Soru

Zorluk: OrtaExponents, Roots, and Powers of Integers

What is the value of 165+165+165+165\sqrt{16^5 + 16^5 + 16^5 + 16^5}?

  1. A
    2102^{10}
  2. 2112^{11}Cevap
  3. C
    2122^{12}
  4. D
    2152^{15}
  5. E
    2202^{20}

Cevap

2112^{11}
Combining the four identical terms inside the radical gives 41654 \cdot 16^5. Expressing both factors with base 2 yields 22(24)5=22220=2222^2 \cdot (2^4)^5 = 2^2 \cdot 2^{20} = 2^{22}. Taking the square root gives 222=211\sqrt{2^{22}} = 2^{11}, which matches the value 2112^{11}.

Adım Adım Çözüm

1
Factor out the common term inside the square root.
165+165+165+165=416516^5 + 16^5 + 16^5 + 16^5 = 4 \cdot 16^5
Adding four identical terms is equivalent to multiplying the term by 4.
2
Convert both numbers to powers of 2.
4=224 = 2^2 and 165=(24)5=22016^5 = (2^4)^5 = 2^{20}, so 4165=22220=2224 \cdot 16^5 = 2^2 \cdot 2^{20} = 2^{22}
Expressing terms with a common prime base allows exponent rules to be applied.
3
Apply the square root to the simplified exponential expression.
222=(222)1/2=211\sqrt{2^{22}} = (2^{22})^{1/2} = 2^{11}
Taking the square root of a base raised to a power is equivalent to dividing the exponent by 2.

Anahtar Kavram

Combining like terms with exponents and applying prime factorization exponent laws under radical signs.
Tahmini Süre:1m 30s
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