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Zorluk: ZorSystems of Linear Equations
Consider the following system of linear equations in variables xx and yy, where kk is a real constant:
kx+4y=8x+ky=k+2\begin{aligned} kx + 4y &= 8 \\ x + ky &= k + 2 \end{aligned}
Which of the following statements are true? Select all that apply.
  1. If k=2k = 2, the system has infinitely many solutions.Cevap
  2. If k=2k = -2, the system has no solutions.Cevap
  3. If k=0k = 0, the unique solution to the system is (x,y)=(2,2)(x, y) = (2, 2).Cevap
  4. D
    If k=3k = 3, the system has no solutions.
  5. E
    If k=1k = 1, the solution to the system satisfies x+y=4x + y = 4.

Cevap

The correct statements are that setting k=2k = 2 results in infinitely many solutions, setting k=2k = -2 results in no solutions, and setting k=0k = 0 yields the unique solution (2,2)(2, 2).
The system has a coefficient matrix determinant of k24k^2 - 4. Setting k=2k = 2 produces identical equations (x+2y=4x + 2y = 4), giving infinitely many solutions. Setting k=2k = -2 produces parallel equations with different constants (x+2y=4-x + 2y = 4 vs x+2y=0-x + 2y = 0), giving no solutions. Setting k=0k = 0 reduces the system directly to y=2y = 2 and x=2x = 2, confirming the unique point (2,2)(2, 2).

Adım Adım Çözüm

1
Analyze the determinant of the coefficient matrix to identify conditions for unique vs. non-unique solutions.
The coefficient matrix determinant is Δ=kk41=k24=(k2)(k+2)\Delta = k\cdot k - 4\cdot 1 = k^2 - 4 = (k - 2)(k + 2).
If Δ0\Delta \neq 0 (i.e., k±2k \neq \pm 2), the system has a unique solution. If Δ=0\Delta = 0 (i.e., k=2k = 2 or k=2k = -2), the lines are either identical or parallel.
2
Test k=2k = 2 in the system.
Equation 1 becomes 2x+4y=8    x+2y=42x + 4y = 8 \implies x + 2y = 4. Equation 2 becomes x+2y=4x + 2y = 4.
Since the equations are identical, the lines coincide, resulting in infinitely many solutions.
3
Test k=2k = -2 in the system.
Equation 1 becomes 2x+4y=8    x+2y=4-2x + 4y = 8 \implies -x + 2y = 4. Equation 2 becomes x2y=0    x+2y=0x - 2y = 0 \implies -x + 2y = 0.
The slopes are equal (1/21/2) but the y-intercepts differ (22 vs 00), meaning the lines are parallel and distinct, yielding zero solutions.
4
Test k=0k = 0 and k=1k = 1 to evaluate remaining choices.
For k=0k = 0, 4y=8    y=24y = 8 \implies y = 2 and x+0=2    x=2x + 0 = 2 \implies x = 2, giving (2,2)(2, 2). For k=1k = 1, Equation 2 is directly x+y=3x + y = 3.
This verifies that the statement for k=0k = 0 is correct, while the statement for k=1k = 1 claiming x+y=4x + y = 4 is false.

Anahtar Kavram

Parametric Linear Systems and Conditions for Solvability
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