Soru

Zorluk: OrtaLinear Inequalities and Absolute Value

If xx is an integer that satisfies the inequality ∣6−3x∣−4≤5|6 - 3x| - 4 \le 5, which of the following could be the value of xx? Select all such values.

  1. A
    −3-3
  2. −1-1Cevap
  3. 22Cevap
  4. 44Cevap
  5. E
    77

Cevap

The correct values of xx are −1-1, 22, and 44.
Isolating the absolute value yields ∣6−3x∣≤9|6 - 3x| \le 9, which expands to −9≤6−3x≤9-9 \le 6 - 3x \le 9. Subtracting 66 gives −15≤−3x≤3-15 \le -3x \le 3. Dividing by −3-3 and reversing the inequality signs results in −1≤x≤5-1 \le x \le 5. Among the given choices, −1-1, 22, and 44 lie within this solution interval [−1,5][-1, 5].

Adım Adım Çözüm

1
Isolate the absolute value expression
∣6−3x∣≤9|6 - 3x| \le 9
Add 44 to both sides of the inequality to isolate the absolute value term.
2
Rewrite as a compound inequality
−9≤6−3x≤9-9 \le 6 - 3x \le 9
The property ∣u∣≤a|u| \le a (where a≥0a \ge 0) expands to −a≤u≤a-a \le u \le a.
3
Subtract 6 from all parts
−15≤−3x≤3-15 \le -3x \le 3
Isolate the variable term −3x-3x by subtracting 66 across the compound inequality.
4
Divide by -3 and reverse inequality signs
5≥x≥−15 \ge x \ge -1, which is equivalent to −1≤x≤5-1 \le x \le 5
Dividing an inequality by a negative quantity requires flipping the inequality direction.

Anahtar Kavram

Solving absolute value inequalities of the form ∣ax+b∣≤c|ax + b| \le c by expanding into a compound inequality −c≤ax+b≤c-c \le ax + b \le c and correctly reversing inequality signs when multiplying or dividing by negative numbers.
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