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Zorluk: OrtaSystems of Linear Equations

If the pair (x,y)(x, y) satisfies the system of linear equations below, what is the value of x−yx - y?

3x−5y=142x+7y=−1\begin{aligned} 3x - 5y &= 14 \\ 2x + 7y &= -1 \end{aligned}
  1. A
    -1
  2. B
    2
  3. C
    3
  4. 4Cevap
  5. E
    5

Cevap

The value of x−yx - y is 44.
Solving the system of linear equations by elimination gives x=3x = 3 and y=−1y = -1. Substituting these values into the target expression x−yx - y yields 3−(−1)=3+1=43 - (-1) = 3 + 1 = 4.

Adım Adım Çözüm

1
Eliminate one variable using the elimination method.
Multiply the first equation by 22 and the second equation by 33:
6x−10y=286x - 10y = 28
6x+21y=−36x + 21y = -3
Creating matching coefficients for xx allows elimination of xx by subtraction.
2
Subtract the first modified equation from the second modified equation to solve for yy.
(6x+21y)−(6x−10y)=−3−28(6x + 21y) - (6x - 10y) = -3 - 28
31y=−31  ⟹  y=−131y = -31 \implies y = -1
Subtracting eliminates xx, isolating yy.
3
Substitute y=−1y = -1 back into one of the original equations to solve for xx.
3x−5(−1)=14  ⟹  3x+5=14  ⟹  3x=9  ⟹  x=33x - 5(-1) = 14 \implies 3x + 5 = 14 \implies 3x = 9 \implies x = 3
Plugging in yy allows direct solution for xx.
4
Evaluate the requested expression x−yx - y.
x−y=3−(−1)=3+1=4x - y = 3 - (-1) = 3 + 1 = 4
Subtracting a negative value is equivalent to adding its positive value.

Anahtar Kavram

Solving systems of linear equations using elimination and evaluating algebraic expressions.
Tahmini Süre:1m 30s
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