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Zorluk: KolayCombinations and Group Selections

A student must choose 33 books to read from a reading list of 66 distinct books. How many different combinations of 33 books can the student select?

  1. A
    1515
  2. B
    1818
  3. 2020Cevap
  4. D
    6060
  5. E
    120120

Cevap

The student can select 2020 different combinations of 33 books.
To find the number of ways to select 33 books from 66 distinct books when order does not matter, use the combination formula (nk)=n!k!(nk)!\binom{n}{k} = \frac{n!}{k!(n-k)!}. Evaluating (63)=6×5×43×2×1=20\binom{6}{3} = \frac{6 \times 5 \times 4}{3 \times 2 \times 1} = 20. Thus, 2020 is the correct number of combinations.

Adım Adım Çözüm

1
Identify the counting method
Since the order in which the books are selected does not matter, use the combinations formula (nk)=n!k!(nk)!\binom{n}{k} = \frac{n!}{k!(n-k)!}.
Selection of a group without regard to order requires combinations.
2
Substitute the given values into the formula
Here n=6n = 6 and k=3k = 3, so (63)=6×5×43×2×1\binom{6}{3} = \frac{6 \times 5 \times 4}{3 \times 2 \times 1}.
Apply n=6n=6 available items and k=3k=3 chosen items.
3
Simplify the expression
1206=20.\frac{120}{6} = 20.
Perform the basic arithmetic division.

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Combinations and Group Selections
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