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Zorluk: KolayProperties of Integers and Divisibility

If nn is an integer that is divisible by 1515, which of the following statements MUST also be true? Select all such statements.

  1. nn is divisible by 33Cevap
  2. nn is divisible by 55Cevap
  3. n+15n + 15 is divisible by 1515Cevap
  4. D
    nn is divisible by 3030
  5. E
    nn is an even integer

Cevap

The statements asserting that nn is divisible by 33, nn is divisible by 55, and n+15n + 15 is divisible by 1515 must all be true.
Any integer divisible by 1515 must be divisible by all factors of 1515, which includes 33 and 55. Furthermore, adding 1515 to a multiple of 1515 yields another multiple of 1515, so n+15n + 15 is also divisible by 1515.

Adım Adım Çözüm

1
Analyze the prime factor decomposition of the divisor
The prime factorization of 1515 is 3×53 \times 5. Therefore, any integer nn that is a multiple of 1515 can be expressed as n=15k=3×5×kn = 15k = 3 \times 5 \times k for some integer kk.
Understanding factor relationships allows evaluation of divisibility rules.
2
Evaluate divisibility of nn by 33 and 55
Since n=3(5k)n = 3(5k), nn is divisible by 33. Since n=5(3k)n = 5(3k), nn is divisible by 55. Both statements are always true.
Any multiple of a composite number is also a multiple of that number's factors.
3
Evaluate the expression n+15n + 15
n+15=15k+15=15(k+1)n + 15 = 15k + 15 = 15(k + 1). Since k+1k + 1 is an integer, n+15n + 15 is a multiple of 1515. This statement is always true.
Adding a multiple of 1515 to another multiple of 1515 yields a multiple of 1515.
4
Test counterexamples for remaining statements
For n=15n = 15: 1515 is not divisible by 3030, so divisibility by 3030 is not guaranteed. Additionally, 1515 is odd, so being an even integer is not guaranteed.
A statement must hold for all possible values of nn to be necessarily true.

Anahtar Kavram

Divisibility by a composite number implies divisibility by all of its factors, and multiples of a number remain multiples when another multiple of that number is added.
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