Data Sufficiency

263 soru

Soru 201Soru

A bio-refinery processes two grades of raw biomass, Grade Alpha and Grade Beta, to produce liquid biofuel. Grade Alpha yields 15%15\% biofuel per ton, while Grade Beta yields 35%35\% biofuel per ton. If a single production batch used a combined total of 1,2001,200 tons of Grade Alpha and Grade Beta biomass, resulting in VV total tons of biofuel, is V>300V > 300?

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Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
The correct answer is the option stating that Statement (1) ALONE is sufficient, but Statement (2) alone is not. Rephrasing the target condition V>300V > 300 yields A<600A < 600. Statement (1) provides A<533.33A < 533.33, which definitively proves A<600A < 600 (a conclusive YES). Statement (2) provides A<700A < 700, which permits values of AA both above and below 600600, rendering it insufficient.

Adım Adım Çözüm

1
Set up algebraic equations for total biomass and total biofuel yield.
Let AA be the tons of Grade Alpha biomass and BB be the tons of Grade Beta biomass. Given A+B=1,200A + B = 1,200, we have B=1,200AB = 1,200 - A. Total biofuel yield is V=0.15A+0.35BV = 0.15A + 0.35B.
Expressing VV in terms of a single variable AA simplifies the target question.
2
Rephrase the target question 'Is V>300V > 300?' in terms of variable AA.
Substitute B=1,200AB = 1,200 - A into the yield equation: V=0.15A+0.35(1,200A)=4200.20AV = 0.15A + 0.35(1,200 - A) = 420 - 0.20A. The condition V>300V > 300 becomes 4200.20A>300    120>0.20A    A<600420 - 0.20A > 300 \implies 120 > 0.20A \implies A < 600. Thus, the question asks: 'Is A<600A < 600?'
Rephrasing reduces the complex weighted average inequality to a straightforward threshold check on AA.
3
Evaluate Statement (1): The ratio of Grade Alpha to Grade Beta tonnage was less than 4:54:5.
AB<45    5A<4B\frac{A}{B} < \frac{4}{5} \implies 5A < 4B. Substituting B=1,200AB = 1,200 - A gives 5A<4(1,200A)    9A<4,800    A<533.335A < 4(1,200 - A) \implies 9A < 4,800 \implies A < 533.33. Since A<533.33A < 533.33 guarantees that A<600A < 600, the answer to 'Is A<600A < 600?' is a definitive YES. Statement (1) is SUFFICIENT.
Determining if Statement (1) alone guarantees A<600A < 600.
4
Evaluate Statement (2): More than 500500 tons of Grade Beta biomass was used in the batch.
B>500    1,200A>500    A<700B > 500 \implies 1,200 - A > 500 \implies A < 700. If A=500A = 500, then A<600A < 600 is TRUE (YES). If A=650A = 650, then A<600A < 600 is FALSE (NO). Because both YES and NO outcomes are possible, Statement (2) is NOT SUFFICIENT.
Checking whether Statement (2) produces a single definitive YES/NO answer.

Anahtar Kavram

Data Sufficiency Question Stem Rephrased for Weighted Averages and Mixture Ratios
Soru 202Soru

If xx and yy are real numbers, is x2+y2<25x^2 + y^2 < 25?

(1) x+y=7x + y = 7
(2) (x3)2+(y4)2=0(x - 3)^2 + (y - 4)^2 = 0

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Cevap: Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

Cevap

Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
Statement (1) allows multiple outcomes for x2+y2x^2 + y^2 (both values less than 25 and values greater than or equal to 25), so it is not sufficient. Statement (2) forces x=3x=3 and y=4y=4 because the sum of non-negative real squares can only be zero when each square term is zero. Substituting x=3x=3 and y=4y=4 yields x2+y2=25x^2 + y^2 = 25, which conclusively answers 'No' to the question stem (25<2525 < 25 is false). Hence, Statement (2) alone is sufficient.

Adım Adım Çözüm

1
Evaluate Statement (1) independently
Statement (1) gives x+y=7x + y = 7. If x=3.5x = 3.5 and y=3.5y = 3.5, then x2+y2=12.25+12.25=24.5<25x^2 + y^2 = 12.25 + 12.25 = 24.5 < 25 (Yes). If x=7x = 7 and y=0y = 0, then x2+y2=49+0=4925x^2 + y^2 = 49 + 0 = 49 \not< 25 (No).
Since both 'Yes' and 'No' are possible, Statement (1) alone is insufficient.
2
Evaluate Statement (2) independently without carrying over Statement (1)
Statement (2) states (x3)2+(y4)2=0(x - 3)^2 + (y - 4)^2 = 0. Since the square of a real number is non-negative, the sum of two squared terms can equal zero if and only if each term is zero: x3=0    x=3x - 3 = 0 \implies x = 3 and y4=0    y=4y - 4 = 0 \implies y = 4.
This uniquely fixes the values of xx and yy.
3
Calculate the target expression using values from Statement (2)
Substitute x=3x = 3 and y=4y = 4 into x2+y2x^2 + y^2: 32+42=9+16=253^2 + 4^2 = 9 + 16 = 25. The question asks if x2+y2<25x^2 + y^2 < 25. Since 25<2525 < 25 is false, the answer is a definitive 'No'.
A definitive 'No' answer means the statement provides enough information to answer the question, so Statement (2) alone is sufficient.

Anahtar Kavram

Statement Independence in Data Sufficiency and Definitive Yes/No Decision Rules
Tahmini Süre:2m 0s
Soru 203Soru

A logistics center uses two sorting systems, Line 1 and Line 2, to process package inventory. Line 1 operates at a constant rate of r1r_1 packages per minute, and Line 2 operates at a constant rate of r2r_2 packages per minute. During a testing run, Line 1 operated for t1t_1 minutes and Line 2 operated for t2t_2 minutes, sorting a total of PP packages. Was the combined average sorting rate during the test run—defined as the total packages sorted divided by total machine-minutes worked, Pt1+t2\frac{P}{t_1 + t_2}—greater than 4040 packages per minute?

(1) Line 1's sorting rate r1r_1 was 50%50\% greater than Line 2's sorting rate r2r_2, and Line 1 operated for a duration t1t_1 that was 50%50\% longer than Line 2's operating duration t2t_2.
(2) If Line 1 and Line 2 were to operate simultaneously for 11 hour, they would sort a combined total of 30003{}000 packages.

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Cevap: BOTH statements TOGETHER are sufficient, but NEITHER statement alone is sufficient.

Cevap

Both statements together are sufficient to determine that the combined average rate is 26 packages per minute, which definitively answers the question with a 'No'. Neither statement alone is sufficient.
The correct option is the one stating that both statements together are sufficient, but neither alone is sufficient. Statement (1) simplifies the weighted average rate to 1.3r21.3 r_2, which is insufficient by itself because r2r_2 is unknown. Statement (2) provides r1+r2=50r_1 + r_2 = 50, which is insufficient alone because individual rates and time proportions are unknown. Combining both statements allows us to solve for r2=20r_2 = 20 and compute the exact weighted average rate of 2626 packages per minute. Since 2626 is not greater than 4040, we obtain a definitive 'No' answer, establishing sufficiency.

Adım Adım Çözüm

1
Rephrase the target question algebraically.
The combined average sorting rate is Average Rate=Pt1+t2=r1t1+r2t2t1+t2\text{Average Rate} = \frac{P}{t_1 + t_2} = \frac{r_1 t_1 + r_2 t_2}{t_1 + t_2}. The target question asks: Is r1t1+r2t2t1+t2>40\frac{r_1 t_1 + r_2 t_2}{t_1 + t_2} > 40?
Establishing the target formula in terms of r1,r2,t1,r_1, r_2, t_1, and t2t_2 allows direct evaluation of each statement.
2
Evaluate Statement (1) independently.
Statement (1) gives r1=1.5r2r_1 = 1.5 r_2 and t1=1.5t2t_1 = 1.5 t_2. Substituting these into the average rate formula gives (1.5r2)(1.5t2)+r2t21.5t2+t2=2.25r2t2+r2t22.5t2=3.25r2t22.5t2=1.3r2\frac{(1.5 r_2)(1.5 t_2) + r_2 t_2}{1.5 t_2 + t_2} = \frac{2.25 r_2 t_2 + r_2 t_2}{2.5 t_2} = \frac{3.25 r_2 t_2}{2.5 t_2} = 1.3 r_2.
Since the value of r2r_2 is unknown, we cannot determine whether 1.3r2>401.3 r_2 > 40. Statement (1) alone is INSUFFICIENT.
3
Evaluate Statement (2) independently.
Operating simultaneously for 11 hour (6060 minutes) produces 30003{}000 packages: 60(r1+r2)=3000    r1+r2=5060(r_1 + r_2) = 3000 \implies r_1 + r_2 = 50 packages per minute.
Knowing r1+r2=50r_1 + r_2 = 50 does not fix the ratio of durations t1/t2t_1 / t_2 or individual rates r1,r2r_1, r_2. The weighted average could be anywhere between r1r_1 and r2r_2. Statement (2) alone is INSUFFICIENT.
4
Evaluate Statements (1) and (2) together.
From Statement (1), r1=1.5r2r_1 = 1.5 r_2. Substituting into Statement (2)'s equation r1+r2=50r_1 + r_2 = 50 yields 1.5r2+r2=50    2.5r2=50    r2=201.5 r_2 + r_2 = 50 \implies 2.5 r_2 = 50 \implies r_2 = 20. Consequently, r1=30r_1 = 30. Substituting r2=20r_2 = 20 into the expression from Statement (1) gives an average rate of 1.3×20=261.3 \times 20 = 26 packages per minute.
Since 2626 is not greater than 4040, we can answer the question with a definitive 'No'. A definitive 'No' means the combined statements are SUFFICIENT.

Anahtar Kavram

Weighted average rate simplification and Yes/No sufficiency determination in Data Sufficiency.
Tahmini Süre:2m 30s
Soru 204Soru

A renewable energy research laboratory tested four experimental photovoltaic panel coatings (Coating Alpha, Coating Beta, Coating Gamma, and Coating Delta) across three sunlight intensity levels (Low, Medium, and High). The table below displays the measured power output, in watts per square meter (W/m2\text{W/m}^2), for each coating under each sunlight intensity level:

CoatingLow IntensityMedium IntensityHigh Intensity
Coating Alpha80180280
Coating Beta90195310
Coating Gamma75170xx
Coating Deltayy200320

What is the average (arithmetic mean) power output of Coating Gamma across all three sunlight intensity levels?

(1) Under High Intensity, the power output of Coating Gamma is 10% greater than the power output of Coating Alpha under High Intensity.

(2) The average (arithmetic mean) power output of Coating Delta across the three intensity levels is equal to the average (arithmetic mean) power output of Coating Beta across the three intensity levels.

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Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Rephrasing the question target shows that finding the average power output of Coating Gamma requires finding the unknown value xx. Statement (1) directly gives a percentage relationship between xx and Coating Alpha's high-intensity output (280 W/m2280 \text{ W/m}^2), allowing us to calculate x=308x = 308 and thus the exact mean. Statement (2) allows us to solve for yy (Coating Delta's low-intensity output), but provides no information about xx. Therefore, Statement (1) alone is sufficient, while Statement (2) alone is not.

Adım Adım Çözüm

1
Rephrase the question stem target
The average power output of Coating Gamma is 75+170+x3=245+x3\frac{75 + 170 + x}{3} = \frac{245 + x}{3}. To find this average, we only need to determine the value of xx.
Simplifying the question target clarifies that finding xx is both necessary and sufficient.
2
Evaluate Statement (1)
Statement (1) states that under High Intensity, Coating Gamma (xx) is 10% greater than Coating Alpha (280). Thus, x=280×1.10=308 W/m2x = 280 \times 1.10 = 308 \text{ W/m}^2. We can compute the average as 245+3083=184.33 W/m2\frac{245 + 308}{3} = 184.33 \text{ W/m}^2.
Since a single unique numerical value for xx is found, Statement (1) ALONE is sufficient.
3
Evaluate Statement (2)
Statement (2) gives the mean of Coating Delta as equal to the mean of Coating Beta. Mean of Coating Beta = 90+195+3103=5953\frac{90 + 195 + 310}{3} = \frac{595}{3}. Setting y+200+3203=5953\frac{y + 200 + 320}{3} = \frac{595}{3} yields y=75 W/m2y = 75 \text{ W/m}^2.
Finding yy gives information about Coating Delta, but provides no information regarding xx for Coating Gamma. Thus, Statement (2) ALONE is not sufficient.

Anahtar Kavram

Target Rephrasing and Independent Statement Evaluation in Tabular Data Sufficiency
Tahmini Süre:2m 0s
Soru 205Soru

A pharmaceutical laboratory manufactures a specialized compound by blending two liquid preparations, Solution XX and Solution YY. Solution XX contains Active Ingredient PP and water in the ratio 3:23:2 by weight. Solution YY contains Active Ingredient PP and water in the ratio 1:41:4 by weight. A master batch is created by mixing xx grams of Solution XX with yy grams of Solution YY, where x>0x > 0 and y>0y > 0. Is the percentage of Active Ingredient PP in the master batch greater than 40%40\% by weight?

(1) 3x4y>03x - 4y > 0
(2) After adding 5050 grams of pure water to the master batch, Active Ingredient PP accounts for less than 13\frac{1}{3} of the total weight of the resulting mixture.

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Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
The correct response identifies that Statement (1) alone is sufficient while Statement (2) alone is not. By rephrasing the question stem, the target condition 'Is the active ingredient concentration greater than 40%?' simplifies directly to the inequality condition x>yx > y. Statement (1) guarantees that x>43yx > \frac{4}{3}y, which directly implies x>yx > y since y>0y > 0, providing a definitive 'Yes'. Statement (2) simplifies to 2xy<1252x - y < 125, which is satisfied by parameter pairs where x>yx > y as well as pairs where x<yx < y, making it insufficient.

Adım Adım Çözüm

1
Rephrase the question stem target algebraically.
Solution X is 33+2=35=0.60\frac{3}{3+2} = \frac{3}{5} = 0.60 (or 60%60\%) Ingredient P by weight. Solution Y is 11+4=15=0.20\frac{1}{1+4} = \frac{1}{5} = 0.20 (or 20%20\%) Ingredient P by weight. The total weight of Ingredient P in the master batch is 0.6x+0.2y0.6x + 0.2y, and the total weight of the batch is x+yx + y. The question asks whether 0.6x+0.2yx+y>0.40\frac{0.6x + 0.2y}{x + y} > 0.40. Since x>0x > 0 and y>0y > 0, multiplying across by (x+y)(x + y) gives 0.6x+0.2y>0.4x+0.4y    0.2x>0.2y    x>y0.6x + 0.2y > 0.4x + 0.4y \implies 0.2x > 0.2y \implies x > y. Thus, the rephrased question is: 'Is x>yx > y?'
Simplifying the question stem before evaluating statements prevents unnecessary system solving and clarifies the exact threshold needed for sufficiency.
2
Evaluate Statement (1): 3x4y>03x - 4y > 0.
Rearranging 3x4y>03x - 4y > 0 gives 3x>4y    x>43y3x > 4y \implies x > \frac{4}{3}y. Because y>0y > 0, 43y>y\frac{4}{3}y > y. Therefore, if x>43yx > \frac{4}{3}y, it must strictly be true that x>yx > y. This yields a definitive 'Yes' to the rephrased question. Hence, Statement (1) ALONE is sufficient.
Since statement 1 establishes a lower bound for x relative to y that is strictly greater than 1y, it answers the question 'Is x > y?' definitively.
3
Evaluate Statement (2): Adding 50 grams of water results in P accounting for less than 13\frac{1}{3} of total weight.
Total weight of P remains 0.6x+0.2y0.6x + 0.2y. The new total weight is x+y+50x + y + 50. The statement gives 0.6x+0.2yx+y+50<13\frac{0.6x + 0.2y}{x + y + 50} < \frac{1}{3}. Multiplying by 3(x+y+50)3(x + y + 50) yields 1.8x+0.6y<x+y+50    0.8x0.4y<50    2xy<1251.8x + 0.6y < x + y + 50 \implies 0.8x - 0.4y < 50 \implies 2x - y < 125. Testing values:
- Case A: Let x=10,y=50x = 10, y = 50. Then 2(10)50=30<1252(10) - 50 = -30 < 125 holds. Here x<yx < y, so the answer is 'No'.
- Case B: Let x=100,y=90x = 100, y = 90. Then 2(100)90=110<1252(100) - 90 = 110 < 125 holds. Here x>yx > y, so the answer is 'Yes'.
Since Statement (2) permits both 'Yes' and 'No' outcomes, Statement (2) ALONE is not sufficient.
An inequality involving absolute scale (50 grams) fails to determine a purely proportional relationship between x and y without additional constraints on total batch size.

Anahtar Kavram

Question Stem Simplification and Mixture Ratio Inequalities
Soru 206Soru

A coffee roaster creates a signature blend using only two types of beans: Arabica and Robusta. In a specific batch of this signature blend, what percentage of the total weight of the batch consists of Arabica beans?

(1) If 10 kilograms of Arabica beans were added to the batch, the ratio of the weight of Arabica beans to the weight of Robusta beans in the batch would be 3:23:2.
(2) The total cost of the Arabica beans in the batch is 50%50\% greater than the total cost of the Robusta beans in the batch, and Arabica beans cost 25%25\% more per kilogram than Robusta beans.

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Cevap: Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

Cevap

Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
Statement (2) alone allows us to express the price per kilogram of Arabica beans in terms of Robusta beans (pA=1.25pRp_A = 1.25 p_R) and set up an equation equating total costs (ApA=1.50RpRA \cdot p_A = 1.50 R \cdot p_R). Dividing out the unit price pRp_R gives a direct constant value for the weight ratio AR=65\frac{A}{R} = \frac{6}{5}, which uniquely determines the percentage of Arabica beans in the batch.

Adım Adım Çözüm

1
Define target variables and simplify the question stem.
Let AA be the weight of Arabica beans (in kg) and RR be the weight of Robusta beans (in kg). The target percentage is AA+R×100%\frac{A}{A + R} \times 100\%, which requires finding the ratio AR\frac{A}{R}.
Rephrasing the stem to finding the ratio AR\frac{A}{R} isolates the exact relation needed to answer the question.
2
Evaluate Statement (1) independently.
Statement (1) gives A+10R=322A+20=3R3R2A=20\frac{A + 10}{R} = \frac{3}{2} \Rightarrow 2A + 20 = 3R \Rightarrow 3R - 2A = 20. This is one linear equation with two unknowns (AA and RR).
Since the ratio AR\frac{A}{R} varies depending on the specific values of AA and RR (e.g., if A=2,R=8A=2, R=8, AR=14\frac{A}{R}=\frac{1}{4}; if A=14,R=16A=14, R=16, AR=78\frac{A}{R}=\frac{7}{8}), Statement (1) alone is NOT sufficient.
3
Evaluate Statement (2) independently.
Let pAp_A and pRp_R be the price per kg of Arabica and Robusta beans, respectively. We are given pA=1.25pR=54pRp_A = 1.25 p_R = \frac{5}{4} p_R. Total cost of Arabica = ApAA \cdot p_A and total cost of Robusta = RpRR \cdot p_R. Statement (2) states ApA=1.50(RpR)=32RpRA \cdot p_A = 1.50 (R \cdot p_R) = \frac{3}{2} R \cdot p_R. Substituting pA=54pRp_A = \frac{5}{4} p_R gives A(54pR)=32RpRA \left(\frac{5}{4} p_R\right) = \frac{3}{2} R \cdot p_R. Dividing both sides by pRp_R yields 54A=32RAR=3/25/4=65\frac{5}{4} A = \frac{3}{2} R \Rightarrow \frac{A}{R} = \frac{3/2}{5/4} = \frac{6}{5}.
Knowing AR=65\frac{A}{R} = \frac{6}{5} allows us to calculate AA+R=66+5=611\frac{A}{A + R} = \frac{6}{6 + 5} = \frac{6}{11}, giving a unique percentage of 60011%54.55%\frac{600}{11}\% \approx 54.55\%. Thus, Statement (2) alone IS sufficient.

Anahtar Kavram

Data Sufficiency Evaluation of Weighted Ratios and Multiplicative Pricing Relationships
Tahmini Süre:2m 0s
Soru 207Soru

If aa and bb are real numbers such that aba \neq b, what is the value of a+bab\frac{a + b}{a - b}?

(1) a2+b2=4aba^2 + b^2 = 4ab
(2) a>b>0a > b > 0

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Cevap: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Cevap

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
Statement (1) allows us to determine that the square of the target expression (a+b)/(ab)(a+b)/(a-b) equals 3, which gives two possible values: 3\sqrt{3} and 3-\sqrt{3}. Statement (2) provides the condition a>b>0a > b > 0, ensuring that both a+ba+b and aba-b are positive, so their quotient must be positive. Combining both statements eliminates 3-\sqrt{3}, uniquely determining that the expression equals 3\sqrt{3}. Thus, both statements together are sufficient.

Adım Adım Çözüm

1
Express the square of the target expression in terms of basic algebraic components.
Let E=a+babE = \frac{a + b}{a - b}. Squaring both sides yields E2=(a+b)2(ab)2=a2+2ab+b2a22ab+b2E^2 = \frac{(a + b)^2}{(a - b)^2} = \frac{a^2 + 2ab + b^2}{a^2 - 2ab + b^2}.
Rewriting the ratio in squared form allows substitution of expressions involving a2+b2a^2 + b^2 and abab.
2
Evaluate Statement (1) independently.
Substitute a2+b2=4aba^2 + b^2 = 4ab into the squared ratio: E2=4ab+2ab4ab2ab=6ab2ab=3E^2 = \frac{4ab + 2ab}{4ab - 2ab} = \frac{6ab}{2ab} = 3. Taking the square root gives E=3E = \sqrt{3} or E=3E = -\sqrt{3}.
Because Statement (1) allows two distinct possible values for EE, Statement (1) alone is NOT sufficient.
3
Evaluate Statement (2) independently.
Statement (2) states a>b>0a > b > 0. This implies a+b>0a + b > 0 and ab>0a - b > 0, so E>0E > 0, but no numerical value is specified.
Without quantitative equations, Statement (2) alone is NOT sufficient.
4
Evaluate Statements (1) and (2) combined.
From Statement (1), E=±3E = \pm\sqrt{3}. From Statement (2), E>0E > 0. Combining both rules out 3-\sqrt{3}, leaving uniquely E=3E = \sqrt{3}.
The two statements together establish a single, unique value for the target expression.

Anahtar Kavram

Evaluating algebraic ratios via squared identities and applying inequality sign constraints to eliminate redundant roots in Data Sufficiency.
Tahmini Süre:1m 30s
Soru 208Soru

In a GMAT Data Sufficiency problem asking for the unique value of an integer xx, Statement (1) establishes that x{3,7}x \in \{3, 7\} and Statement (2) establishes that x5=2|x - 5| = 2. Evaluating both statements together provides sufficient information to determine a unique value for xx.

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Cevap: False

Cevap

The statement is False. Combining both statements yields the intersection set {3, 7}, which still contains two possible values for x and therefore does not uniquely determine x.
The statement is false because solving Statement (2)'s absolute value equation x5=2|x - 5| = 2 produces x=7x = 7 or x=3x = 3, which is identical to the candidate set given by Statement (1). Combining two identical solution sets leaves the candidate set as {3,7}\{3, 7\}, which does not yield a single unique value for xx.

Adım Adım Çözüm

1
Evaluate Statement (1) solution set
Statement (1) restricts xx to the set {3,7}\{3, 7\}.
Statement (1) explicitly provides two candidate values for xx.
2
Evaluate Statement (2) solution set independently
Statement (2) yields x5=2    x=7|x - 5| = 2 \implies x = 7 or x=3x = 3. The solution set is {3,7}\{3, 7\}.
Solving the absolute value equation yields the two roots 3 and 7 without using any information from Statement (1).
3
Combine Statement (1) and Statement (2)
The intersection of the two solution sets is {3,7}{3,7}={3,7}\{3, 7\} \cap \{3, 7\} = \{3, 7\}.
When combining statements in Data Sufficiency, valid values must satisfy both statements simultaneously.
4
Determine sufficiency of the combined statements
Since xx can still be either 3 or 7, a single unique value is not determined. The combined statements are insufficient.
A Value Data Sufficiency question requires a single, unique numerical value to be considered sufficient.

Anahtar Kavram

Statement Combination and Redundancy in Data Sufficiency
Soru 209Soru

A commercial real estate firm leased office space across two properties, Property X and Property Y. The rental rate per square foot for space in Property X was 20%20\% higher than the rental rate per square foot for space in Property Y. Was the total rental revenue generated from Property X greater than the total rental revenue generated from Property Y?

(1) Property X accounted for more than 45%45\% of the total square feet of office space leased across both properties.
(2) Property Y accounted for less than 54%54\% of the total square feet of office space leased across both properties.

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Cevap: Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

Cevap

Statement (2) ALONE is sufficient to answer the question with a definitive 'Yes', but Statement (1) ALONE is not sufficient.
The correct response identifies that Statement (2) alone is sufficient because it establishes that Property X's area share relative to Property Y yields a ratio SXSY>2327\frac{S_X}{S_Y} > \frac{23}{27}. Because 2327>56\frac{23}{27} > \frac{5}{6}, the revenue of Property X is guaranteed to exceed that of Property Y, providing a definitive 'Yes'. Statement (1) alone is insufficient because it permits ratios below 56\frac{5}{6}.

Adım Adım Çözüm

1
Rephrase the question stem in terms of algebraic variables.
Let SXS_X and SYS_Y be the square footage leased in Property X and Property Y, respectively, and let rr be the rate per sq ft for Property Y. The rate for Property X is 1.20r1.20r. Revenue from X is 1.20rSX1.20r S_X and revenue from Y is rSYr S_Y. The question asks whether 1.20rSX>rSY1.20r S_X > r S_Y, which simplifies to asking whether SXSY>11.20=56\frac{S_X}{S_Y} > \frac{1}{1.20} = \frac{5}{6}.
Simplifying the target question into a ratio threshold SXSY>560.8333\frac{S_X}{S_Y} > \frac{5}{6} \approx 0.8333 streamlines the statement evaluation.
2
Evaluate Statement (1): SX>0.45(SX+SY)S_X > 0.45(S_X + S_Y).
0.55SX>0.45SY    SXSY>0.450.55=9110.81820.55 S_X > 0.45 S_Y \implies \frac{S_X}{S_Y} > \frac{0.45}{0.55} = \frac{9}{11} \approx 0.8182. Since 911<56\frac{9}{11} < \frac{5}{6}, SXSY\frac{S_X}{S_Y} could be 0.820.82 (giving a 'No' answer to the question) or 1.01.0 (giving a 'Yes' answer).
Statement (1) allows values both above and below the required threshold of 5/65/6, making it insufficient.
3
Evaluate Statement (2): SY<0.54(SX+SY)S_Y < 0.54(S_X + S_Y).
0.46SY<0.54SX    SXSY>0.460.54=23270.85190.46 S_Y < 0.54 S_X \implies \frac{S_X}{S_Y} > \frac{0.46}{0.54} = \frac{23}{27} \approx 0.8519. Comparing 2327\frac{23}{27} and 56\frac{5}{6}: 23×6=13823 \times 6 = 138 and 27×5=13527 \times 5 = 135. Since 138>135138 > 135, 2327>56\frac{23}{27} > \frac{5}{6}. Thus, SXSY\frac{S_X}{S_Y} must be strictly greater than 56\frac{5}{6}.
Statement (2) forces SXSY\frac{S_X}{S_Y} to be strictly greater than 5/65/6, yielding a definitive 'Yes' to the question stem.

Anahtar Kavram

Question Stem Rephrasing and Threshold Analysis in Data Sufficiency Ratio Problems
Tahmini Süre:2m 0s
Soru 210Soru

If uu and vv are non-zero real numbers, what is the value of u2vu+v\frac{u - 2v}{u + v}?

(1) 3u25uv2v2=03u^2 - 5uv - 2v^2 = 0
(2) u>v>0u > v > 0

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Cevap: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Cevap

Both statements together are sufficient, but neither statement alone is sufficient.
The correct answer identifies that neither statement alone provides a unique value for the expression, but combining them eliminates the negative root case, leaving a unique value of 0 for the target expression.

Adım Adım Çözüm

1
Rephrase the target expression
Dividing numerator and denominator by vv, the target expression is uv2uv+1\frac{\frac{u}{v} - 2}{\frac{u}{v} + 1}. Finding a unique value for uv\frac{u}{v} determines the target expression.
Simplifying the question target clarifies what information is necessary to achieve sufficiency.
2
Evaluate Statement (1) independently
Factor 3u25uv2v2=03u^2 - 5uv - 2v^2 = 0 as (3u+v)(u2v)=0(3u + v)(u - 2v) = 0. This gives 3u+v=0    u=v33u + v = 0 \implies u = -\frac{v}{3} or u2v=0    u=2vu - 2v = 0 \implies u = 2v. If u=2vu = 2v, then u2vu+v=03v=0\frac{u - 2v}{u + v} = \frac{0}{3v} = 0. If u=v3u = -\frac{v}{3}, then u2vu+v=v32vv3+v=73v23v=72\frac{u - 2v}{u + v} = \frac{-\frac{v}{3} - 2v}{-\frac{v}{3} + v} = \frac{-\frac{7}{3}v}{\frac{2}{3}v} = -\frac{7}{2}. Two different values are possible.
Since Statement (1) produces two distinct numerical outcomes, it is not sufficient alone.
3
Evaluate Statement (2) independently
Statement (2) states u>v>0u > v > 0. This indicates that both uu and vv are positive, but gives no fixed algebraic equality for uv\frac{u}{v}.
Infinitely many positive pairs (u,v)(u, v) satisfy u>v>0u > v > 0 while yielding different values for the expression. Statement (2) is not sufficient alone.
4
Evaluate Statements (1) and (2) combined
From Statement (2), u>0u > 0 and v>0v > 0, so 3u+v>03u + v > 0. Therefore, the factor 3u+v=03u + v = 0 is impossible. This leaves u2v=0u - 2v = 0 as the only valid relation, so u=2vu = 2v. Substituting u=2vu = 2v yields 2v2v2v+v=0\frac{2v - 2v}{2v + v} = 0.
Combining the inequality constraint with the quadratic factorization uniquely determines the value of the target expression.

Anahtar Kavram

Algebraic Equations and Systems in Data Sufficiency
Tahmini Süre:2m 0s
Soru 211Soru

An investment portfolio consists of three funds: Fund Alpha, Fund Beta, and Fund Gamma. The table below presents the capital committed (in millions of dollars) and the annual yield percentage for each fund during the past fiscal year:

FundCapital Committed ($ millions)Annual Yield (%)
Fund Alpha408%
Fund Beta6012%
Fund Gammaccy%y\%

What was the overall annual yield percentage for the combined portfolio of all three funds?

(1) The capital committed to Fund Gamma, cc, was equal to the total capital committed to Fund Alpha and Fund Beta combined.
(2) The annual yield percentage for Fund Gamma, y%y\%, was equal to the weighted average annual yield percentage of Fund Alpha and Fund Beta combined.

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Cevap: Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

Cevap

Statement (2) ALONE is sufficient to answer the question, but statement (1) alone is not sufficient.
The option stating that Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient is correct. Fund Alpha and Fund Beta combined have a weighted average yield of 40(8%)+60(12%)100=10.4%\frac{40(8\%) + 60(12\%)}{100} = 10.4\%. Statement (2) tells us that Fund Gamma's yield is also 10.4%10.4\%. Combining any two groups with identical average yields results in an overall average yield equal to 10.4%10.4\%, regardless of the amount of capital cc in Fund Gamma. Statement (1) provides only the capital amount c=100c = 100, leaving the yield yy unknown and thus insufficient.

Adım Adım Çözüm

1
Formulate the algebraic expression for the overall portfolio yield.
Overall Portfolio Yield = 40(8%)+60(12%)+c(y%)40+60+c=3.2+7.2+cy100100+c=10.4+cy100100+c\frac{40(8\%) + 60(12\%) + c(y\%)}{40 + 60 + c} = \frac{3.2 + 7.2 + \frac{cy}{100}}{100 + c} = \frac{10.4 + \frac{cy}{100}}{100 + c}
The total annual return is the sum of returns from each fund, divided by total capital committed.
2
Calculate the combined weighted average yield of Fund Alpha and Fund Beta.
Sub-portfolio yield = 40(8)+60(12)40+60=320+720100=10.4%\frac{40(8) + 60(12)}{40 + 60} = \frac{320 + 720}{100} = 10.4\%
Determining the performance of the known portion of the portfolio simplifies statement evaluation.
3
Evaluate Statement (1) independently: c=40+60=100c = 40 + 60 = 100.
Overall Yield = 10.4+y200×100%=10.4+y2%\frac{10.4 + y}{200} \times 100\% = \frac{10.4 + y}{2}\%. Since yy is unknown, this value is not unique.
Without knowing Fund Gamma's yield rate y%y\%, the capital amount alone does not provide a definitive overall yield.
4
Evaluate Statement (2) independently: y%=10.4%y\% = 10.4\%.
Overall Yield = 100(10.4%)+c(10.4%)100+c=10.4%(100+c)100+c=10.4%\frac{100(10.4\%) + c(10.4\%)}{100 + c} = \frac{10.4\%(100 + c)}{100 + c} = 10.4\%.
When a new component is added to a group with a value equal to the group's current average, the overall average remains unchanged regardless of the size (cc) of the new component.

Anahtar Kavram

Weighted Average Invariance in Data Sufficiency
Soru 212Soru

An investment fund allocates its capital between two asset classes, Class PP and Class QQ. At the beginning of a given year, the ratio of capital in Class PP to capital in Class QQ was 3:23 : 2. During the year, Class PP earned an annual return of rp%r_p\% and Class QQ earned an annual return of rq%r_q\%. At the end of the year, a management fee of 2%2\% was deducted from the total ending value of Class PP, and a management fee of 5%5\% was deducted from the total ending value of Class QQ. Was the total dollar amount of the management fee deducted from Class PP greater than the total dollar amount of the management fee deducted from Class QQ?

(1) rprq=10r_p - r_q = 10
(2) At the end of the year, before management fees were deducted, the total value of Class PP was 60%60\% greater than the total value of Class QQ.

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Cevap: Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

Cevap

Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
Statement (2) alone allows us to express both fee amounts in terms of the single variable VQV_Q, the ending value of Class QQ. Because FP=0.02(1.6VQ)=0.032VQF_P = 0.02(1.6 V_Q) = 0.032 V_Q and FQ=0.05VQF_Q = 0.05 V_Q, we know with certainty that FP<FQF_P < F_Q. This provides a definitive 'No' answer to whether FP>FQF_P > F_Q, which makes Statement (2) alone sufficient. Statement (1) alone leaves the relationship dependent on the unconstrained value of rqr_q, so it is not sufficient.

Adım Adım Çözüm

1
Algebraically rephrase the question target.
Let initial capital be P0P_0 and Q0Q_0, where P0=1.5Q0P_0 = 1.5 Q_0. Ending values before fees are VP=1.5Q0(1+rp100)V_P = 1.5 Q_0 (1 + \frac{r_p}{100}) and VQ=Q0(1+rq100)V_Q = Q_0 (1 + \frac{r_q}{100}). The fees are FP=0.02VP=0.03Q0(1+rp100)F_P = 0.02 V_P = 0.03 Q_0 (1 + \frac{r_p}{100}) and FQ=0.05VQ=0.05Q0(1+rq100)F_Q = 0.05 V_Q = 0.05 Q_0 (1 + \frac{r_q}{100}). The question 'Is FP>FQF_P > F_Q?' simplifies to 'Is 0.03(100+rp)>0.05(100+rq)0.03(100 + r_p) > 0.05(100 + r_q)?' or 'Is 3rp5rq>2003 r_p - 5 r_q > 200?'
Rephrased targets clarify the exact mathematical relationship required to answer the Data Sufficiency prompt.
2
Evaluate Statement (1): rprq=10r_p - r_q = 10.
Substituting rp=rq+10r_p = r_q + 10 into the inequality yields 3(rq+10)5rq=302rq>2003(r_q + 10) - 5 r_q = 30 - 2 r_q > 200, which simplifies to rq<85r_q < -85. Since rqr_q can be any real number (e.g., rq=0r_q = 0 yields 'No', while rq=100r_q = -100 yields 'Yes'), Statement (1) alone is NOT sufficient.
Without specific values for rqr_q, the inequality cannot be answered definitively.
3
Evaluate Statement (2): VP=1.6VQV_P = 1.6 V_Q.
We are given that VP=1.6VQV_P = 1.6 V_Q. Substituting this directly into the fee expressions gives FP=0.02VP=0.02(1.6VQ)=0.032VQF_P = 0.02 V_P = 0.02 (1.6 V_Q) = 0.032 V_Q. Since FQ=0.05VQF_Q = 0.05 V_Q and portfolio value VQ>0V_Q > 0, 0.032VQ0.032 V_Q is strictly less than 0.05VQ0.05 V_Q. Thus, FP>FQF_P > F_Q is definitively FALSE.
A definitive 'No' answer is sufficient in Data Sufficiency decision logic.

Anahtar Kavram

Data Sufficiency Yes/No decision logic and algebraic target rephrasing for percentage adjustments and fee calculations.
Tahmini Süre:2m 0s
Soru 213Soru

If aa and bb are positive integers, is a2ba^2b divisible by 1212?

(1) ab2ab^2 is divisible by 1818.
(2) a3ba^3b is divisible by 7272.

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Cevap: Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

Cevap

Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
Statement (2) alone guarantees that a3ba^3b contains at least three factors of 22 and two factors of 33. Analyzing the exponent bounds for non-negative integers proves that a2ba^2b must contain at least two factors of 22 and one factor of 33, ensuring a2ba^2b is divisible by 1212. Statement (1) alone is insufficient because a=3,b=6a=3, b=6 makes ab2=108ab^2=108 (divisible by 1818) but a2b=54a^2b=54 (not divisible by 1212). Thus, Statement (2) ALONE is sufficient.

Adım Adım Çözüm

1
Rephrase the target question in terms of prime factorization
For a2ba^2b to be divisible by 12=22×3112 = 2^2 \times 3^1, we need 2v2(a)+v2(b)22 v_2(a) + v_2(b) \ge 2 and 2v3(a)+v3(b)12 v_3(a) + v_3(b) \ge 1, where vp(n)v_p(n) is the exponent of prime pp in the prime factorization of nn.
Decomposing divisibility into prime factor exponent inequalities allows definitive evaluation of sufficiency.
2
Evaluate Statement (1): ab2ab^2 is divisible by 18=21×3218 = 2^1 \times 3^2
This gives v2(a)+2v2(b)1v_2(a) + 2 v_2(b) \ge 1 and v3(a)+2v3(b)2v_3(a) + 2 v_3(b) \ge 2. Test counterexample a=3,b=6a=3, b=6: ab2=3×36=108ab^2 = 3 \times 36 = 108 (divisible by 18), but a2b=9×6=54a^2b = 9 \times 6 = 54, which is not divisible by 12.
A single valid counterexample proves Statement (1) is NOT sufficient.
3
Evaluate Statement (2): a3ba^3b is divisible by 72=23×3272 = 2^3 \times 3^2
This gives 3v2(a)+v2(b)33 v_2(a) + v_2(b) \ge 3 and 3v3(a)+v3(b)23 v_3(a) + v_3(b) \ge 2. If v2(a)=0v_2(a) = 0, then v2(b)3    2v2(a)+v2(b)32v_2(b) \ge 3 \implies 2 v_2(a) + v_2(b) \ge 3 \ge 2. If v2(a)1v_2(a) \ge 1, then 2v2(a)+v2(b)2(1)+0=22 v_2(a) + v_2(b) \ge 2(1) + 0 = 2. Similarly for prime 3: if v3(a)=0v_3(a) = 0, v3(b)2    2v3(a)+v3(b)21v_3(b) \ge 2 \implies 2 v_3(a) + v_3(b) \ge 2 \ge 1; if v3(a)1v_3(a) \ge 1, 2v3(a)+v3(b)212 v_3(a) + v_3(b) \ge 2 \ge 1. Thus a2ba^2b is always divisible by 12.
Statement (2) strictly guarantees that the prime factor counts for 2 and 3 in a2ba^2b meet or exceed the required thresholds, yielding a definitive 'Yes'.

Anahtar Kavram

Divisibility analysis using prime factor exponent inequalities in Data Sufficiency.
Soru 214Soru

A retailer sold standard boxes at $s\$s each and premium boxes at $p\$p each yesterday, generating a total revenue of $900\$900. If the retailer sold xx standard boxes and yy premium boxes, where xx and yy are positive integers, did the retailer sell more standard boxes than premium boxes?

(1) Standard boxes cost $15\$15 each and premium boxes cost $25\$25 each.
(2) The average (arithmetic mean) price of all boxes sold yesterday was $18\$18, and premium boxes cost $10\$10 more per box than standard boxes.

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Cevap: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Cevap

Both statements together are sufficient, but neither statement alone is sufficient.
The correct option is the one stating that both statements together are sufficient, but neither statement alone is sufficient. Statement (1) allows multiple positive integer pairs for (x,y)(x, y) such that x>yx > y in some cases and x<yx < y in others, making it insufficient on its own. Statement (2) alone leaves the base price ss unknown, so the ratio of standard to premium boxes cannot be determined without Statement (1). Combining s=15s = 15 from Statement (1) with Statement (2) establishes that xy=73\frac{x}{y} = \frac{7}{3}, which definitively proves x>yx > y.

Adım Adım Çözüm

1
Evaluate Statement (1) independently.
Statement (1) provides s=15s = 15 and p=25p = 25, yielding the equation 15x+25y=90015x + 25y = 900, which simplifies to 3x+5y=1803x + 5y = 180. Testing positive integer solutions gives multiple valid pairs: for instance, (x,y)=(55,3)(x, y) = (55, 3) yields x>yx > y (Yes), while (x,y)=(10,30)(x, y) = (10, 30) yields x<yx < y (No). Because both Yes and No are possible, Statement (1) alone is NOT sufficient.
A statement must yield a single definitive Yes or No answer to be sufficient.
2
Evaluate Statement (2) independently without using information from Statement (1).
Statement (2) states that p=s+10p = s + 10 and the average price is sx+pyx+y=18\frac{sx + py}{x + y} = 18. Substituting p=s+10p = s + 10 gives sx+(s+10)yx+y=18\frac{sx + (s + 10)y}{x + y} = 18, which simplifies to s+10yx+y=18s + \frac{10y}{x + y} = 18. Because the individual box price ss is unknown, yx+y\frac{y}{x + y} can vary depending on ss (e.g., if s=10s = 10, x<yx < y; if s=15s = 15, x>yx > y). Thus, Statement (2) alone is NOT sufficient.
Information from Statement (1) must never be carried over when testing Statement (2) independently.
3
Combine Statements (1) and (2).
From Statement (1), s=15s = 15. Substituting s=15s = 15 into the simplified average equation from Statement (2), 15+10yx+y=1815 + \frac{10y}{x + y} = 18, gives 10yx+y=3    10y=3x+3y    7y=3x    xy=73\frac{10y}{x + y} = 3 \implies 10y = 3x + 3y \implies 7y = 3x \implies \frac{x}{y} = \frac{7}{3}. Since xx and yy are positive integers, xy>1\frac{x}{y} > 1, which definitively proves that x>yx > y (Yes).
Combining the known price from Statement (1) with the weighted average equation from Statement (2) uniquely determines the ratio of xx to yy.

Anahtar Kavram

Statement Independence and Statement Combination in Data Sufficiency
Soru 215Soru

If aa and bb are real numbers, what is the value of a2b2a^2 - b^2?

(1) a+b=5a + b = 5
(2) (ab)2=9(a - b)^2 = 9

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Cevap: Statements (1) and (2) TOGETHER are NOT sufficient.

Cevap

The statements together are not sufficient to determine a unique value for a2b2a^2 - b^2, because a2b2a^2 - b^2 can equal either 1515 or 15-15.
The correct option states that both statements together are not sufficient. Factoring the target expression yields a2b2=(a+b)(ab)a^2 - b^2 = (a+b)(a-b). Statement (1) tells us a+b=5a+b = 5, and Statement (2) tells us ab=±3a-b = \pm 3. Combining them yields two possible numerical results (1515 and 15-15). Since Data Sufficiency requires a single, unique numerical value, the information remains insufficient.

Adım Adım Çözüm

1
Rephrase the target expression using algebraic identities.
The target expression a2b2a^2 - b^2 factors into (a+b)(ab)(a + b)(a - b). To find a unique value, we need a unique value for the product (a+b)(ab)(a + b)(a - b).
Factoring highlights the required components: the sum (a+b)(a + b) and the difference (ab)(a - b).
2
Evaluate Statement (1) independently.
Statement (1) gives a+b=5a + b = 5. However, the value of aba - b is completely unknown.
Since (ab)(a - b) can be any real number, a2b2=5(ab)a^2 - b^2 = 5(a - b) can take infinitely many values. Statement (1) is not sufficient.
3
Evaluate Statement (2) independently.
Statement (2) gives (ab)2=9(a - b)^2 = 9, which implies ab=3a - b = 3 or ab=3a - b = -3.
The sum a+ba + b is completely unknown, and aba - b has two potential values. Statement (2) is not sufficient.
4
Evaluate Statements (1) and (2) together.
From (1), a+b=5a + b = 5. From (2), ab=3a - b = 3 or ab=3a - b = -3.
If ab=3a - b = 3, then a2b2=(5)(3)=15a^2 - b^2 = (5)(3) = 15.
If ab=3a - b = -3, then a2b2=(5)(3)=15a^2 - b^2 = (5)(-3) = -15.
Because there are two distinct outcomes (1515 and 15-15), a unique value cannot be determined. Therefore, both statements together are not sufficient.

Anahtar Kavram

Quadratic non-linearity and root ambiguity in Data Sufficiency systems
Soru 216Soru

If xx and yy are non-zero real numbers, is xy\frac{x}{y} an integer?

(1) x2+y2=5xyx^2 + y^2 = 5xy
(2) xx is a prime number and xyxy is an integer.

Cevabı ve açıklamayı göster

Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (1) allows us to set up a quadratic equation for the ratio xy\frac{x}{y}, yielding (xy)25(xy)+1=0\left(\frac{x}{y}\right)^2 - 5\left(\frac{x}{y}\right) + 1 = 0. The roots of this quadratic equation are 5±212\frac{5 \pm \sqrt{21}}{2}, which are irrational numbers. Therefore, xy\frac{x}{y} cannot be an integer under any circumstance, providing a definitive 'No' answer to the question. Statement (1) is therefore sufficient. Statement (2) allows xy\frac{x}{y} to be an integer (e.g., x=3,y=1x=3, y=1) or a non-integer (e.g., x=3,y=2x=3, y=2), so it is not sufficient. Thus, the option stating that Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient is the correct choice.

Adım Adım Çözüm

1
Analyze the target question stem
The target asks if the quotient xy\frac{x}{y} is an integer, where xx and yy are real numbers (not restricted to integers).
Establishing that xx and yy are real numbers prevents making unjustified integer assumptions.
2
Evaluate Statement (1): x2+y2=5xyx^2 + y^2 = 5xy
Divide both sides by y2y^2 (since y0y \neq 0): (xy)2+1=5(xy)\left(\frac{x}{y}\right)^2 + 1 = 5\left(\frac{x}{y}\right), which rearranges to (xy)25(xy)+1=0\left(\frac{x}{y}\right)^2 - 5\left(\frac{x}{y}\right) + 1 = 0. Setting k=xyk = \frac{x}{y}, we get k25k+1=0k^2 - 5k + 1 = 0. Solving for kk using the quadratic formula gives k=5±212k = \frac{5 \pm \sqrt{21}}{2}.
Since 21\sqrt{21} is irrational, k=xyk = \frac{x}{y} is an irrational number and can NEVER be an integer.
3
Determine sufficiency for Statement (1)
Statement (1) yields a definitive 'No' to the question 'Is xy\frac{x}{y} an integer?'. Thus, Statement (1) alone is SUFFICIENT.
In Data Sufficiency Yes/No questions, a definitive 'No' answer is a sufficient result.
4
Evaluate Statement (2): xx is a prime number and xyxy is an integer
Case A: Let x=3x = 3 and y=1y = 1. Then xy=3xy = 3 (an integer), and xy=3\frac{x}{y} = 3 (an integer) -> YES.
Case B: Let x=3x = 3 and y=2y = 2. Then xy=6xy = 6 (an integer), and xy=32\frac{x}{y} = \frac{3}{2} (not an integer) -> NO.
Because xy\frac{x}{y} can be an integer or not an integer, Statement (2) alone is NOT sufficient.

Anahtar Kavram

Data Sufficiency Yes/No decision logic combined with irrational root analysis and real number constraints.
Tahmini Süre:2m 0s
Soru 217Soru

A logistics center operates two automated sorting divisions: Division PP and Division QQ. Yesterday, Division PP had an error rate of x%x\% of the packages it processed, and Division QQ had an error rate of y%y\% of the packages it processed. What was the overall package error rate for the two divisions combined yesterday?

(1) Division PP processed 50%50\% more packages yesterday than Division QQ processed yesterday, and Division PP's error rate was 2.0%2.0\%.
(2) Yesterday, Division QQ processed 40%40\% of the total packages processed by both divisions combined, and Division QQ's error rate was 5.0%5.0\%.

Cevabı ve açıklamayı göster

Cevap: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Cevap

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
The correct answer is the option stating that both statements together are sufficient, but neither alone is sufficient. Statement (1) provides the relative volume weights and Division PP's error rate, but lacks Division QQ's error rate. Statement (2) provides the relative volume weights and Division QQ's error rate, but lacks Division PP's error rate. Combining both statements supplies all necessary values (x=2.0%x = 2.0\%, y=5.0%y = 5.0\%, and volume ratio 60:4060:40) to uniquely calculate the combined weighted error rate of 3.2%3.2\%.

Adım Adım Çözüm

1
Formulate the algebraic target for the overall combined error rate.
Let NPN_P and NQN_Q represent the package volumes processed by Division PP and Division QQ, respectively. The overall error rate EE is given by the weighted average equation: E=xNP+yNQNP+NQ=x(NPNP+NQ)+y(NQNP+NQ)E = \frac{x\cdot N_P + y\cdot N_Q}{N_P + N_Q} = x\left(\frac{N_P}{N_P + N_Q}\right) + y\left(\frac{N_Q}{N_P + N_Q}\right). To find EE, we need xx, yy, and the relative weight ratio NPNQ\frac{N_P}{N_Q} (or the fraction of total volume contributed by each division).
Rephrasing the Data Sufficiency question stem shows that absolute counts for NPN_P and NQN_Q are unnecessary; only the error rates xx and yy and their relative proportions are required.
2
Evaluate Statement (1) independently.
Statement (1) states that NP=1.5NQN_P = 1.5 N_Q, which means NPNQ=32\frac{N_P}{N_Q} = \frac{3}{2} and the relative weights are NPNP+NQ=0.60\frac{N_P}{N_P + N_Q} = 0.60 and NQNP+NQ=0.40\frac{N_Q}{N_P + N_Q} = 0.40. It also gives x=2.0%x = 2.0\%. However, no information is provided about Division QQ's error rate (yy). Thus, E=0.60(2.0%)+0.40(y%)E = 0.60(2.0\%) + 0.40(y\%), which varies depending on yy. Statement (1) alone is INSUFFICIENT.
Without yy, a unique numerical value for EE cannot be calculated.
3
Evaluate Statement (2) independently.
Statement (2) states that Division QQ processed 40%40\% of the total packages, meaning NQNP+NQ=0.40\frac{N_Q}{N_P + N_Q} = 0.40 and NPNP+NQ=0.60\frac{N_P}{N_P + N_Q} = 0.60. It also provides y=5.0%y = 5.0\%. However, no information is provided about Division PP's error rate (xx). Thus, E=0.60(x%)+0.40(5.0%)E = 0.60(x\%) + 0.40(5.0\%), which varies depending on xx. Statement (2) alone is INSUFFICIENT.
Without xx, a unique numerical value for EE cannot be calculated.
4
Evaluate Statements (1) and (2) together.
Combining both statements gives x=2.0%x = 2.0\%, y=5.0%y = 5.0\%, and consistent relative weights (NPNP+NQ=0.60\frac{N_P}{N_P + N_Q} = 0.60 and NQNP+NQ=0.40\frac{N_Q}{N_P + N_Q} = 0.40). The overall combined error rate can be computed directly: E=0.60(2.0%)+0.40(5.0%)=1.2%+2.0%=3.2%E = 0.60(2.0\%) + 0.40(5.0\%) = 1.2\% + 2.0\% = 3.2\%. A unique value is obtained. Both statements together are SUFFICIENT.
All required variables (xx, yy, and relative volume weighting) are known when combining both statements.

Anahtar Kavram

Weighted Averages and Ratio Sufficiency in Data Sufficiency
Tahmini Süre:2m 0s
Soru 218Soru

A private equity firm allocated its initial capital between two portfolio ventures: Venture X and Venture Y. In 2025, Venture X yielded a profit equal to 20%20\% of its initial investment, while Venture Y incurred a loss equal to 10%10\% of its initial investment. What was the firm's overall percentage profit or loss across both ventures combined?

Cevabı ve açıklamayı göster

Cevap: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Cevap

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Rephrasing the question target shows that the overall percentage return depends strictly on the ratio of the investment amounts, XY\frac{X}{Y}. Statement (1) directly gives X=1.5YX = 1.5Y, establishing a fixed ratio XY=32\frac{X}{Y} = \frac{3}{2}, which uniquely yields an overall profit of 8%8\%. Statement (2) reveals the dollar investment in Venture X (200,000200,000) but leaves the investment in Venture Y completely unconstrained, making it impossible to compute a unique overall percentage.

Adım Adım Çözüm

1
Rephrase the target question algebraically.
Let XX be the initial investment in Venture X and YY be the initial investment in Venture Y. The total net profit is 0.20X0.10Y0.20X - 0.10Y, and the total investment is X+YX + Y. The overall percentage return is given by 0.20X0.10YX+Y×100%=(0.20(XX+Y)0.10(YX+Y))×100%\frac{0.20X - 0.10Y}{X + Y} \times 100\% = \left(0.20 \left(\frac{X}{X+Y}\right) - 0.10 \left(\frac{Y}{X+Y}\right)\right) \times 100\%. Thus, finding the ratio XY\frac{X}{Y} is sufficient to determine the overall return.
Data Sufficiency stems asking for a combined percentage rate depend only on the ratio of the component base values, not their absolute amounts.
2
Evaluate Statement (1): The amount invested in Venture X was 50%50\% greater than the amount invested in Venture Y.
This implies X=1.5Y=32YX = 1.5Y = \frac{3}{2}Y, so XY=32\frac{X}{Y} = \frac{3}{2}. Substituting X=1.5YX = 1.5Y into the overall return formula yields 0.20(1.5Y)0.10Y1.5Y+Y=0.30Y0.10Y2.5Y=0.20Y2.5Y=0.202.5=0.08=8%\frac{0.20(1.5Y) - 0.10Y}{1.5Y + Y} = \frac{0.30Y - 0.10Y}{2.5Y} = \frac{0.20Y}{2.5Y} = \frac{0.20}{2.5} = 0.08 = 8\% profit.
Since a unique overall percentage (8% profit) is determined, Statement (1) alone is sufficient.
3
Evaluate Statement (2): The dollar amount of profit generated by Venture X was $40,000\$40,000.
This gives 0.20X=40,000    X=200,0000.20X = 40,000 \implies X = 200,000. However, no information is provided about the value of YY. If Y=100,000Y = 100,000, overall profit is 40,00010,000300,000=10%\frac{40,000 - 10,000}{300,000} = 10\%. If Y=400,000Y = 400,000, overall profit is 40,00040,000600,000=0%\frac{40,000 - 40,000}{600,000} = 0\%.
Multiple overall percentage returns are possible depending on YY, so Statement (2) alone is not sufficient.

Anahtar Kavram

Weighted Average Percentage Yields and Stem Simplification in Data Sufficiency
Tahmini Süre:2m 0s
Soru 219Soru

If mm and nn are real numbers, what is the value of m+nm + n?

(1) m2n2=0m^2 - n^2 = 0
(2) m2+n2=50m^2 + n^2 = 50

Cevabı ve açıklamayı göster

Cevap: Statements (1) and (2) TOGETHER are NOT sufficient.

Cevap

Statements (1) and (2) TOGETHER are NOT sufficient.
Evaluating both statements together yields four possible coordinate pairs: (5,5)(5, 5), (5,5)(-5, -5), (5,5)(5, -5), and (5,5)(-5, 5). The sum m+nm + n can equal 1010, 10-10, or 00. Because a Data Sufficiency question requires a single unique value to be deemed sufficient, having three distinct possible values means the statements together are insufficient.

Adım Adım Çözüm

1
Evaluate Statement (1) independently.
m2n2=0    (mn)(m+n)=0    m=nm^2 - n^2 = 0 \implies (m - n)(m + n) = 0 \implies m = n or m=nm = -n.
If m=nm = -n, then m+n=0m + n = 0. However, if m=nm = n, then m+n=2mm + n = 2m, which varies. Since we cannot determine a single numerical value for m+nm + n, Statement (1) alone is NOT sufficient.
2
Evaluate Statement (2) independently.
m2+n2=50m^2 + n^2 = 50.
Different pairs (m,n)(m, n) satisfy m2+n2=50m^2 + n^2 = 50. For example, if (m,n)=(5,5)(m, n) = (5, 5), then m+n=10m + n = 10. If (m,n)=(7,1)(m, n) = (7, 1), then m+n=8m + n = 8. Since m+nm + n is not uniquely determined, Statement (2) alone is NOT sufficient.
3
Evaluate Statements (1) and (2) combined.
From (1), m2=n2m^2 = n^2. Substitute into (2): n2+n2=50    2n2=50    n2=25    n=5n^2 + n^2 = 50 \implies 2n^2 = 50 \implies n^2 = 25 \implies n = 5 or n=5n = -5.
Since m2=25m^2 = 25, mm can also be 55 or 5-5. The possible ordered pairs (m,n)(m, n) are (5,5)(5, 5), (5,5)(-5, -5), (5,5)(5, -5), and (5,5)(-5, 5). Calculating m+nm + n for these pairs gives 1010, 10-10, and 00. Because multiple outcomes are possible, the combined statements are NOT sufficient.

Anahtar Kavram

Non-Linear Systems and Multiple Solution Ambiguity in Data Sufficiency
Soru 220Soru

A manufacturing plant produces two types of electronic components: Component A and Component B. In Year 1, the unit production cost of Component A was 20%20\% greater than the unit production cost of Component B. In Year 2, the unit production cost of Component A increased by 10%10\%, while the unit production cost of Component B increased by 25%25\%. Was the overall average unit production cost across all components produced by the plant higher in Year 2 than in Year 1?

(1) In Year 2, the plant produced 50%50\% more units of Component B than it did in Year 1.
(2) In Year 1, Component A accounted for 60%60\% of the total number of components produced by the plant.

Cevabı ve açıklamayı göster

Cevap: EACH statement ALONE is sufficient.

Cevap

EACH statement ALONE is sufficient to answer the question with a definitive 'Yes'.
The correct answer is the option stating that EACH statement ALONE is sufficient. Analyzing the range of possible weighted averages directly from the stem reveals that the minimum possible average unit cost in Year 2 (1.25c1.25c) is strictly greater than the maximum possible average unit cost in Year 1 (1.20c1.20c). Thus, the average unit cost in Year 2 must be greater than in Year 1 regardless of the proportion of Component A and Component B produced in either year. Since the stem alone proves a definitive 'Yes', each statement alone is sufficient.

Adım Adım Çözüm

1
Define variables for Year 1 unit costs and establish the range of Year 1 overall average cost.
Let the Year 1 unit cost of Component B be cc, where c>0c > 0. Then the Year 1 unit cost of Component A is 1.20c1.20c. Any weighted average of these two costs in Year 1, Avg1\text{Avg}_1, must satisfy cAvg11.20cc \le \text{Avg}_1 \le 1.20c. In particular, Avg11.20c\text{Avg}_1 \le 1.20c.
The overall weighted average of a set of values cannot exceed the maximum individual value in that set.
2
Calculate Year 2 unit costs and establish the range of Year 2 overall average cost.
In Year 2, the unit cost of Component A becomes 1.20c×1.10=1.32c1.20c \times 1.10 = 1.32c. The unit cost of Component B becomes c×1.25=1.25cc \times 1.25 = 1.25c. Any weighted average in Year 2, Avg2\text{Avg}_2, must satisfy 1.25cAvg21.32c1.25c \le \text{Avg}_2 \le 1.32c. In particular, Avg21.25c\text{Avg}_2 \ge 1.25c.
The overall weighted average of a set of values cannot be less than the minimum individual value in that set.
3
Compare the upper bound of Year 1 average cost with the lower bound of Year 2 average cost.
Since Avg21.25c>1.20cAvg1\text{Avg}_2 \ge 1.25c > 1.20c \ge \text{Avg}_1, it follows that Avg2>Avg1\text{Avg}_2 > \text{Avg}_1 holds unconditionally for all possible production volumes and ratios in both years.
The minimum possible average cost in Year 2 (1.25c1.25c) is strictly greater than the maximum possible average cost in Year 1 (1.20c1.20c).
4
Evaluate Data Sufficiency statements based on the stem analysis.
Because the stem alone yields a definitive 'Yes' answer, Statement (1) alone is sufficient and Statement (2) alone is sufficient.
When the question stem itself contains sufficient information to answer the target question definitively, each statement independently yields a definitive answer.

Anahtar Kavram

Weighted Average Extreme Value Bounds in Data Sufficiency
ÖncekiSayfa 11 / 14Sonraki
Data Sufficiency Alıştırma Soruları — GMAT — Sayfa 11 | Examkin