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Zorluk: Çok zorProperties of Integers and Divisibility

How many positive integers nn less than 3030 satisfy the condition that n21n^2 - 1 is divisible by 2424?

  1. A
    5
  2. B
    8
  3. C
    9
  4. 10Cevap
  5. E
    15

Cevap

10
For n21n^2 - 1 to be divisible by 24=8×324 = 8 \times 3, nn must be an odd integer that is not divisible by 3, which means gcd(n,6)=1\gcd(n, 6) = 1. The positive integers less than 30 coprime to 6 are 1, 5, 7, 11, 13, 17, 19, 23, 25, and 29, totaling 10 integers.

Adım Adım Çözüm

1
Factor the expression and analyze divisibility requirements for 24.
n21=(n1)(n+1)n^2 - 1 = (n - 1)(n + 1). Since 24=8×324 = 8 \times 3 with gcd(8,3)=1\gcd(8, 3) = 1, n21n^2 - 1 must be divisible by both 88 and 33.
Decompose 24 into coprime prime-power factors to evaluate modular conditions independently.
2
Determine the condition for n21n^2 - 1 to be divisible by 8.
If nn is even, n21n^2 - 1 is odd and cannot be divisible by 8. If nn is odd, let n=2k+1n = 2k + 1; then n21=4k(k+1)n^2 - 1 = 4k(k + 1). Since one of kk or k+1k + 1 is always even, 4k(k+1)4k(k + 1) is divisible by 8. Thus, nn must be odd.
Analyze parity requirements for the power of 2.
3
Determine the condition for n21n^2 - 1 to be divisible by 3.
If nn is a multiple of 3, n211(mod3)n^2 - 1 \equiv -1 \pmod 3, which is not divisible by 3. If nn is not a multiple of 3, n1n \equiv 1 or 2(mod3)2 \pmod 3, so n21(mod3)n^2 \equiv 1 \pmod 3 and n21n^2 - 1 is divisible by 3. Thus, nn cannot be a multiple of 3.
Analyze remainder properties modulo 3.
4
Combine the conditions and count valid positive integers n<30n < 30.
The combined requirement is gcd(n,6)=1\gcd(n, 6) = 1 (nn is odd and not a multiple of 3). The positive integers less than 30 satisfying this are 1, 5, 7, 11, 13, 17, 19, 23, 25, and 29. Counting these yields 10 integers.
Enumerate all integers meeting the coprime condition within the specified domain.

Anahtar Kavram

Modular arithmetic properties of quadratic expressions and coprimality constraints
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