab=(0.5)(3)=1.5>0ab = (0.5)(3) = 1.5 > 0 (NO).
Because Statement (2) permits both ab<0ab < 0 and ab>0ab > 0, it cannot determine whether ab<0ab < 0. Statement (2) ALONE is insufficient.

Anahtar Kavram

Properties of Absolute Value Inequalities and Rephrased Data Sufficiency Targets
Tahmini Süre:2m 0s
Soru 20Soru →

If xx is a real number, is ∣x+4∣>2x|x + 4| > 2x?

(1) ∣x−1∣<3|x - 1| < 3
(2) x2−x−6<0x^2 - x - 6 < 0

Cevabı ve açıklamayı göster

Cevap: EACH statement ALONE is sufficient.

Cevap

EACH statement ALONE is sufficient.
Rephrasing the question stem shows that ∣x+4∣>2x|x + 4| > 2x is equivalent to x<4x < 4. Statement (1) establishes that −2<x<4-2 < x < 4, which guarantees x<4x < 4 (definitive Yes). Statement (2) establishes that −2<x<3-2 < x < 3, which also guarantees x<4x < 4 (definitive Yes). Therefore, each statement alone is sufficient.

Adım Adım Çözüm

1
Rephrase the target question stem algebraically.
The inequality ∣x+4∣>2x|x + 4| > 2x simplifies to x<4x < 4.
If x≥−4x \ge -4, then x+4>2x  ⟹  x<4x + 4 > 2x \implies x < 4. If x<−4x < -4, ∣x+4∣=−(x+4)>2x  ⟹  3x<−4  ⟹  x<−4/3|x + 4| = -(x + 4) > 2x \implies 3x < -4 \implies x < -4/3, which holds for all x<−4x < -4. Thus, ∣x+4∣>2x|x + 4| > 2x is true if and only if x<4x < 4.
2
Evaluate Statement (1): ∣x−1∣<3|x - 1| < 3.
Statement (1) yields the range −2<x<4-2 < x < 4.
Unpacking ∣x−1∣<3|x - 1| < 3 gives −3<x−1<3  ⟹  −2<x<4-3 < x - 1 < 3 \implies -2 < x < 4. Since every value in (−2,4)(-2, 4) is strictly less than 44, the answer to 'Is x<4x < 4?' is a definitive 'Yes'. Thus, Statement (1) alone is sufficient.
3
Evaluate Statement (2): x2−x−6<0x^2 - x - 6 < 0.
Statement (2) yields the range −2<x<3-2 < x < 3.
Factoring gives (x−3)(x+2)<0  ⟹  −2<x<3(x - 3)(x + 2) < 0 \implies -2 < x < 3. Since every value in (−2,3)(-2, 3) is strictly less than 44, the answer to 'Is x<4x < 4?' is a definitive 'Yes'. Thus, Statement (2) alone is sufficient.

Anahtar Kavram

Rephrasing absolute value inequalities in Data Sufficiency Yes/No questions
Tahmini Süre:1m 30s
Sayfa 1 / 2Sonraki