Tüm alıştırma soruları

387 soru

Soru 181Soru

An inventory manager is organizing items into storage boxes. When the items are packed into boxes of 2424, 3636, or 4545 items each, there are always 1111 items remaining unpacked. If the total number of items is between 700700 and 1,0001,000, how many items are there in total?

Cevabı ve açıklamayı göster

Cevap: 731

Cevap

731
The number of items NN satisfies N11(mod24)N \equiv 11 \pmod{24}, N11(mod36)N \equiv 11 \pmod{36}, and N11(mod45)N \equiv 11 \pmod{45}. Consequently, N11N - 11 is a multiple of LCM(24,36,45)\text{LCM}(24, 36, 45). The prime factorizations are 24=23×324 = 2^3 \times 3, 36=22×3236 = 2^2 \times 3^2, and 45=32×545 = 3^2 \times 5. The LCM is 23×32×5=3602^3 \times 3^2 \times 5 = 360. Thus, N=360k+11N = 360k + 11 for some positive integer kk. Testing values of kk within the range 700<N<1,000700 < N < 1,000 yields k=2k = 2, giving N=360(2)+11=731N = 360(2) + 11 = 731.

Adım Adım Çözüm

1
Find the Least Common Multiple (LCM) of the divisors 24, 36, and 45.
LCM(24, 36, 45) = 360
Any number that leaves a constant remainder when divided by a set of numbers must be a constant remainder greater than a common multiple of those numbers.
2
Formulate the general equation for the total number of items N.
N = 360k + 11
Adding the common remainder 11 to any multiple of the LCM yields a valid total number of items.
3
Evaluate integer values of k to satisfy the constraint 700 < N < 1,000.
k = 2 gives N = 731
k = 1 gives 371, which is too small, and k = 3 gives 1,091, which exceeds 1,000.

Anahtar Kavram

Least Common Multiple (LCM) with Constant Remainder
Soru 182Soru

Let N=1943+1143643N = 19^{43} + 11^{43} - 6^{43}. What is the remainder when NN is divided by 77?

Cevabı ve açıklamayı göster

Cevap: 3

Cevap

3
Reducing each base modulo 7 simplifies the expression significantly: 192(mod7)19 \equiv -2 \pmod{7}, 114(mod7)11 \equiv 4 \pmod{7}, and 61(mod7)6 \equiv -1 \pmod{7}. Utilizing the cyclicity period of 3 for powers of 2 modulo 7 (231(mod7)2^3 \equiv 1 \pmod{7}), 1943(243)25(mod7)19^{43} \equiv -(2^{43}) \equiv -2 \equiv 5 \pmod{7}. Similarly, 1143443=286=(23)28×44(mod7)11^{43} \equiv 4^{43} = 2^{86} = (2^3)^{28} \times 4 \equiv 4 \pmod{7}. Lastly, 643(1)43=1(mod7)6^{43} \equiv (-1)^{43} = -1 \pmod{7}. Combining these yields N5+4(1)=103(mod7)N \equiv 5 + 4 - (-1) = 10 \equiv 3 \pmod{7}.

Adım Adım Çözüm

1
Reduce each base modulo 7
192(mod7)19 \equiv -2 \pmod{7}, 114(mod7)11 \equiv 4 \pmod{7}, and 61(mod7)6 \equiv -1 \pmod{7}
Simplifying bases using modular arithmetic reduces large power evaluations to smaller equivalents.
2
Evaluate 1943(mod7)19^{43} \pmod{7} using cyclicity
194325(mod7)19^{43} \equiv -2 \equiv 5 \pmod{7}
Since 231(mod7)2^3 \equiv 1 \pmod{7} and 43=3(14)+143 = 3(14) + 1, 2432(mod7)2^{43} \equiv 2 \pmod{7}, so (2)43=(243)2(mod7)(-2)^{43} = -(2^{43}) \equiv -2 \pmod{7}.
3
Evaluate 1143(mod7)11^{43} \pmod{7} using powers of 2
11434(mod7)11^{43} \equiv 4 \pmod{7}
1143443=286=(23)28×22128×4=4(mod7)11^{43} \equiv 4^{43} = 2^{86} = (2^3)^{28} \times 2^2 \equiv 1^{28} \times 4 = 4 \pmod{7}.
4
Evaluate 643(mod7)6^{43} \pmod{7}
6431(mod7)6^{43} \equiv -1 \pmod{7}
Any odd power of 1-1 equals 1-1.
5
Combine all components to determine the final remainder
N5+4(1)=103(mod7)N \equiv 5 + 4 - (-1) = 10 \equiv 3 \pmod{7}
Summing the individual remainders modulo 7 gives a final positive remainder of 3.

Anahtar Kavram

Modular Arithmetic and Cyclicity of Powers
Soru 183Soru

A positive integer nn is divisible by 2020 but is not divisible by 88. If nn has exactly 1515 positive divisors and 10n10n has exactly 2424 positive divisors, what is the value of nn?

Cevabı ve açıklamayı göster

Cevap: 2500

Cevap

2500
To determine nn, analyze its prime factorization. Divisibility by 20=225120 = 2^2 \cdot 5^1 requires that nn contains 22 raised to at least the power of 22 and 55 raised to at least the power of 11. The condition that nn is not divisible by 8=238 = 2^3 restricts the exponent of 22 to exactly 22. Thus, n=225bKn = 2^2 \cdot 5^b \cdot K', where b1b \ge 1 and KK' is a product of powers of distinct prime factors other than 22 and 55. The number of positive divisors of nn is d(n)=(2+1)(b+1)K=3(b+1)K=15d(n) = (2+1)(b+1)K = 3(b+1)K = 15, which simplifies to (b+1)K=5(b+1)K = 5. Because b1b \ge 1, we have b+12b+1 \ge 2. Since 55 is a prime number, its only divisor greater than or equal to 22 is 55. Thus, b+1=5b+1 = 5, giving b=4b = 4, and K=1K = 1, which means nn has no prime factors other than 22 and 55. Therefore, n=2254=4625=2500n = 2^2 \cdot 5^4 = 4 \cdot 625 = 2500. We verify that 10n=235510n = 2^3 \cdot 5^5 has (3+1)(5+1)=24(3+1)(5+1) = 24 positive divisors, confirming the solution.

Adım Adım Çözüm

1
Determine the power of 2 in the prime factorization of nn
The exponent of 22 in nn is exactly 22
Because nn is a multiple of 20=22520 = 2^2 \cdot 5 but not a multiple of 8=238 = 2^3, 222^2 divides nn but 232^3 does not.
2
Set up the divisor counting formula for nn
d(n)=(2+1)(b+1)K=15    (b+1)K=5d(n) = (2+1)(b+1)K = 15 \implies (b+1)K = 5, where b1b \ge 1 is the exponent of 55 and KK represents the product of terms from any additional prime factors
The total number of positive divisors of an integer N=p1a1p2a2N = p_1^{a_1} p_2^{a_2} \dots is given by (a1+1)(a2+1)(a_1+1)(a_2+1)\dots
3
Solve for the exponents and prime factors of nn
b=4b = 4 and K=1K = 1, giving n=2254n = 2^2 \cdot 5^4
Since nn is divisible by 2020, 55 is a prime factor of nn, so b1b \ge 1, which implies b+12b+1 \ge 2. Since 55 is prime, its only factor greater than 11 is 55, forcing b+1=5b+1 = 5 and K=1K = 1.
4
Verify d(10n)d(10n) and evaluate nn
10n=235510n = 2^3 \cdot 5^5 has (3+1)(5+1)=24(3+1)(5+1) = 24 divisors, and n=4625=2500n = 4 \cdot 625 = 2500
Multiplying nn by 10=2510 = 2 \cdot 5 increases the exponent of 22 from 22 to 33 and the exponent of 55 from 44 to 55.

Anahtar Kavram

Divisor Count Formula and Prime Factorization Constraints
Soru 184Soru

If the quadratic equation x2kx+36=0x^2 - kx + 36 = 0 has two distinct positive integer roots, r1r_1 and r2r_2, and r1+2r_1 + 2 and r2+2r_2 + 2 are the roots of the quadratic equation x219x+m=0x^2 - 19x + m = 0, what is the value of mm?

Cevabı ve açıklamayı göster

Cevap: 70

Cevap

The value of mm is 70.
By applying Vieta's formulas to both quadratic equations, we find that the sum of the original roots is r1+r2=15r_1 + r_2 = 15 and their product is r1r2=36r_1 r_2 = 36. Factoring x215x+36=(x3)(x12)=0x^2 - 15x + 36 = (x-3)(x-12) = 0 confirms the original roots are 33 and 1212. The new roots are 3+2=53+2=5 and 12+2=1412+2=14. Their product m=5×14=70m = 5 \times 14 = 70.

Adım Adım Çözüm

1
Apply Vieta's relations to the first quadratic equation
r1+r2=kr_1 + r_2 = k and r1r2=36r_1 \cdot r_2 = 36
For any quadratic equation x2+bx+c=0x^2 + bx + c = 0, the sum of roots is b-b and the product of roots is cc.
2
Apply Vieta's relations to the second quadratic equation
(r1+2)+(r2+2)=19    r1+r2=15(r_1 + 2) + (r_2 + 2) = 19 \implies r_1 + r_2 = 15
The coefficient of xx in x219x+m=0x^2 - 19x + m = 0 dictates that the sum of its roots equals 1919.
3
Determine the roots r1r_1 and r2r_2 and check integer constraints
r1=3r_1 = 3 and r2=12r_2 = 12
The integer factors of 3636 that sum to 1515 are 33 and 1212, satisfying all conditions.
4
Compute the constant term mm for the transformed equation
m=(3+2)(12+2)=5×14=70m = (3 + 2)(12 + 2) = 5 \times 14 = 70
The constant term mm equals the product of the transformed roots (r1+2)(r_1 + 2) and (r2+2)(r_2 + 2).

Anahtar Kavram

Vieta's Formulas and Quadratic Root Transformations
Tahmini Süre:2m 0s
Soru 185Soru

Scanner X can scan a batch of archival documents in 66 hours operating alone at a constant rate. Scanner Y can scan the exact same batch of documents in 33 hours operating alone at a constant rate. Working together simultaneously at their respective constant rates, how many hours will it take Scanner X and Scanner Y to scan the entire batch of documents?

Cevabı ve açıklamayı göster

Cevap: 2

Cevap

It will take Scanner X and Scanner Y a total of 22 hours to scan the batch of documents together.
To calculate combined completion time, add the rates of each machine rather than their completion times. Scanner X completes 16\frac{1}{6} of the task per hour, and Scanner Y completes 13\frac{1}{3} (or 26\frac{2}{6}) of the task per hour. Together, they complete 16+26=36=12\frac{1}{6} + \frac{2}{6} = \frac{3}{6} = \frac{1}{2} of the task per hour. The inverse of this rate gives the total time required: 22 hours.

Adım Adım Çözüm

1
Calculate individual work rates per hour.
Scanner X rate = 16\frac{1}{6} batch/hour, Scanner Y rate = 13\frac{1}{3} batch/hour.
Work rate is defined as Rate=WorkTime\text{Rate} = \frac{\text{Work}}{\text{Time}}.
2
Add the individual rates together to find the total combined rate.
Combined rate = 16+13=36=12\frac{1}{6} + \frac{1}{3} = \frac{3}{6} = \frac{1}{2} batch/hour.
When entities work together simultaneously, their work rates are additive.
3
Compute total time taken for 1 whole batch.
Total Time = 22 hours.
Time is the reciprocal of the combined work rate: Time=1Combined Rate\text{Time} = \frac{1}{\text{Combined Rate}}.

Anahtar Kavram

Combined Work Rate
Tahmini Süre:45s
Soru 186Soru

Three automated data-processing pipelines, AA, BB, and CC, process incoming dataset files at constant individual rates. Pipeline AA operating alone can complete a standard processing job in 1010 hours, while Pipeline BB operating alone can complete the same job in 1515 hours.

The processing begins with Pipelines AA and BB working together at their standard rates for 22 hours. At that point, Pipeline AA encounters a network slowdown that reduces its processing rate by 50%50\% for the remainder of the job. Pipelines AA and BB continue working at these modified rates for another 22 hours, after which Pipeline CC is brought online to assist them. If Pipeline CC operating alone at its constant rate could finish the entire job in 1010 hours, how many total hours from the start of the processing will it take for the job to be completed?

Cevabı ve açıklamayı göster

Cevap: 6

Cevap

The total time required to complete the job is 6 hours.
To solve multi-stage work rate problems, determine the rate per unit of time for each participant, multiply by the duration of each operational phase, and track the remaining fraction of the job. In the first 2 hours, Pipelines AA and BB complete 13\frac{1}{3} of the job. In the next 2 hours with Pipeline AA at half speed (rate 120\frac{1}{20}), they complete an additional 730\frac{7}{30} of the job, leaving 1330\frac{13}{30} unfinished. When Pipeline CC (rate 110\frac{1}{10}) joins, the combined rate becomes 1360\frac{13}{60} per hour, taking exactly 2 more hours to complete the remaining 1330\frac{13}{30} of the job. Adding all three intervals (2+2+22 + 2 + 2) yields a total time of 6 hours.

Adım Adım Çözüm

1
Determine the individual hourly work rates for each pipeline
Rate of Pipeline A=110A = \frac{1}{10} job/hr, Rate of Pipeline B=115B = \frac{1}{15} job/hr, Rate of Pipeline C=110C = \frac{1}{10} job/hr.
Work rate is the reciprocal of the total time taken to complete one full job.
2
Calculate work completed during Stage 1 (first 2 hours)
Combined rate = 110+115=16\frac{1}{10} + \frac{1}{15} = \frac{1}{6} job/hr. Work done = 2×16=132 \times \frac{1}{6} = \frac{1}{3} of the job.
Both Pipeline AA and Pipeline BB operate together at their standard rates for 2 hours.
3
Calculate work completed during Stage 2 (next 2 hours)
Modified rate of Pipeline A=0.50×110=120A = 0.50 \times \frac{1}{10} = \frac{1}{20} job/hr. Combined rate = 120+115=760\frac{1}{20} + \frac{1}{15} = \frac{7}{60} job/hr. Work done = 2×760=7302 \times \frac{7}{60} = \frac{7}{30} of the job.
Pipeline AA's efficiency drops by 50%, while Pipeline BB remains unchanged.
4
Calculate the remaining work after 4 hours
Total work completed = 13+730=1730\frac{1}{3} + \frac{7}{30} = \frac{17}{30}. Remaining work = 11730=13301 - \frac{17}{30} = \frac{13}{30}.
Subtracting cumulative work done from the total job (1) leaves the remaining portion.
5
Calculate the duration of Stage 3 when Pipeline CC joins
Combined rate = 120+115+110=1360\frac{1}{20} + \frac{1}{15} + \frac{1}{10} = \frac{13}{60} job/hr. Time required = 13/3013/60=2\frac{13/30}{13/60} = 2 hours.
Dividing remaining work by the combined rate of all three active pipelines gives the remaining time.
6
Sum the durations of all stages to find total elapsed time
Total time = 2 hours+2 hours+2 hours=6 hours2\text{ hours} + 2\text{ hours} + 2\text{ hours} = 6\text{ hours}.
The question asks for total elapsed time from the start of processing.

Anahtar Kavram

Multi-stage combined work rate problems require tracking accumulated work completed across distinct intervals with changing worker rates.
Soru 187Soru

A beverage recipe requires mixing orange juice and cranberry juice in a ratio of 4:14 : 1. If a caterer uses 1212 liters of orange juice, how many liters of cranberry juice must be added to maintain this ratio?

Cevabı ve açıklamayı göster

Cevap: 3

Cevap

The caterer must add 3 liters of cranberry juice.
The ratio of orange juice to cranberry juice is 4:14:1. Since 1212 liters of orange juice represents 44 parts, each part equals 124=3\frac{12}{4} = 3 liters. Therefore, 11 part of cranberry juice equals 33 liters.

Adım Adım Çözüm

1
Set up the ratio equation based on the recipe requirements.
Orange Juice : Cranberry Juice = 4:14 : 1
The problem states that for every 4 parts of orange juice, 1 part of cranberry juice is required.
2
Calculate the unknown amount of cranberry juice using the given quantity of orange juice.
Cranberry Juice = 124=3\frac{12}{4} = 3 liters
Since 12 liters represents 4 equal parts, dividing 12 by 4 yields the size of 1 part.

Anahtar Kavram

Direct Ratio and Proportion Scaling
Soru 188Soru

A corporate marketing team initially allocates its quarterly budget among Digital, Print, and Event advertising in the ratio 5:3:25 : 3 : 2, respectively. Midway through the quarter, $12,000\$12,000 is reallocated from Digital advertising to Event advertising, while the Print advertising budget remains unchanged. As a result of this transfer, the ratio of the Digital advertising budget to the Event advertising budget becomes 4:34 : 3. What was the total initial quarterly budget, in dollars, allocated across all three advertising categories?

Cevabı ve açıklamayı göster

Cevap: 120000

Cevap

The total initial quarterly budget allocated across all three categories was 120,000 dollars.
By representing the initial amounts as 5x5x, 3x3x, and 2x2x, the total initial budget is 10x10x. Accounting for the $12,000\$12,000 shift gives 5x12,0002x+12,000=43\frac{5x - 12,000}{2x + 12,000} = \frac{4}{3}. Solving yields x=12,000x = 12,000, which gives a total initial budget of 10×12,000=120,00010 \times 12,000 = 120,000 dollars.

Adım Adım Çözüm

1
Define initial allocations using a multiplier variable
Digital = 5x5x, Print = 3x3x, Event = 2x2x, Total Initial Budget = 10x10x
Representing ratio components algebraically allows set up of linear equations.
2
Adjust allocations according to the budget transfer
New Digital = 5x12,0005x - 12,000, New Event = 2x+12,0002x + 12,000
Reallocating $12,000\$12,000 reduces Digital by 12,000 and increases Event by 12,000.
3
Set up and solve the ratio equation for xx
5x12,0002x+12,000=4315x36,000=8x+48,0007x=84,000x=12,000\frac{5x - 12,000}{2x + 12,000} = \frac{4}{3} \Rightarrow 15x - 36,000 = 8x + 48,000 \Rightarrow 7x = 84,000 \Rightarrow x = 12,000
Equating the altered ratio of Digital to Event to 4/34/3 allows solving for multiplier xx.
4
Compute the total initial budget
Total = 10×12,000=120,00010 \times 12,000 = 120,000
Substituting x=12,000x = 12,000 back into the total initial expression 10x10x gives the final answer.

Anahtar Kavram

Altering non-isolated ratios through part-to-part modifications
Soru 189Soru

For all real numbers xx and yy, the custom operation \diamondsuit is defined by xy=3x2y+1x \diamondsuit y = 3x - 2y + 1. What is the value of 545 \diamondsuit 4?

Cevabı ve açıklamayı göster

Cevap: 8

Cevap

The value of 545 \diamondsuit 4 is 8.
Substituting x=5x = 5 and y=4y = 4 into the operation xy=3x2y+1x \diamondsuit y = 3x - 2y + 1 yields 3(5)2(4)+1=158+1=83(5) - 2(4) + 1 = 15 - 8 + 1 = 8.

Adım Adım Çözüm

1
Substitute the operands into the custom operator rule
5 \diamondsuit 4 = 3(5) - 2(4) + 1
The first term 55 corresponds to xx and the second term 44 corresponds to yy in the formula.
2
Simplify the numeric expression
15 - 8 + 1 = 8
Multiply first, then perform subtraction and addition from left to right.

Anahtar Kavram

Function Definitions, Evaluation, and Custom Operators
Soru 190Soru

An executive board must arrange 7 books side-by-side on a display shelf: 3 identical copies of a Finance textbook, 2 identical copies of an Economics textbook, and 2 distinct novels (Novel A and Novel B). How many distinct linear arrangements of these 7 books are possible such that Novel A and Novel B are not placed adjacent to each other?

Cevabı ve açıklamayı göster

Cevap: 300

Cevap

300
To find the number of distinct arrangements where Novel A and Novel B are not adjacent, use complementary counting. First, compute the total distinct arrangements of the 7 books with identical items: 7! / (3! * 2!) = 420. Next, find the number of arrangements where Novel A and Novel B ARE adjacent by bundling them as one unit [AB], which has 2 internal orderings (AB or BA). Arranging the 6 units ([AB], 3 Finance, 2 Economics) gives 6! / (3! * 2!) = 60 ways. Multiplying by 2 internal orderings gives 120 adjacent arrangements. Subtracting these from the total yields 420 - 120 = 300.

Adım Adım Çözüm

1
Calculate the unrestricted total number of distinct permutations of the 7 books.
420 distinct arrangements
There are 7 total items with 3 identical Finance books and 2 identical Economics books. Using the formula N! / (n1! * n2! ...), we get 7! / (3! * 2!) = 5,040 / 12 = 420.
2
Calculate the number of forbidden arrangements where Novel A and Novel B are adjacent.
120 forbidden arrangements
Treat Novel A and Novel B as a single composite item [AB]. There are 2! = 2 ways to order A and B inside this block (AB or BA). Then, arrange the 6 items ([AB] and the 5 textbooks with repetitions): 6! / (3! * 2!) = 60. Multiplying by 2 internal orderings gives 2 * 60 = 120.
3
Subtract the forbidden (adjacent) arrangements from the total unrestricted arrangements.
300 valid arrangements
By complementary counting, Valid = Total - Forbidden = 420 - 120 = 300.

Anahtar Kavram

Counting permutations with indistinguishable items and non-adjacency restrictions using complementary counting
Tahmini Süre:2m 0s
Soru 191Soru

For all non-zero real numbers xx, the function ff is defined by f(x)=x242xf(x) = \frac{x^2 - 4}{2x}, and the function gg is defined by g(x)=3x1g(x) = 3x - 1. What is the positive value of aa for which f(g(a))=0f(g(a)) = 0?

Cevabı ve açıklamayı göster

Cevap: 1

Cevap

The positive value of aa for which f(g(a))=0f(g(a)) = 0 is 1.
To solve f(g(a))=0f(g(a)) = 0, first find the values of yy where f(y)=0f(y) = 0. The numerator of f(y)=y242yf(y) = \frac{y^2 - 4}{2y} equals zero when y24=0y^2 - 4 = 0, yielding y=2y = 2 and y=2y = -2. Setting g(a)=3a1g(a) = 3a - 1 equal to these roots gives 3a1=2    a=13a - 1 = 2 \implies a = 1 and 3a1=2    a=1/33a - 1 = -2 \implies a = -1/3. Since aa must be positive, the correct value is 1.

Adım Adım Çözüm

1
Determine the values of the argument yy that satisfy f(y)=0f(y) = 0.
y=2y = 2 or y=2y = -2.
A fraction equals zero when its numerator is zero and its denominator is non-zero. Setting y24=0y^2 - 4 = 0 gives y=±2y = \pm 2.
2
Substitute g(a)=3a1g(a) = 3a - 1 into yy to solve for aa.
Solving 3a1=23a - 1 = 2 yields a=1a = 1; solving 3a1=23a - 1 = -2 yields a=1/3a = -1/3.
Setting the expression for g(a)g(a) equal to each root of f(y)=0f(y) = 0 identifies all potential values for aa.
3
Select the value of aa matching the positivity condition.
a=1a = 1.
The question explicitly specifies finding the positive value of aa.

Anahtar Kavram

Function composition and evaluation of nested functional equations.
Soru 192Soru

At a bio-tech research facility, the ratio of male to female scientists is initially 5:35 : 3. After 44 female scientists leave and 1212 male scientists join the facility, the ratio of male to female scientists becomes 4:14 : 1. If a group of NN additional female scientists subsequently joins the facility, changing the ratio of male to female scientists to 8:58 : 5, what is the value of NN?

Cevabı ve açıklamayı göster

Cevap: 12

Cevap

The value of NN is 12.
By setting up ratio equations stage-by-stage using multiplier kk, we determine that k=4k = 4, yielding 32 male and 8 female scientists after the first change. Solving 328+N=85\frac{32}{8+N} = \frac{8}{5} yields N=12N = 12.

Adım Adım Çözüm

1
Define initial variables using a common ratio multiplier kk.
Male scientists = 5k5k, Female scientists = 3k3k.
Ratios preserve proportionality through a constant multiplier.
2
Formulate and solve the equation for the first population adjustment.
5k+123k4=4    5k+12=12k16    7k=28    k=4\frac{5k + 12}{3k - 4} = 4 \implies 5k + 12 = 12k - 16 \implies 7k = 28 \implies k = 4.
Adding 12 males and removing 4 females sets the new ratio to 4:14 : 1.
3
Determine the exact number of male and female scientists at the facility after the first adjustment.
Male scientists = 5(4)+12=325(4) + 12 = 32; Female scientists = 3(4)4=83(4) - 4 = 8.
Substitute k=4k = 4 back into the adjusted quantity expressions.
4
Formulate and solve the equation for the second population adjustment involving NN.
328+N=85    8(8+N)=160    64+8N=160    8N=96    N=12\frac{32}{8 + N} = \frac{8}{5} \implies 8(8 + N) = 160 \implies 64 + 8N = 160 \implies 8N = 96 \implies N = 12.
The number of male scientists remains 32 while female scientists increase by NN to achieve an 8:58 : 5 ratio.

Anahtar Kavram

Multi-step ratio manipulation and algebraic modeling
Tahmini Süre:2m 0s
Soru 193Soru

For all non-zero real numbers aa and bb, the binary operator \diamond is defined by ab=abaa \diamond b = a - \frac{b}{a}. If kk is a positive integer such that (k3)3=12(k \diamond 3) \diamond 3 = \frac{1}{2}, what is the value of kk?

Cevabı ve açıklamayı göster

Cevap: 3

Cevap

The positive integer value of kk is 3.
Applying the non-commutative custom operator definition ab=abaa \diamond b = a - \frac{b}{a} to the nested expression (k3)3=12(k \diamond 3) \diamond 3 = \frac{1}{2} requires working from the inside out. Letting u=k3=k3ku = k \diamond 3 = k - \frac{3}{k}, the outer equation becomes u3=u3u=12u \diamond 3 = u - \frac{3}{u} = \frac{1}{2}. Multiplying through by 2u2u gives 2u2u6=02u^2 - u - 6 = 0, which factors as (2u+3)(u2)=0(2u + 3)(u - 2) = 0, yielding u=2u = 2 or u=32u = -\frac{3}{2}. Substituting u=2u = 2 back into k3k=2k - \frac{3}{k} = 2 produces k22k3=0k^2 - 2k - 3 = 0, which factors as (k3)(k+1)=0(k - 3)(k + 1) = 0. Since kk must be a positive integer, k=3k = 3. Testing u=32u = -\frac{3}{2} gives 2k2+3k6=02k^2 + 3k - 6 = 0, which has no integer solutions.

Adım Adım Çözüm

1
Substitute a temporary variable for the inner custom operator expression.
Let u=k3=k3ku = k \diamond 3 = k - \frac{3}{k}.
Simplifies the nested expression (k3)3=12(k \diamond 3) \diamond 3 = \frac{1}{2} to a single variable operation u3=12u \diamond 3 = \frac{1}{2}.
2
Apply the operator definition to u3u \diamond 3 and solve the resulting quadratic equation for uu.
u3u=12    2u2u6=0    (2u+3)(u2)=0u - \frac{3}{u} = \frac{1}{2} \implies 2u^2 - u - 6 = 0 \implies (2u + 3)(u - 2) = 0, so u=2u = 2 or u=32u = -\frac{3}{2}.
Clearing the denominator uu transforms the custom operator equation into a standard quadratic equation.
3
Solve for positive integer kk using the obtained values of uu.
Setting k3k=2k - \frac{3}{k} = 2 yields k22k3=0    (k3)(k+1)=0k^2 - 2k - 3 = 0 \implies (k - 3)(k + 1) = 0. Since kk must be a positive integer, k=3k = 3. Setting k3k=32k - \frac{3}{k} = -\frac{3}{2} yields 2k2+3k6=02k^2 + 3k - 6 = 0, which has non-integer discriminant 57\sqrt{57}.
Only u=2u = 2 yields an integer solution for kk, satisfying all problem constraints.

Anahtar Kavram

Custom Operator Evaluation and Nested Functional Equations
Soru 194Soru

For all non-zero real numbers xx, the function ff satisfies the equation 2f(x)+f(1x)=6x2f(x) + f\left(\frac{1}{x}\right) = 6x. What is the value of f(2)f(2)?

Cevabı ve açıklamayı göster

Cevap: 7

Cevap

The value of f(2)f(2) is 7.
Substituting x=2x = 2 into the functional equation gives 2f(2)+f(12)=122f(2) + f\left(\frac{1}{2}\right) = 12. Substituting x=12x = \frac{1}{2} gives 2f(12)+f(2)=32f\left(\frac{1}{2}\right) + f(2) = 3. Multiplying the first equation by 2 and subtracting the second equation eliminates f(12)f\left(\frac{1}{2}\right), producing 3f(2)=213f(2) = 21, so f(2)=7f(2) = 7.

Adım Adım Çözüm

1
Substitute x=2x = 2 into the functional equation
2f(2)+f(12)=122f(2) + f\left(\frac{1}{2}\right) = 12
This establishes a linear relation between f(2)f(2) and f(12)f\left(\frac{1}{2}\right).
2
Substitute x=12x = \frac{1}{2} into the functional equation
2f(12)+f(2)=32f\left(\frac{1}{2}\right) + f(2) = 3
This establishes a second linear relation involving the reciprocal input.
3
Eliminate f(12)f\left(\frac{1}{2}\right) by solving the system of equations
f(2)=7f(2) = 7
Multiplying the first equation by 2 yields 4f(2)+2f(12)=244f(2) + 2f\left(\frac{1}{2}\right) = 24. Subtracting the second equation gives 3f(2)=213f(2) = 21, which simplifies to f(2)=7f(2) = 7.

Anahtar Kavram

Evaluating functional equations by reciprocal variable substitution to form and solve a linear system.
Tahmini Süre:2m 0s
Soru 195Soru

How many distinct 8-digit positive integers can be formed by rearranging all of the digits 1,1,1,2,2,3,3,1, 1, 1, 2, 2, 3, 3, and 33 such that the resulting integer is even and no two 11 s are adjacent?

Cevabı ve açıklamayı göster

Cevap: 40

Cevap

40
To ensure the 8-digit number is even, the units (8th) digit must be 2. This leaves 7 positions to fill with three 1s, one 2, and three 3s. By arranging the 4 non-1 digits ({2, 3, 3, 3}) first, there are 4! / (1! 3!) = 4 distinct arrangements. Placing 4 digits creates 5 distinct gaps where the 1s can be placed without being adjacent. Choosing 3 gaps out of 5 for the three identical 1s gives C(5, 3) = 10 ways. Thus, the total number of valid integers is 4 * 10 = 40.

Adım Adım Çözüm

1
Fix the last digit to satisfy the even integer restriction
The 8th digit is fixed as 2, leaving 7 positions to fill with the remaining digits {1, 1, 1, 2, 3, 3, 3}.
An integer is even if and only if its units digit is even. The digit 2 is the only even digit in the set.
2
Calculate the arrangements of the non-restricted digits
4! / (1! * 3!) = 4 distinct arrangements.
Arranging the four non-1 digits ({2, 3, 3, 3}) first sets up the framework for placing the restricted 1s.
3
Place the three identical 1s into the gaps using the combination formula
C(5, 3) = 10 distinct gap selections.
The 4 arranged digits create 5 gaps. Selecting 3 distinct gaps ensures no two 1s are adjacent.
4
Multiply the arrangements of non-1 digits by the number of gap choices
4 * 10 = 40.
By the Fundamental Counting Principle, each non-1 arrangement can be combined with any valid gap placement.

Anahtar Kavram

Permutations with Indistinguishable Objects and Non-Adjacency Restrictions (Gap Method)
Tahmini Süre:2m 0s
Soru 196Soru

If 2 is a root of the quadratic equation x2kx+24=0x^2 - kx + 24 = 0, where kk is a constant, and the quadratic equation x2(k+2)x+m=0x^2 - (k + 2)x + m = 0 has exactly one real solution, what is the value of mm?

Cevabı ve açıklamayı göster

Cevap: 64

Cevap

The value of mm is 64.
Substituting x=2x = 2 into x2kx+24=0x^2 - kx + 24 = 0 gives 42k+24=04 - 2k + 24 = 0, which simplifies to 2k=282k = 28 or k=14k = 14. Substituting k=14k = 14 into x2(k+2)x+m=0x^2 - (k + 2)x + m = 0 produces x216x+m=0x^2 - 16x + m = 0. For a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 to have exactly one real solution, its discriminant b24acb^2 - 4ac must equal 0. Therefore, (16)24(1)(m)=0(-16)^2 - 4(1)(m) = 0, which means 2564m=0256 - 4m = 0, giving m=64m = 64.

Adım Adım Çözüm

1
Substitute the known root x=2x = 2 into the equation x2kx+24=0x^2 - kx + 24 = 0.
k=14k = 14
Since x=2x = 2 is a root of the quadratic equation, evaluating the expression at x=2x = 2 must equal zero.
2
Substitute k=14k = 14 into the second quadratic equation x2(k+2)x+m=0x^2 - (k + 2)x + m = 0.
x216x+m=0x^2 - 16x + m = 0
This determines the linear coefficient of the second quadratic equation.
3
Set the discriminant of x216x+m=0x^2 - 16x + m = 0 to zero.
m=64m = 64
A quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 has exactly one real solution if and only if its discriminant b24acb^2 - 4ac equals zero.

Anahtar Kavram

Solving quadratic equations via root substitution and applying the discriminant condition for repeated roots.
Tahmini Süre:1m 30s
Soru 197Soru

A bookshelf is to be arranged using 3 identical Mathematics books, 2 identical Physics books, and 1 Chemistry book. In how many distinct ways can all 6 books be arranged in a single row such that the Chemistry book is not adjacent to any Mathematics book?

Cevabı ve açıklamayı göster

Cevap: 12

Cevap

12
The single Chemistry book must not touch any of the 3 Mathematics books. This leaves three mutually exclusive possibilities for the Chemistry book: at the left end preceded by a Physics book (4 ways), at the right end followed by a Physics book (4 ways), or sandwiched between both Physics books as a single block (4 ways). Summing these gives 12 total valid arrangements.

Adım Adım Çözüm

1
Analyze the placement restriction on the Chemistry book
The Chemistry book (C) cannot be placed next to any Mathematics book (M). Thus, C can only be adjacent to Physics books (P) or placed at the boundary of the row touching a P.
Eliminating adjacency to M restricts C to touch only P or the ends of the shelf.
2
Count valid arrangements when C is at the far left (position 1)
The row begins with C-P. The remaining 4 spots must be filled with 3 identical M's and 1 P, yielding 4! / (3! 1!) = 4 distinct ways.
Position 1 has only one neighbor (position 2), which must be P.
3
Count valid arrangements when C is at the far right (position 6)
The row ends with P-C. The remaining 4 spots must be filled with 3 identical M's and 1 P, yielding 4! / (3! 1!) = 4 distinct ways.
Position 6 has only one neighbor (position 5), which must be P.
4
Count valid arrangements when C is in an interior position (positions 2 through 5)
C must be sandwiched between two P's, forming the block (P-C-P). Arranging this single block along with the 3 identical M's (total of 4 items) yields 4! / (3! 1!) = 4 distinct ways.
Any interior placement requires both adjacent neighbors of C to be P.
5
Sum the counts from all mutually exclusive cases
Total valid arrangements = 4 + 4 + 4 = 12.
The three cases cover all possible non-overlapping valid placements for C.

Anahtar Kavram

Counting permutations with identical elements and positional restrictions using case analysis and block formation.
Tahmini Süre:1m 30s
Soru 198Soru

A commercial bakery has two industrial ovens, Oven A and Oven B. Working alone at its constant rate, Oven A can bake a full order of 1,8001,800 pastries in 66 hours. Working alone at its constant rate, Oven B can bake the same order in 99 hours. If Oven A begins baking the order alone and is joined by Oven B after 22 hours, how many total hours will it take from the time Oven A starts until the full order of 1,8001,800 pastries is baked?

Cevabı ve açıklamayı göster

Cevap: 4.4

Cevap

The total time required to complete the entire order of pastries is 4.4 hours.
The total time of 4.4 hours is derived by determining Oven A's rate (1/6 job/hour) and Oven B's rate (1/9 job/hour). In the first 2 hours, Oven A completes 1/3 of the job, leaving 2/3. Operating together, their combined rate is 5/18 job/hour, which finishes the remaining 2/3 of the job in 2.4 hours. Summing 2 hours and 2.4 hours yields 4.4 total hours.

Adım Adım Çözüm

1
Determine the individual work rates per hour.
Oven A completes 16\frac{1}{6} of the job per hour; Oven B completes 19\frac{1}{9} of the job per hour.
Work rate is the reciprocal of the total time needed to complete one full job.
2
Calculate the fraction of work completed during the first 2 hours by Oven A.
Oven A completes 2×16=132 \times \frac{1}{6} = \frac{1}{3} of the total job.
Work done equals rate multiplied by time spent working.
3
Find the remaining fraction of work to be done.
Remaining work is 113=231 - \frac{1}{3} = \frac{2}{3} of the job.
Subtract the completed fraction from 1 (the whole job).
4
Calculate the combined rate of Oven A and Oven B working together.
Combined rate is 16+19=318+218=518\frac{1}{6} + \frac{1}{9} = \frac{3}{18} + \frac{2}{18} = \frac{5}{18} job per hour.
When entities work together, their individual rates add up.
5
Calculate the time spent by both ovens working together to complete the remaining work.
Time together is 2/35/18=125=2.4\frac{2/3}{5/18} = \frac{12}{5} = 2.4 hours.
Time equals remaining work divided by the combined rate.
6
Calculate total time from the start.
Total time = 2+2.4=4.42 + 2.4 = 4.4 hours.
Add the initial single-agent work duration to the combined work duration.

Anahtar Kavram

Work Rate and Combined Work
Soru 199Soru

For all real numbers xx except 00 and 11, the function f(x)f(x) satisfies the relation f(x)+2f(11x)=9xf(x) + 2f\left(\frac{1}{1-x}\right) = 9x. What is the value of f(2)f(2)?

Cevabı ve açıklamayı göster

Cevap: 6

Cevap

The value of f(2)f(2) is 66.
Evaluating the functional equation f(x)+2f(11x)=9xf(x) + 2f\left(\frac{1}{1-x}\right) = 9x at the values x=2x = 2, x=1x = -1, and x=12x = \frac{1}{2} creates a system of three linear equations in terms of f(2)f(2), f(1)f(-1), and f(12)f\left(\frac{1}{2}\right). Solving this system yields 9f(2)=549f(2) = 54, which simplifies directly to f(2)=6f(2) = 6.

Adım Adım Çözüm

1
Evaluate the functional equation at x=2x = 2
f(2)+2f(112)=9(2)    f(2)+2f(1)=18f(2) + 2f\left(\frac{1}{1-2}\right) = 9(2) \implies f(2) + 2f(-1) = 18
Applying the input x=2x = 2 creates an equation connecting f(2)f(2) and f(1)f(-1).
2
Evaluate the functional equation at x=1x = -1
f(1)+2f(11(1))=9(1)    f(1)+2f(12)=9f(-1) + 2f\left(\frac{1}{1-(-1)}\right) = 9(-1) \implies f(-1) + 2f\left(\frac{1}{2}\right) = -9
Evaluating at the new input x=1x = -1 generates a second equation connecting f(1)f(-1) and f(12)f\left(\frac{1}{2}\right).
3
Evaluate the functional equation at x=12x = \frac{1}{2}
f(12)+2f(111/2)=9(12)    f(12)+2f(2)=4.5f\left(\frac{1}{2}\right) + 2f\left(\frac{1}{1-1/2}\right) = 9\left(\frac{1}{2}\right) \implies f\left(\frac{1}{2}\right) + 2f(2) = 4.5
Evaluating at x=12x = \frac{1}{2} completes the cyclic chain by linking back to f(2)f(2).
4
Solve the system of three linear equations for f(2)f(2)
From equation 3, f(12)=4.52f(2)f\left(\frac{1}{2}\right) = 4.5 - 2f(2). Substituting into equation 2 yields f(1)=4f(2)18f(-1) = 4f(2) - 18. Substituting into equation 1 gives f(2)+2(4f(2)18)=18    9f(2)=54    f(2)=6f(2) + 2(4f(2) - 18) = 18 \implies 9f(2) = 54 \implies f(2) = 6.
Eliminating f(12)f\left(\frac{1}{2}\right) and f(1)f(-1) isolated f(2)f(2) to find its exact numerical value.

Anahtar Kavram

Cyclic Functional Equations and Substitution Systems
Soru 200Soru

If 2x2+5x3=02x^2 + 5x - 3 = 0 and x>0x > 0, what is the value of xx?

Cevabı ve açıklamayı göster

Cevap: 0.5

Cevap

The value of xx is 0.5.
Factoring the quadratic equation 2x2+5x3=02x^2 + 5x - 3 = 0 yields (2x1)(x+3)=0(2x - 1)(x + 3) = 0. Setting each linear factor equal to zero gives two possible solutions for xx: x=0.5x = 0.5 and x=3x = -3. Because the problem stipulates that x>0x > 0, the negative solution is discarded, leaving x=0.5x = 0.5.

Adım Adım Çözüm

1
Factor the quadratic expression
(2x1)(x+3)=0(2x - 1)(x + 3) = 0
Splitting the middle term 5x5x into 6xx6x - x allows grouping to factor by grouping.
2
Find the roots of the equation
x=0.5x = 0.5 or x=3x = -3
By the zero-product property, if the product of two factors is zero, at least one factor must be zero.
3
Apply the positivity constraint x>0x > 0
x=0.5x = 0.5
The root x=3x = -3 violates the given condition that xx must be strictly greater than zero.

Anahtar Kavram

Solving quadratic equations by factoring and applying domain constraints
ÖncekiSayfa 10 / 20Sonraki
Tüm alıştırma soruları — GMAT | Examkin