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Zorluk: OrtaSurface Area and Volume of 3D Solids

A solid right pyramid has a square base with a side length of 6 cm6\text{ cm} and a vertical height of 4 cm4\text{ cm}. What is the total surface area of the pyramid in square centimeters?

Cevap: 96 cm^2

Cevap

The total surface area of the pyramid is 96 cm296\text{ cm}^2.
To determine the total surface area of a square pyramid, sum the base area and the total area of the four triangular faces. The base area is 6×6=36 cm26 \times 6 = 36\text{ cm}^2. The slant height of each triangular face is found via the Pythagorean theorem using half the base side length (3 cm3\text{ cm}) and the vertical height (4 cm4\text{ cm}), yielding 32+42=5 cm\sqrt{3^2 + 4^2} = 5\text{ cm}. The area of one triangular face is 12×6×5=15 cm2\frac{1}{2} \times 6 \times 5 = 15\text{ cm}^2, making four faces equal to 60 cm260\text{ cm}^2. Adding the base area gives 36+60=96 cm236 + 60 = 96\text{ cm}^2.

Adım Adım Çözüm

1
Calculate the area of the square base
Base area = 36 cm236\text{ cm}^2
The base is a square of side 6 cm6\text{ cm}, so Area=62=36 cm2\text{Area} = 6^2 = 36\text{ cm}^2.
2
Find the slant height of each triangular lateral face
Slant height l=5 cml = 5\text{ cm}
The slant height forms the hypotenuse of a right-angled triangle inside the pyramid with legs equal to the vertical height (4 cm4\text{ cm}) and half the base edge (3 cm3\text{ cm}): l=42+32=5 cml = \sqrt{4^2 + 3^2} = 5\text{ cm}.
3
Calculate the combined area of the four triangular faces
Lateral area = 60 cm260\text{ cm}^2
Each triangle has base 6 cm6\text{ cm} and height 5 cm5\text{ cm}, giving an area of 12×6×5=15 cm2\frac{1}{2} \times 6 \times 5 = 15\text{ cm}^2. For 4 identical faces, the total is 4×15=60 cm24 \times 15 = 60\text{ cm}^2.
4
Calculate total surface area
Total Surface Area = 96 cm296\text{ cm}^2
Sum the base area and the total lateral area: 36+60=96 cm236 + 60 = 96\text{ cm}^2.

Anahtar Kavram

Total Surface Area of a Right Pyramid
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