Two long, straight, parallel horizontal conductors are separated vertically by a distance of . The upper conductor has a mass per unit length of and carries a steady current of . Assuming the currents in the two conductors flow in opposite directions so that the resulting magnetic force is repulsive, what current (in amperes) must flow through the lower conductor to magnetically levitate and balance the weight of the upper conductor? (Take and )
Cevap: 784 A
Cevap
The required current in the lower conductor is .
Equating magnetic repulsion per unit length to weight per unit length gives , which simplifies to , yielding .
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Anahtar Kavram
Interaction force between parallel current-carrying conductors and mechanical equilibrium