Data Sufficiency

263 soru

Soru 181Soru

If xx is a real number, is xx an integer?

(1) x2x^2 is an integer.
(2) 3x3x is an integer.

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Cevap: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Cevap

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
Evaluating Statement (1) alone allows x=2x = \sqrt{2} (not an integer) or x=2x = 2 (an integer), so Statement (1) is insufficient. Evaluating Statement (2) alone allows x=13x = \frac{1}{3} (not an integer) or x=1x = 1 (an integer), so Statement (2) is insufficient. Combining both statements establishes that x=m3x = \frac{m}{3} for an integer mm, and x2=m29=kx^2 = \frac{m^2}{9} = k for an integer kk. This requires m2=9km^2 = 9k, which implies mm must be a multiple of 3. Hence xx must be an integer, giving a definitive 'Yes' answer. Thus, both statements together are sufficient.

Adım Adım Çözüm

1
Analyze the question stem constraint
xx is constrained to be a real number (xRx \in \mathbb{R}). The target question is a Yes/No question: 'Is xx an integer?'
Without an explicit integer constraint in the stem, non-integer real numbers must be tested as counterexamples.
2
Evaluate Statement (1) alone
If x=2x = \sqrt{2}, then x2=2x^2 = 2 (an integer), but xx is not an integer (Answer: No). If x=2x = 2, then x2=4x^2 = 4 (an integer), and xx is an integer (Answer: Yes). Statement (1) is NOT sufficient.
Statement (1) allows both integer and non-integer values for xx.
3
Evaluate Statement (2) alone
If x=13x = \frac{1}{3}, then 3x=13x = 1 (an integer), but xx is not an integer (Answer: No). If x=1x = 1, then 3x=33x = 3 (an integer), and xx is an integer (Answer: Yes). Statement (2) is NOT sufficient.
Statement (2) allows fractional values with a denominator of 3 as well as integers.
4
Evaluate Statements (1) and (2) together
From Statement (2), x=m3x = \frac{m}{3} for some integer mm. Substituting into Statement (1) yields x2=(m3)2=m29=kx^2 = \left(\frac{m}{3}\right)^2 = \frac{m^2}{9} = k, where kk is an integer. Thus, m2=9km^2 = 9k. Since 9k9k is a multiple of 9, m2m^2 is divisible by 9, which means mm must be a multiple of 3. Let m=3pm = 3p for some integer pp. Then x=3p3=px = \frac{3p}{3} = p, which guarantees that xx is an integer. The answer is a definitive 'Yes'. Statements (1) and (2) together are SUFFICIENT.
Combining both conditions restricts xx to rational numbers whose square is an integer, forcing xx to be an integer.

Anahtar Kavram

Number Properties and Integer Constraints in Data Sufficiency
Tahmini Süre:1m 30s
Soru 182Soru

If mm and nn are positive integers such that mnm \neq n, is m2+mn2n2mn\frac{m^2 + mn - 2n^2}{m - n} an even integer?

(1) m+3m + 3 is an odd integer.
(2) nn is an odd integer.

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Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
By factoring the numerator of the expression in the question stem, m2+mn2n2mn=(m+2n)(mn)mn=m+2n\frac{m^2 + mn - 2n^2}{m - n} = \frac{(m + 2n)(m - n)}{m - n} = m + 2n. Since 2n2n is always even, m+2nm + 2n is even if and only if mm is even. Rephrasing the question target yields: "Is mm an even integer?" Statement (1) tells us m+3m + 3 is odd, which means mm must be even (giving a definitive "Yes" answer). Statement (2) provides information about nn, which is irrelevant to whether mm is even. Thus, Statement (1) alone is sufficient, but Statement (2) alone is not.

Adım Adım Çözüm

1
Simplify the target expression in the question stem
m2+mn2n2mn=(m+2n)(mn)mn=m+2n\frac{m^2 + mn - 2n^2}{m - n} = \frac{(m + 2n)(m - n)}{m - n} = m + 2n
Factoring the numerator simplifies the target expression for mnm \neq n.
2
Rephrase the target question using parity properties
Since 2n2n is an even integer for any integer nn, m+2nm + 2n is even if and only if mm is an even integer. The rephrased question target is: "Is mm an even integer?"
Simplifying the target question eliminates the variable nn from the requirement.
3
Evaluate Statement (1): m+3m + 3 is an odd integer
If m+3m + 3 is odd, then m=odd3=evenm = \text{odd} - 3 = \text{even}. Thus, mm is definitively even. Statement (1) alone is SUFFICIENT.
Subtracting an odd integer from an odd integer yields an even integer.
4
Evaluate Statement (2): nn is an odd integer
Statement (2) gives information about nn, but gives no information about mm. Since the rephrased question depends solely on mm, Statement (2) alone is INSUFFICIENT.
Knowing nn does not determine whether mm is even.

Anahtar Kavram

Algebraic factoring and target rephrasing in Data Sufficiency questions
Soru 183Soru

A regional logistics firm operates four distribution centers: Facility Alpha, Facility Beta, Facility Gamma, and Facility Delta. The table below displays the total tonnage of cargo processed and the average processing cost per ton (in dollars) at each facility during the last quarter:

Distribution CenterTotal Tonnage Processed (tons)Average Cost per Ton ($)
Facility Alpha2,40050
Facility Beta1,60040
Facility GammaTT80
Facility Delta3,000CC

Is the overall average processing cost per ton across all four distribution centers combined less than $60?

(1) Facility Gamma processed 2,000 tons of cargo (T=2,000T = 2,000).
(2) Facility Delta's average cost per ton was 55(55 ( C = 55$).

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Cevap: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Cevap

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
The correct answer is the option stating that both statements together are sufficient, but neither alone is sufficient. By setting up the total cost and total tonnage expressions from the table, the question 'Is the overall average cost less than 60?simplifiestotheinequalityIs60?' simplifies to the inequality 'Is T + 150C < 11,800 ?.Neitherstatementalonesuppliesbothvariables(?'. Neither statement alone supplies both variables ( T and and C ),buttogethertheyspecify), but together they specify T = 2,000 and and C = 55 ,giving, giving 2,000 + 8,250 = 10,250 < 11,800$, which answers the question with a definitive 'Yes'.

Adım Adım Çözüm

1
Set up the algebraic expression for the overall combined average processing cost.
Total Tonnage = 2,400+1,600+T+3,000=7,000+T2,400 + 1,600 + T + 3,000 = 7,000 + T.
Total Cost ()=) = (2,400 \times 50) + (1,600 \times 40) + (T \times 80) + (3,000 \times C) = 120,000 + 64,000 + 80T + 3,000C = 184,000 + 80T + 3,000C$.
Weighted average requires dividing total dollar expenditure across all facilities by total tonnage processed.
2
Rephrase the target question inequality.
Is 184,000+80T+3,000C7,000+T<60\frac{184,000 + 80T + 3,000C}{7,000 + T} < 60?
Multiply by (7,000+T)(7,000 + T):
184,000+80T+3,000C<60(7,000+T)184,000 + 80T + 3,000C < 60(7,000 + T)
184,000+80T+3,000C<420,000+60T184,000 + 80T + 3,000C < 420,000 + 60T
20T+3,000C<236,00020T + 3,000C < 236,000
Divide by 20:
Is T+150C<11,800T + 150C < 11,800?
Simplifying the target question establishes a direct numerical threshold to test against both statements.
3
Evaluate Statement (1) alone.
Given T=2,000T = 2,000, the target inequality becomes: Is 2,000+150C<11,800    150C<9,800    C<65.332,000 + 150C < 11,800 \implies 150C < 9,800 \implies C < 65.33?
Since CC is unknown, if C=50C = 50, the answer is Yes (9,500<11,8009,500 < 11,800). If C=70C = 70, the answer is No (12,50011,80012,500 \not< 11,800).
Statement (1) leaves CC undetermined, allowing both 'Yes' and 'No' outcomes.
4
Evaluate Statement (2) alone.
Given C=55C = 55, the target inequality becomes: Is T+150(55)<11,800    T+8,250<11,800    T<3,550T + 150(55) < 11,800 \implies T + 8,250 < 11,800 \implies T < 3,550?
Since TT is unknown, if T=2,000T = 2,000, the answer is Yes (10,250<11,80010,250 < 11,800). If T=4,000T = 4,000, the answer is No (12,25011,80012,250 \not< 11,800).
Statement (2) leaves TT undetermined, allowing both 'Yes' and 'No' outcomes.
5
Evaluate Statements (1) and (2) together.
Combining T=2,000T = 2,000 and C=55C = 55 into the rephrased inequality:
T+150C=2,000+150(55)=2,000+8,250=10,250T + 150C = 2,000 + 150(55) = 2,000 + 8,250 = 10,250.
Since 10,250<11,80010,250 < 11,800, we obtain a definitive 'Yes'.
Both variables are uniquely determined, resolving the target inequality definitively.

Anahtar Kavram

Weighted Average Calculation and Data Sufficiency Inequality Rephrasing
Tahmini Süre:2m 0s
Soru 184Soru

In a GMAT Data Sufficiency Value question asking for the unique numerical value of a variable xx, if Statement (1) alone restricts xx to a set of two distinct real numbers and Statement (2) alone also restricts xx to a set of two distinct real numbers, then combining Statement (1) and Statement (2) is guaranteed to determine a unique value for xx.

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Cevap: False

Cevap

The statement is false because the intersection of the solution sets of two statements can contain multiple values, failing to yield a unique numerical answer.
The statement is false. Combining two Data Sufficiency statements requires finding the values common to both solution sets. If both statements individually narrow the variable to the exact same pair of values, combining them does not eliminate either value. Consequently, the combined statements still leave multiple possibilities and remain insufficient.

Adım Adım Çözüm

1
Formulate the mathematical condition for combining Data Sufficiency statements
Evaluating Statement (1) and Statement (2) together requires finding the set of values that satisfy both statements simultaneously, which is the set intersection S1S2S_1 \cap S_2 of their individual solution sets S1S_1 and S2S_2.
Both statements are taken to be true at the same time when analyzing their combined sufficiency.
2
Analyze whether the intersection of two 2-element sets necessarily contains exactly one element
If S1={2,3}S_1 = \{2, 3\} and S2={2,3}S_2 = \{2, 3\}, then S1S2={2,3}S_1 \cap S_2 = \{2, 3\}, which contains two elements rather than one.
Two independent DS statements can be algebraically redundant or share identical candidate roots without contradicting one another.
3
Determine the sufficiency outcome of the combined statements
Since xx can still equal either 22 or 33, the combined statements do not yield a single, unique value for xx.
A Value-type Data Sufficiency question requires a single, unambiguous value for a condition to be deemed sufficient.

Anahtar Kavram

Statement Combination and Solution Set Intersection
Soru 185Soru

A medical research trial evaluated 100100 patients, each of whom experienced side effect A, side effect B, or both. Exactly 6565 patients experienced side effect A, and exactly 5555 patients experienced side effect B. What was the average (arithmetic mean) duration of side effect A, in days, among all patients who experienced side effect A?

(1) The average duration of side effect A for patients who experienced ONLY side effect A was 88 days.
(2) The average duration of side effect A for patients who experienced BOTH side effects was 1212 days.

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Cevap: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Cevap

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
The correct choice indicates that both statements combined provide sufficient data while neither is sufficient on its own. Using the standard inclusion-exclusion principle for two sets, 100=65+55N(Both)100 = 65 + 55 - N(\text{Both}), giving exactly 2020 patients with both side effects and 4545 patients with only side effect A. Statement (1) provides the sum of durations for the 4545 patients (45×8=36045 \times 8 = 360), and Statement (2) provides the sum of durations for the 2020 patients (20×12=24020 \times 12 = 240). Neither statement alone gives both sums, but together they yield a total sum of 600600 days for 6565 patients, resulting in a single definitive mean of 60065\frac{600}{65} days.

Adım Adım Çözüm

1
Rephrase the question stem using overlapping sets principles.
Let N(A)=65N(A) = 65, N(B)=55N(B) = 55, and total patients N(AB)=100N(A \cup B) = 100. Using the set formula N(AB)=N(A)+N(B)N(AB)N(A \cup B) = N(A) + N(B) - N(A \cap B), we get 100=65+55N(AB)100 = 65 + 55 - N(A \cap B), so N(AB)=20N(A \cap B) = 20.
Determining the exact count of patients in the overlap region (ABA \cap B) and the exclusive region (A onlyA \text{ only}) is necessary to set up the weighted average formula.
2
Calculate the subgroup sizes for patients experiencing side effect A.
Patients with ONLY side effect A = N(A)N(AB)=6520=45N(A) - N(A \cap B) = 65 - 20 = 45. Patients with BOTH side effects = 2020. Total patients with side effect A = 6565.
The total duration of side effect A across all 6565 patients is the sum of durations from the 4545 'only A' patients and the 2020 'both' patients.
3
Evaluate Statement (1) independently.
Statement (1) states that the mean for the 4545 'only A' patients is 88 days. The total duration for this group is 45×8=36045 \times 8 = 360 days. However, the duration for the 2020 'both' patients is unknown.
Without the total duration for the overlap group, the overall mean cannot be determined. Thus, Statement (1) alone is NOT sufficient.
4
Evaluate Statement (2) independently.
Statement (2) states that the mean for the 2020 'both' patients is 1212 days. The total duration for this group is 20×12=24020 \times 12 = 240 days. However, the duration for the 4545 'only A' patients is unknown.
Without the total duration for the exclusive A group, the overall mean cannot be determined. Thus, Statement (2) alone is NOT sufficient.
5
Evaluate Statement (1) and Statement (2) together.
Combining both statements, the total duration for all 6565 patients with side effect A is 360+240=600360 + 240 = 600 days. The overall average duration is 60065=12013\frac{600}{65} = \frac{120}{13} days.
A unique numerical value is obtained for the target question, so both statements together are sufficient.

Anahtar Kavram

Combining overlapping set subgroup sizes with weighted arithmetic mean formulas to evaluate Data Sufficiency statements.
Tahmini Süre:2m 0s
Soru 186Soru

If aa and bb are non-zero real numbers, what is the value of a2+9b2ab\frac{a^2 + 9b^2}{ab}?

(1) a23ab18b2=0a^2 - 3ab - 18b^2 = 0
(2) a>0a > 0 and b>0b > 0

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Cevap: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Cevap

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
The correct option is the choice stating that both statements together are sufficient, but neither statement alone is sufficient. Statement (1) produces two valid roots for the ratio of the variables, which lead to two different target values. Statement (2) specifies that both variables are positive, which eliminates the negative root and uniquely identifies the ratio and target value when combined with Statement (1).

Adım Adım Çözüm

1
Rephrase the target expression in terms of the ratio k=abk = \frac{a}{b}.
a2+9b2ab=a2ab+9b2ab=ab+9(ba)=k+9k\frac{a^2 + 9b^2}{ab} = \frac{a^2}{ab} + \frac{9b^2}{ab} = \frac{a}{b} + 9\left(\frac{b}{a}\right) = k + \frac{9}{k}. Finding the ratio k=abk = \frac{a}{b} is sufficient to answer the question.
Dividing the numerator by the denominator simplifies the expression into a function of a single ratio variable.
2
Evaluate Statement (1) independently.
Divide a23ab18b2=0a^2 - 3ab - 18b^2 = 0 by b2b^2 to get (ab)23(ab)18=0\left(\frac{a}{b}\right)^2 - 3\left(\frac{a}{b}\right) - 18 = 0, or k23k18=0k^2 - 3k - 18 = 0. Factoring yields (k6)(k+3)=0(k - 6)(k + 3) = 0, so k=6k = 6 or k=3k = -3. If k=6k = 6, target value is 6+96=7.56 + \frac{9}{6} = 7.5. If k=3k = -3, target value is 3+93=6-3 + \frac{9}{-3} = -6.
Since two distinct numerical outcomes are possible for the target expression, Statement (1) alone is NOT sufficient.
3
Evaluate Statement (2) independently.
a>0a > 0 and b>0b > 0 implies k=ab>0k = \frac{a}{b} > 0, but gives no numerical constraint on kk.
Without an equation linking aa and bb, Statement (2) alone is NOT sufficient.
4
Evaluate Statement (1) and Statement (2) combined.
Statement (1) gives k=6k = 6 or k=3k = -3. Statement (2) requires k>0k > 0, eliminating k=3k = -3 and establishing k=6k = 6 uniquely. Thus, the target value is uniquely 7.57.5.
Combining both statements uniquely determines the ratio kk and therefore the target expression.

Anahtar Kavram

Rephrasing homogeneous algebraic expressions into single ratio variables and analyzing degree constraints in quadratic systems.
Soru 187Soru

If xx and yy are real numbers, what is the value of x+yx + y?

(1) x2+y2=252xyx^2 + y^2 = 25 - 2xy
(2) x3+y3=1253xy(x+y)x^3 + y^3 = 125 - 3xy(x+y)

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Cevap: Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

Cevap

Statement (2) ALONE is sufficient to determine that x+y=5x + y = 5, but Statement (1) ALONE is not sufficient because it allows x+y=5x + y = 5 or x+y=5x + y = -5.
Statement (2) alone allows us to factor the expression into (x+y)3=125(x+y)^3 = 125. Because real numbers have a unique real cube root, x+yx+y must equal 55. Thus, Statement (2) alone provides a single, definitive answer to the question stem. Statement (1) yields (x+y)2=25(x+y)^2 = 25, which leads to x+y=5x+y = 5 or x+y=5x+y = -5, making it insufficient on its own.

Adım Adım Çözüm

1
Rephrase the target question
The target is to find a unique numerical value for the expression (x+y)(x + y). We do not need individual values for xx and yy.
Data Sufficiency targets involving expressions often do not require solving for individual variables.
2
Evaluate Statement (1): x2+y2=252xyx^2 + y^2 = 25 - 2xy
Rearranging terms gives x2+2xy+y2=25x^2 + 2xy + y^2 = 25, which factors as (x+y)2=25(x + y)^2 = 25. Taking the square root gives x+y=5x + y = 5 or x+y=5x + y = -5.
Since there are two distinct real values for x+yx + y, Statement (1) alone is insufficient.
3
Evaluate Statement (2): x3+y3=1253xy(x+y)x^3 + y^3 = 125 - 3xy(x+y)
Rearranging terms gives x3+3xy(x+y)+y3=125x^3 + 3xy(x+y) + y^3 = 125, which is the expanded form of (x+y)3=125(x + y)^3 = 125. Taking the cube root gives x+y=5x + y = 5.
For real numbers, every real number has exactly one real cube root. Thus, x+y=5x + y = 5 uniquely. Statement (2) alone is sufficient.

Anahtar Kavram

Algebraic Rephrasing and Degree of Real Polynomial Identities
Tahmini Süre:2m 0s
Soru 188Soru

If xx is a positive real number, is xx an integer?

(1) x+1xx + \frac{1}{x} is an integer.

(2) x2+1xx^2 + \frac{1}{x} is an integer.

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Cevap: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Cevap

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
The option stating that both statements together are sufficient is correct. Evaluating Statement (1) alone allows irrational solutions like x=3+52x = \frac{3+\sqrt{5}}{2}. Evaluating Statement (2) alone allows irrational roots of x33x+1=0x^3 - 3x + 1 = 0. However, combining both statements reveals that x2xx^2 - x is an integer. Subtracting the resulting linear system forces xx to be a rational number. For any positive rational x=pqx = \frac{p}{q} in simplest form, x+1xx + \frac{1}{x} being an integer requires p=1p = 1 and q=1q = 1, proving that x=1x = 1, which is an integer.

Adım Adım Çözüm

1
Evaluate Statement (1) independently.
Statement (1) is NOT sufficient.
If x=1x = 1, then x+1x=2x + \frac{1}{x} = 2 (an integer), and xx is an integer. However, if x=3+522.618x = \frac{3 + \sqrt{5}}{2} \approx 2.618 (a positive real non-integer), then x+1x=3+52+352=3x + \frac{1}{x} = \frac{3 + \sqrt{5}}{2} + \frac{3 - \sqrt{5}}{2} = 3 (an integer). Since xx can be an integer or a non-integer, Statement (1) alone does not uniquely answer the question.
2
Evaluate Statement (2) independently.
Statement (2) is NOT sufficient.
If x=1x = 1, then x2+1x=2x^2 + \frac{1}{x} = 2 (an integer), and xx is an integer. If x2+1x=3x^2 + \frac{1}{x} = 3, multiplying by xx yields x33x+1=0x^3 - 3x + 1 = 0. Evaluating f(x)=x33x+1f(x) = x^3 - 3x + 1 shows f(1)=1<0f(1) = -1 < 0 and f(2)=3>0f(2) = 3 > 0, so by the Intermediate Value Theorem, there exists a real root x(1,2)x \in (1, 2), which is positive but not an integer. Hence, Statement (2) alone is insufficient.
3
Evaluate Statement (1) and Statement (2) together.
Both statements together are SUFFICIENT.
Let x+1x=ax + \frac{1}{x} = a and x2+1x=bx^2 + \frac{1}{x} = b, where aa and bb are integers. Subtracting Statement (1) from Statement (2) gives (x2+1x)(x+1x)=ba    x2x=k\left(x^2 + \frac{1}{x}\right) - \left(x + \frac{1}{x}\right) = b - a \implies x^2 - x = k, where k=bak = b - a is an integer. From Statement (1), x2ax+1=0x^2 - ax + 1 = 0, and from the difference, x2xk=0x^2 - x - k = 0. Subtracting these two quadratic equations gives (1a)x+(1+k)=0(1 - a)x + (1 + k) = 0. For any positive real xx, a=x+1x2a = x + \frac{1}{x} \ge 2, so 1a01 - a \neq 0. Thus x=1+ka1x = \frac{1 + k}{a - 1}. Because kk and aa are integers, xx must be a rational number. Let x=pqx = \frac{p}{q} in lowest terms, where pp and qq are positive integers with gcd(p,q)=1\gcd(p, q) = 1. Then x+1x=pq+qp=p2+q2pq=a    p2+q2=apqx + \frac{1}{x} = \frac{p}{q} + \frac{q}{p} = \frac{p^2 + q^2}{pq} = a \implies p^2 + q^2 = a p q. Since p2=q(apq)p^2 = q(ap - q), qq must divide p2p^2. But gcd(p,q)=1\gcd(p, q) = 1, so q=1q = 1. Similarly, pp must divide q2q^2, so p=1p = 1. Thus x=1x = 1, which is an integer. Both statements together definitively answer YES.

Anahtar Kavram

Deduce integer constraints and rationality by combining non-linear algebraic expressions for real variables in Data Sufficiency.
Soru 189Soru

If pp and qq are positive real numbers, is pp an integer?

(1) p2+pqp^2 + pq is an integer.
(2) q2+pqq^2 + pq is an integer.

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Cevap: Statements (1) and (2) TOGETHER are NOT sufficient.

Cevap

Statements (1) and (2) TOGETHER are NOT sufficient to determine if pp is an integer.
The correct answer states that statements (1) and (2) together are not sufficient. Statement (1) alone allows p=0.5,q=1.5p = 0.5, q = 1.5 (giving p2+pq=1p^2+pq=1) as well as p=1,q=1p = 1, q = 1 (giving p2+pq=2p^2+pq=2). Statement (2) alone similarly allows p=0.5,q=1.5p = 0.5, q = 1.5 (giving q2+pq=3q^2+pq=3) as well as p=1,q=1p = 1, q = 1 (giving q2+pq=2q^2+pq=2). When both statements are evaluated together, adding the two equations reveals p+q=(p2+pq)+(q2+pq)p+q = \sqrt{(p^2+pq) + (q^2+pq)}. Choosing p2+pq=1p^2+pq = 1 and q2+pq=3q^2+pq = 3 yields p+q=2p+q = 2 and p=0.5p = 0.5, demonstrating that pp does not have to be an integer even when both statements are satisfied.

Adım Adım Çözüm

1
Analyze the Question Stem and Constraints
Variables pp and qq are positive real numbers (not constrained to integers). The goal is to determine if pp must be an integer.
Recognizing that variables are real numbers prevents premature integer assumptions.
2
Evaluate Statement (1) independently: p2+pq=p(p+q)p^2 + pq = p(p+q) is an integer
Case 1: If p=1p = 1 and q=1q = 1, then p(p+q)=1(2)=2p(p+q) = 1(2) = 2 (integer), so pp IS an integer.
Case 2: If p=0.5p = 0.5 and q=1.5q = 1.5, then p(p+q)=0.5(2)=1p(p+q) = 0.5(2) = 1 (integer), so pp IS NOT an integer.
Statement (1) is INSUFFICIENT.
Testing non-integer real values tests whether the condition forces pp to be an integer.
3
Evaluate Statement (2) independently: q2+pq=q(p+q)q^2 + pq = q(p+q) is an integer
Case 1: If p=1p = 1 and q=1q = 1, then q(p+q)=1(2)=2q(p+q) = 1(2) = 2 (integer), so pp IS an integer.
Case 2: If p=0.5p = 0.5 and q=1.5q = 1.5, then q(p+q)=1.5(2)=3q(p+q) = 1.5(2) = 3 (integer), so pp IS NOT an integer.
Statement (2) is INSUFFICIENT.
Statement (2) primarily constrains q(p+q)q(p+q), leaving pp unconstrained.
4
Evaluate Statements (1) and (2) Combined
Let p(p+q)=k1p(p+q) = k_1 and q(p+q)=k2q(p+q) = k_2 where k1,k2k_1, k_2 are positive integers.
Adding gives (p+q)2=k1+k2    p+q=k1+k2(p+q)^2 = k_1 + k_2 \implies p+q = \sqrt{k_1 + k_2}.
Thus, p=k1k1+k2p = \frac{k_1}{\sqrt{k_1 + k_2}}.
Case 1: Let k1=1k_1 = 1 and k2=3k_2 = 3. Then p+q=4=2    p=12=0.5p+q = \sqrt{4} = 2 \implies p = \frac{1}{2} = 0.5 (not an integer).
Case 2: Let k1=2k_1 = 2 and k2=2k_2 = 2. Then p+q=4=2    p=22=1p+q = \sqrt{4} = 2 \implies p = \frac{2}{2} = 1 (an integer).
Since pp can still be either an integer or a non-integer, both statements combined are INSUFFICIENT.
Algebraic combination yields p=k1k1+k2p = \frac{k_1}{\sqrt{k_1 + k_2}}, which produces non-integers for appropriate choices of integer constants k1k_1 and k2k_2.

Anahtar Kavram

Avoiding Implicit Integer Assumptions in Real-Valued Data Sufficiency
Tahmini Süre:2m 0s
Soru 190Soru

A tech consulting firm billed a client for a project completed by senior developers and junior developers. Senior developers were billed at a constant hourly rate of xx, and junior developers were billed at a constant hourly rate of yy. What was the average (arithmetic mean) hourly rate billed across all developer hours on the project?

(1) The total amount billed for senior developer hours was 50%50\% greater than the total amount billed for junior developer hours.
(2) Senior developers worked 40%40\% fewer total hours on the project than junior developers did.

Cevabı ve açıklamayı göster

Cevap: Statements (1) and (2) TOGETHER are NOT sufficient.

Cevap

Statements (1) and (2) TOGETHER are NOT sufficient.
The correct choice is the option stating that both statements together are not sufficient. Statement (1) provides the ratio of total revenues between the two developer types, which is insufficient to find the overall average rate. Statement (2) provides the ratio of hours worked between senior and junior developers, which is also insufficient on its own. Combining both statements allows us to find that senior developers earn 2.52.5 times the hourly rate of junior developers and to express the average hourly rate as 1.5625y1.5625 y. However, because neither statement provides an absolute dollar amount for xx, yy, or total revenue, the numerical average hourly rate cannot be calculated.

Adım Adım Çözüm

1
Rephrase the target question mathematically.
Let hsh_s be the senior hours and hjh_j be the junior hours. Total billing is xhs+yhjx h_s + y h_j, and total hours is hs+hjh_s + h_j. The average hourly rate is A=xhs+yhjhs+hjA = \frac{x h_s + y h_j}{h_s + h_j}. A specific numerical value for AA is required.
Clarifying the target prevents confusing relative ratios with absolute dollar values.
2
Evaluate Statement (1) independently.
Statement (1) states that xhs=1.5yhjx h_s = 1.5 y h_j. Total billing equals 2.5yhj2.5 y h_j, so A=2.5yhjhs+hjA = \frac{2.5 y h_j}{h_s + h_j}.
Without knowing the ratio of hours hshj\frac{h_s}{h_j} or specific dollar values for xx or yy, AA cannot be determined. Statement (1) alone is insufficient.
3
Evaluate Statement (2) independently.
Statement (2) states that hs=0.6hjh_s = 0.6 h_j. Thus A=0.6xhj+yhj1.6hj=0.6x+y1.6A = \frac{0.6 x h_j + y h_j}{1.6 h_j} = \frac{0.6 x + y}{1.6}.
Without the specific values of xx and yy, AA cannot be determined. Statement (2) alone is insufficient.
4
Evaluate Statements (1) and (2) together.
From (2), substitute hs=0.6hjh_s = 0.6 h_j into (1): x(0.6hj)=1.5yhj    0.6x=1.5y    x=2.5yx (0.6 h_j) = 1.5 y h_j \implies 0.6 x = 1.5 y \implies x = 2.5 y. Substituting x=2.5yx = 2.5 y and hs=0.6hjh_s = 0.6 h_j into AA yields A=(2.5y)(0.6hj)+yhj1.6hj=1.5yhj+yhj1.6hj=2.5y1.6=1.5625yA = \frac{(2.5 y)(0.6 h_j) + y h_j}{1.6 h_j} = \frac{1.5 y h_j + y h_j}{1.6 h_j} = \frac{2.5 y}{1.6} = 1.5625 y.
Combining both statements allows us to express the average rate as a multiple of yy (1.5625y1.5625 y), but since no concrete dollar value for yy or xx is provided in either statement, the exact average dollar rate cannot be calculated. Thus, both statements together are insufficient.

Anahtar Kavram

Distinguishing relative ratios from absolute numerical values in Data Sufficiency
Tahmini Süre:2m 0s
Soru 191Soru

If nn is a positive integer, is nn divisible by 18?

(1) n2n^2 is divisible by 54.
(2) n3n^3 is divisible by 108.

Cevabı ve açıklamayı göster

Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (1) establishes that n2n^2 is divisible by 54=21×3354 = 2^1 \times 3^3. Because the exponent of 3 in n2n^2 is 2b2b, the condition 2b32b \geq 3 implies b1.5b \geq 1.5, which forces b2b \geq 2 since bb must be an integer. Similarly, 2a1    a12a \geq 1 \implies a \geq 1. Therefore, nn must contain at least 21×32=182^1 \times 3^2 = 18 as a factor, guaranteeing that nn is divisible by 18 (Definitive Yes). Statement (2) establishes that n3n^3 is divisible by 108=22×33108 = 2^2 \times 3^3, which only forces a1a \geq 1 and b1b \geq 1, so nn must only be a multiple of 6. Since n=6n = 6 yields a 'No' and n=18n = 18 yields a 'Yes', Statement (2) is insufficient.

Adım Adım Çözüm

1
Rephrase the question target in terms of prime factorization
For a positive integer nn to be divisible by 18=21×3218 = 2^1 \times 3^2, the prime factorization of nn must contain at least one factor of 2 and at least two factors of 3.
Decomposing the target integer into prime factors establishes clear minimum exponent thresholds for evaluation.
2
Evaluate Statement (1): n2n^2 is divisible by 54=21×3354 = 2^1 \times 3^3
If n=2a×3b×kn = 2^a \times 3^b \times k, then n2=22a×32b×k2n^2 = 2^{2a} \times 3^{2b} \times k^2. Divisibility by 21×332^1 \times 3^3 requires 2a1    a12a \geq 1 \implies a \geq 1 and 2b3    b22b \geq 3 \implies b \geq 2 (since aa and bb are integers). Thus nn must contain at least 21×32=182^1 \times 3^2 = 18, giving a definitive YES.
Integer constraints on exponents force fractional lower bounds to round up to the next integer.
3
Evaluate Statement (2): n3n^3 is divisible by 108=22×33108 = 2^2 \times 3^3
If n3=23a×33b×k3n^3 = 2^{3a} \times 3^{3b} \times k^3, then 3a2    a13a \geq 2 \implies a \geq 1 and 3b3    b13b \geq 3 \implies b \geq 1. Thus nn must be divisible by 21×31=62^1 \times 3^1 = 6. Testing values: if n=6n = 6, 63=2166^3 = 216 (divisible by 108), but 6 is NOT divisible by 18 (NO). If n=18n = 18, 183=583218^3 = 5832 (divisible by 108), and 18 IS divisible by 18 (YES). Statement (2) is INSUFFICIENT.
Testing specific values demonstrates that Statement (2) allows both 'Yes' and 'No' outcomes.

Anahtar Kavram

Prime Factor Exponent Analysis under Integer Constraints in Data Sufficiency
Tahmini Süre:2m 0s
Soru 192Soru

If xx and yy are non-zero real numbers, is xy>1\frac{x}{y} > 1?

(1) x2y>xy2x^2 y > x y^2
(2) xyx>0\frac{x - y}{x} > 0

Cevabı ve açıklamayı göster

Cevap: Statements (1) and (2) TOGETHER are NOT sufficient.

Cevap

Statements (1) and (2) TOGETHER are NOT sufficient to determine whether xy>1\frac{x}{y} > 1.
The choice stating that statements (1) and (2) together are not sufficient is correct because combining both statements permits two valid cases: case 1 (x=3,y=2x=3, y=2) yields a 'Yes' answer to the stem, while case 2 (x=1,y=2x=-1, y=2) satisfies both statements but yields a 'No' answer to the stem.

Adım Adım Çözüm

1
Rephrase the target question
The condition xy>1\frac{x}{y} > 1 is equivalent to xyy>0\frac{x - y}{y} > 0, meaning xyx - y and yy must have the same sign.
Simplifying the question target allows direct testing of signs.
2
Evaluate Statement (1) independently
Statement (1) states x2y>xy2    xy(xy)>0x^2 y > x y^2 \iff x y (x - y) > 0. If x=3,y=2x = 3, y = 2, then xy(xy)=6>0xy(x-y) = 6 > 0 and xy=1.5>1\frac{x}{y} = 1.5 > 1 (Yes). If x=2,y=3x = -2, y = -3, then xy(xy)=6>0xy(x-y) = 6 > 0 and xy=23<1\frac{x}{y} = \frac{2}{3} < 1 (No). Insufficient.
Testing positive and negative pairs shows Statement (1) alone yields both Yes and No.
3
Evaluate Statement (2) independently without carrying over Statement (1) information
Statement (2) states xyx>0\frac{x - y}{x} > 0, meaning xx and xyx - y have the same sign. If x=3,y=2x = 3, y = 2, 13>0\frac{1}{3} > 0 and xy=1.5>1\frac{x}{y} = 1.5 > 1 (Yes). If x=2,y=3x = 2, y = -3, 52>0\frac{5}{2} > 0 and xy=23<1\frac{x}{y} = -\frac{2}{3} < 1 (No). Insufficient.
Statement (2) evaluated strictly in isolation also yields both Yes and No.
4
Evaluate Statements (1) and (2) combined
From Statement (1), xy(xy)>0xy(x-y) > 0. From Statement (2), xyx>0    x(xy)>0\frac{x-y}{x} > 0 \implies x(x-y) > 0. Combining these implies y>0y > 0. Since y>0y > 0, if x>0x > 0, then xy>0    x>y>0    xy>1x - y > 0 \implies x > y > 0 \implies \frac{x}{y} > 1 (Yes). However, if x<0x < 0, since y>0y > 0, xy<0x - y < 0, satisfying x(xy)>0x(x-y) > 0 and xy(xy)>0xy(x-y) > 0. For example, x=1,y=2x = -1, y = 2 satisfies both statements but gives xy=0.5<1\frac{x}{y} = -0.5 < 1 (No). Insufficient.
Even combined, two distinct cases exist (x>y>0x > y > 0 giving Yes, and x<0<yx < 0 < y giving No).

Anahtar Kavram

Statement Independence Evaluation and Statement Combination with Real Number Sign Traps
Soru 193Soru

If mm and nn are positive real numbers, is m+nm + n an integer?

(1) m2n2m^2 - n^2 is a prime number.
(2) mnm - n is a positive integer.

Cevabı ve açıklamayı göster

Cevap: Statements (1) and (2) TOGETHER are NOT sufficient.

Cevap

Statements (1) and (2) together are NOT sufficient.
The correct answer is that both statements combined are insufficient. A common high-level trap in GMAT Data Sufficiency is assuming variables must be integers when the stem specifies 'real numbers'. Combining (mn)(m+n)=p(m - n)(m + n) = p (prime) with mn=km - n = k (positive integer) gives m+n=pkm + n = \frac{p}{k}. If m=2.25m = 2.25 and n=0.25n = 0.25, we get mn=2m - n = 2 (integer) and m2n2=5m^2 - n^2 = 5 (prime), but m+n=2.5m + n = 2.5 (not an integer). Conversely, m=2m = 2 and n=1n = 1 gives mn=1m - n = 1 and m2n2=3m^2 - n^2 = 3 (prime), where m+n=3m + n = 3 (an integer). Because both an affirmative and a negative answer are possible, the information remains insufficient.

Adım Adım Çözüm

1
Evaluate Statement (1) independently.
Statement (1) is NOT sufficient.
If m2n2=2m^2 - n^2 = 2 (a prime number), we could have m=2m = 2 and n=2n = √2, giving m+n=2+2m + n = 2 + √2 (not an integer). Alternatively, m=2m = 2 and n=1n = 1 gives m2n2=3m^2 - n^2 = 3 (prime) and m+n=3m + n = 3 (an integer). Hence, Statement (1) alone is insufficient.
2
Evaluate Statement (2) independently.
Statement (2) is NOT sufficient.
If mn=2m - n = 2, we could have m=3.5m = 3.5 and n=1.5n = 1.5, giving m+n=5m + n = 5 (an integer). Or we could have m=3.2m = 3.2 and n=1.2n = 1.2, giving m+n=4.4m + n = 4.4 (not an integer). Hence, Statement (2) alone is insufficient.
3
Evaluate Statements (1) and (2) combined.
Test for consistency with both integer and non-integer outcomes for m+nm + n.
We know m2n2=(mn)(m+n)=pm^2 - n^2 = (m - n)(m + n) = p, where pp is prime and mn=km - n = k is a positive integer. Thus k(m+n)=pk(m + n) = p, so m+n=pkm + n = \frac{p}{k}.
4
Construct concrete counterexamples under both combined statements.
Statements (1) and (2) together are NOT sufficient.
Case 1 (YES): Let m=2m = 2 and n=1n = 1. Then m2n2=3m^2 - n^2 = 3 (prime) and mn=1m - n = 1 (positive integer). Here, m+n=3m + n = 3, which IS an integer.
Case 2 (NO): Let m=2.25m = 2.25 and n=0.25n = 0.25. Both are positive real numbers. mn=2.250.25=2m - n = 2.25 - 0.25 = 2 (positive integer). m2n2=(2.250.25)(2.25+0.25)=2×2.5=5m^2 - n^2 = (2.25 - 0.25)(2.25 + 0.25) = 2 \times 2.5 = 5 (prime number). But m+n=2.25+0.25=2.5m + n = 2.25 + 0.25 = 2.5, which is NOT an integer. Since m+nm + n can be an integer or a non-integer, both statements together are not sufficient.

Anahtar Kavram

Implicit Integer Constraints vs. Real Number Definitions in Data Sufficiency
Soru 194Soru

A dataset consists of 1515 distinct positive integers. Is the median of the dataset greater than its arithmetic mean?

(1) The sum of the 77 smallest integers in the dataset is 4242, and the sum of the 77 largest integers in the dataset is 140140.
(2) The dataset forms an arithmetic progression.

Cevabı ve açıklamayı göster

Cevap: Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

Cevap

Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
The option stating that Statement (2) alone is sufficient while Statement (1) alone is not sufficient is correct because Statement (2) establishes that the dataset is an arithmetic progression, where median always equals mean. This provides a definitive 'No' to the question of whether the median is strictly greater than the mean, satisfying sufficiency. Statement (1) allows values of the median both above and below 1313, yielding both 'Yes' and 'No' outcomes.

Adım Adım Çözüm

1
Rephrase the question stem mathematically.
Let the 15 distinct positive integers be ordered as x1<x2<<x7<x8<x9<<x15x_1 < x_2 < \dots < x_7 < x_8 < x_9 < \dots < x_{15}. The median is x8x_8, and the arithmetic mean is μ=i=115xi15\mu = \frac{\sum_{i=1}^{15} x_i}{15}. We need to determine whether x8>μx_8 > \mu.
Simplifying the question target clarifies what information is necessary for sufficiency.
2
Evaluate Statement (1) independently.
Statement (1) gives i=17xi=42\sum_{i=1}^7 x_i = 42 and i=915xi=140\sum_{i=9}^{15} x_i = 140. The total sum is 42+x8+140=182+x842 + x_8 + 140 = 182 + x_8, so the mean is μ=182+x815\mu = \frac{182 + x_8}{15}. The inequality x8>182+x815x_8 > \frac{182 + x_8}{15} simplifies to 14x8>18214 x_8 > 182, or x8>13x_8 > 13. If x8=10x_8 = 10 (with x1x7={3,4,5,6,7,8,9}x_1 \dots x_7 = \{3,4,5,6,7,8,9\} and x9x15={11,12,13,14,15,16,59}x_9 \dots x_{15} = \{11,12,13,14,15,16,59\}), then x813x_8 \le 13 yields 'No'. If x8=15x_8 = 15 (with x1x7={1,2,3,4,5,13,14}x_1 \dots x_7 = \{1,2,3,4,5,13,14\} and x9x15={16,17,18,19,20,21,29}x_9 \dots x_{15} = \{16,17,18,19,20,21,29\}), then x8>13x_8 > 13 yields 'Yes'.
Since Statement (1) allows for both 'Yes' and 'No' answers, it is NOT sufficient.
3
Evaluate Statement (2) independently.
Statement (2) states that the elements form an arithmetic progression. In any set of numbers that forms an arithmetic progression, the distribution is perfectly symmetric, so the arithmetic mean is exactly equal to the median (x8=μx_8 = \mu). Therefore, x8>μx_8 > \mu is false, giving a definitive answer of 'No'.
In Data Sufficiency Yes/No questions, a definitive 'No' answer establishes that the statement IS sufficient.

Anahtar Kavram

Data Sufficiency evaluation of data distributions, comparing median and arithmetic mean in symmetric versus asymmetric datasets.
Soru 195Soru

If xx and yy are real numbers, what is the value of xyx - y?

(1) x2y2=12(x+y)x^2 - y^2 = 12(x + y) and x+y0x + y \neq 0
(2) x2+y2=2xy+144x^2 + y^2 = 2xy + 144

Cevabı ve açıklamayı göster

Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
The option stating that Statement (1) ALONE is sufficient while Statement (2) ALONE is not sufficient is correct. Factoring Statement (1) gives (xy)(x+y)=12(x+y)(x - y)(x + y) = 12(x + y). Because x+y0x + y \neq 0, dividing both sides by (x+y)(x + y) establishes xy=12x - y = 12 uniquely. In contrast, Statement (2) simplifies to (xy)2=144(x - y)^2 = 144, yielding two possible values (1212 and 12-12), which makes Statement (2) insufficient on its own.

Adım Adım Çözüm

1
Evaluate Statement (1) independently
The statement gives x2y2=12(x+y)x^2 - y^2 = 12(x + y). Factoring the difference of squares gives (xy)(x+y)=12(x+y)(x - y)(x + y) = 12(x + y). Since x+y0x + y \neq 0, divide both sides by (x+y)(x + y) to get xy=12x - y = 12.
Because a unique numerical value for xyx - y is obtained, Statement (1) ALONE is sufficient.
2
Evaluate Statement (2) independently
Rearranging x2+y2=2xy+144x^2 + y^2 = 2xy + 144 yields x22xy+y2=144x^2 - 2xy + y^2 = 144, which contracts to (xy)2=144(x - y)^2 = 144. Taking the square root gives xy=12x - y = 12 or xy=12x - y = -12.
Because there are two distinct potential values for xyx - y, Statement (2) ALONE is not sufficient.
3
Combine the evaluations
Statement (1) alone is sufficient, whereas Statement (2) alone is not sufficient.
No combination of statements is required since Statement (1) alone uniquely determines the target value.

Anahtar Kavram

Algebraic Stem Simplification and Degree Ambiguity in Data Sufficiency
Tahmini Süre:2m 0s
Soru 196Soru

In a GMAT Data Sufficiency Yes/No question asking whether x>0x > 0, if Statement (1) implies x3x=0x^3 - x = 0 and Statement (2) implies x21=0x^2 - 1 = 0, then combining both statements is sufficient to answer the question because combining them narrows the set of possible values of xx to a smaller set than either statement alone.

Cevabı ve açıklamayı göster

Cevap: False

Cevap

False
The correct evaluation is False. In GMAT Data Sufficiency Yes/No questions, combining statements is sufficient only if every remaining value in the combined solution set yields the exact same answer (either all 'Yes' or all 'No'). Here, the combined set {1,1}\{-1, 1\} contains x=1x = -1 (which yields 'No') and x=1x = 1 (which yields 'Yes'), so the combined statements remain insufficient.

Adım Adım Çözüm

1
Analyze Statement (1) independently.
Solving x3x=0x^3 - x = 0 yields x(x1)(x+1)=0x(x - 1)(x + 1) = 0, so x{1,0,1}x \in \{-1, 0, 1\}. Testing these values against the question 'Is x>0x > 0?': x=1x = -1 gives No, x=0x = 0 gives No, and x=1x = 1 gives Yes. Because both Yes and No are possible, Statement (1) alone is insufficient.
Each statement must first be evaluated independently by checking if all allowed values yield a uniform answer.
2
Analyze Statement (2) independently.
Solving x21=0x^2 - 1 = 0 yields x{1,1}x \in \{-1, 1\}. Testing these values: x=1x = -1 gives No and x=1x = 1 gives Yes. Because both Yes and No are possible, Statement (2) alone is insufficient.
Statement (2) must be evaluated strictly without carrying over any information or restrictions from Statement (1).
3
Evaluate the combined statement information.
Taking the intersection of the solution sets from both statements gives {1,0,1}{1,1}={1,1}\{-1, 0, 1\} \cap \{-1, 1\} = \{-1, 1\}.
Combining statements requires finding all values that satisfy both Statement (1) and Statement (2) simultaneously.
4
Determine sufficiency of the combined set for a Yes/No question.
Within the combined set {1,1}\{-1, 1\}, x=1x = -1 yields 'No' (x0x \ngtr 0) while x=1x = 1 yields 'Yes' (x>0x > 0). Since a definitive Yes or No answer cannot be reached, the statements together remain insufficient.
For a Yes/No Data Sufficiency question, sufficiency requires that EVERY value in the combined solution set leads to the exact same answer.

Anahtar Kavram

Data Sufficiency Statement Combination for Yes/No Questions
Soru 197Soru

If xx and yy are real numbers such that x+y0x + y \neq 0, what is the value of the product xyxy?

(1) x3+y3=28(x+y)x^3 + y^3 = 28(x + y)
(2) x2+y2=20xyx^2 + y^2 = 20 - xy

Cevabı ve açıklamayı göster

Cevap: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Cevap

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
Combining both statements provides two independent linear equations in terms of (x+y)2(x+y)^2 and xyxy. Subtracting Statement (1) from Statement (2) eliminates the squared sum term (x+y)2(x+y)^2 and yields a unique value of 4-4 for the product xyxy, with real solutions existing for xx and yy. Therefore, both statements together are sufficient.

Adım Adım Çözüm

1
Analyze Statement (1) algebraically.
(x+y)23xy=28(x + y)^2 - 3xy = 28
Factor x3+y3x^3 + y^3 as (x+y)(x2xy+y2)(x + y)(x^2 - xy + y^2). Since x+y0x + y \neq 0, divide both sides by (x+y)(x + y) to obtain x2xy+y2=28x^2 - xy + y^2 = 28. Express x2+y2x^2 + y^2 as (x+y)22xy(x + y)^2 - 2xy, yielding (x+y)23xy=28(x + y)^2 - 3xy = 28. Because (x+y)2(x + y)^2 is unknown, xyxy can take multiple real values (e.g., if (x+y)2=16(x+y)^2 = 16, xy=4xy = -4; if (x+y)2=36(x+y)^2 = 36, xy=8/3xy = 8/3). Thus, Statement (1) alone is insufficient.
2
Analyze Statement (2) algebraically.
(x+y)2xy=20(x + y)^2 - xy = 20
Rearrange x2+y2=20xyx^2 + y^2 = 20 - xy to x2+xy+y2=20x^2 + xy + y^2 = 20. Express x2+y2x^2 + y^2 as (x+y)22xy(x + y)^2 - 2xy, yielding (x+y)2xy=20(x + y)^2 - xy = 20. Again, since (x+y)2(x + y)^2 is unknown, xyxy is not uniquely determined (e.g., if (x+y)2=16(x+y)^2 = 16, xy=4xy = -4; if (x+y)2=4(x+y)^2 = 4, xy=16xy = -16). Thus, Statement (2) alone is insufficient.
3
Combine both statements and solve the system of equations.
xy=4xy = -4
Let u=(x+y)2u = (x + y)^2 and v=xyv = xy. Statement (1) gives u3v=28u - 3v = 28 and Statement (2) gives uv=20u - v = 20. Subtracting the first equation from the second yields (uv)(u3v)=2028    2v=8    v=4(u - v) - (u - 3v) = 20 - 28 \implies 2v = -8 \implies v = -4. Hence, xy=4xy = -4 uniquely.
4
Verify existence of real solutions for xx and yy.
Real solutions exist because the discriminant is positive.
With u=16u = 16, we have x+y=4x + y = 4 or x+y=4x + y = -4. For x+y=4x + y = 4 and xy=4xy = -4, xx and yy are roots of t24t4=0t^2 - 4t - 4 = 0, which has discriminant 164(1)(4)=32>016 - 4(1)(-4) = 32 > 0. Thus real values of xx and yy exist.

Anahtar Kavram

System rephrasing in Data Sufficiency by substituting composite variables like (x+y)2(x+y)^2 and xyxy.
Soru 198Soru

If rr and ss are non-zero real numbers, what is the value of r2+2s2rs\frac{r^2 + 2s^2}{rs}?

(1) r23rs+2s2=0r^2 - 3rs + 2s^2 = 0
(2) r+s=6r + s = 6

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Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
The correct option states that Statement (1) alone is sufficient while Statement (2) is not. Rephrasing the target expression r2+2s2rs\frac{r^2 + 2s^2}{rs} as rs+2(sr)\frac{r}{s} + 2\left(\frac{s}{r}\right) shows that the target value depends exclusively on the ratio t=rst = \frac{r}{s}. Statement (1) factors into (rs)(r2s)=0(r - s)(r - 2s) = 0, giving t=1t = 1 or t=2t = 2. Testing t=1t = 1 yields 1+2=31 + 2 = 3, and testing t=2t = 2 yields 2+1=32 + 1 = 3. Because both possible values of tt evaluate to the same constant result (33), Statement (1) alone uniquely determines the target value and is sufficient. Statement (2) allows infinitely many ratios for r/sr/s, giving different outcomes, and is therefore insufficient.

Adım Adım Çözüm

1
Rephrase the target expression algebraically.
Dividing each term in the numerator by the denominator gives r2+2s2rs=rs+2(sr)\frac{r^2 + 2s^2}{rs} = \frac{r}{s} + 2\left(\frac{s}{r}\right). Letting t=rst = \frac{r}{s}, the target expression is t+2tt + \frac{2}{t}.
Simplifying the question stem reveals that we only need to know the ratio rs\frac{r}{s}.
2
Evaluate Statement (1): r23rs+2s2=0r^2 - 3rs + 2s^2 = 0.
Divide the entire equation by s2s^2 (since s0s \neq 0) to get (rs)23(rs)+2=0\left(\frac{r}{s}\right)^2 - 3\left(\frac{r}{s}\right) + 2 = 0, or t23t+2=0t^2 - 3t + 2 = 0. Factoring yields (t1)(t2)=0(t - 1)(t - 2) = 0, so t=1t = 1 or t=2t = 2.
If t=1t = 1, t+2t=1+2=3t + \frac{2}{t} = 1 + 2 = 3.
If t=2t = 2, t+2t=2+22=3t + \frac{2}{t} = 2 + \frac{2}{2} = 3.
In both cases, the target expression equals 33.
Although there are two solutions for the ratio tt, both lead to the identical value of 33 for the target expression. Thus, Statement (1) alone is sufficient.
3
Evaluate Statement (2): r+s=6r + s = 6.
If r=2r = 2 and s=4s = 4, then rs=12\frac{r}{s} = \frac{1}{2}, giving a target value of 12+4=4.5\frac{1}{2} + 4 = 4.5.
If r=3r = 3 and s=3s = 3, then rs=1\frac{r}{s} = 1, giving a target value of 1+2=31 + 2 = 3.
Since different pairs of rr and ss yield different values for the expression, Statement (2) alone is not sufficient.
Knowing only the linear sum of two variables does not uniquely fix their ratio.

Anahtar Kavram

Question Stem Rephrasing and Symmetry in Homogeneous Quadratic Expressions
Soru 199Soru

A logistics center processes packages using two sorting machines, Machine X and Machine Y, each operating continuously at its own constant hourly rate. On a given operational shift, Machine X processed packages for txt_x hours and Machine Y processed packages for tyt_y hours. What percentage of the total number of packages processed by both machines combined during the shift was processed by Machine X?

(1) If Machine X had operated for 20%20\% more time and Machine Y had operated for 20%20\% less time, Machine X would have processed 50%50\% more packages than Machine Y.

(2) The ratio of the hourly processing rate of Machine X to the hourly processing rate of Machine Y was 3:23:2, and the total operating time of both machines combined was 1010 hours.

Cevabı ve açıklamayı göster

Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (1) alone is sufficient because translating the percentage modifications into an equation gives 1.2Px=1.5×(0.8Py)1.2 P_x = 1.5 \times (0.8 P_y), which simplifies to 1.2Px=1.2Py1.2 P_x = 1.2 P_y, or Px=PyP_x = P_y. This proves Machine X processed exactly 50%50\% of the total packages. Statement (2) alone is not sufficient because knowing tx+ty=10t_x + t_y = 10 and rx/ry=3/2r_x / r_y = 3/2 allows infinitely many different package output ratios depending on how the 1010 hours are split between the two machines.

Adım Adım Çözüm

1
Define target variable algebraically from question stem
Let rxr_x and ryr_y be the constant hourly processing rates of Machine X and Machine Y, respectively. The total packages processed by Machine X is Px=rxtxP_x = r_x t_x, and by Machine Y is Py=rytyP_y = r_y t_y. The target percentage processed by Machine X is PxPx+Py×100%=11+PyPx×100%\frac{P_x}{P_x + P_y} \times 100\% = \frac{1}{1 + \frac{P_y}{P_x}} \times 100\%. Finding the ratio PxPy\frac{P_x}{P_y} is necessary and sufficient.
Rephrasing the question stem shows that finding the single ratio of total packages Px/PyP_x / P_y is sufficient to answer the question.
2
Evaluate Statement (1)
Under the hypothetical scenario in Statement (1), the new operating time for Machine X is 1.2tx1.2 t_x and for Machine Y is 0.8ty0.8 t_y. The new package totals are rx(1.2tx)=1.2Pxr_x (1.2 t_x) = 1.2 P_x and ry(0.8ty)=0.8Pyr_y (0.8 t_y) = 0.8 P_y. The statement specifies that 1.2Px=1.5×(0.8Py)1.2 P_x = 1.5 \times (0.8 P_y). Simplifying the right-hand side: 1.5×0.8=1.21.5 \times 0.8 = 1.2, so 1.2Px=1.2Py    Px=Py1.2 P_x = 1.2 P_y \implies P_x = P_y. Thus, PxPy=1\frac{P_x}{P_y} = 1, which means Machine X processed PxPx+Px=50%\frac{P_x}{P_x + P_x} = 50\% of the total packages.
Algebraic simplification yields a unique value for the target percentage, making Statement (1) sufficient.
3
Evaluate Statement (2)
Statement (2) gives rxry=32\frac{r_x}{r_y} = \frac{3}{2} and tx+ty=10t_x + t_y = 10. The ratio of total packages processed is PxPy=(rxry)(txty)=32(txty)\frac{P_x}{P_y} = \left(\frac{r_x}{r_y}\right) \left(\frac{t_x}{t_y}\right) = \frac{3}{2} \left(\frac{t_x}{t_y}\right). Since txt_x and tyt_y can take any positive real values summing to 1010 (e.g., tx=2,ty=8    PxPy=38t_x = 2, t_y = 8 \implies \frac{P_x}{P_y} = \frac{3}{8} vs. tx=6,ty=4    PxPy=94t_x = 6, t_y = 4 \implies \frac{P_x}{P_y} = \frac{9}{4}), the percentage varies.
Without individual values for txt_x and tyt_y, multiple target percentages are possible, so Statement (2) is not sufficient.

Anahtar Kavram

Question Stem Rephrasing and Algebraic Simplification of Combined Rates
Tahmini Süre:2m 30s
Soru 200Soru

If rr and ss are positive integers, is r2s2r^2 - s^2 divisible by 8?

(1) rr and ss are both odd integers.
(2) r+sr + s is divisible by 4.

Cevabı ve açıklamayı göster

Cevap: EACH statement ALONE is sufficient.

Cevap

Each statement alone is sufficient to answer the question with a definitive 'Yes'.
The correct response identifies that each statement alone gives a definitive 'Yes' answer. Statement (1) shows that the square of any odd integer is 1(mod8)1 \pmod 8, so subtracting two odd squares gives 0(mod8)0 \pmod 8. Statement (2) shows r+sr+s is a multiple of 4, which forces rr and ss to share parity, making rsr-s even and their product (r+s)(rs)(r+s)(r-s) a multiple of 4×2=84 \times 2 = 8.

Adım Adım Çözüm

1
Rephrase the question target using algebraic factorization.
Note that r2s2=(r+s)(rs)r^2 - s^2 = (r + s)(r - s). The question asks whether (r+s)(rs)(r + s)(r - s) is a multiple of 8.
Factoring difference of squares isolates the sum and difference components to easily test parity and divisibility.
2
Evaluate Statement (1): rr and ss are both odd integers.
Any odd integer can be written as 2k+12k + 1. Squaring gives (2k+1)2=4k2+4k+1=4k(k+1)+1(2k + 1)^2 = 4k^2 + 4k + 1 = 4k(k + 1) + 1. Since k(k+1)k(k + 1) is the product of two consecutive integers, it is always even, making 4k(k+1)4k(k + 1) a multiple of 8. Thus, any odd integer squared leaves a remainder of 1 when divided by 8. Therefore, r21(mod8)r^2 \equiv 1 \pmod 8 and s21(mod8)s^2 \equiv 1 \pmod 8, so r2s211=0(mod8)r^2 - s^2 \equiv 1 - 1 = 0 \pmod 8.
Statement (1) alone yields a definitive 'Yes', so Statement (1) is sufficient.
3
Evaluate Statement (2): r+sr + s is divisible by 4.
If r+sr + s is divisible by 4, then r+s=4mr + s = 4m for some integer mm. Since r+sr + s is even, rr and ss must have the same parity (either both even or both odd). Consequently, their difference rs=(r+s)2s=4m2s=2(2ms)r - s = (r + s) - 2s = 4m - 2s = 2(2m - s) is an even integer (a multiple of 2). Multiplying (r+s)(r + s) by (rs)(r - s) yields (multiple of 4)×(multiple of 2)=multiple of 8(\text{multiple of } 4) \times (\text{multiple of } 2) = \text{multiple of } 8.
Statement (2) alone yields a definitive 'Yes', so Statement (2) is sufficient.

Anahtar Kavram

Divisibility Rules of Difference of Squares and Parity of Integers
Tahmini Süre:2m 0s
ÖncekiSayfa 10 / 14Sonraki
Data Sufficiency Alıştırma Soruları — GMAT — Sayfa 10 | Examkin