Lines and Angles

13 soru

Soru 1Soru

In the plane, line L1L_1 is parallel to line L2L_2. A transversal line TT intersects L1L_1 and L2L_2. One of the acute angles formed at the intersection of L1L_1 and TT measures (4x10)(4x - 10)^\circ, and an alternate interior angle on L2L_2 measures (2x+30)(2x + 30)^\circ. What is the degree measure of one of the obtuse angles formed at the intersection of L1L_1 and TT?

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Cevap: 110110^\circ

Cevap

The degree measure of the obtuse angle is 110110^\circ.
Since lines L1L_1 and L2L_2 are parallel, alternate interior angles are equal in measure. Setting (4x10)=(2x+30)(4x - 10)^\circ = (2x + 30)^\circ gives 2x=402x = 40, so x=20x = 20. Substituting x=20x = 20 into 4x104x - 10 gives an acute angle of 7070^\circ. Because angles on a straight line are supplementary, the obtuse angle measures 18070=110180^\circ - 70^\circ = 110^\circ, which corresponds to the correct choice.

Adım Adım Çözüm

1
Set alternate interior angles equal to solve for xx.
4x10=2x+30    2x=40    x=204x - 10 = 2x + 30 \implies 2x = 40 \implies x = 20
When two parallel lines are cut by a transversal, alternate interior angles are congruent.
2
Substitute x=20x = 20 into the expression for the acute angle.
Acute angle =4(20)10=70= 4(20) - 10 = 70^\circ
This yields the degree measure of the acute angle formed by the intersection.
3
Calculate the measure of the supplementary obtuse angle.
Obtuse angle =18070=110= 180^\circ - 70^\circ = 110^\circ
Adjacent angles along a straight line are supplementary and sum to 180180^\circ.

Anahtar Kavram

Alternate Interior Angles and Supplementary Angles
Tahmini Süre:50s
Soru 2Soru

In the figure, line l1l_1 is parallel to line l2l_2. Point AA lies on line l1l_1, while points BB and CC lie on line l2l_2 such that BB is to the left of CC. Line segments ABAB and ACAC extend from line l1l_1 to line l2l_2 to form ABC\triangle ABC. The measure of interior angle BAC\angle BAC is (2x+10)(2x + 10)^\circ, the measure of interior angle ABC\angle ABC is (3x15)(3x - 15)^\circ, and the measure of the exterior angle at vertex CC along line l2l_2 is (6x35)(6x - 35)^\circ. What is the degree measure of angle BAC\angle BAC?

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Cevap: 7070^\circ

Cevap

The degree measure of angle BAC\angle BAC is 7070^\circ.
According to the Exterior Angle Theorem, the measure of an exterior angle of a triangle is equal to the sum of the measures of its two non-adjacent (remote) interior angles. Setting up the equation (2x+10)+(3x15)=6x35(2x + 10) + (3x - 15) = 6x - 35 gives 5x5=6x355x - 5 = 6x - 35, which simplifies to x=30x = 30. Substituting x=30x = 30 into the expression for BAC\angle BAC, (2x+10)(2x + 10)^\circ, yields 2(30)+10=702(30) + 10 = 70^\circ.

Adım Adım Çözüm

1
Apply the Exterior Angle Theorem to set up an algebraic equation.
(2x+10)+(3x15)=6x35(2x + 10) + (3x - 15) = 6x - 35
The measure of an exterior angle of a triangle equals the sum of the measures of its two remote interior angles.
2
Simplify and solve the linear equation for xx.
5x5=6x35    x=305x - 5 = 6x - 35 \implies x = 30
Combining like terms yields 5x5=6x355x - 5 = 6x - 35. Subtracting 5x5x from both sides gives 5=x35-5 = x - 35, so x=30x = 30.
3
Substitute x=30x = 30 into the expression for angle BAC\angle BAC.
mBAC=2(30)+10=70\text{m}\angle BAC = 2(30) + 10 = 70^\circ
The question asks for the degree measure of angle BAC\angle BAC, which is given by (2x+10)(2x + 10)^\circ.

Anahtar Kavram

Exterior Angle Theorem and Angle Relationships in Parallel Lines
Soru 3Soru

Two straight lines, L1L_1 and L2L_2, intersect at point OO. One of the angles formed by their intersection measures (3x15)(3x - 15)^\circ, and the vertically opposite angle measures (x+25)(x + 25)^\circ. What is the degree measure of an angle adjacent to (3x15)(3x - 15)^\circ?

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Cevap: 135135^\circ

Cevap

135135^\circ
Since vertically opposite angles are equal, setting 3x15=x+253x - 15 = x + 25 yields x=20x = 20. Substituting x=20x = 20 into 3x153x - 15 gives an angle of 4545^\circ. Because adjacent angles on intersecting lines form a straight line (a linear pair), they are supplementary. Therefore, the adjacent angle measures 18045=135180^\circ - 45^\circ = 135^\circ.

Adım Adım Çözüm

1
Set the vertically opposite angle expressions equal to each other.
3x15=x+253x - 15 = x + 25
Vertically opposite angles formed by two intersecting lines are equal in measure.
2
Solve for the variable xx.
2x=40    x=202x = 40 \implies x = 20
Subtract xx and add 1515 to both sides of the equation.
3
Calculate the degree measure of the angle (3x15)(3x - 15)^\circ.
3(20)15=6015=453(20) - 15 = 60 - 15 = 45^\circ
Substitute x=20x = 20 back into the angle expression.
4
Calculate the measure of an adjacent angle.
18045=135180^\circ - 45^\circ = 135^\circ
Adjacent angles along a straight line are supplementary and sum to 180180^\circ.

Anahtar Kavram

Vertically opposite angles are equal, and adjacent angles forming a linear pair are supplementary.
Soru 4Soru

Lines l1l_1 and l2l_2 intersect at point PP to form an acute angle measuring 4444^\circ. Line b1b_1 is the angle bisector of this acute angle. A third line, l3l_3, is drawn perpendicular to b1b_1 and intersects line l1l_1 at point QQ (where QPQ \neq P). What is the measure, in degrees, of the acute angle formed by the intersection of line l2l_2 and line l3l_3?

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Cevap: 6868^\circ

Cevap

The measure of the acute angle formed by the intersection of line l2l_2 and line l3l_3 is 6868^\circ.
The correct answer is 6868^\circ. Line b1b_1 divides the 4444^\circ angle between l1l_1 and l2l_2 into two 2222^\circ angles. Because line l3l_3 is perpendicular to b1b_1, it forms a right triangle with l1l_1 and b1b_1, making the angle between l1l_1 and l3l_3 equal to 9022=6890^\circ - 22^\circ = 68^\circ. Considering the large triangle formed by lines l1l_1, l2l_2, and l3l_3, two of its angles are 4444^\circ and 6868^\circ. Thus, the third interior angle at the intersection of l2l_2 and l3l_3 is 180(44+68)=68180^\circ - (44^\circ + 68^\circ) = 68^\circ, which is acute.

Adım Adım Çözüm

1
Determine the angle formed by the angle bisector b1b_1 with line l1l_1 and line l2l_2.
Since line b1b_1 bisects the 4444^\circ acute angle between l1l_1 and l2l_2, the angle between l1l_1 and b1b_1 is 442=22\frac{44^\circ}{2} = 22^\circ, and the angle between l2l_2 and b1b_1 is also 2222^\circ.
An angle bisector divides an angle into two equal congruent parts.
2
Find the measure of the interior angle between line l1l_1 and line l3l_3.
Line l3l_3 is perpendicular to b1b_1, forming a right triangle with l1l_1 and b1b_1. The interior angle between l1l_1 and l3l_3 is 1809022=68180^\circ - 90^\circ - 22^\circ = 68^\circ.
The sum of interior angles in any triangle is 180180^\circ.
3
Calculate the interior angle at the intersection of line l2l_2 and line l3l_3 in the main triangle formed by l1l_1, l2l_2, and l3l_3.
The interior angle at the intersection of l2l_2 and l3l_3 is 1804468=68180^\circ - 44^\circ - 68^\circ = 68^\circ.
The interior angles of the triangle formed by lines l1l_1, l2l_2, and l3l_3 must sum to 180180^\circ.
4
Verify that the calculated angle is acute.
Since 68<9068^\circ < 90^\circ, the acute angle formed by lines l2l_2 and l3l_3 is 6868^\circ.
An angle measuring strictly less than 9090^\circ is defined as an acute angle.

Anahtar Kavram

Angle bisector properties, perpendicular lines, and interior angle sum theorem for triangles.
Soru 5Soru

In the geometric plane, line l1l_1 is parallel to line l2l_2. Point AA lies on line l1l_1 and point BB lies on line l2l_2. Point CC is located between lines l1l_1 and l2l_2 such that CC lies to the right of both AA and BB.

The acute angle between segment ACAC and the ray extending to the right from AA along line l1l_1 measures xx^\circ.

The acute angle between segment BCBC and the ray extending to the right from BB along line l2l_2 measures yy^\circ.

The interior angle ACB=118\angle ACB = 118^\circ, and y=2x14y = 2x - 14.

Line kk passes through point CC and is perpendicular to segment ACAC. Line kk intersects line l2l_2 at point EE, where point EE lies to the right of point BB.

What is the measure, in degrees, of the acute angle CEB\angle CEB formed by line kk and line l2l_2?

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Cevap: 4646^\circ

Cevap

The measure of the acute angle CEB\angle CEB is 4646^\circ.
By the parallel lines angle property, drawing a parallel line through vertex CC shows that ACB=x+y=118\angle ACB = x + y = 118^\circ. Substituting y=2x14y = 2x - 14 yields 3x14=1183x - 14 = 118, giving x=44x = 44^\circ. Since line l1l_1 is parallel to line l2l_2, segment ACAC intersects line l2l_2 at an acute angle of 4444^\circ. Line kk is constructed perpendicular to segment ACAC, so the acute angle formed by line kk and line l2l_2 is complementary to 4444^\circ, which gives 9044=4690^\circ - 44^\circ = 46^\circ.

Adım Adım Çözüm

1
Set up the parallel lines zig-zag relationship to find xx and yy.
ACB=x+y=118\angle ACB = x + y = 118^\circ
By drawing an auxiliary line through CC parallel to l1l_1 and l2l_2, the interior angle ACB\angle ACB facing left equals the sum of the alternate interior angles xx and yy.
2
Substitute the given algebraic relation y=2x14y = 2x - 14 into the sum equation.
x+(2x14)=118    3x14=118    3x=132    x=44x + (2x - 14) = 118 \implies 3x - 14 = 118 \implies 3x = 132 \implies x = 44^\circ
Solving the linear system gives the exact value of angle xx.
3
Determine the angle that line ACAC makes with line l2l_2.
Line ACAC intersects line l2l_2 at an acute angle of 4444^\circ.
Since l1l2l_1 \parallel l_2, alternate interior angles formed by transversal line ACAC are equal (x=44x = 44^\circ).
4
Calculate the acute angle CEB\angle CEB between line kk and line l2l_2.
CEB=9044=46\angle CEB = 90^\circ - 44^\circ = 46^\circ
Line kk is perpendicular to segment ACAC, so the angle it forms with line l2l_2 is the complementary angle to the angle line ACAC forms with line l2l_2.

Anahtar Kavram

Parallel Line Angle Relationships and Perpendicular Line Complements
Soru 6Soru

Three straight lines, RR, SS, and TT, all intersect at a single point PP. Line RR is perpendicular to line SS. Line TT intersects line RR such that one of the acute angles formed between line RR and line TT measures 3535^\circ. Which of the following degree measures represent angles formed between any two of the intersecting lines at point PP? Select all that apply.

Geçerli olan tümünü seçin

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Cevap: 5555^\circ; 9090^\circ; 145145^\circ

Cevap

The degree measures 5555^\circ, 9090^\circ, and 145145^\circ are all valid angle measures formed by the intersecting lines at point PP.
The intersecting lines form several distinct angle measures at point PP. The right angle between lines RR and SS measures 9090^\circ. The acute angle between lines TT and SS is complementary to the 3535^\circ angle, giving 9035=5590^\circ - 35^\circ = 55^\circ. The obtuse angle between lines TT and RR along straight line RR is supplementary to 3535^\circ, giving 18035=145180^\circ - 35^\circ = 145^\circ. Therefore, the options stating 5555^\circ, 9090^\circ, and 145145^\circ are all correct.

Adım Adım Çözüm

1
Identify the angle measure between perpendicular lines R and S.
Since line RSR \perp S, the angle between them is 9090^\circ.
Perpendicular lines intersect at right angles (9090^\circ).
2
Calculate the acute angle between line T and line S.
Angle between TT and SS = 9035=5590^\circ - 35^\circ = 55^\circ.
The given 3535^\circ angle between RR and TT and the adjacent angle between TT and SS form the 9090^\circ right angle between RR and SS.
3
Determine the supplementary obtuse angles formed by line T with line R and line S.
Supplementary angle to 3535^\circ is 18035=145180^\circ - 35^\circ = 145^\circ. Supplementary angle to 5555^\circ is 18055=125180^\circ - 55^\circ = 125^\circ.
Adjacent angles along a straight line sum to 180180^\circ.
4
Compare calculated angle measures with the options.
The valid angle measures are 3535^\circ, 5555^\circ, 9090^\circ, 125125^\circ, and 145145^\circ. Thus 5555^\circ, 9090^\circ, and 145145^\circ are correct.
Matching calculated angle measures with the choices provided.

Anahtar Kavram

Perpendicular line relationships and supplementary angle properties of intersecting lines.
Tahmini Süre:1m 0s
Soru 7Soru

In the geometric plane, line kk is parallel to line mm. A transversal line tt intersects line kk at point PP and line mm at point QQ. Ray PRPR extends along line kk to the right of PP, and ray QSQS extends along line mm to the right of QQ. The measure of interior angle RPQ\angle RPQ is represented by (3x+20)(3x + 20)^\circ and the measure of interior angle PQS\angle PQS is represented by (2x+10)(2x + 10)^\circ. Which of the following statements must be true? Select all such statements.

Geçerli olan tümünü seçin

Cevabı ve açıklamayı göster

Cevap: The value of xx is 3030.; The measure of angle RPQ\angle RPQ is 110110^\circ.; The acute angle formed by line tt and line kk at point PP measures 7070^\circ.

Cevap

The true statements are that x=30x = 30, the measure of angle RPQ\angle RPQ is 110110^\circ, and the acute angle formed by line tt and line kk at point PP measures 7070^\circ.
Lines kk and mm are parallel, so interior angles on the same side of transversal tt (angles RPQ\angle RPQ and PQS\angle PQS) are supplementary. Solving (3x+20)+(2x+10)=180(3x + 20) + (2x + 10) = 180 gives x=30x = 30. Substituting x=30x = 30 yields RPQ=110\angle RPQ = 110^\circ and PQS=70\angle PQS = 70^\circ. The adjacent angle to RPQ\angle RPQ at point PP is 180110=70180^\circ - 110^\circ = 70^\circ, which is acute.

Adım Adım Çözüm

1
Set up the geometric equation using the parallel line angle relationship.
(3x+20)+(2x+10)=180(3x + 20) + (2x + 10) = 180
When two parallel lines are cut by a transversal, consecutive interior angles on the same side of the transversal are supplementary (their sum is 180180^\circ).
2
Solve the linear equation for xx.
5x+30=180    5x=150    x=305x + 30 = 180 \implies 5x = 150 \implies x = 30
Combine like terms and isolate xx using basic algebra.
3
Calculate the specific angle measures.
m RPQ=3(30)+20=110\angle RPQ = 3(30) + 20 = 110^\circ and m PQS=2(30)+10=70\angle PQS = 2(30) + 10 = 70^\circ
Substitute x=30x = 30 into the given algebraic angle expressions.
4
Determine the supplementary acute angle at point PP.
180110=70180^\circ - 110^\circ = 70^\circ
Angles along a straight line form a linear pair and sum to 180180^\circ.

Anahtar Kavram

Parallel Lines and Consecutive Interior Angles
Soru 8Soru

In a geometric plane, straight lines L1L_1 and L2L_2 intersect at point PP. The measure of the obtuse angle formed by the intersection of L1L_1 and L2L_2 is (5x10)(5x - 10)^\circ, and the measure of an adjacent acute angle is (2x+15)(2x + 15)^\circ. Ray PQPQ originates from point PP, is perpendicular to line L1L_1, and lies entirely within the interior of the (5x10)(5x - 10)^\circ obtuse angle. What is the measure, in degrees, of the angle formed between ray PQPQ and line L2L_2?

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Cevap: 2525^\circ

Cevap

2525^\circ
Two intersecting lines form adjacent angles that sum to 180180^\circ. Solving (5x10)+(2x+15)=180(5x - 10) + (2x + 15) = 180 gives 7x+5=1807x + 5 = 180, so x=25x = 25. The obtuse angle measure is 5(25)10=1155(25) - 10 = 115^\circ. Since ray PQPQ is perpendicular to line L1L_1, it forms a 9090^\circ angle with line L1L_1. The remaining angle between ray PQPQ and line L2L_2 within the obtuse angle region is 11590=25115^\circ - 90^\circ = 25^\circ.

Adım Adım Çözüm

1
Set up an algebraic equation using the supplementary angle relationship.
(5x10)+(2x+15)=180(5x - 10) + (2x + 15) = 180
Adjacent angles formed by two intersecting straight lines lie on a straight line and are supplementary, summing to 180180^\circ.
2
Solve for the variable xx.
7x+5=180    7x=175    x=257x + 5 = 180 \implies 7x = 175 \implies x = 25
Combining like terms simplifies the linear equation.
3
Calculate the degree measure of the obtuse angle.
Obtuse angle = 5(25)10=12510=1155(25) - 10 = 125 - 10 = 115^\circ
Substitute x=25x = 25 back into the expression (5x10)(5x - 10)^\circ.
4
Calculate the angle between ray PQPQ and line L2L_2.
Angle = 11590=25115^\circ - 90^\circ = 25^\circ
Ray PQPQ is perpendicular to line L1L_1 (9090^\circ) and lies inside the 115115^\circ angle, dividing the obtuse angle into a 9090^\circ portion and the remaining angle adjacent to line L2L_2.

Anahtar Kavram

Supplementary angles on a straight line and angle subtraction with perpendicular rays
Tahmini Süre:1m 30s
Soru 9Soru

Lines L1L_1 and L2L_2 intersect at point PP to form an acute angle of 5454^\circ. Line MM passes through point PP and is perpendicular to line L1L_1. Ray RR originates at point PP and lies in the interior of one of the obtuse angles formed by L1L_1 and L2L_2. If Ray RR bisects the angle formed between line MM and line L2L_2, what is the measure, in degrees, of the acute angle formed by Ray RR and line L1L_1?

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Cevap: 72

Cevap

The measure of the acute angle formed by Ray RR and line L1L_1 is 7272^\circ.
Lines L1L_1 and L2L_2 form an obtuse angle of 18054=126180^\circ - 54^\circ = 126^\circ. Perpendicular line MM consumes 9090^\circ of this angle relative to L1L_1, leaving 3636^\circ between line MM and line L2L_2. Bisecting this remaining angle gives 1818^\circ. Ray RR therefore lies 1818^\circ away from perpendicular line MM, making an acute angle of 9018=7290^\circ - 18^\circ = 72^\circ with line L1L_1.

Adım Adım Çözüm

1
Determine the measure of the obtuse angle between lines L1L_1 and L2L_2.
The obtuse angle measures 18054=126180^\circ - 54^\circ = 126^\circ.
Adjacent angles along intersecting straight lines are supplementary and sum to 180180^\circ.
2
Find the angle between perpendicular line MM and line L2L_2.
The angle between line MM and line L2L_2 within the obtuse region is 12690=36126^\circ - 90^\circ = 36^\circ.
Line MM is perpendicular to line L1L_1, taking up 9090^\circ of the 126126^\circ obtuse angle.
3
Determine the angle formed by Ray RR after bisecting the 3636^\circ angle.
The angle between Ray RR and line MM is 36/2=1836^\circ / 2 = 18^\circ.
An angle bisector divides an angle into two equal parts.
4
Calculate the acute angle between Ray RR and line L1L_1.
The acute angle formed between Ray RR and line L1L_1 is 9018=7290^\circ - 18^\circ = 72^\circ.
Line MM forms a 9090^\circ angle with line L1L_1. Subtracting the 1818^\circ offset created by Ray RR yields the acute angle of 7272^\circ.

Anahtar Kavram

Supplementary angles, perpendicular lines, and angle bisectors
Tahmini Süre:2m 0s
Soru 10Soru

In the geometric plane, line kk is parallel to line mm (kmk \parallel m). Transversal line tt intersects line kk at point AA and line mm at point BB. Point CC lies on line kk to the left of AA, such that interior acute angle CAB=(3x10)\angle CAB = (3x - 10)^\circ. Ray ADAD bisects CAB\angle CAB. Ray BFBF is drawn into the region between lines kk and mm making an angle ABF=(x+35)\angle ABF = (x + 35)^\circ with transversal segment ABAB. Ray ADAD and ray BFBF intersect at point PP inside the parallel region. Line PBPB is extended past PP to intersect line kk at point QQ. If ray ADAD is perpendicular to ray BFBF, what is the measure of the obtuse angle formed at the intersection of line QBQB and line kk?

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Cevap: 121121^\circ

Cevap

The measure of the obtuse angle formed at the intersection of line QBQB and line kk is 121121^\circ.
The measure 121121^\circ is correct because ray ADAD bisects CAB\angle CAB, giving PAB=(1.5x5)\angle PAB = (1.5x - 5)^\circ. Since ADBFAD \perp BF, APB\triangle APB is a right triangle where (1.5x5)+(x+35)=90(1.5x - 5) + (x + 35) = 90, yielding x=24x = 24. Consequently, QAB=62\angle QAB = 62^\circ and ABQ=59\angle ABQ = 59^\circ. In ABQ\triangle ABQ, the acute angle AQB=180(62+59)=59\angle AQB = 180^\circ - (62^\circ + 59^\circ) = 59^\circ. The supplementary obtuse angle along line kk is 18059=121180^\circ - 59^\circ = 121^\circ.

Adım Adım Çözüm

1
Express the angle PAB\angle PAB in terms of xx.
Since ray ADAD bisects CAB=(3x10)\angle CAB = (3x - 10)^\circ, PAB=3x102=(1.5x5)\angle PAB = \frac{3x - 10}{2} = (1.5x - 5)^\circ.
An angle bisector divides an angle into two equal halves.
2
Set up an equation using triangle APB\triangle APB.
In APB\triangle APB, APB=90\angle APB = 90^\circ because ray ADAD \perp ray BFBF. Therefore, PAB+ABP=90    (1.5x5)+(x+35)=90    2.5x+30=90    2.5x=60    x=24\angle PAB + \angle ABP = 90^\circ \implies (1.5x - 5) + (x + 35) = 90 \implies 2.5x + 30 = 90 \implies 2.5x = 60 \implies x = 24.
The acute angles in a right triangle sum to 9090^\circ.
3
Calculate the measures of CAB\angle CAB and ABQ\angle ABQ.
CAB=3(24)10=62\angle CAB = 3(24) - 10 = 62^\circ, and ABQ=ABF=24+35=59\angle ABQ = \angle ABF = 24 + 35 = 59^\circ.
Substitute x=24x = 24 back into the original angle expressions.
4
Determine the acute angle AQB\angle AQB in triangle ABQ\triangle ABQ.
In ABQ\triangle ABQ, points Q,C,AQ, C, A lie on line kk, so QAB=CAB=62\angle QAB = \angle CAB = 62^\circ. Sum of angles in ABQ\triangle ABQ: AQB=180(62+59)=180121=59\angle AQB = 180^\circ - (62^\circ + 59^\circ) = 180^\circ - 121^\circ = 59^\circ.
The interior angles of any triangle sum to 180180^\circ.
5
Find the supplementary obtuse angle at intersection point QQ.
Obtuse angle =18059=121= 180^\circ - 59^\circ = 121^\circ.
Angles forming a linear pair on a straight line are supplementary.

Anahtar Kavram

Parallel Lines, Transversals, Angle Bisectors, and Triangle Angle Sum Theorem
Soru 11Soru

Four rays, OA\vec{OA}, OB\vec{OB}, OC\vec{OC}, and OD\vec{OD}, radiate from a common point OO in consecutive clockwise order such that OAOC\vec{OA} \perp \vec{OC} and OBOD\vec{OB} \perp \vec{OD}. If the measure of angle AOD\angle AOD is 3.53.5 times the measure of angle BOC\angle BOC, what is the measure, in degrees, of angle AOB\angle AOB?

Cevabı ve açıklamayı göster

Cevap: 5050^\circ

Cevap

5050^\circ
Because OAOC\vec{OA} \perp \vec{OC} and OBOD\vec{OB} \perp \vec{OD}, we know AOB+BOC=90\angle AOB + \angle BOC = 90^\circ and BOC+COD=90\angle BOC + \angle COD = 90^\circ, which implies AOB=COD\angle AOB = \angle COD. The total angle AOD=AOB+BOD=AOB+90\angle AOD = \angle AOB + \angle BOD = \angle AOB + 90^\circ. Using the given condition AOD=3.5×BOC\angle AOD = 3.5 \times \angle BOC, we substitute BOC=90AOB\angle BOC = 90^\circ - \angle AOB to get AOB+90=3.5(90AOB)\angle AOB + 90^\circ = 3.5(90^\circ - \angle AOB), which solves to AOB=50\angle AOB = 50^\circ.

Adım Adım Çözüm

1
Set up angle variable definitions and perpendicular relationships.
Let AOB=x\angle AOB = x, BOC=y\angle BOC = y, and COD=z\angle COD = z. Since OAOC\vec{OA} \perp \vec{OC}, we have x+y=90x + y = 90^\circ. Since OBOD\vec{OB} \perp \vec{OD}, we have y+z=90y + z = 90^\circ.
Perpendicular rays form right angles measuring 9090^\circ.
2
Deduce the relationship between xx, yy, and zz, and express AOD\angle AOD in terms of xx.
Subtracting yy from both equations gives x=90yx = 90^\circ - y and z=90yz = 90^\circ - y, so x=zx = z. Thus, AOD=x+y+z=x+90\angle AOD = x + y + z = x + 90^\circ.
Adjacent angles sharing a vertex add up to form the overall combined angle.
3
Formulate and solve the equation based on the given ratio.
We are given AOD=3.5×BOC\angle AOD = 3.5 \times \angle BOC, so x+90=3.5yx + 90^\circ = 3.5y. Substituting y=90xy = 90^\circ - x yields x+90=3.5(90x)    x+90=3153.5x    4.5x=225    x=50x + 90^\circ = 3.5(90^\circ - x) \implies x + 90^\circ = 315^\circ - 3.5x \implies 4.5x = 225^\circ \implies x = 50^\circ.
Substitution creates a single linear equation in terms of x=AOBx = \angle AOB.

Anahtar Kavram

Perpendicular Ray Systems and Angle Addition
Tahmini Süre:1m 30s
Soru 12Soru

In a plane, lines l1l_1 and l2l_2 are parallel (l1l2l_1 \parallel l_2). A transversal line tt intersects l1l_1 at point PP and l2l_2 at point QQ. The measures of two consecutive interior angles on the same side of transversal tt are (4x10)(4x - 10)^\circ on line l1l_1 and (3x+50)(3x + 50)^\circ on line l2l_2. A third line l3l_3 passes through point PP and is perpendicular to line l2l_2.

Which of the following statements MUST be true? Select all that apply.

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Cevabı ve açıklamayı göster

Cevap: x=20x = 20; The acute angle formed between line tt and line l3l_3 at point PP measures 2020^\circ.; The sum of all four interior angles located between lines l1l_1 and l2l_2 along transversal line tt is 360360^\circ.

Cevap

The correct statements are that x=20x = 20, the acute angle formed between line tt and line l3l_3 at point PP measures 2020^\circ, and the sum of all four interior angles located between lines l1l_1 and l2l_2 along transversal line tt is 360360^\circ.
The statements confirming x=20x = 20, the 2020^\circ acute angle between lines tt and l3l_3, and the 360360^\circ interior angle sum are all correct because consecutive interior angles sum to 180180^\circ, perpendicular lines create 9090^\circ angles, and the four interior angles sum to 360360^\circ.

Adım Adım Çözüm

1
Set up an equation for consecutive interior angles.
(4x10)+(3x+50)=180(4x - 10) + (3x + 50) = 180^\circ
Consecutive interior angles on the same side of a transversal intersecting parallel lines are supplementary.
2
Solve the algebraic equation for xx.
7x+40=180    7x=140    x=207x + 40 = 180 \implies 7x = 140 \implies x = 20
Combine like terms and isolate xx.
3
Calculate the interior angle measures at points PP and QQ.
Angle at P=4(20)10=70P = 4(20) - 10 = 70^\circ; Angle at Q=3(20)+50=110Q = 3(20) + 50 = 110^\circ
Substitute x=20x = 20 back into the original expressions.
4
Determine perpendicular relationships and angle measure between line tt and line l3l_3.
Angle between tt and l3l_3 at PP is 9070=2090^\circ - 70^\circ = 20^\circ
Line l3l2l_3 \perp l_2 implies l3l1l_3 \perp l_1 because l1l2l_1 \parallel l_2. Thus l3l_3 forms a 9090^\circ angle with l1l_1 at PP.
5
Sum the four interior angles between lines l1l_1 and l2l_2.
70+110+70+110=36070^\circ + 110^\circ + 70^\circ + 110^\circ = 360^\circ
The four interior angles comprise two pairs of interior angles measuring 7070^\circ and 110110^\circ each.

Anahtar Kavram

Parallel line angle theorems (consecutive interior angles, alternate interior angles) and perpendicular line relationships.
Soru 13Soru

In a geometric plane, line L1L_1 is parallel to line L2L_2. Points AA and CC lie on line L1L_1, and points BB and DD lie on line L2L_2. Line segments ABAB and CDCD intersect at point XX located between lines L1L_1 and L2L_2. If measure of XAC=42\angle XAC = 42^\circ and measure of XDB=35\angle XDB = 35^\circ, what is the measure, in degrees, of AXC\angle AXC?

Cevabı ve açıklamayı göster

Cevap: 103

Cevap

The measure of AXC\angle AXC is 103103^\circ.
Line L1L_1 is parallel to line L2L_2, meaning segment ACAC is parallel to segment BDBD. Transversal line CDCD intersects both parallel lines, creating alternate interior angles XCA\angle XCA and XDB\angle XDB. Hence, XCA=XDB=35\angle XCA = \angle XDB = 35^\circ. Inside triangle ACXACX, the three interior angles must sum to 180180^\circ. Substituting the values yields AXC=180(42+35)=103\angle AXC = 180^\circ - (42^\circ + 35^\circ) = 103^\circ.

Adım Adım Çözüm

1
Identify parallel lines and the transversal line
Line segment CDCD acts as a transversal line intersecting parallel lines L1L_1 and L2L_2.
Points AA and CC lie on line L1L_1 while points BB and DD lie on line L2L_2 with L1L2L_1 \parallel L_2.
2
Apply the alternate interior angles theorem
\angle XCA = \angle XDB = 35^\circ
When a transversal intersects two parallel lines, alternate interior angles are equal.
3
Calculate the target angle using the sum of interior angles in a triangle
\angle AXC = 180^\circ - (42^\circ + 35^\circ) = 103^\circ
The sum of interior angles in triangle ACXACX is 180180^\circ.

Anahtar Kavram

Properties of parallel lines intersected by a transversal and the triangle angle sum theorem.