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Zorluk: OrtaTetraoxosulfate(VI) Acid: Contact Process and Properties
When copper turnings are heated with concentrated tetraoxosulfate(VI) acid (H2SO4H_2SO_4), a gas (SO2SO_2) that turns acidified potassium heptaoxodichromate(VI) solution from orange to green is evolved according to the equation:
Cu(s)+2H2SO4(aq)→CuSO4(aq)+2H2O(l)+SO2(g)Cu_{(s)} + 2H_2SO_{4(aq)} \rightarrow CuSO_{4(aq)} + 2H_2O_{(l)} + SO_{2(g)}
Which property of concentrated tetraoxosulfate(VI) acid is demonstrated in this reaction?
  1. A
    Dehydrating agent
  2. Oxidizing agentCevap
  3. C
    Reducing agent
  4. D
    Drying agent

Cevap

Oxidizing agent
In this reaction, elemental copper (CuCu) with an oxidation state of 00 is oxidized to Cu2+Cu^{2+} (+2+2 oxidation state in CuSO4CuSO_4). Concentrated tetraoxosulfate(VI) acid acts as the oxidizing agent because it causes this oxidation while itself being reduced to sulfur(IV) oxide (SO2SO_2), in which sulfur has an oxidation state of +4+4.

Adım Adım Çözüm

1
Analyze the oxidation state changes of copper and sulfur in the given balanced equation
Copper (CuCu) goes from oxidation state 00 to +2+2 in CuSO4CuSO_4 (loss of electrons / oxidation). Sulfur in H2SO4H_2SO_4 goes from +6+6 to +4+4 in SO2SO_2 (gain of electrons / reduction).
Determining oxidation number changes identifies which reactant is oxidized and which acts as the oxidizing agent.
2
Identify the role of concentrated tetraoxosulfate(VI) acid
Since H2SO4H_2SO_4 causes copper to be oxidized to Cu2+Cu^{2+} ions while itself being reduced to SO2SO_2, concentrated H2SO4H_2SO_4 is acting as an oxidizing agent.
An oxidizing agent accepts electrons and undergoes reduction during a redox reaction.

Anahtar Kavram

Oxidizing property of concentrated tetraoxosulfate(VI) acid with metals
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Konular

Tetraoxosulfate(VI) Acid: Contact Process and Properties

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