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Zorluk: KolayDifferentiation of Trigonometric, Exponential, and Logarithmic Functions

If y=e4xsinxy = e^{4x} - \sin x, what is dydx\frac{dy}{dx}?

  1. 4e4xcosx4e^{4x} - \cos xCevap
  2. B
    4e4x+cosx4e^{4x} + \cos x
  3. C
    e4xcosxe^{4x} - \cos x
  4. D
    e4x+cosxe^{4x} + \cos x

Cevap

4e4xcosx4e^{4x} - \cos x
Differentiating e4xe^{4x} gives 4e4x4e^{4x} by applying the chain rule, and differentiating sinx-\sin x yields cosx-\cos x. Combining these terms gives the correct derivative 4e4xcosx4e^{4x} - \cos x.

Adım Adım Çözüm

1
Apply the sum/difference rule of differentiation.
\frac{dy}{dx} = \frac{d}{dx}(e^{4x}) - \frac{d}{dx}(\sin x)
The derivative of a difference of two terms is the difference of their individual derivatives.
2
Differentiate the exponential term e4xe^{4x} using the chain rule.
ddx(e4x)=4e4x\frac{d}{dx}(e^{4x}) = 4e^{4x}
By the chain rule, \frac{d}{dx}(e^{k x}) = k e^{k x}.
3
Differentiate the trigonometric term sinx\sin x.
ddx(sinx)=cosx\frac{d}{dx}(\sin x) = \cos x
The standard derivative of sinx\sin x with respect to xx is cosx\cos x.
4
Combine the results.
\frac{dy}{dx} = 4e^{4x} - \cos x
Subtracting the derivative of sinx\sin x from the derivative of e4xe^{4x} gives the final answer.

Anahtar Kavram

Differentiation of Exponential and Trigonometric Functions
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