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Zorluk: KolaySimplifying and Factoring Algebraic Expressions

For all real numbers aa and bb, which of the following expressions are equivalent to (a+b)2(ab)2(a + b)^2 - (a - b)^2? Select all that apply.

  1. 4ab4abCevap
  2. (2a)(2b)(2a)(2b)Cevap
  3. C
    00
  4. D
    2a2+2b22a^2 + 2b^2
  5. E
    2ab2ab

Cevap

The expressions 4ab4ab and (2a)(2b)(2a)(2b) are equivalent to (a+b)2(ab)2(a + b)^2 - (a - b)^2.
Expanding the squared expressions gives (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2 and (ab)2=a22ab+b2(a-b)^2 = a^2 - 2ab + b^2. Subtracting the second expression from the first yields (a2+2ab+b2)(a22ab+b2)=4ab(a^2 + 2ab + b^2) - (a^2 - 2ab + b^2) = 4ab. Since (2a)(2b)(2a)(2b) also equals 4ab4ab, both 4ab4ab and (2a)(2b)(2a)(2b) are mathematically equivalent to the original expression.

Adım Adım Çözüm

1
Expand (a+b)2(a + b)^2 using the binomial square formula.
(a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2
Squaring a sum produces a trinomial containing two squared terms and a middle product term.
2
Expand (ab)2(a - b)^2 using the binomial square formula.
(ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2
Squaring a difference produces a trinomial with a negative middle product term.
3
Subtract the second expanded trinomial from the first.
(a2+2ab+b2)(a22ab+b2)=a2a2+2ab+2ab+b2b2=4ab(a^2 + 2ab + b^2) - (a^2 - 2ab + b^2) = a^2 - a^2 + 2ab + 2ab + b^2 - b^2 = 4ab
Distributing the negative sign across (a22ab+b2)(a^2 - 2ab + b^2) changes the signs inside the second set of parentheses.
4
Compare the simplified result 4ab4ab against all given choices.
Both 4ab4ab and (2a)(2b)=4ab(2a)(2b) = 4ab are identical to the calculated result.
Algebraic multiplication shows (2a)(2b)=4ab(2a)(2b) = 4ab.

Anahtar Kavram

Binomial expansion and combination of like terms
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