Soru

Zorluk: OrtaMatrices and Determinants

If the matrix A=(3275)A = \begin{pmatrix} 3 & 2 \\ 7 & 5 \end{pmatrix}, which matrix represents the inverse A−1A^{-1}?

  1. (5−2−73)\begin{pmatrix} 5 & -2 \\ -7 & 3 \end{pmatrix}Cevap
  2. B
    (5273)\begin{pmatrix} 5 & 2 \\ 7 & 3 \end{pmatrix}
  3. C
    (−527−3)\begin{pmatrix} -5 & 2 \\ 7 & -3 \end{pmatrix}
  4. D
    (3−2−75)\begin{pmatrix} 3 & -2 \\ -7 & 5 \end{pmatrix}

Cevap

(5−2−73)\begin{pmatrix} 5 & -2 \\ -7 & 3 \end{pmatrix}
The correct inverse matrix is computed by evaluating the determinant det⁡(A)=3(5)−2(7)=1\det(A) = 3(5) - 2(7) = 1 and constructing the adjugate matrix by swapping the diagonal elements 33 and 55 while changing the signs of 22 and 77, resulting in (5−2−73)\begin{pmatrix} 5 & -2 \\ -7 & 3 \end{pmatrix}.

Adım Adım Çözüm

1
Calculate the determinant of matrix AA
det⁡(A)=(3)(5)−(2)(7)=15−14=1\det(A) = (3)(5) - (2)(7) = 15 - 14 = 1
The inverse requires dividing the adjugate matrix by the determinant of AA.
2
Find the adjugate of matrix AA
adj(A)=(5−2−73)\text{adj}(A) = \begin{pmatrix} 5 & -2 \\ -7 & 3 \end{pmatrix}
For a 2x2 matrix (abcd)\begin{pmatrix} a & b \\ c & d \end{pmatrix}, swap the main diagonal elements (aa and dd) and change the signs of the off-diagonal elements (bb and cc).
3
Compute A−1=1det⁡(A)adj(A)A^{-1} = \frac{1}{\det(A)} \text{adj}(A)
A−1=11(5−2−73)=(5−2−73)A^{-1} = \frac{1}{1} \begin{pmatrix} 5 & -2 \\ -7 & 3 \end{pmatrix} = \begin{pmatrix} 5 & -2 \\ -7 & 3 \end{pmatrix}
Multiply the adjugate matrix by the reciprocal of the determinant.

Anahtar Kavram

2x2 Matrix Inversion
Tahmini Süre:1m 0s
Bu soruyu puanla