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Zorluk: KolayCombinations and Group Selections

A research team needs to select a subcommittee of 3 scientists from a department containing 7 scientists. How many different 3-member subcommittees can be selected?

Cevap: 35 subcommittees

Cevap

35 different subcommittees can be selected.
The total number of ways to choose a committee of 3 members from a group of 7 without regard to order is given by the combination formula C(7,3)=7×6×53×2×1=35C(7,3) = \frac{7 \times 6 \times 5}{3 \times 2 \times 1} = 35.

Adım Adım Çözüm

1
Determine whether the selection depends on order.
Order does not matter since all 3 members of the subcommittee have equal roles.
When order does not matter in group selection, combinations (nCrnCr) must be used rather than permutations (nPrnPr).
2
Apply the combination formula C(n,k)=n!k!(nk)!C(n,k) = \frac{n!}{k!(n-k)!} with n=7n=7 and k=3k=3.
C(7,3)=7×6×53×2×1C(7,3) = \frac{7 \times 6 \times 5}{3 \times 2 \times 1}
This counts the unique groups of 3 that can be chosen from a pool of 7.
3
Calculate the numerical result.
35
Dividing 7×6×5=2107 \times 6 \times 5 = 210 by 3×2×1=63 \times 2 \times 1 = 6 yields 35.

Anahtar Kavram

Combinations and Group Selections
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