Soru

Zorluk: ZorNuclear Fission and Nuclear Fusion
A Uranium-235 nucleus undergoes nuclear fission after absorbing a thermal neutron according to the reaction equation:
92235U+01n54140Xe+3894Sr+x 01n{^{235}_{92}\text{U}} + {^{1}_{0}\text{n}} \rightarrow {^{140}_{54}\text{Xe}} + {^{94}_{38}\text{Sr}} + x\ {^{1}_{0}\text{n}}
Given the rest masses:
- Mass of 92235U=235.0439 u{^{235}_{92}\text{U}} = 235.0439\text{ u}
- Mass of 54140Xe=139.9216 u{^{140}_{54}\text{Xe}} = 139.9216\text{ u}
- Mass of 3894Sr=93.9154 u{^{94}_{38}\text{Sr}} = 93.9154\text{ u}
- Mass of 01n=1.0087 u{^{1}_{0}\text{n}} = 1.0087\text{ u}
- 1 u=931.5 MeV1\text{ u} = 931.5\text{ MeV}

Calculate the total energy released during this fission process in MeV.

Cevap: 184.62 MeV

Cevap

184.62 MeV
The total energy released is calculated by first balancing the nuclear equation to determine that 2 neutrons are emitted (x=2x = 2). The total mass of reactants is 236.0526 u236.0526\text{ u} and the products is 235.8544 u235.8544\text{ u}. The mass defect of 0.1982 u0.1982\text{ u} multiplied by 931.5 MeV/u931.5\text{ MeV/u} yields 184.62 MeV184.62\text{ MeV}.

Adım Adım Çözüm

1
Balance the mass numbers in the nuclear equation to find the number of emitted neutrons (xx)
x=2x = 2 neutrons
Conservation of mass number requires 235+1=140+94+x235 + 1 = 140 + 94 + x, giving 236=234+x236 = 234 + x, so x=2x = 2.
2
Calculate the total mass of the reactants before fission
236.0526 u236.0526\text{ u}
Summing the mass of U-235 (235.0439 u235.0439\text{ u}) and the incident neutron (1.0087 u1.0087\text{ u}).
3
Calculate the total mass of the products after fission
235.8544 u235.8544\text{ u}
Summing masses of Xe-140 (139.9216 u139.9216\text{ u}), Sr-94 (93.9154 u93.9154\text{ u}), and 2 neutrons (2×1.0087 u=2.0174 u2 \times 1.0087\text{ u} = 2.0174\text{ u}).
4
Determine the mass defect (mass difference)
Δm=0.1982 u\Delta m = 0.1982\text{ u}
Mass defect Δm=mreactantsmproducts=236.0526235.8544=0.1982 u\Delta m = m_{\text{reactants}} - m_{\text{products}} = 236.0526 - 235.8544 = 0.1982\text{ u}.
5
Convert mass defect to energy using 1 u=931.5 MeV1\text{ u} = 931.5\text{ MeV}
184.62 MeV184.62\text{ MeV}
Multiplying mass defect 0.1982 u0.1982\text{ u} by 931.5 MeV/u931.5\text{ MeV/u} gives 184.6233 MeV184.6233\text{ MeV}, which rounds to 184.62 MeV184.62\text{ MeV}.

Anahtar Kavram

Mass defect and mass-energy equivalence in nuclear fission reactions
Tahmini Süre:2m 30s
Bu soruyu puanla