Table Analysis

63 soru

Soru 41Soru

The table below details 2025 annual operational metrics for eight commercial container terminals at a regional maritime port hub:

TerminalAnnual Cargo Volume (Thousand TEUs)Automated Crane Ratio (%)Average Berth Dwell Time (Hours)On-Time Vessel Clearance Rate (%)
Terminal A1,25080%18.592%
Terminal B84065%24.085%
Terminal C2,10090%14.296%
Terminal D62040%31.074%
Terminal E1,60075%21.588%
Terminal F95050%26.881%
Terminal G1,85085%16.094%
Terminal H1,10060%22.486%

Based on the table, evaluate the following claim: Exactly two of the three statements below are True.

Statement I: When the terminals are sorted in descending order by Annual Cargo Volume, the median Average Berth Dwell Time for the top 4 terminals is less than 17.017.0 hours.
Statement II: For every terminal where the Automated Crane Ratio is at least 75%75\%, the On-Time Vessel Clearance Rate is greater than 87%87\%.
Statement III: The mean Annual Cargo Volume across all 8 terminals is greater than 1,3501,350 thousand TEUs.

Cevabı ve açıklamayı göster

Cevap: False

Cevap

False. Only Statement II is True (Statement I and Statement III are both False). Therefore, exactly one statement is True, making the overall claim False.
Evaluating each component statement reveals that Statement I is False (median is 17.2517.25 hours, which is not less than 17.017.0), Statement II is True (all four terminals with 75%\ge 75\% crane automation exceed 87%87\% clearance rate), and Statement III is False (mean cargo volume is 1,288.751,288.75, not greater than 1,3501,350). Because only one statement is True, the claim stating that exactly two statements are True is False.

Adım Adım Çözüm

1
Evaluate Statement I by sorting terminals descending by Annual Cargo Volume and finding the median dwell time of the top 4.
Top 4 terminals by volume: Terminal C (2,1002,100), Terminal G (1,8501,850), Terminal E (1,6001,600), and Terminal A (1,2501,250). Their Average Berth Dwell Times are 14.214.2, 16.016.0, 21.521.5, and 18.518.5 hours, respectively. Ordered ascending, these values are 14.2,16.0,18.5,21.514.2, 16.0, 18.5, 21.5. The median is the average of the two middle values: 16.0+18.52=17.25\frac{16.0 + 18.5}{2} = 17.25 hours. Since 17.25>17.017.25 > 17.0, Statement I is False.
Correctly identifying the median of an even set requires ordering the values and taking the midpoint of the two central numbers.
2
Evaluate Statement II by checking the On-Time Vessel Clearance Rate for terminals with an Automated Crane Ratio 75%\ge 75\%.
Terminals with Automated Crane Ratio 75%\ge 75\% are Terminal A (80%80\%, Clearance 92%92\%), Terminal C (90%90\%, Clearance 96%96\%), Terminal E (75%75\%, Clearance 88%88\%), and Terminal G (85%85\%, Clearance 94%94\%). All four have Clearance Rates strictly greater than 87%87\%. Statement II is True.
Conditional filtering requires verifying every single row that satisfies the specified antecedent condition.
3
Evaluate Statement III by calculating the aggregate arithmetic mean of Annual Cargo Volume across all 8 terminals.
Sum of volume =1250+840+2100+620+1600+950+1850+1100=10,310= 1250 + 840 + 2100 + 620 + 1600 + 950 + 1850 + 1100 = 10,310 thousand TEUs. Mean =10,3108=1,288.75= \frac{10,310}{8} = 1,288.75 thousand TEUs. Since 1,288.75<1,3501,288.75 < 1,350, Statement III is False.
Computing aggregate mean requires dividing total cargo sum by total terminal count.
4
Synthesize the boolean values of the three statements to evaluate the claim.
Statement I = False, Statement II = True, Statement III = False. Exactly 1 statement is True. The claim asserts that exactly 2 statements are True, which is False.
Comparing the count of True statements to the claim's requirement determines the overall boolean result.

Anahtar Kavram

Multi-Statement Boolean Evaluation using tabular data sorting, conditional filtering, and descriptive statistics.
Soru 42Soru

The table below lists key operational and financial metrics for 10 enterprise data center facilities operated by a global cloud services provider:

Facility IDTier ClassificationServer RacksPower Usage Effectiveness (PUE)Monthly Maintenance Cost ($ in thousands)
Facility ATier III4501.3564
Facility BTier IV6001.2094
Facility CTier III5201.4878
Facility DTier III4801.4272
Facility ETier II3001.6540
Facility FTier III4001.3052
Facility GTier III5501.5586
Facility HTier IV6501.2598
Facility ITier III4601.3868
Facility JTier II3501.6082

Based on the table, what is the median monthly maintenance cost for the subset of facilities classified as Tier III?

Cevabı ve açıklamayı göster

Cevap: $70,000

Cevap

The median monthly maintenance cost for Tier III facilities is $70,000.
To find the median monthly maintenance cost of Tier III facilities, first isolate the 6 relevant rows: Facility A (64k),FacilityC(64k), Facility C ( 78k), Facility D (72k),FacilityF(72k), Facility F ( 52k), Facility G (86k),andFacilityI(86k), and Facility I ( 68k). Sorting these costs from lowest to highest yields: 52,000,52,000, 64,000, 68,000,68,000, 72,000, 78,000,78,000, 86,000. Because there are 6 values (an even count), the median is the average of the 3rd (68,000)and4th(68,000) and 4th ( 72,000) terms. 68,000+72,0002=70,000\frac{68,000 + 72,000}{2} = 70,000. Therefore, $70,000 is the correct answer.

Adım Adım Çözüm

1
Filter the table data for facilities classified as 'Tier III'.
Six facilities match this condition: Facility A (64k),FacilityC(64k), Facility C ( 78k), Facility D (72k),FacilityF(72k), Facility F ( 52k), Facility G (86k),andFacilityI(86k), and Facility I ( 68k).
The question specifically targets the subset of facilities with Tier III classification.
2
Sort the monthly maintenance costs for the filtered Tier III facilities in ascending numerical order.
52,000,52,000, 64,000, 68,000,68,000, 72,000, 78,000,78,000, 86,000.
Determining percentile or rank statistics such as the median requires ordering data from smallest to largest.
3
Calculate the median for this even-count dataset (N = 6).
Average of the 3rd value (68,000)and4thvalue(68,000) and 4th value ( 72,000): 68,000+72,0002=70,000\frac{68,000 + 72,000}{2} = 70,000.
When a dataset contains an even number of observations, the median is the arithmetic mean of the two middle terms.

Anahtar Kavram

Descriptive Statistics Interpretation (Even-Count Filtered Median)
Soru 43Soru

The table below details Q1 2026 operational and financial performance metrics for seven urban vertical farming facilities operated by GreenGrid AgriTech:

Facility CodeCrop Yield (metric tons)Energy Consumption (MWh)Water Recycled (%)Operating Cost ($/kg)Revenue ($ thousands)
VF-10112048092%4.50720
VF-1028531588%5.20460
VF-10315060095%3.80975
VF-1049541884%4.80513
VF-10511046290%4.10682
VF-1067029486%5.60364
VF-10713054694%3.90858

Evaluate the truth value of the following overarching claim:

Statement: Exactly two of the three statements below evaluate to True based on the table data.

I. For all facilities where Water Recycled is at least 90%, the median Revenue per metric ton of Crop Yield is greater than $6,000.
II. The facility with the highest Energy Consumption per metric ton of Crop Yield also has the highest Operating Cost per kg.
III. The mean Energy Consumption across all seven facilities is less than 450 MWh.

Cevabı ve açıklamayı göster

Cevap: True

Cevap

The statement is True because Statements I and III evaluate to True, while Statement II evaluates to False, making exactly two statements True.
The overarching statement is correct because evaluating each of the three sub-statements shows that Statement I is True (median is \$6,350/ton), Statement II is False (VF-104 has the highest energy per ton but not the highest operating cost), and Statement III is True (mean energy is 445 MWh). Therefore, exactly two statements are True.

Adım Adım Çözüm

1
Filter facilities with Water Recycled 90%\ge 90\% and calculate their Revenue per metric ton of Crop Yield.
Matching facilities: VF-101 (92%92\%), VF-103 (95%95\%), VF-105 (90%90\%), VF-107 (94%94\%).
Revenue per metric ton calculations:
- VF-101: $720,000120=$6,000/ton\frac{\$720,000}{120} = \$6,000/\text{ton}
- VF-103: $975,000150=$6,500/ton\frac{\$975,000}{150} = \$6,500/\text{ton}
- VF-105: $682,000110=$6,200/ton\frac{\$682,000}{110} = \$6,200/\text{ton}
- VF-107: $858,000130=$6,600/ton\frac{\$858,000}{130} = \$6,600/\text{ton}
Statement I requires computing revenue yield efficiency for a subset of rows filtered by water recycling rate.
2
Find the median of the filtered revenue per metric ton values to test Statement I.
Ordered set: {$6,000,$6,200,$6,500,$6,600}\{\$6,000, \$6,200, \$6,500, \$6,600\}. Median = $6,200+$6,5002=$6,350\frac{\$6,200 + \$6,500}{2} = \$6,350. Since $6,350>$6,000\$6,350 > \$6,000, Statement I is TRUE.
The median of an even-numbered dataset is the arithmetic mean of the two middle values.
3
Calculate Energy Consumption per metric ton of Crop Yield for all facilities to identify the maximum, then compare with Operating Cost per kg to test Statement II.
Energy per metric ton rates:
- VF-101: 480120=4.0 MWh/ton\frac{480}{120} = 4.0\text{ MWh/ton}
- VF-102: 315853.71 MWh/ton\frac{315}{85} \approx 3.71\text{ MWh/ton}
- VF-103: 600150=4.0 MWh/ton\frac{600}{150} = 4.0\text{ MWh/ton}
- VF-104: 41895=4.4 MWh/ton\frac{418}{95} = 4.4\text{ MWh/ton} (Highest)
- VF-105: 462110=4.2 MWh/ton\frac{462}{110} = 4.2\text{ MWh/ton}
- VF-106: 29470=4.2 MWh/ton\frac{294}{70} = 4.2\text{ MWh/ton}
- VF-107: 546130=4.2 MWh/ton\frac{546}{130} = 4.2\text{ MWh/ton}

VF-104 has the highest Energy per metric ton (4.44.4). Its Operating Cost is \$4.80/kg. However, VF-106 has the highest Operating Cost at \$5.60/kg. Thus, Statement II is FALSE.
Testing Statement II requires identifying the maximum value of a calculated row-level ratio and checking if it coincides with the column maximum of another metric.
4
Calculate the mean Energy Consumption across all seven facilities to test Statement III.
Sum of Energy Consumption = 480+315+600+418+462+294+546=3,115 MWh480 + 315 + 600 + 418 + 462 + 294 + 546 = 3,115\text{ MWh}. Mean = 3,1157=445 MWh\frac{3,115}{7} = 445\text{ MWh}. Since 445<450445 < 450, Statement III is TRUE.
Determining the truth value of Statement III requires computing an aggregate mean across the entire dataset.
5
Synthesize the boolean evaluations of the three statements to determine the final truth value.
Statement I: True, Statement II: False, Statement III: True. Exactly two of the three statements are True, which confirms that the overarching statement is True.
The main question stem asserts that exactly two statements are True.

Anahtar Kavram

Multi-Statement Boolean Evaluation using tabular filtering, ratio calculation, descriptive statistics (median and mean), and multi-column comparison.
Soru 44Soru

The table below presents the annual municipal water supply metrics and resident population for four administrative districts in 2025. Note that 1 cubic meter (m3)=1,000 liters1\text{ cubic meter } (\text{m}^3) = 1,000\text{ liters}.

DistrictAnnual Water Supplied (in millions of m3\text{m}^3)Total Revenue (in tens of thousands of USD)Resident Population (in thousands)
Metro North21.9876200
Riverdale8.76438120
Coastal Bay14.6730160
Highland Peak13.14525.6150

Based on the data provided, what was the average daily water consumption per resident in Coastal Bay in 2025, expressed in liters per person per day? (Assume a 365-day year.)

Cevabı ve açıklamayı göster

Cevap: 250

Cevap

The average daily water consumption per resident in Coastal Bay in 2025 was 250 liters per person per day.
To find the average daily water consumption per resident in Coastal Bay, first read the values for Coastal Bay from the table: Annual Water Supplied is 14.6 million m314.6\text{ million m}^3 and Resident Population is 160 thousand160\text{ thousand}. Convert water volume to liters: 14.6×106×1,000=14,600,000,000 liters14.6 \times 10^6 \times 1,000 = 14,600,000,000\text{ liters}. Convert population to individual count: 160×1,000=160,000 residents160 \times 1,000 = 160,000\text{ residents}. Calculate total annual resident-days: 160,000×365=58,400,000 resident-days160,000 \times 365 = 58,400,000\text{ resident-days}. Finally, divide total liters by total resident-days: 14,600,000,00058,400,000=250 liters per person per day\frac{14,600,000,000}{58,400,000} = 250\text{ liters per person per day}.

Adım Adım Çözüm

1
Table Lookup and Scale Expansion for Water Supplied
Water supplied = 14.6×106 m3=14,600,000 m314.6 \times 10^6 \text{ m}^3 = 14,600,000 \text{ m}^3
The table header specifies that values are given in millions of cubic meters.
2
Unit Conversion from Cubic Meters to Liters
Total liters = 14,600,000 m3×1,000 L/m3=14,600,000,000 L14,600,000 \text{ m}^3 \times 1,000 \text{ L/m}^3 = 14,600,000,000 \text{ L}
Each cubic meter contains 1,0001,000 liters as stated in the problem note.
3
Population Scale Expansion and Resident-Days Calculation
Total resident-days = (160×1,000 people)×365 days=58,400,000 person-days(160 \times 1,000 \text{ people}) \times 365 \text{ days} = 58,400,000 \text{ person-days}
The population header specifies values in thousands, and a full year comprises 365 days.
4
Calculate Per Capita Daily Rate
Daily per capita rate = 14,600,000,000 L58,400,000 person-days=250 L/person/day\frac{14,600,000,000 \text{ L}}{58,400,000 \text{ person-days}} = 250 \text{ L/person/day}
Dividing total annual volume by total person-days yields the average daily consumption per person.

Anahtar Kavram

Unit Conversion and Scale Interpretation in Table Analysis
Soru 45Soru

The table below presents operating metrics for 10 regional micro-grid stations during an annual monitoring period:

Station IDElevation (m)Solar Irradiance (kWh/m²)Wind Capacity Factor (%)Battery Degradation Rate (%/yr)System Efficiency (%)
ST-011505.8323.484
ST-023205.5383.182
ST-034805.2412.885
ST-046104.9452.581
ST-057505.1492.287
ST-068904.3521.983
ST-0710404.0561.788
ST-0811803.7601.486
ST-0913503.4641.189
ST-1015003.1680.891

Evaluate the following statement based on the data provided:

'When all 10 stations are ordered by increasing Elevation, there is a strictly monotonic inverse relationship between Elevation and Solar Irradiance.'

Cevabı ve açıklamayı göster

Cevap: False

Cevap

False. The relationship between Elevation and Solar Irradiance is not strictly monotonic because Solar Irradiance increases from ST-04 to ST-05.
The evaluated statement claims a strictly monotonic inverse relationship between Elevation and Solar Irradiance. Checking the values sequentially by increasing elevation shows that Solar Irradiance decreases from ST-01 (5.85.8) through ST-04 (4.94.9), but increases at ST-05 (5.15.1). Consequently, the relationship is not strictly monotonic.

Adım Adım Çözüm

1
Verify table ordering by Elevation
The table is already sorted in ascending order of Elevation from ST-01 (150 m150\text{ m}) to ST-10 (1500 m1500\text{ m}).
To evaluate monotonicity across Elevation, we must inspect Solar Irradiance values sequentially from lowest to highest elevation.
2
Examine Solar Irradiance values sequentially
ST-01: 5.85.8, ST-02: 5.55.5, ST-03: 5.25.2, ST-04: 4.94.9, ST-05: 5.15.1.
A strict inverse monotonic trend requires that every successive value be strictly smaller than the preceding value.
3
Identify non-monotonic exception
Between ST-04 and ST-05, Solar Irradiance increases from 4.9 kWh/m24.9\text{ kWh/m}^2 to 5.1 kWh/m25.1\text{ kWh/m}^2.
Because 5.1>4.95.1 > 4.9, there is a local increase, which invalidates a strict monotonic inverse correlation across the full dataset.

Anahtar Kavram

Evaluating strict monotonicity vs. general macro trends across sorted multi-column tables
Soru 46Soru

The table below details physical and operational performance metrics for 10 commercial office properties managed by a real estate investment trust:

Property IDBuilding GradeLeasable Area (sq ft)Occupancy Rate (%)Energy Intensity (kWh/sq ft)
P-101Class A120,00092%18.4
P-102Class B85,00088%22.1
P-103Class A210,00095%14.8
P-104Class A165,00084%19.2
P-105Class B95,00091%24.5
P-106Class A140,00096%16.0
P-107Class B110,00079%21.0
P-108Class A180,00090%15.6
P-109Class A250,00089%17.2
P-110Class B75,00094%23.8

What is the median annual energy intensity, in kWh/sq ft, of the properties that have an occupancy rate of at least 90%?

Cevabı ve açıklamayı göster

Cevap: 17.2

Cevap

17.2
Filtering the table for properties with an Occupancy Rate of at least 90% selects 6 properties: P-101 (18.4), P-103 (14.8), P-105 (24.5), P-106 (16.0), P-108 (15.6), and P-110 (23.8). Sorting these 6 values gives [14.8, 15.6, 16.0, 18.4, 23.8, 24.5]. Since the count is even (N=6N=6), the median is the average of the two middle values, 16.0 and 18.4, which equals 17.2.

Adım Adım Çözüm

1
Filter the dataset based on the occupancy rate criteria
Properties meeting the condition (Occupancy Rate 90%\ge 90\%) are P-101 (92%), P-103 (95%), P-105 (91%), P-106 (96%), P-108 (90%), and P-110 (94%). This yields a subset of 6 properties.
Only properties meeting the threshold of at least 90% occupancy should be included in the statistical calculation.
2
Extract the corresponding Energy Intensity values for the filtered subset
The corresponding Energy Intensity values (in kWh/sq ft) are: 18.4, 14.8, 24.5, 16.0, 15.6, and 23.8.
Target descriptive metric calculation requires the specific Energy Intensity values for the 6 selected properties.
3
Order the extracted values from smallest to largest
Ordered values: 14.8, 15.6, 16.0, 18.4, 23.8, 24.5.
Finding the median requires arranging numerical data in sequential order.
4
Compute the median for the even-count dataset (N=6N=6)
The 3rd value is 16.0 and the 4th value is 18.4. The median is 16.0+18.42=34.42=17.2\frac{16.0 + 18.4}{2} = \frac{34.4}{2} = 17.2.
When a dataset contains an even number of elements, the median is the arithmetic mean of the two middle elements.

Anahtar Kavram

Descriptive Statistics Interpretation
Soru 47Soru

The table below presents operational data for seven regional flight routes operated by an airline during Q1 2026:

Route CodeDistance (miles)Flights ScheduledOn-Time Arrival RateAverage Passenger Load FactorFuel Consumption (gallons/flight)
R-10145012088%82%1,400
R-1028209075%86%2,300
R-1031,2506092%78%3,600
R-10431015084%74%1,100
R-1059608080%90%2,850
R-1061,5004594%85%4,200
R-10768011085%88%1,950

Match each of the following statements to its corresponding truth value and evaluation justification based on the table.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Statement I: For all routes with a distance greater than 800 miles, the median On-Time Arrival Rate is greater than 85%.
Statement II: The route with the highest Average Passenger Load Factor also has the fewest total number of scheduled flights.
Statement III: The ratio of Fuel Consumption per flight to Distance is strictly decreasing as Route Distance increases across all seven routes.

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

Statement I matches with the evaluation of True (median rate is 86%). Statement II matches with the evaluation of False (R-105 has 80 flights while minimum is 45). Statement III matches with the evaluation of False (the ratio increases from R-102 to R-105).
Each statement is evaluated against the quantitative data provided in the table. Statement I correctly identifies the four routes exceeding 800 miles and calculates their median as 86%. Statement II correctly identifies that R-105 has the highest load factor (90%) but 80 flights, whereas R-106 has the minimum flights (45). Statement III correctly identifies a counterexample where the fuel-to-distance ratio increases from R-102 to R-105.

Adım Adım Çözüm

1
Filter and compute the median for Statement I.
Qualifying routes (>800 miles): R-102 (75%), R-105 (80%), R-103 (92%), R-106 (94%). Sorted rates: [75%, 80%, 92%, 94%]. Median = \(\frac{80\% + 92\%}{2} = 86\%\) > 85%.
Identify sub-population based on distance criterion and determine the median of an even-sized dataset.
2
Locate maximum load factor and compare scheduled flights for Statement II.
Max load factor = 90% (R-105, 80 flights). Fewest flights overall = 45 flights (R-106). Since 80 != 45, statement is False.
Identify row-level extrema across two independent columns (Load Factor and Flights Scheduled).
3
Calculate rates/ratios for Statement III across increasing distances.
R-102 (820 miles): \(\frac{2300}{820} \approx 2.805\) gal/mi. R-105 (960 miles): \(\frac{2850}{960} = 2.96875\) gal/mi. Ratio increases, so trend is not strictly decreasing.
Test monotonic trend hypothesis by evaluating specific calculated ratios across sorted distances.

Anahtar Kavram

Multi-statement boolean verification requiring subset filtering, descriptive statistics (median of even-sized set), cross-column extrema matching, and rate trend testing.
Soru 48Soru

The table below presents response metrics for eight municipal fire stations.

Station IDDistrictAverage Response Time (min)On-Time Response Rate (%)Annual Emergency Calls
Station 101North4.893.0%1,420
Station 102North5.291.0%1,850
Station 103East4.296.0%1,100
Station 104South5.888.5%2,100
Station 105West4.895.0%1,600
Station 106East5.589.0%1,350
Station 107West4.595.5%1,750
Station 108South5.092.5%1,900

True or False: If the table is sorted in ascending order by Average Response Time (min), with any ties broken by sorting in descending order by On-Time Response Rate (%), Station 101 is ranked 4th from the top.

Cevabı ve açıklamayı göster

Cevap: True

Cevap

True
Sorting primarily by Average Response Time (ascending) places Station 103 (4.2) first, Station 107 (4.5) second, and creates a tie between Station 101 and Station 105 at 4.8 minutes. Applying the secondary sort by On-Time Response Rate (descending) puts Station 105 (95.0%) in 3rd place and Station 101 (93.0%) in 4th place, confirming the statement.

Adım Adım Çözüm

1
Sort the dataset by the primary criterion: Average Response Time (min) in ascending order.
Station 103 (4.2 min) is 1st, Station 107 (4.5 min) is 2nd. Station 101 and Station 105 tie for the next positions with 4.8 min.
Ascending order places smaller response times first.
2
Apply the secondary tie-breaker criterion to the tied stations (Station 101 and Station 105): On-Time Response Rate (%) in descending order.
Station 105 (95.0%) is ranked 3rd, and Station 101 (93.0%) is ranked 4th.
Descending order places higher percentages above lower percentages.
3
Verify the rank of Station 101 against the statement in the prompt.
Station 101 is indeed ranked 4th overall.
The evaluation confirms the statement is true.

Anahtar Kavram

Multi-Column Table Sorting and Tie-Breaking
Tahmini Süre:1m 30s
Soru 49Soru

The table below presents operational metrics for seven regional grain storage elevators.

Elevator IDRegionStorage Capacity (thousand metric tons)Annual Throughput Rate (%)Average Loading Time (hours)
AlphaMidwest52082%3.2
BetaPlains52078%4.1
GammaMidwest60085%2.8
DeltaDelta45091%3.5
EpsilonPlains45088%2.9
ZetaMidwest60074%3.1
EtaDelta38095%2.4

If the table is sorted in descending order by Storage Capacity (thousand metric tons), and ties are broken by sorting in ascending order by Average Loading Time (hours), which elevator occupies the 4th position from the top?

Cevabı ve açıklamayı göster

Cevap: Beta

Cevap

Elevator Beta occupies the 4th position from the top after primary sorting descending by Storage Capacity and secondary sorting ascending by Average Loading Time.
Sorting the table primarily by Storage Capacity in descending order places the two elevators with 600 thousand metric tons (Gamma and Zeta) at the top, occupying positions 1 and 2. The next highest capacity tier is 520 thousand metric tons, shared by Alpha and Beta. Applying the secondary sort rule (Average Loading Time in ascending order), Alpha has a shorter loading time (3.2 hours3.2\text{ hours}) than Beta (4.1 hours4.1\text{ hours}). Thus, Alpha takes the 3rd position and Beta takes the 4th position.

Adım Adım Çözüm

1
Group facilities by the primary column: Storage Capacity (thousand metric tons) in descending order.
Group 1 (600 thousand metric tons): Gamma, Zeta; Group 2 (520 thousand metric tons): Alpha, Beta; Group 3 (450 thousand metric tons): Delta, Epsilon; Group 4 (380 thousand metric tons): Eta.
Primary sort priority dictates ordering largest values to smallest values first.
2
Apply the tie-breaker criterion (Average Loading Time in ascending order) to Group 1 (Capacity = 600).
Gamma (2.8 hours) comes before Zeta (3.1 hours). Positions 1 and 2 are Gamma and Zeta.
Shorter loading times rank higher in ascending order.
3
Apply the tie-breaker criterion (Average Loading Time in ascending order) to Group 2 (Capacity = 520).
Alpha (3.2 hours) comes before Beta (4.1 hours). Position 3 is Alpha, and Position 4 is Beta.
Since 3.2<4.13.2 < 4.1, Alpha takes the 3rd spot and Beta takes the 4th spot.

Anahtar Kavram

Multi-Column Table Sorting and Secondary Tie-Breaking Logic

Alternatif Yöntem

Filter out the lower capacity groups (450 and 380 thousand metric tons) immediately since the top 4 spots must belong to the highest capacity groups (600 and 520). Compare only Alpha and Beta for the 4th spot by looking at their loading times.
Tahmini Süre:1m 30s
Soru 50Soru

The table below presents monthly operational and climate metrics for seven commercial cold-storage logistics facilities operated by a regional food distributor during 2025:

Facility CodeStorage Volume (1000 m31000\text{ m}^3)Energy Consumed (MWh/month\text{MWh/month})Avg Storage Temp (C^\circ\text{C})Capacity UtilizationOperating Cost ($1000/month\$1000/\text{month})
F-1120480-2285%144
F-2200700-1892%210
F-3150525-2578%175
F-490390-2095%120
F-5250875-2280%260
F-6180630-2488%198
F-73001050-1975%315

True or False: Among the facilities maintaining an average storage temperature colder than 20C-20^\circ\text{C}, the median monthly operating cost is greater than $180,000\$180,000.

Cevabı ve açıklamayı göster

Cevap: True

Cevap

True
The statement is True because the four facilities with average storage temperatures strictly below 20C-20^\circ\text{C} (F-1, F-3, F-5, and F-6) have monthly operating costs of $144,000\$144,000, $175,000\$175,000, $198,000\$198,000, and $260,000\$260,000. The median of these four values is 175+1982×1000=$186,500\frac{175 + 198}{2} \times 1000 = \$186,500, which is strictly greater than $180,000\$180,000.

Adım Adım Çözüm

1
Filter the facilities based on the specified temperature condition.
Identified facilities F-1 (22C-22^\circ\text{C}), F-3 (25C-25^\circ\text{C}), F-5 (22C-22^\circ\text{C}), and F-6 (24C-24^\circ\text{C}). Facility F-4 (20C-20^\circ\text{C}) is excluded because 20C-20^\circ\text{C} is not strictly colder than 20C-20^\circ\text{C}.
The criterion requires temperatures strictly below 20C-20^\circ\text{C}.
2
Extract and order the monthly operating costs (in thousands of dollars) for the filtered subset.
Ordered values: 144,175,198,260144, 175, 198, 260.
Sorting values in ascending order is necessary to calculate the median.
3
Calculate the median of the four operating cost values.
Median=175+1982=186.5\text{Median} = \frac{175 + 198}{2} = 186.5 thousand dollars, which equals $186,500\$186,500.
For an even number of observations (n=4n = 4), the median is the mean of the 2nd and 3rd ordered values.
4
Compare the calculated median to the threshold value in the statement.
$186,500>$180,000\$186,500 > \$180,000, confirming the statement is True.
The median operating cost exceeds the threshold of $180,000\$180,000.

Anahtar Kavram

Conditional Table Filtering and Median Calculation
Soru 51Soru

The table below presents operational metrics for eight EV charging station networks.

Network IDRegionTotal ChargersFast Chargers (%)Average Uptime (%)Monthly Utilization (hrs/charger)
Alpha-1North4540%98.2%310
Beta-2South6025%97.5%280
Gamma-3East3060%99.1%340
Delta-4North8015%96.8%290
Epsilon-5West5050%98.7%320
Zeta-6South4045%97.0%350
Eta-7East7030%99.4%260
Theta-8West5560%98.0%330

Statement: If the table is sorted by Region in ascending alphabetical order, and any ties in Region are broken by sorting Fast Chargers (%) in descending order, the network in the North region with the higher Monthly Utilization will appear before the other North region network.

Cevabı ve açıklamayı göster

Cevap: True

Cevap

The statement is True.
Sorting by Region alphabetically places the North region second (after East). To order the two North rows (Alpha-1 and Delta-4), we sort Fast Chargers (%) in descending order. Since 40% > 15%, Alpha-1 (Monthly Utilization = 310) precedes Delta-4 (Monthly Utilization = 290), making the statement true.

Adım Adım Çözüm

1
Identify networks located in the North region.
The North region includes Alpha-1 (Fast Chargers: 40%, Utilization: 310) and Delta-4 (Fast Chargers: 15%, Utilization: 290).
Filtering the table for the North region is necessary before applying the tie-breaker.
2
Apply the secondary sort rule (Fast Chargers % in descending order) to break the tie in the North region.
40% > 15%, so Alpha-1 comes before Delta-4.
Descending order puts higher percentages first.
3
Compare the Monthly Utilization values of the ordered North region networks.
Alpha-1 (310 hrs/charger) appears before Delta-4 (290 hrs/charger). The network with the higher utilization appears first.
This directly satisfies the condition stated.

Anahtar Kavram

Multi-column sorting requires applying a primary sort order to a categorical column and resolving identical values using a secondary quantitative column.
Tahmini Süre:1m 15s
Soru 52Soru

The table below presents clinical trial enrollment and quality metrics for eight medical research sites participating in a pharmaceutical study:

Research SiteRegionTarget EnrollmentAchieved Enrollment (%)Protocol Deviations (per 100 subjects)
Site 101North15095%4.5
Site 102East12095%3.8
Site 103South20092%4.2
Site 104West15092%1.8
Site 105North20090%2.5
Site 106East25088%3.1
Site 107West18085%1.8
Site 108South20085%2.5

If the table is sorted in descending order by Achieved Enrollment (%), and any ties are broken by sorting in ascending order by Protocol Deviations (per 100 subjects), which research site will be listed 4th from the top?

Cevabı ve açıklamayı göster

Cevap: Site 103

Cevap

Site 103 will be listed 4th from the top after applying the primary descending sort on Achieved Enrollment (%) and the secondary ascending sort tie-breaker on Protocol Deviations.
Sorting the table primarily by Achieved Enrollment (%) in descending order places the two 95% sites first, followed by the two 92% sites. Applying the secondary sort (Protocol Deviations in ascending order) places Site 104 (1.8 deviations) in 3rd position and Site 103 (4.2 deviations) in 4th position.

Adım Adım Çözüm

1
Group research sites by the primary sort key: Achieved Enrollment (%) in descending order.
Groups in order: 95% (Sites 101, 102), 92% (Sites 103, 104), 90% (Site 105), 88% (Site 106), 85% (Sites 107, 108).
Primary sort priority dictates that higher percentage values must appear before lower percentage values.
2
Apply the secondary tie-breaking condition: Protocol Deviations (per 100 subjects) in ascending order for tied groups.
For the 95% group: Site 102 (3.8) comes before Site 101 (4.5) -> Positions 1 and 2.
For the 92% group: Site 104 (1.8) comes before Site 103 (4.2) -> Positions 3 and 4.
Ascending order means lower numerical deviation values rank higher among tied entries.
3
Determine the site occupying the 4th position.
1st: Site 102, 2nd: Site 101, 3rd: Site 104, 4th: Site 103.
Site 103 is the second site within the 92% group after tie-breaking.

Anahtar Kavram

Multi-Column Sorting with Primary and Secondary Tie-Breaking Rules
Tahmini Süre:1m 30s
Soru 53Soru

The table below lists performance metrics for seven regional logistics distribution hubs:

Logistics HubRegionOrder Fulfillment Rate (orders/hr)On-Time Delivery Rate (%)Storage Capacity (thousand sq ft)
Hub AlphaNorth42094.5%150
Hub BetaEast51091.2%210
Hub GammaNorth42096.8%180
Hub DeltaWest38098.1%120
Hub EpsilonSouth51095.4%190
Hub ZetaEast47093.0%160
Hub EtaSouth51092.5%220

True or False: If the table is sorted primarily by Order Fulfillment Rate (orders/hr) in descending order, and ties are broken by On-Time Delivery Rate (%) in descending order, the hub ranked 3rd in the ordered list has a greater Storage Capacity than the hub ranked 5th.

Cevabı ve açıklamayı göster

Cevap: True

Cevap

True
Sorting the table by Order Fulfillment Rate descending places hubs with 510 orders/hr in the top positions. Breaking ties by On-Time Delivery Rate descending orders these three hubs as Hub Epsilon (95.4%), Hub Eta (92.5%), and Hub Beta (91.2%), making Hub Beta 3rd. The next group (420 orders/hr) orders Hub Gamma (96.8%) ahead of Hub Alpha (94.5%), placing Hub Gamma 5th overall. Comparing Hub Beta's storage capacity (210) to Hub Gamma's (180) confirms that 210>180210 > 180.

Adım Adım Çözüm

1
Group hubs by the primary sort key: Order Fulfillment Rate (orders/hr) in descending order.
Group 1 (510 orders/hr): Hub Beta, Hub Epsilon, Hub Eta. Group 2 (470 orders/hr): Hub Zeta. Group 3 (420 orders/hr): Hub Alpha, Hub Gamma. Group 4 (380 orders/hr): Hub Delta.
Primary ordering establishes the initial rank blocks.
2
Break ties within Group 1 and Group 3 using On-Time Delivery Rate (%) in descending order.
Group 1 order: Hub Epsilon (95.4%), Hub Eta (92.5%), Hub Beta (91.2%). Group 3 order: Hub Gamma (96.8%), Hub Alpha (94.5%).
Higher percentage values receive higher priority when sorting descending.
3
Combine the ordered groups to find the 3rd and 5th hubs.
1st: Hub Epsilon, 2nd: Hub Eta, 3rd: Hub Beta, 4th: Hub Zeta, 5th: Hub Gamma, 6th: Hub Alpha, 7th: Hub Delta.
Determines exact multi-column rank order.
4
Compare Storage Capacity for the 3rd-ranked hub (Hub Beta) and the 5th-ranked hub (Hub Gamma).
Hub Beta Storage Capacity = 210. Hub Gamma Storage Capacity = 180. 210>180210 > 180.
Directly evaluates the condition stated in the prompt.

Anahtar Kavram

Multi-column sorting and tie-breaker rank evaluation
Soru 54Soru

The table below lists operational and financial metrics for 8 tech startups evaluated by a venture capital firm.

StartupSectorAnnual Revenue Growth (%)Customer Retention Rate (%)Burn MultipleEmployee Headcount
AlphaTechAI140851.845
BetaDataFinTech110921.460
GammaCloudSaaS140881.280
DeltaHealthHealthTech165782.135
EpsilonCyberCybersecurity110921.150
ZetaRoboticsAI140851.540
EtaPayFinTech165841.670
ThetaSecureCybersecurity110891.355

Suppose the table is sorted in descending order by Annual Revenue Growth (%). For any startups tied in Annual Revenue Growth (%), the table is secondary sorted in descending order by Customer Retention Rate (%). If a tie still remains, the table is tertiary sorted in ascending order (lowest to highest) by Burn Multiple. Which startup will appear in the 4th position from the top after this multi-column sort?

Cevabı ve açıklamayı göster

Cevap: ZetaRobotics

Cevap

ZetaRobotics is in the 4th position from the top.
To determine the 4th startup after the multi-column sort:
1. Primary Sort (Annual Revenue Growth %, Descending):
- 165%: EtaPay, DeltaHealth
- 140%: GammaCloud, AlphaTech, ZetaRobotics
- 110%: BetaData, EpsilonCyber, ThetaSecure

2. Secondary Sort (Customer Retention Rate %, Descending):
- For the 165% group: EtaPay (84%) is 1st, DeltaHealth (78%) is 2nd.
- For the 140% group: GammaCloud (88%) is 3rd. AlphaTech (85%) and ZetaRobotics (85%) remain tied for 4th and 5th.

3. Tertiary Sort (Burn Multiple, Ascending):
- ZetaRobotics has a Burn Multiple of 1.5.
- AlphaTech has a Burn Multiple of 1.8.
- Since 1.5 is lower than 1.8, ZetaRobotics comes first among the tied pair, placing it in the 4th position overall.

Adım Adım Çözüm

1
Primary Sort: Order startups by Annual Revenue Growth (%) in descending order.
The highest growth rate is 165% (EtaPay, DeltaHealth), followed by 140% (AlphaTech, GammaCloud, ZetaRobotics), and 110% (BetaData, EpsilonCyber, ThetaSecure).
Groups must first be organized by the primary sorting column.
2
Evaluate the 165% Revenue Growth group to determine positions 1 and 2.
EtaPay (Retention 84%) and DeltaHealth (Retention 78%). Sorting by Customer Retention Rate descending puts EtaPay 1st and DeltaHealth 2nd.
Secondary sorting dictates that within ties, higher retention rates come first.
3
Evaluate the 140% Revenue Growth group to determine positions 3, 4, and 5.
GammaCloud has Retention 88% (ranks 3rd). AlphaTech and ZetaRobotics both have Retention 85% and remain tied.
GammaCloud has the highest secondary value in this group.
4
Apply the tertiary sort to break the tie between AlphaTech and ZetaRobotics for positions 4 and 5.
Sort by Burn Multiple ascending (lowest to highest): ZetaRobotics has a Burn Multiple of 1.5, while AlphaTech has 1.8. Thus, ZetaRobotics ranks 4th and AlphaTech ranks 5th.
Lower Burn Multiple takes priority in ascending tertiary order.

Anahtar Kavram

Multi-column hierarchical sorting with tie-breaker logic
Soru 55Soru

The table below presents 2025 operational performance and cost metrics for eight regional commercial biofuel production facilities:

Facility NameFeedstock TypeAnnual Output (Million L)Operating Cost ($/L)Carbon Intensity Reduction (%)Capacity Utilization Rate (%)
BioAlphaCellulosic850.7268%88%
EcoEthanolCorn Stover1200.5545%92%
GreenFuel XAlgae401.1082%75%
PureBioUsed Cooking Oil950.6474%95%
TerraFuelCellulosic1100.6865%82%
Vanguard BioAlgae600.9885%80%
SunFuel NorthCorn Stover1500.5042%90%
NextGen FuelUsed Cooking Oil750.7670%85%

Based on the data provided, evaluate whether the following overall assertion is True or False:

"Exactly two of the three statements below are True:
- Statement 1: The median Annual Output among facilities with a Carbon Intensity Reduction of at least 70% is 67.5 Million Liters.
- Statement 2: For all facilities utilizing Cellulosic or Algae feedstock, the Operating Cost per Liter is strictly greater than $0.65.
- Statement 3: The facility with the highest Capacity Utilization Rate incurred a lower total annual operating cost (calculated as Annual Output × Operating Cost) than the facility with the lowest Capacity Utilization Rate."

Cevabı ve açıklamayı göster

Cevap: True

Cevap

True. Statements 1 and 2 are True, while Statement 3 is False, meaning exactly two of the three statements are True.
Evaluating the individual statements reveals that Statement 1 is True (the median of {40, 60, 75, 95} is 67.5), Statement 2 is True (operating costs for Cellulosic and Algae facilities are 0.72,0.72, 1.10, 0.68,and0.68, and 0.98, all greater than 0.65),andStatement3isFalse(PureBiostotalcostof0.65), and Statement 3 is False (PureBio's total cost of 60.8 Million exceeds GreenFuel X's total cost of $44.0 Million). Since exactly two statements are True, the overall compound assertion is True.

Adım Adım Çözüm

1
Evaluate Statement 1: Identify facilities with Carbon Intensity Reduction ≥ 70% and calculate their median Annual Output.
Facilities satisfying the condition are GreenFuel X (82%), PureBio (74%), Vanguard Bio (85%), and NextGen Fuel (70%). Their outputs are 40, 95, 60, and 75 Million Liters, respectively. Ordering these values: 40, 60, 75, 95. The median of an even set of four numbers is (60+75)/2=67.5(60 + 75) / 2 = 67.5 Million Liters. Thus, Statement 1 is True.
Correctly filtering by the conditional threshold (70%) and sorting the output values is required to calculate the median of an even dataset.
2
Evaluate Statement 2: Filter for facilities using Cellulosic or Algae feedstock and compare their Operating Costs to $0.65.
Facilities matching Cellulosic or Algae feedstock are BioAlpha (0.72),GreenFuelX(0.72), GreenFuel X ( 1.10), TerraFuel (0.68),andVanguardBio(0.68), and Vanguard Bio ( 0.98). Every single one of these operating costs is strictly greater than $0.65. Thus, Statement 2 is True.
A universal condition ('for all') requires checking every matching row to ensure no counterexample exists.
3
Evaluate Statement 3: Identify facilities with the highest and lowest Capacity Utilization Rates, compute their total annual operating costs, and compare.
Highest Capacity Utilization Rate: PureBio (95%). Total annual operating cost = 95 Million L×$0.64/L=$60.8 Million95 \text{ Million L} \times \$0.64/\text{L} = \$60.8 \text{ Million}. Lowest Capacity Utilization Rate: GreenFuel X (75%). Total annual operating cost = 40 Million L×$1.10/L=$44.0 Million40 \text{ Million L} \times \$1.10/\text{L} = \$44.0 \text{ Million}. Since $60.8 Million>$44.0 Million\$60.8 \text{ Million} > \$44.0 \text{ Million}, the highest utilization facility did NOT incur a lower cost. Thus, Statement 3 is False.
Row-level product calculations must be performed accurately for both extreme values before evaluating the inequality.
4
Synthesize the truth values of the three statements to evaluate the overall assertion.
Statement 1 = True, Statement 2 = True, Statement 3 = False. Total number of True statements = 2. Therefore, the assertion 'Exactly two of the three statements below are True' is True.
The top-level boolean logic requires assessing whether the count of True individual statements equals 2.

Anahtar Kavram

Multi-Statement Boolean Evaluation
Soru 56Soru

The table below presents operational metrics for 8 oceanographic research vessels participating in a global marine survey:

Vessel IDRegionActive DaysFuel Efficiency (nmi/ton)Grants ($M)
Triton-1Pacific24014.23.8
Nereus-4Atlantic21518.54.2
Proteus-2Pacific24016.02.9
Oceanus-7Arctic19012.15.1
Calypso-3Atlantic26015.43.1
Glaucus-5Pacific21519.24.6
Thalassa-9Indian26013.84.0
Doris-6Atlantic19014.53.5

Based on the table above, evaluate whether the following statement is True or False:

"If the table is sorted primarily by Active Days in descending order, with ties broken by Fuel Efficiency in descending order, the vessel that ranks 4th from the top is Triton-1."

Cevabı ve açıklamayı göster

Cevap: True

Cevap

True
Sorting primarily by Active Days descending places Calypso-3 and Thalassa-9 in positions 1–2, and Proteus-2 and Triton-1 in positions 3–4. Applying the secondary sort by Fuel Efficiency descending resolves the tie between Proteus-2 (16.0 nmi/ton) and Triton-1 (14.2 nmi/ton), placing Proteus-2 3rd and Triton-1 4th.

Adım Adım Çözüm

1
Group and sort vessels by the primary criterion (Active Days in descending order).
Tier 1 (260 days): Calypso-3, Thalassa-9. Tier 2 (240 days): Triton-1, Proteus-2. Tier 3 (215 days): Nereus-4, Glaucus-5. Tier 4 (190 days): Oceanus-7, Doris-6.
Primary sort determines the overarching rank brackets.
2
Apply the secondary tie-breaker (Fuel Efficiency in descending order) to resolve order within tied groups.
For Tier 1 (260 days): Calypso-3 (15.4) > Thalassa-9 (13.8) -> Ranks 1 and 2. For Tier 2 (240 days): Proteus-2 (16.0) > Triton-1 (14.2) -> Ranks 3 and 4.
Higher fuel efficiency takes precedence when active days are identical.
3
Identify the vessel occupying the 4th position.
Position 4 is occupied by Triton-1.
Proteus-2 claims 3rd place, leaving Triton-1 in 4th place.

Anahtar Kavram

Multi-Column Tie-Breaking and Hierarchical Table Sorting
Tahmini Süre:1m 30s
Soru 57Soru

The table below presents operating and compliance metrics for seven municipal water treatment plants during 2025:

Plant NameDaily Capacity (MGD)Operating Cost ($/MG)Compliance Rate (%)Energy Consumption (kWh/MG)Staff Count
Clearwater Station4532098.4%1,45028
Blue River Plant8028099.1%1,20042
Oak Valley Works3041097.8%1,68022
Pine Creek Facility11025099.5%1,15050
Cedar Ridge Station6034098.9%1,38035
Ironwood Treatment2545096.5%1,75018
Laurel Heights7031098.7%1,30031

Match each statement on the left with its correct boolean evaluation outcome and quantitative justification on the right.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

Statement I: The plant with the median Staff Count has an Operating Cost greater than the mean Operating Cost of all seven plants.
Statement II: For plants with a Compliance Rate above 98.5%, the ratio of total Daily Capacity to total Staff Count exceeds 2.0 MGD per staff member.
Statement III: When sorted in ascending order by Energy Consumption, the plant with the third-lowest energy usage has a higher Daily Capacity than the plant with the lowest Operating Cost.

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

Statement I matches with the outcome stating it evaluates to FALSE (310<310 < 337.14); Statement II matches with the outcome stating it evaluates to TRUE (2.03 > 2.0); Statement III matches with the outcome stating it evaluates to FALSE (70 MGD < 110 MGD).
Each statement matches its exact evaluation outcome based on standard tabular data calculations: Statement I evaluates to False because 310perMGisbelowthe310 per MG is below the 337.14 per MG mean; Statement II evaluates to True because 320 divided by 158 equals approximately 2.03, which is greater than 2.0; Statement III evaluates to False because a capacity of 70 MGD is less than 110 MGD.

Adım Adım Çözüm

1
Evaluate Statement I by determining the median staff count and mean operating cost.
Sorted staff counts: 18, 22, 28, 31 (Laurel Heights), 35, 42, 50. Median plant is Laurel Heights with an operating cost of 310.Meanoperatingcost=(320+280+410+250+340+450+310)/7=2360/7310. Mean operating cost = (320 + 280 + 410 + 250 + 340 + 450 + 310) / 7 = 2360 / 7 ≈ 337.14. Since 310islessthan310 is less than 337.14, Statement I is False.
Identify the median position (4th out of 7) and compare its specific column value to the unweighted mean across all rows.
2
Evaluate Statement II by filtering plants with compliance > 98.5% and calculating aggregate capacity to staff ratio.
Qualifying plants are Blue River, Pine Creek, Cedar Ridge, and Laurel Heights. Total capacity = 80 + 110 + 60 + 70 = 320 MGD. Total staff = 42 + 50 + 35 + 31 = 158. Ratio = 320 / 158 ≈ 2.025 MGD/staff. Since 2.025 > 2.0, Statement II is True.
Filter rows according to a conditional threshold, aggregate columns across the selected subset, and perform ratio division.
3
Evaluate Statement III by sorting by Energy Consumption and comparing capacities of the 3rd-lowest energy plant and 1st-lowest cost plant.
Energy ordered plants: Pine Creek (1,150), Blue River (1,200), Laurel Heights (1,300). 3rd-lowest is Laurel Heights (Capacity = 70 MGD). Lowest operating cost plant is Pine Creek ($250, Capacity = 110 MGD). Comparing capacities: 70 MGD < 110 MGD. Statement III is False.
Sort table columns independently to locate specified ordinal positions (3rd-lowest energy, 1st-lowest cost) and compare their respective cross-column properties.

Anahtar Kavram

Multi-Statement Boolean Evaluation using tabular sorting, descriptive statistics, conditional filtering, and cross-column ratios.
Tahmini Süre:2m 0s
Soru 58Soru

The table below lists operational data for seven regional hydroelectric power stations:

Station NameRiver SystemInstalled Capacity (MW)Annual Generation (GWh)Operating Efficiency (%)
Apex DamColumbia4501,80088%
Beacon HydroSnake3201,44092%
Crest FallsColumbia5001,95085%
Delta FlowMissouri2801,12090%
Eagle RidgeSnake4001,60086%
Frontier HydroMissouri3501,47091%
Glacier PeakColumbia4201,76489%

Statement: If the table is sorted in ascending alphabetical order by River System, and any ties in River System are broken by sorting Operating Efficiency in descending order, Beacon Hydro will appear immediately above Eagle Ridge in the sorted list.

Cevabı ve açıklamayı göster

Cevap: True

Cevap

True
Sorting primarily by River System (alphabetical) places the two Snake stations at the bottom of the table. Breaking the tie by sorting Operating Efficiency descending places Beacon Hydro (92%) above Eagle Ridge (86%), confirming Beacon Hydro immediately precedes Eagle Ridge.

Adım Adım Çözüm

1
Group rows by the primary sort key: River System in ascending alphabetical order.
The river systems are ordered as Columbia, then Missouri, then Snake.
Alphabetical sorting orders C before M, and M before S.
2
Sort the entries within each river system group by the tie-breaker rule: Operating Efficiency in descending order.
Columbia group: Glacier Peak (89%), Apex Dam (88%), Crest Falls (85%). Missouri group: Frontier Hydro (91%), Delta Flow (90%). Snake group: Beacon Hydro (92%), Eagle Ridge (86%).
Descending efficiency puts higher percentage values above lower percentage values within each group.
3
Combine the ordered groups to form the complete sorted list.
Position 1: Glacier Peak, Position 2: Apex Dam, Position 3: Crest Falls, Position 4: Frontier Hydro, Position 5: Delta Flow, Position 6: Beacon Hydro, Position 7: Eagle Ridge.
Evaluating positions shows Beacon Hydro (6th) is placed directly above Eagle Ridge (7th).

Anahtar Kavram

Sorting and Multi-Column Ordering
Soru 59Soru

The table below presents 2025 operational and patient triage metrics for seven regional emergency departments:

Hospital NameAnnual Patient Volume (thousands)Median Wait Time (min)Mean Treatment Duration (hrs)Left Without Being Seen (LWBS) Rate30-Day Readmission Rate
St. Jude Regional48243.51.8%4.2%
Metro Central85424.83.5%5.8%
Valley General62304.02.4%4.5%
Highland Medical35183.21.2%3.8%
Pinecrest Community28152.80.9%3.5%
University Health92485.24.1%6.2%
Riverside Care54283.82.1%4.9%

Evaluate whether the following statement is True or False:
"For every hospital with an annual patient volume exceeding 50,000, the ratio of Median Wait Time (in minutes) to Mean Treatment Duration (in hours) is strictly greater than 7.0."

Cevabı ve açıklamayı göster

Cevap: True

Cevap

True. All four hospitals with annual patient volume exceeding 50,000 have a wait-to-treatment duration ratio greater than 7.0.
Filtering the table for hospitals with annual patient volume exceeding 50 thousand isolates Metro Central, Valley General, University Health, and Riverside Care. Calculating the ratio of median wait time (minutes) to mean treatment duration (hours) yields 8.75, 7.50, 9.23, and 7.37 respectively. Because every single one of these values exceeds 7.0, the statement is True.

Adım Adım Çözüm

1
Filter the dataset based on the volume condition.
Identified four hospitals with annual volume > 50k: Metro Central (85), Valley General (62), University Health (92), and Riverside Care (54).
The statement specifies a condition that applies only to hospitals with patient volume over 50 thousand.
2
Calculate the ratio of Median Wait Time (minutes) to Mean Treatment Duration (hours) for each qualifying hospital.
Metro Central = 8.75; Valley General = 7.50; University Health ≈ 9.23; Riverside Care ≈ 7.37.
Determines the exact numerical value of the ratio for each qualifying row.
3
Compare each calculated ratio to the threshold value of 7.0.
All four calculated ratios are strictly greater than 7.0.
Verifies whether the universal claim ('for every hospital...') holds true.

Anahtar Kavram

Multi-Statement Boolean Evaluation via Conditional Data Filtering and Ratio Analysis
Soru 60Soru

The table below displays performance metrics for seven regional freight rail terminals.

Terminal IDRegionCargo Handled (Thousand Tons)On-Time Dispatch Rate (%)Operating Cost per Ton ($)
T-1East45092.5%14.20
T-2West62088.0%11.50
T-3North45094.0%15.80
T-4South58092.5%12.10
T-5East62091.5%10.80
T-6North39095.5%16.40
T-7West58089.0%13.00

If the table is sorted in descending order by Cargo Handled, and any ties are broken by sorting in descending order by On-Time Dispatch Rate, which terminal will be listed fourth from the top?

Cevabı ve açıklamayı göster

Cevap: Terminal T-7

Cevap

Terminal T-7
Primary sorting by Cargo Handled in descending order groups the top two tiers as 620 thousand tons (T-5, T-2) and 580 thousand tons (T-4, T-7). Secondary sorting by On-Time Dispatch Rate in descending order ranks T-4 (92.5%) above T-7 (89.0%) within the 580 thousand tons group. This places T-5 first, T-2 second, T-4 third, and Terminal T-7 fourth.

Adım Adım Çözüm

1
Group and order the table by the primary column: Cargo Handled (descending).
Highest tier (620 thousand tons): T-2, T-5; Second tier (580 thousand tons): T-4, T-7; Third tier (450 thousand tons): T-1, T-3; Lowest tier (390 thousand tons): T-6.
The primary sort requires arranging entries from largest to smallest cargo volume.
2
Apply the secondary sort criterion (On-Time Dispatch Rate descending) to break ties in each cargo tier.
Tier 1 (620 thousand tons): T-5 (91.5%) is 1st, T-2 (88.0%) is 2nd. Tier 2 (580 thousand tons): T-4 (92.5%) is 3rd, T-7 (89.0%) is 4th.
When primary values are identical, higher on-time dispatch rates take precedence.
3
Identify the item in the 4th position of the fully sorted list.
The 4th terminal in sequence is Terminal T-7.
Terminal T-7 is second in the 580 thousand tons tier due to its 89.0% dispatch rate compared to T-4's 92.5%.

Anahtar Kavram

Multi-Column Sorting and Tie-Breaking
Tahmini Süre:1m 30s
ÖncekiSayfa 3 / 4Sonraki