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Zorluk: OrtaLinear Inequalities and Absolute Value

Which of the following values of xx satisfy the inequality ∣6−3x∣>9|6 - 3x| > 9? Select all that apply.

  1. −4-4Cevap
  2. −2-2Cevap
  3. C
    11
  4. D
    33
  5. 66Cevap

Cevap

The values −4-4, −2-2, and 66 satisfy the inequality ∣6−3x∣>9|6 - 3x| > 9.
The absolute value inequality ∣6−3x∣>9|6 - 3x| > 9 is equivalent to 6−3x>96 - 3x > 9 or 6−3x<−96 - 3x < -9. Solving these yields x<−1x < -1 or x>5x > 5. Among the given choices, −4-4, −2-2, and 66 fall within these solution ranges.

Adım Adım Çözüm

1
Set up the compound linear inequalities from the absolute value inequality ∣6−3x∣>9|6 - 3x| > 9.
6−3x>96 - 3x > 9 or 6−3x<−96 - 3x < -9
An absolute value inequality of the form ∣u∣>c|u| > c (where c>0c > 0) splits into u>cu > c or u<−cu < -c.
2
Solve the first inequality 6−3x>96 - 3x > 9.
−3x>3  ⟹  x<−1-3x > 3 \implies x < -1
Subtracting 66 gives −3x>3-3x > 3. Dividing both sides by −3-3 reverses the inequality sign to yield x<−1x < -1.
3
Solve the second inequality 6−3x<−96 - 3x < -9.
−3x<−15  ⟹  x>5-3x < -15 \implies x > 5
Subtracting 66 gives −3x<−15-3x < -15. Dividing both sides by −3-3 reverses the inequality sign to yield x>5x > 5.
4
Combine the solution sets and evaluate the given options.
The solution set consists of all real numbers where x<−1x < -1 or x>5x > 5. Therefore, −4-4, −2-2, and 66 are valid solutions.
Values −4-4 and −2-2 are strictly less than −1-1, while 66 is strictly greater than 55.

Anahtar Kavram

Solving absolute value inequalities and reversing inequality signs when multiplying or dividing by negative numbers.
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