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Zorluk: OrtaLinear Inequalities and Absolute Value

If xx and yy are real numbers that satisfy the absolute value inequalities ∣2x−6∣≤4|2x - 6| \le 4 and ∣y+3∣≤5|y + 3| \le 5, which of the following values could be equal to the product xyxy? Indicate all such values.

  1. A
    −45-45
  2. −35-35Cevap
  3. 00Cevap
  4. 88Cevap
  5. E
    1515

Cevap

The possible values for the product xyxy are −35-35, 00, and 88.
Solving ∣2x−6∣≤4|2x - 6| \le 4 yields 1≤x≤51 \le x \le 5, and solving ∣y+3∣≤5|y + 3| \le 5 yields −8≤y≤2-8 \le y \le 2. The product xyxy attains its minimum at 5×(−8)=−405 \times (-8) = -40 and its maximum at 5×2=105 \times 2 = 10. Since xyxy can take any value in the continuous interval [−40,10][-40, 10], the values −35-35, 00, and 88 are all valid choices.

Adım Adım Çözüm

1
Solve the inequality ∣2x−6∣≤4|2x - 6| \le 4 for xx.
−4≤2x−6≤4  ⟹  2≤2x≤10  ⟹  1≤x≤5-4 \le 2x - 6 \le 4 \implies 2 \le 2x \le 10 \implies 1 \le x \le 5.
Unfold the absolute value into a compound inequality to determine the valid range for xx.
2
Solve the inequality ∣y+3∣≤5|y + 3| \le 5 for yy.
−5≤y+3≤5  ⟹  −8≤y≤2-5 \le y + 3 \le 5 \implies -8 \le y \le 2.
Unfold the absolute value into a compound inequality to determine the valid range for yy.
3
Determine the minimum and maximum possible values of the product xyxy.
Evaluating the extreme product combinations of endpoints: 1×(−8)=−81 \times (-8) = -8, 1×2=21 \times 2 = 2, 5×(−8)=−405 \times (-8) = -40, and 5×2=105 \times 2 = 10. Thus, −40≤xy≤10-40 \le xy \le 10.
The continuous product of two real intervals [a,b][a, b] and [c,d][c, d] spans from the minimum endpoint product to the maximum endpoint product.
4
Select all options that fall within the interval [−40,10][-40, 10].
The values −35-35, 00, and 88 lie within [−40,10][-40, 10], while −45-45 and 1515 fall outside.
Any real number within the closed interval [−40,10][-40, 10] can be formed by valid choices of xx and yy.

Anahtar Kavram

Determining the range of a product from two independent absolute value inequalities.
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