Word Problems and Applied Math

188 soru

Soru 41Soru

A commercial bank's loan portfolio consists of three categories of loans: small business loans, residential mortgages, and commercial real estate loans. Small business loans carry an average annual interest rate of 8.5%8.5\% and account for 30%30\% of the portfolio's total value. Residential mortgages carry an average annual interest rate of 5.0%5.0\%, and commercial real estate loans carry an average annual interest rate of 6.5%6.5\%. If the overall weighted average annual interest rate for the entire portfolio is 6.35%6.35\%, what percentage of the portfolio's total value is invested in commercial real estate loans?

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Cevap: 20%20\%

Cevap

The commercial real estate loans account for 20%20\% of the portfolio's total value.
The overall portfolio rate of 6.35%6.35\% is a weighted average of small business loans (8.5%8.5\% rate, 30%30\% weight), residential mortgages (5.0%5.0\% rate, x%x\% weight), and commercial real estate loans (6.5%6.5\% rate, (70x)%(70-x)\% weight). Solving 0.30(8.5)+0.05x+0.065(70x)=6.350.30(8.5) + 0.05x + 0.065(70 - x) = 6.35 gives x=50%x = 50\%, which means commercial real estate loans constitute 70%50%=20%70\% - 50\% = 20\% of the total portfolio.

Adım Adım Çözüm

1
Define variables for the unknown portfolio weight components.
Let w1=0.30w_1 = 0.30 (small business loans), w2=xw_2 = x (residential mortgages), and w3=0.70xw_3 = 0.70 - x (commercial real estate loans).
The sum of all weights across the three portfolio categories must equal 100%100\% (1.001.00). Since small business loans constitute 30%30\%, the remaining two categories must sum to 70%70\% (0.700.70).
2
Set up the weighted average formula for the overall portfolio interest rate.
0.30(8.5)+x(5.0)+(0.70x)(6.5)=6.350.30(8.5) + x(5.0) + (0.70 - x)(6.5) = 6.35
The overall weighted average interest rate is the sum of each component's rate multiplied by its respective weight in the portfolio.
3
Expand and simplify the algebraic equation.
2.55+5.0x+4.556.5x=6.35    7.101.5x=6.352.55 + 5.0x + 4.55 - 6.5x = 6.35 \implies 7.10 - 1.5x = 6.35
Multiplying out terms allows combining like terms to solve for xx.
4
Solve for xx to find the weight of residential mortgages, then find the weight of commercial real estate loans.
1.5x=0.75    x=0.501.5x = 0.75 \implies x = 0.50 (50%50\%). Thus, commercial real estate weight =0.700.50=0.20= 0.70 - 0.50 = 0.20 (20%20\%).
Subtracting x=50%x = 50\% from the total remaining 70%70\% gives the exact share allocated to commercial real estate loans.

Anahtar Kavram

Weighted Averages in Multi-Component Portfolios
Soru 42Soru

A private equity firm allocated its total investment capital between two tech startups, Company X and Company Y. Over the first year, the value of the investment in Company X increased by 60%60\%, while the value of the investment in Company Y increased by 20%20\%. Over the second year, the value of Company X decreased by 25%25\% from its Year 1 value, while the value of Company Y increased by 25%25\% from its Year 1 value. If the total combined value of the two investments at the end of the second year was 38%38\% greater than the original total investment capital allocated, what percent of the original total investment capital was allocated to Company X?

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Cevap: 40

Cevap

40%
Evaluating successive percent changes gives growth multipliers of 1.60×0.75=1.201.60 \times 0.75 = 1.20 for Company X and 1.20×1.25=1.501.20 \times 1.25 = 1.50 for Company Y. Setting the weighted sum of final values equal to 1.38(X+Y)1.38(X + Y) yields 1.20X+1.50Y=1.38X+1.38Y1.20X + 1.50Y = 1.38X + 1.38Y, which simplifies to 0.18X=0.12Y0.18X = 0.12Y or Y=1.5XY = 1.5X. The proportion allocated to Company X is XX+1.5X=12.5=40%\frac{X}{X + 1.5X} = \frac{1}{2.5} = 40\%.

Adım Adım Çözüm

1
Calculate the cumulative growth multiplier for Company X over the two-year period.
Company X's final value is 1.20X1.20X, representing a net increase of 20%20\%.
Successive percent changes are calculated by multiplying the growth factors: (1+0.60)×(10.25)=1.60×0.75=1.20(1 + 0.60) \times (1 - 0.25) = 1.60 \times 0.75 = 1.20.
2
Calculate the cumulative growth multiplier for Company Y over the two-year period.
Company Y's final value is 1.50Y1.50Y, representing a net increase of 50%50\%.
Successive percent changes are calculated by multiplying the growth factors: (1+0.20)×(1+0.25)=1.20×1.25=1.50(1 + 0.20) \times (1 + 0.25) = 1.20 \times 1.25 = 1.50.
3
Set up an equation for the combined final portfolio value relative to initial capital.
1.20X+1.50Y=1.38(X+Y)1.20X + 1.50Y = 1.38(X + Y).
The problem states that the combined final value is 38%38\% greater than the total initial capital X+YX + Y.
4
Simplify the equation to express YY in terms of XX.
0.12Y=0.18X    Y=1.5X0.12Y = 0.18X \implies Y = 1.5X.
Expanding 1.38X+1.38Y1.38X + 1.38Y and collecting like terms yields 1.50Y1.38Y=1.38X1.20X1.50Y - 1.38Y = 1.38X - 1.20X.
5
Determine Company X's proportion of the total initial allocation.
XX+1.5X=12.5=40%\frac{X}{X + 1.5X} = \frac{1}{2.5} = 40\%.
The initial percentage allocated to Company X is XX+Y×100%\frac{X}{X + Y} \times 100\%.

Anahtar Kavram

Weighted Successive Percent Change
Soru 43Soru

A medical distributor purchased a lot of 6060 identical diagnostic kits for a total cost of $4,800\$4,800. The distributor marked up the cost price of each kit by 50%50\% to set its regular retail price. After selling 4040 kits at the regular retail price, the distributor sold the remaining 2020 kits at a clearance discount of 30%30\% off the regular retail price. What was the distributor's total net profit, in dollars, from the sale of all 6060 diagnostic kits?

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Cevap: 1680

Cevap

The distributor's total net profit from the sale of all 60 diagnostic kits is $1,680.
To calculate net profit, first determine the unit cost: $4,80060=$80\frac{\$4,800}{60} = \$80. The marked-up regular price is $80×1.50=$120\$80 \times 1.50 = \$120. Selling 4040 kits at $120\$120 yields $4,800\$4,800. The remaining 2020 kits are sold at a 30%30\% discount off $120\$120, giving a clearance price of $120×0.70=$84\$120 \times 0.70 = \$84 per kit and revenue of 20×$84=$1,68020 \times \$84 = \$1,680. Total revenue is $4,800+$1,680=$6,480\$4,800 + \$1,680 = \$6,480. Subtracting the total cost of $4,800\$4,800 yields a net profit of $1,680\$1,680.

Adım Adım Çözüm

1
Determine the cost price per unit.
Cost per kit is $4,80060=$80\frac{\$4,800}{60} = \$80.
Dividing total initial cost by total units gives the unit cost price.
2
Calculate the regular retail price per unit.
Regular retail price is $80×(1+0.50)=$120\$80 \times (1 + 0.50) = \$120.
The 50%50\% markup is applied directly to the cost price of $80\$80.
3
Calculate revenue from the full-price sales segment.
Revenue from 4040 kits is 40×$120=$4,80040 \times \$120 = \$4,800.
Multiply quantity sold at full price by regular retail price.
4
Determine clearance price and revenue for remaining units.
Clearance price is $120×(10.30)=$84\$120 \times (1 - 0.30) = \$84. Revenue from 2020 kits is 20×$84=$1,68020 \times \$84 = \$1,680.
The clearance discount of 30%30\% is taken off the regular retail price, not cost.
5
Calculate total revenue and net profit.
Total revenue is $4,800+$1,680=$6,480\$4,800 + \$1,680 = \$6,480. Net profit is $6,480$4,800=$1,680\$6,480 - \$4,800 = \$1,680.
Net profit equals total revenue minus total cost.

Anahtar Kavram

Profit, Loss, and Markup
Soru 44Soru

A freight boat travels downstream along a river from Dock A to Dock B in 44 hours. On the return trip upstream from Dock B to Dock A, engine trouble causes the boat's speed in still water to decrease by 25%25\% for the entire return trip. If the speed of the river current is a constant 33 miles per hour and the upstream return trip takes 88 hours, what is the distance, in miles, between Dock A and Dock B?

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Cevap: 84

Cevap

The distance between Dock A and Dock B is 84 miles.
The correct distance of 84 miles is determined by accounting for both the constant river current of 3 mph and the 25% reduction in still-water boat speed on the return trip. Setting the downstream distance formula equal to the upstream distance formula yields a still-water initial speed of 18 mph, giving a one-way distance of 84 miles.

Adım Adım Çözüm

1
Define variables for the boat's speed in still water and write expressions for effective speeds.
Let vv be the initial speed of the boat in still water (in mph). The downstream speed is (v+3)(v + 3) mph. Due to a 25%25\% reduction on the return leg, the boat's upstream speed in still water is 0.75v0.75v mph, making the effective upstream speed (0.75v3)(0.75v - 3) mph.
Effective speed downstream equals still-water speed plus current speed, while effective speed upstream equals still-water speed minus current speed.
2
Set up distance equations for both directions using Distance=Rate×Time\text{Distance} = \text{Rate} \times \text{Time}.
Downstream distance: D=4(v+3)D = 4(v + 3). Upstream distance: D=8(0.75v3)D = 8(0.75v - 3).
The distance between Dock A and Dock B is the same in both directions.
3
Equate the two distance expressions and solve for vv.
4(v+3)=8(0.75v3)    v+3=1.5v6    0.5v=9    v=184(v + 3) = 8(0.75v - 3) \implies v + 3 = 1.5v - 6 \implies 0.5v = 9 \implies v = 18 mph.
Equating the two representations of distance allows for solving the single unknown variable vv.
4
Calculate the total distance DD.
D=4(18+3)=4(21)=84D = 4(18 + 3) = 4(21) = 84 miles.
Substituting v=18v = 18 back into the downstream distance formula yields the exact distance.

Anahtar Kavram

Rate, Time, and Distance with Currents and Variable Speeds
Tahmini Süre:2m 30s
Soru 45Soru

A commercial real estate company manages three office buildings: Building A, Building B, and Building C. Building A contains 20,00020,000 square feet of rentable space leased at an average rate of $45\$45 per square foot per year. Building B contains 30,00030,000 square feet of rentable space leased at an average rate of $50\$50 per square foot per year. Building C contains 50,00050,000 square feet of rentable space. If the overall weighted average rental rate for all three buildings combined is $52\$52 per square foot per year, what is the average annual rental rate per square foot, in dollars, for Building C?

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Cevap: 56

Cevap

The average annual rental rate for Building C is 5656 dollars per square foot.
To find the average annual rental rate for Building C, determine the total revenue generated by all three buildings combined. With a total square footage of 20,000+30,000+50,000=100,00020,000 + 30,000 + 50,000 = 100,000 sq ft and an overall weighted average rate of $52\$52/sq ft, the total revenue is 100,000×52=5,200,000100,000 \times 52 = 5,200,000 dollars. Subtracting the revenue generated by Building A (20,000×45=900,00020,000 \times 45 = 900,000 dollars) and Building B (30,000×50=1,500,00030,000 \times 50 = 1,500,000 dollars) leaves 5,200,0002,400,000=2,800,0005,200,000 - 2,400,000 = 2,800,000 dollars that must be contributed by Building C. Dividing this by Building C's 50,00050,000 square feet yields an average rate of 5656 dollars per square foot.

Adım Adım Çözüm

1
Determine total combined rentable area and total combined revenue
Total area =20,000+30,000+50,000=100,000= 20,000 + 30,000 + 50,000 = 100,000 sq ft. Total revenue =100,000×52=5,200,000= 100,000 \times 52 = 5,200,000 dollars.
Weighted average rate multiplied by total square footage gives total annual rental revenue across all properties.
2
Calculate known annual revenues from Building A and Building B
Building A revenue =20,000×45=900,000= 20,000 \times 45 = 900,000 dollars. Building B revenue =30,000×50=1,500,000= 30,000 \times 50 = 1,500,000 dollars. Combined A and B revenue =2,400,000= 2,400,000 dollars.
Multiplying individual component weights by their respective rates yields individual group totals.
3
Subtract known revenues from total revenue and divide by Building C's square footage
Building C revenue =5,200,0002,400,000=2,800,000= 5,200,000 - 2,400,000 = 2,800,000 dollars. Building C rate =2,800,00050,000=56= \frac{2,800,000}{50,000} = 56 dollars.
Isolating the remaining revenue requirement and dividing by Building C's area yields its average rental rate per square foot.

Anahtar Kavram

Weighted Average = Total Weighted Sum / Total Weight Sum
Soru 46Soru

A commercial machinery supplier purchased a batch of industrial generators. The supplier marked up the wholesale cost of each generator by 40%40\% to set the original retail price. During an end-of-quarter promotion, the supplier offered a 15%15\% discount off the original retail price. If a customer purchased a generator at the promotional price for $4,760\$4,760, what was the supplier's profit, in dollars, on that sale?

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Cevap: 760

Cevap

The supplier's profit on the sale was $760.
Let CC represent the wholesale cost of a generator. A 40%40\% markup yields an original retail price of 1.40C1.40C. Applying a 15%15\% discount to this retail price produces a promotional selling price of 0.85×1.40C=1.19C0.85 \times 1.40C = 1.19C. Setting 1.19C=4,7601.19C = 4,760 gives C=4,000C = 4,000. The profit is the promotional selling price minus wholesale cost: $4,760$4,000=$760\$4,760 - \$4,000 = \$760.

Adım Adım Çözüm

1
Define the relationship between wholesale cost and original retail price.
Original Retail Price = 1.40×C1.40 \times C
A 40%40\% markup on wholesale cost CC increases the price to 140%140\% of CC.
2
Apply the discount to calculate the promotional selling price.
Selling Price = 0.85×(1.40×C)=1.19×C0.85 \times (1.40 \times C) = 1.19 \times C
A 15%15\% discount off the retail price leaves 85%85\% of the retail price.
3
Solve for the wholesale cost CC.
C=4,7601.19=4,000C = \frac{4,760}{1.19} = 4,000
Given that the final selling price is $4,760\$4,760, set 1.19C=4,7601.19C = 4,760 and divide.
4
Calculate the profit made on the sale.
Profit = $4,760$4,000=$760\$4,760 - \$4,000 = \$760
Profit equals total revenue (selling price) minus total cost.

Anahtar Kavram

Successive markup and discount calculations with distinct base values.
Soru 47Soru

An investor deposited a principal sum of money into an account that earns simple annual interest at a rate of r%r\%. At the end of 44 years, the total accumulated balance in the account (principal plus interest) was $7,200\$7,200. If the account had instead earned simple annual interest at a rate of (r+2)%(r + 2)\% over the same 44-year period, the total accumulated balance would have been $7,680\$7,680. What was the original principal amount deposited, in dollars?

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Cevap: 6000

Cevap

The original principal amount deposited was 6,0006,000 dollars.
The difference in accumulated balances over 44 years is $7,680$7,200=$480\$7,680 - \$7,200 = \$480. Since simple interest is calculated strictly on the original principal PP, an annual rate increase of 2%2\% yields an additional 2%2\% of PP each year. Over 44 years, this total rate increase is 4×2%=8%4 \times 2\% = 8\%. Therefore, 8%8\% of PP equals $480\$480, giving 0.08P=4800.08P = 480, which yields P=6,000P = 6,000 dollars.

Adım Adım Çözüm

1
Calculate the difference between the two final balances.
$7,680$7,200=$480\$7,680 - \$7,200 = \$480
The additional $480\$480 represents the total extra simple interest earned over 44 years due to the higher interest rate.
2
Determine the cumulative percentage rate increase over the 4-year period.
4 years×2% per year=8%4 \text{ years} \times 2\% \text{ per year} = 8\%
Simple interest is calculated solely on the original principal for each year.
3
Set up and solve the equation for the principal amount PP.
8% of P=$480    0.08P=480    P=6,0008\% \text{ of } P = \$480 \implies 0.08P = 480 \implies P = 6,000
Dividing the additional dollar amount by the additional percentage yields the original base principal.

Anahtar Kavram

Simple Interest and Rate Sensitivity
Tahmini Süre:1m 30s
Soru 48Soru

A boutique investment fund allocates its capital among Technology, Healthcare, and Renewable Energy in the ratio 3:4:53 : 4 : 5, respectively. After receiving an additional $12\$12 million in new capital, the entire new amount is invested in Healthcare, changing the ratio of capital among Technology, Healthcare, and Renewable Energy to 3:6:53 : 6 : 5. What was the total initial capital, in millions of dollars, invested in the fund?

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Cevap: 7272

Cevap

7272 million dollars
Let the initial capital allocations be 3x3x, 4x4x, and 5x5x million dollars for Technology, Healthcare, and Renewable Energy, respectively. The initial total capital is 3x+4x+5x=12x3x + 4x + 5x = 12x. When $12\$12 million is added to Healthcare, its new amount becomes 4x+124x + 12. Comparing the unchanged Technology amount to the updated Healthcare amount gives the proportion 3x4x+12=36=12\frac{3x}{4x + 12} = \frac{3}{6} = \frac{1}{2}. Cross-multiplying yields 6x=4x+126x = 4x + 12, so 2x=122x = 12 and x=6x = 6. The total initial capital is 12×6=7212 \times 6 = 72 million dollars.

Adım Adım Çözüm

1
Represent initial allocations using a multiplier xx
Technology =3x= 3x, Healthcare =4x= 4x, Renewable Energy =5x= 5x
Ratios represent proportional parts, so multiplying each term by a common constant xx expresses the actual amounts.
2
Set up the equation following the addition of $12\$12 million to Healthcare
New Healthcare allocation =4x+12= 4x + 12. The new ratio is 3x:(4x+12):5x=3:6:53x : (4x + 12) : 5x = 3 : 6 : 5.
Only the Healthcare amount changes, while Technology and Renewable Energy allocations remain 3x3x and 5x5x respectively.
3
Solve for xx using the ratio between Technology and Healthcare
\frac{3x}{4x + 12} = \frac{3}{6} \implies \frac{3x}{4x + 12} = \frac{1}{2} \implies 6x = 4x + 12 \implies 2x = 12 \implies x = 6
Equating the algebraic ratio of Technology to Healthcare to the new simplified ratio allows solving for xx.
4
Calculate the total initial capital
\text{Total initial capital} = 3x + 4x + 5x = 12x = 12(6) = 72
Summing the initial parts (12x12x) and substituting x=6x = 6 yields the initial total.

Anahtar Kavram

Ratio scaling and constant-part proportion adjustments
Tahmini Süre:1m 30s
Soru 49Soru

Three industrial machines, AA, BB, and CC, operating independently at their respective constant rates, can complete a production order of 1,2001,200 units in 1212 hours, 1515 hours, and 2020 hours, respectively. All three machines start working simultaneously on the order at 8:00 AM. At 10:00 AM, Machine AA experiences a mechanical failure and stops working permanently. Machine BB and Machine CC continue working together until 11:00 AM, at which point Machine BB's operating efficiency drops by 50%50\% due to overheating, while Machine CC continues at its original rate. At what time will the production order of 1,2001,200 units be fully completed?

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Cevap: 4:48 PM

Cevap

The production order will be completed at 4:48 PM.
The correct answer of 4:48 PM is derived by dividing the job into three distinct stages. From 8:00 AM to 10:00 AM (2 hours), Machines A, B, and C produce 240 units/hour, yielding 480 units. From 10:00 AM to 11:00 AM (1 hour), Machines B and C produce 140 units/hour, yielding 140 units, leaving 580 units remaining. After 11:00 AM, Machine B operates at 40 units/hour and Machine C at 60 units/hour, producing a combined rate of 100 units/hour. Dividing 580 remaining units by 100 units/hour gives 5.8 hours (5 hours 48 minutes), placing completion at exactly 4:48 PM.

Adım Adım Çözüm

1
Determine individual production rates for each machine.
Machine AA produces 1,20012=100\frac{1,200}{12} = 100 units/hour. Machine BB produces 1,20015=80\frac{1,200}{15} = 80 units/hour. Machine CC produces 1,20020=60\frac{1,200}{20} = 60 units/hour.
Establishing hourly rates is necessary to calculate work completed in each time interval.
2
Calculate work completed during Stage 1 (8:00 AM to 10:00 AM).
Combined rate of A+B+C=100+80+60=240A + B + C = 100 + 80 + 60 = 240 units/hour. In 22 hours, work completed =240×2=480= 240 \times 2 = 480 units. Remaining units =1,200480=720= 1,200 - 480 = 720 units.
All three machines work together for 2 full hours before Machine A breaks down.
3
Calculate work completed during Stage 2 (10:00 AM to 11:00 AM).
Combined rate of B+C=80+60=140B + C = 80 + 60 = 140 units/hour. In 11 hour, work completed =140×1=140= 140 \times 1 = 140 units. Remaining units =720140=580= 720 - 140 = 580 units.
Machine A is inactive, leaving only Machines B and C operating at full capacity for 1 hour.
4
Calculate the time required for Stage 3 (from 11:00 AM until completion).
Machine BB's reduced rate =80×0.50=40= 80 \times 0.50 = 40 units/hour. New combined rate of B+C=40+60=100B + C = 40 + 60 = 100 units/hour. Time needed =580100=5.8= \frac{580}{100} = 5.8 hours =5= 5 hours and 4848 minutes.
Machine B operates at half speed while Machine C continues at full speed to finish the remaining 580 units.
5
Determine the final completion clock time.
11:00 AM +5+ 5 hours and 4848 minutes =4:48= 4:48 PM.
Adding the duration of the final stage to the starting time of 11:00 AM gives the exact completion time.

Anahtar Kavram

Multi-stage combined work problems require calculating individual rates, tracking partial work completed in each phase, and adjusting combined rates whenever active entities or their individual rates change.
Tahmini Süre:3m 0s
Soru 50Soru

An investment fund initially divides its total capital among three portfolios—Real Estate, Stocks, and Bonds—in the ratio 3:4:53 : 4 : 5. During a financial restructuring, a portion of capital is transferred directly from the Bonds portfolio to the Real Estate portfolio while the capital in Stocks remains unchanged, resulting in a new ratio of Real Estate to Stocks of 5:45 : 4. Subsequently, an additional $60,000\$60,000 in external capital is deposited into the Bonds portfolio, making the ratio of Stocks to Bonds 2:32 : 3. What was the total initial capital in the fund across all three portfolios?

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Cevap: $240,000

Cevap

The total initial capital in the fund was $240,000.
The correct answer of 240,000isobtainedbytrackingeachportfoliosbalanceacrossthetwosequentialchanges.Initially,RealEstate,Stocks,andBondsare240,000 is obtained by tracking each portfolio's balance across the two sequential changes. Initially, Real Estate, Stocks, and Bonds are 3x ,, 4x ,and, and 5x respectively(total respectively (total 12x ).WhenRealEstateincreasesto). When Real Estate increases to 5x relativetoStocks( relative to Stocks ( 4x ),therequiredcapitalcomesentirelyfromBonds,reducingBondsfrom), the required capital comes entirely from Bonds, reducing Bonds from 5x to to 3x .Adding. Adding \60,00060,000 to Bonds gives a new balance of 3x+60,0003x + 60,000. Establishing the new Stocks to Bonds ratio 4x3x+60,000=23\frac{4x}{3x + 60,000} = \frac{2}{3} yields x=20,000x = 20,000. Multiplying by the initial total of 12 parts yields 12×20,000=12 \times 20,000 = 240,000$.

Adım Adım Çözüm

1
Express initial portfolio amounts in terms of a multiplier xx
Real Estate = 3x3x, Stocks = 4x4x, Bonds = 5x5x. Total initial capital = 3x+4x+5x=12x3x + 4x + 5x = 12x.
The given initial ratio of Real Estate : Stocks : Bonds is 3:4:53 : 4 : 5.
2
Account for the internal capital transfer between Bonds and Real Estate
Real Estate becomes 5x5x, Stocks remains 4x4x, and Bonds becomes 3x3x.
Stocks remains 4x4x. Since the ratio of Real Estate to Stocks becomes 5:45 : 4, Real Estate must equal 5x5x. Because capital was only moved internally from Bonds to Real Estate, the sum of Real Estate and Bonds remains 3x+5x=8x3x + 5x = 8x, leaving Bonds with 8x5x=3x8x - 5x = 3x.
3
Set up an algebraic proportion after adding $60,000\$60,000 to Bonds
4x3x+60,000=23\frac{4x}{3x + 60,000} = \frac{2}{3}
The new ratio of Stocks to Bonds is given as 2:32 : 3.
4
Solve for the multiplier xx and determine the total initial capital
3(4x)=2(3x+60,000)12x=6x+120,0006x=120,000x=20,0003(4x) = 2(3x + 60,000) \Rightarrow 12x = 6x + 120,000 \Rightarrow 6x = 120,000 \Rightarrow x = 20,000. Total initial capital =12x=12×20,000== 12x = 12 \times 20,000 = 240,000$.
Cross-multiplying yields the value of xx, which is then scaled by the total initial ratio sum of 12 parts.

Anahtar Kavram

Multi-Step Ratio Adjustments and Internal vs. External Capital Changes
Tahmini Süre:2m 0s
Soru 51Soru

Printer Alpha can fabricate a set of architectural prototypes in 44 hours operating alone at a constant rate. Printer Beta can fabricate the exact same set of prototypes in 1212 hours operating alone at a constant rate. If both printers operate simultaneously at their respective constant rates, how many hours will it take them to fabricate one set of architectural prototypes?

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Cevap: 33 hours

Cevap

33 hours
The correct answer is 33 hours. The rate of Printer Alpha is 14\frac{1}{4} of the prototype set per hour, and the rate of Printer Beta is 112\frac{1}{12} of the set per hour. Their combined rate when operating simultaneously is 14+112=412=13\frac{1}{4} + \frac{1}{12} = \frac{4}{12} = \frac{1}{3} set per hour. Therefore, the time required to complete 11 set working together is 113=3\frac{1}{\frac{1}{3}} = 3 hours.

Adım Adım Çözüm

1
Determine the individual work rate for Printer Alpha.
Printer Alpha completes 14\frac{1}{4} of the job per hour.
Work rate is defined as job completed divided by time taken.
2
Determine the individual work rate for Printer Beta.
Printer Beta completes 112\frac{1}{12} of the job per hour.
Work rate is defined as job completed divided by time taken.
3
Add the individual rates to find the combined work rate.
Combined rate = 14+112=312+112=412=13\frac{1}{4} + \frac{1}{12} = \frac{3}{12} + \frac{1}{12} = \frac{4}{12} = \frac{1}{3} of the job per hour.
When entities work together, their individual rates add up.
4
Calculate the total time required for the combined rate to complete 1 job.
Time = 1Combined Rate=113=3\frac{1}{\text{Combined Rate}} = \frac{1}{\frac{1}{3}} = 3 hours.
Time is the reciprocal of the combined rate.

Anahtar Kavram

Combined Work Rate
Tahmini Süre:45s
Soru 52Soru

Data Pipeline A can process a standard batch of records in 1212 hours, while Data Pipeline B can process the same batch of records in 1818 hours. Data Pipeline A begins processing a batch alone and operates for 44 hours before Data Pipeline B is brought online to assist. Both pipelines then continue processing together at their respective constant rates until the batch is completely processed. What is the total time, in hours, required to process the entire batch of records from start to finish?

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Cevap: 8.88.8

Cevap

8.88.8 hours (or 8458\frac{4}{5} hours)
The rate of Pipeline A is 112\frac{1}{12} per hour, so in 44 hours it completes 4×112=134 \times \frac{1}{12} = \frac{1}{3} of the job. The remaining 23\frac{2}{3} of the job is completed by both pipelines working together. Their combined rate is 112+118=536\frac{1}{12} + \frac{1}{18} = \frac{5}{36} per hour. The time required for the joint phase is 2/35/36=4.8\frac{2/3}{5/36} = 4.8 hours. Adding the initial 44 hours gives a total time of 8.88.8 hours.

Adım Adım Çözüm

1
Calculate the work completed by Data Pipeline A alone during the first 44 hours.
Pipeline A's rate is 112\frac{1}{12} batch/hour. Work done in 44 hours = 4×112=134 \times \frac{1}{12} = \frac{1}{3} of the batch.
Determining the completed portion establishes how much work remains for the combined phase.
2
Determine the remaining fraction of work to be done.
Remaining work = 113=231 - \frac{1}{3} = \frac{2}{3} of the batch.
The combined pipelines only need to finish the remaining portion of the job.
3
Calculate the combined processing rate of both pipelines.
Combined rate = 112+118=336+236=536\frac{1}{12} + \frac{1}{18} = \frac{3}{36} + \frac{2}{36} = \frac{5}{36} batch/hour.
Rates add when entities work simultaneously on the same task.
4
Calculate the time required for both pipelines to finish the remaining work together.
Joint time = Remaining WorkCombined Rate=2/35/36=23×365=245=4.8\frac{\text{Remaining Work}}{\text{Combined Rate}} = \frac{2/3}{5/36} = \frac{2}{3} \times \frac{36}{5} = \frac{24}{5} = 4.8 hours.
Dividing remaining work by the combined rate gives the duration of the second phase.
5
Calculate total time from start to finish.
Total time = 4 hours (phase 1)+4.8 hours (phase 2)=8.84 \text{ hours (phase 1)} + 4.8 \text{ hours (phase 2)} = 8.8 hours.
Summing both phase durations gives the total time required for the entire process.

Anahtar Kavram

Work Rate and Combined Work
Tahmini Süre:2m 0s
Soru 53Soru

At a software company, the ratio of senior developers to junior developers was initially 3:73 : 7. During a quarterly hiring push, 1212 senior developers and 1818 junior developers were hired, but 66 junior developers resigned shortly thereafter. As a result, the ratio of senior developers to junior developers became 4:94 : 9. If a certain number NN of senior developers were subsequently promoted out of the developer pool such that the ratio of senior developers to junior developers became 5:125 : 12, what is the value of NN?

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Cevap: 12

Cevap

The value of NN is 1212.
By defining the initial counts as 3x3x and 7x7x, accounting for the net additions (+12+12 seniors and +12+12 juniors), and solving 3x+127x+12=49\frac{3x+12}{7x+12} = \frac{4}{9}, we find x=60x = 60. Thus, there are 192192 senior developers and 432432 junior developers after hiring. Setting the final ratio 192N432=512\frac{192-N}{432} = \frac{5}{12} gives 192N=180192 - N = 180, which yields N=12N = 12.

Adım Adım Çözüm

1
Define initial quantities using a common multiplier xx.
Initial senior developers = 3x3x, Initial junior developers = 7x7x.
The given initial ratio of senior to junior developers is 3:73 : 7.
2
Account for changes in staffing and set up the equation for the new ratio.
Senior developers after hiring = 3x+123x + 12; Net junior developer change = +186=+12+18 - 6 = +12, so Junior developers after hiring = 7x+127x + 12. Equation: 3x+127x+12=49\frac{3x + 12}{7x + 12} = \frac{4}{9}.
12 seniors were added, while 18 juniors were hired and 6 resigned.
3
Solve for the multiplier xx.
9(3x+12)=4(7x+12)    27x+108=28x+48    x=609(3x + 12) = 4(7x + 12) \implies 27x + 108 = 28x + 48 \implies x = 60.
Cross-multiplication yields the value of the algebraic multiplier xx.
4
Calculate post-hiring developer counts.
Senior developers post-hiring = 3(60)+12=1923(60) + 12 = 192; Junior developers post-hiring = 7(60)+12=4327(60) + 12 = 432.
Substitute x=60x = 60 back into the expressions for post-hiring developer counts.
5
Determine NN using the final ratio 5:125 : 12.
192N432=512    192N=5×36=180    N=192180=12\frac{192 - N}{432} = \frac{5}{12} \implies 192 - N = 5 \times 36 = 180 \implies N = 192 - 180 = 12.
Junior developer count remains unchanged (432432) while senior developer count decreases by NN.

Anahtar Kavram

Multi-step algebraic ratio setup and alteration of part-to-part proportions
Soru 54Soru

Scanner X can scan a batch of archival documents in 66 hours operating alone at a constant rate. Scanner Y can scan the exact same batch of documents in 33 hours operating alone at a constant rate. Working together simultaneously at their respective constant rates, how many hours will it take Scanner X and Scanner Y to scan the entire batch of documents?

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Cevap: 2

Cevap

It will take Scanner X and Scanner Y a total of 22 hours to scan the batch of documents together.
To calculate combined completion time, add the rates of each machine rather than their completion times. Scanner X completes 16\frac{1}{6} of the task per hour, and Scanner Y completes 13\frac{1}{3} (or 26\frac{2}{6}) of the task per hour. Together, they complete 16+26=36=12\frac{1}{6} + \frac{2}{6} = \frac{3}{6} = \frac{1}{2} of the task per hour. The inverse of this rate gives the total time required: 22 hours.

Adım Adım Çözüm

1
Calculate individual work rates per hour.
Scanner X rate = 16\frac{1}{6} batch/hour, Scanner Y rate = 13\frac{1}{3} batch/hour.
Work rate is defined as Rate=WorkTime\text{Rate} = \frac{\text{Work}}{\text{Time}}.
2
Add the individual rates together to find the total combined rate.
Combined rate = 16+13=36=12\frac{1}{6} + \frac{1}{3} = \frac{3}{6} = \frac{1}{2} batch/hour.
When entities work together simultaneously, their work rates are additive.
3
Compute total time taken for 1 whole batch.
Total Time = 22 hours.
Time is the reciprocal of the combined work rate: Time=1Combined Rate\text{Time} = \frac{1}{\text{Combined Rate}}.

Anahtar Kavram

Combined Work Rate
Tahmini Süre:45s
Soru 55Soru

Three automated data-processing pipelines, AA, BB, and CC, process incoming dataset files at constant individual rates. Pipeline AA operating alone can complete a standard processing job in 1010 hours, while Pipeline BB operating alone can complete the same job in 1515 hours.

The processing begins with Pipelines AA and BB working together at their standard rates for 22 hours. At that point, Pipeline AA encounters a network slowdown that reduces its processing rate by 50%50\% for the remainder of the job. Pipelines AA and BB continue working at these modified rates for another 22 hours, after which Pipeline CC is brought online to assist them. If Pipeline CC operating alone at its constant rate could finish the entire job in 1010 hours, how many total hours from the start of the processing will it take for the job to be completed?

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Cevap: 6

Cevap

The total time required to complete the job is 6 hours.
To solve multi-stage work rate problems, determine the rate per unit of time for each participant, multiply by the duration of each operational phase, and track the remaining fraction of the job. In the first 2 hours, Pipelines AA and BB complete 13\frac{1}{3} of the job. In the next 2 hours with Pipeline AA at half speed (rate 120\frac{1}{20}), they complete an additional 730\frac{7}{30} of the job, leaving 1330\frac{13}{30} unfinished. When Pipeline CC (rate 110\frac{1}{10}) joins, the combined rate becomes 1360\frac{13}{60} per hour, taking exactly 2 more hours to complete the remaining 1330\frac{13}{30} of the job. Adding all three intervals (2+2+22 + 2 + 2) yields a total time of 6 hours.

Adım Adım Çözüm

1
Determine the individual hourly work rates for each pipeline
Rate of Pipeline A=110A = \frac{1}{10} job/hr, Rate of Pipeline B=115B = \frac{1}{15} job/hr, Rate of Pipeline C=110C = \frac{1}{10} job/hr.
Work rate is the reciprocal of the total time taken to complete one full job.
2
Calculate work completed during Stage 1 (first 2 hours)
Combined rate = 110+115=16\frac{1}{10} + \frac{1}{15} = \frac{1}{6} job/hr. Work done = 2×16=132 \times \frac{1}{6} = \frac{1}{3} of the job.
Both Pipeline AA and Pipeline BB operate together at their standard rates for 2 hours.
3
Calculate work completed during Stage 2 (next 2 hours)
Modified rate of Pipeline A=0.50×110=120A = 0.50 \times \frac{1}{10} = \frac{1}{20} job/hr. Combined rate = 120+115=760\frac{1}{20} + \frac{1}{15} = \frac{7}{60} job/hr. Work done = 2×760=7302 \times \frac{7}{60} = \frac{7}{30} of the job.
Pipeline AA's efficiency drops by 50%, while Pipeline BB remains unchanged.
4
Calculate the remaining work after 4 hours
Total work completed = 13+730=1730\frac{1}{3} + \frac{7}{30} = \frac{17}{30}. Remaining work = 11730=13301 - \frac{17}{30} = \frac{13}{30}.
Subtracting cumulative work done from the total job (1) leaves the remaining portion.
5
Calculate the duration of Stage 3 when Pipeline CC joins
Combined rate = 120+115+110=1360\frac{1}{20} + \frac{1}{15} + \frac{1}{10} = \frac{13}{60} job/hr. Time required = 13/3013/60=2\frac{13/30}{13/60} = 2 hours.
Dividing remaining work by the combined rate of all three active pipelines gives the remaining time.
6
Sum the durations of all stages to find total elapsed time
Total time = 2 hours+2 hours+2 hours=6 hours2\text{ hours} + 2\text{ hours} + 2\text{ hours} = 6\text{ hours}.
The question asks for total elapsed time from the start of processing.

Anahtar Kavram

Multi-stage combined work rate problems require tracking accumulated work completed across distinct intervals with changing worker rates.
Soru 56Soru

Pumps X, Y, and Z, operating simultaneously at their respective constant rates, can fill an empty reservoir in 44 hours. Operating alone at its constant rate, Pump X can fill 15\frac{1}{5} of the reservoir in 22 hours. The rate at which Pump Y fills the reservoir is 50%50\% greater than the rate at which Pump Z fills the reservoir. If Pump X and Pump Z work together for 33 hours, and then Pump Y is turned on so that all three pumps work together until the reservoir is full, how many additional hours will it take to finish filling the remainder of the reservoir?

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Cevap: 22252 \frac{2}{25} hours

Cevap

22252 \frac{2}{25} hours
The rate of Pump X is 110\frac{1}{10} reservoir/hour, and the combined rate of all three pumps is 14\frac{1}{4} reservoir/hour. Thus, the combined rate of Pumps Y and Z is 14110=320\frac{1}{4} - \frac{1}{10} = \frac{3}{20} reservoir/hour. Given ry=1.5rzr_y = 1.5 r_z, setting 52rz=320\frac{5}{2} r_z = \frac{3}{20} yields rz=350r_z = \frac{3}{50} and ry=9100r_y = \frac{9}{100}. The combined rate of Pumps X and Z is 110+350=425\frac{1}{10} + \frac{3}{50} = \frac{4}{25}. In 33 hours, Pumps X and Z complete 3×425=12253 \times \frac{4}{25} = \frac{12}{25} of the reservoir, leaving 1325\frac{13}{25} un-filled. When all three pumps operate, their combined rate is 14\frac{1}{4}. The additional time required is 13/251/4=5225=2225\frac{13/25}{1/4} = \frac{52}{25} = 2 \frac{2}{25} hours.

Adım Adım Çözüm

1
Determine the individual rate of Pump X and the total combined rate of all three pumps.
Pump X's rate rx=1/52=110r_x = \frac{1/5}{2} = \frac{1}{10} of the reservoir per hour. The total combined rate of Pumps X, Y, and Z is rx+ry+rz=14r_x + r_y + r_z = \frac{1}{4} of the reservoir per hour.
Work rate is equal to work completed divided by time elapsed.
2
Determine the individual work rates of Pump Y and Pump Z.
The combined rate of Y and Z is ry+rz=14110=320r_y + r_z = \frac{1}{4} - \frac{1}{10} = \frac{3}{20}. Since ry=1.5rz=32rzr_y = 1.5 r_z = \frac{3}{2} r_z, we have 52rz=320\frac{5}{2} r_z = \frac{3}{20}, which gives rz=350r_z = \frac{3}{50} and ry=9100r_y = \frac{9}{100}.
Use the given relationship between the rates of Pump Y and Pump Z to solve for their individual values.
3
Calculate the work completed during the first 3 hours by Pumps X and Z working together, and find the remaining work.
The combined rate of X and Z is rx+rz=110+350=850=425r_x + r_z = \frac{1}{10} + \frac{3}{50} = \frac{8}{50} = \frac{4}{25}. In 3 hours, they complete 3×425=12253 \times \frac{4}{25} = \frac{12}{25} of the reservoir. The remaining work is 11225=13251 - \frac{12}{25} = \frac{13}{25}.
Work done equals combined rate multiplied by time worked.
4
Calculate the additional time required for all three pumps working together to finish the remaining work.
Time t=Remaining WorkCombined Rate of X, Y, Z=13/251/4=5225=2225t = \frac{\text{Remaining Work}}{\text{Combined Rate of X, Y, Z}} = \frac{13/25}{1/4} = \frac{52}{25} = 2 \frac{2}{25} hours.
Time needed is remaining work divided by the total combined rate of all active pumps.

Anahtar Kavram

Work Rate and Combined Work
Tahmini Süre:2m 30s
Soru 57Soru

A beverage recipe requires mixing orange juice and cranberry juice in a ratio of 4:14 : 1. If a caterer uses 1212 liters of orange juice, how many liters of cranberry juice must be added to maintain this ratio?

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Cevap: 3

Cevap

The caterer must add 3 liters of cranberry juice.
The ratio of orange juice to cranberry juice is 4:14:1. Since 1212 liters of orange juice represents 44 parts, each part equals 124=3\frac{12}{4} = 3 liters. Therefore, 11 part of cranberry juice equals 33 liters.

Adım Adım Çözüm

1
Set up the ratio equation based on the recipe requirements.
Orange Juice : Cranberry Juice = 4:14 : 1
The problem states that for every 4 parts of orange juice, 1 part of cranberry juice is required.
2
Calculate the unknown amount of cranberry juice using the given quantity of orange juice.
Cranberry Juice = 124=3\frac{12}{4} = 3 liters
Since 12 liters represents 4 equal parts, dividing 12 by 4 yields the size of 1 part.

Anahtar Kavram

Direct Ratio and Proportion Scaling
Soru 58Soru

A corporate marketing team initially allocates its quarterly budget among Digital, Print, and Event advertising in the ratio 5:3:25 : 3 : 2, respectively. Midway through the quarter, $12,000\$12,000 is reallocated from Digital advertising to Event advertising, while the Print advertising budget remains unchanged. As a result of this transfer, the ratio of the Digital advertising budget to the Event advertising budget becomes 4:34 : 3. What was the total initial quarterly budget, in dollars, allocated across all three advertising categories?

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Cevap: 120000

Cevap

The total initial quarterly budget allocated across all three categories was 120,000 dollars.
By representing the initial amounts as 5x5x, 3x3x, and 2x2x, the total initial budget is 10x10x. Accounting for the $12,000\$12,000 shift gives 5x12,0002x+12,000=43\frac{5x - 12,000}{2x + 12,000} = \frac{4}{3}. Solving yields x=12,000x = 12,000, which gives a total initial budget of 10×12,000=120,00010 \times 12,000 = 120,000 dollars.

Adım Adım Çözüm

1
Define initial allocations using a multiplier variable
Digital = 5x5x, Print = 3x3x, Event = 2x2x, Total Initial Budget = 10x10x
Representing ratio components algebraically allows set up of linear equations.
2
Adjust allocations according to the budget transfer
New Digital = 5x12,0005x - 12,000, New Event = 2x+12,0002x + 12,000
Reallocating $12,000\$12,000 reduces Digital by 12,000 and increases Event by 12,000.
3
Set up and solve the ratio equation for xx
5x12,0002x+12,000=4315x36,000=8x+48,0007x=84,000x=12,000\frac{5x - 12,000}{2x + 12,000} = \frac{4}{3} \Rightarrow 15x - 36,000 = 8x + 48,000 \Rightarrow 7x = 84,000 \Rightarrow x = 12,000
Equating the altered ratio of Digital to Event to 4/34/3 allows solving for multiplier xx.
4
Compute the total initial budget
Total = 10×12,000=120,00010 \times 12,000 = 120,000
Substituting x=12,000x = 12,000 back into the total initial expression 10x10x gives the final answer.

Anahtar Kavram

Altering non-isolated ratios through part-to-part modifications
Soru 59Soru

At a bio-tech research facility, the ratio of male to female scientists is initially 5:35 : 3. After 44 female scientists leave and 1212 male scientists join the facility, the ratio of male to female scientists becomes 4:14 : 1. If a group of NN additional female scientists subsequently joins the facility, changing the ratio of male to female scientists to 8:58 : 5, what is the value of NN?

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Cevap: 12

Cevap

The value of NN is 12.
By setting up ratio equations stage-by-stage using multiplier kk, we determine that k=4k = 4, yielding 32 male and 8 female scientists after the first change. Solving 328+N=85\frac{32}{8+N} = \frac{8}{5} yields N=12N = 12.

Adım Adım Çözüm

1
Define initial variables using a common ratio multiplier kk.
Male scientists = 5k5k, Female scientists = 3k3k.
Ratios preserve proportionality through a constant multiplier.
2
Formulate and solve the equation for the first population adjustment.
5k+123k4=4    5k+12=12k16    7k=28    k=4\frac{5k + 12}{3k - 4} = 4 \implies 5k + 12 = 12k - 16 \implies 7k = 28 \implies k = 4.
Adding 12 males and removing 4 females sets the new ratio to 4:14 : 1.
3
Determine the exact number of male and female scientists at the facility after the first adjustment.
Male scientists = 5(4)+12=325(4) + 12 = 32; Female scientists = 3(4)4=83(4) - 4 = 8.
Substitute k=4k = 4 back into the adjusted quantity expressions.
4
Formulate and solve the equation for the second population adjustment involving NN.
328+N=85    8(8+N)=160    64+8N=160    8N=96    N=12\frac{32}{8 + N} = \frac{8}{5} \implies 8(8 + N) = 160 \implies 64 + 8N = 160 \implies 8N = 96 \implies N = 12.
The number of male scientists remains 32 while female scientists increase by NN to achieve an 8:58 : 5 ratio.

Anahtar Kavram

Multi-step ratio manipulation and algebraic modeling
Tahmini Süre:2m 0s
Soru 60Soru

A commercial bakery has two industrial ovens, Oven A and Oven B. Working alone at its constant rate, Oven A can bake a full order of 1,8001,800 pastries in 66 hours. Working alone at its constant rate, Oven B can bake the same order in 99 hours. If Oven A begins baking the order alone and is joined by Oven B after 22 hours, how many total hours will it take from the time Oven A starts until the full order of 1,8001,800 pastries is baked?

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Cevap: 4.4

Cevap

The total time required to complete the entire order of pastries is 4.4 hours.
The total time of 4.4 hours is derived by determining Oven A's rate (1/6 job/hour) and Oven B's rate (1/9 job/hour). In the first 2 hours, Oven A completes 1/3 of the job, leaving 2/3. Operating together, their combined rate is 5/18 job/hour, which finishes the remaining 2/3 of the job in 2.4 hours. Summing 2 hours and 2.4 hours yields 4.4 total hours.

Adım Adım Çözüm

1
Determine the individual work rates per hour.
Oven A completes 16\frac{1}{6} of the job per hour; Oven B completes 19\frac{1}{9} of the job per hour.
Work rate is the reciprocal of the total time needed to complete one full job.
2
Calculate the fraction of work completed during the first 2 hours by Oven A.
Oven A completes 2×16=132 \times \frac{1}{6} = \frac{1}{3} of the total job.
Work done equals rate multiplied by time spent working.
3
Find the remaining fraction of work to be done.
Remaining work is 113=231 - \frac{1}{3} = \frac{2}{3} of the job.
Subtract the completed fraction from 1 (the whole job).
4
Calculate the combined rate of Oven A and Oven B working together.
Combined rate is 16+19=318+218=518\frac{1}{6} + \frac{1}{9} = \frac{3}{18} + \frac{2}{18} = \frac{5}{18} job per hour.
When entities work together, their individual rates add up.
5
Calculate the time spent by both ovens working together to complete the remaining work.
Time together is 2/35/18=125=2.4\frac{2/3}{5/18} = \frac{12}{5} = 2.4 hours.
Time equals remaining work divided by the combined rate.
6
Calculate total time from the start.
Total time = 2+2.4=4.42 + 2.4 = 4.4 hours.
Add the initial single-agent work duration to the combined work duration.

Anahtar Kavram

Work Rate and Combined Work
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Word Problems and Applied Math Alıştırma Soruları — GMAT — Sayfa 3 | Examkin