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Zorluk: KolayWater of Crystallization, Efflorescence, Deliquescence, and Hygroscopy

A 24.6 g24.6\text{ g} sample of hydrated magnesium tetraoxosulfate(VI), MgSO4xH2O\text{MgSO}_4 \cdot x\text{H}_2\text{O}, was heated strongly until all the water of crystallization was driven off, leaving behind 12.0 g12.0\text{ g} of anhydrous MgSO4\text{MgSO}_4. What is the value of xx? [Mg=24,S=32,O=16,H=1][\text{Mg} = 24, \text{S} = 32, \text{O} = 16, \text{H} = 1]

Cevap: 7

Cevap

The value of xx is 7.
Heating the sample evaporates 12.6 g12.6\text{ g} of water of crystallization (24.6 g12.0 g24.6\text{ g} - 12.0\text{ g}). Converting the masses to moles gives 0.1 mol0.1\text{ mol} of anhydrous MgSO4\text{MgSO}_4 (12.0 g/120 g/mol12.0\text{ g} / 120\text{ g/mol}) and 0.7 mol0.7\text{ mol} of H2O\text{H}_2\text{O} (12.6 g/18 g/mol12.6\text{ g} / 18\text{ g/mol}). The mole ratio of water to salt is 0.7/0.1=70.7 / 0.1 = 7, which means x=7x = 7.

Adım Adım Çözüm

1
Calculate the mass of water of crystallization lost during heating.
Mass of water = 24.6 g12.0 g=12.6 g24.6\text{ g} - 12.0\text{ g} = 12.6\text{ g}.
The decrease in mass after heating represents the mass of water driven off from the hydrated salt.
2
Determine the molar masses of MgSO4\text{MgSO}_4 and H2O\text{H}_2\text{O}.
Molar mass of MgSO4=24+32+(4×16)=120 g/mol\text{MgSO}_4 = 24 + 32 + (4 \times 16) = 120\text{ g/mol}; Molar mass of H2O=(2×1)+16=18 g/mol\text{H}_2\text{O} = (2 \times 1) + 16 = 18\text{ g/mol}.
Molar masses are required to convert the measured masses into chemical amounts (moles).
3
Calculate the number of moles of anhydrous salt and water.
Moles of MgSO4=12.0 g120 g/mol=0.1 mol\text{MgSO}_4 = \frac{12.0\text{ g}}{120\text{ g/mol}} = 0.1\text{ mol}; Moles of H2O=12.6 g18 g/mol=0.7 mol\text{H}_2\text{O} = \frac{12.6\text{ g}}{18\text{ g/mol}} = 0.7\text{ mol}.
The chemical formula stoichiometry is determined by the molar ratio of components.
4
Determine the mole ratio of water to anhydrous salt (xx).
x=Moles of H2OMoles of MgSO4=0.7 mol0.1 mol=7x = \frac{\text{Moles of } \text{H}_2\text{O}}{\text{Moles of } \text{MgSO}_4} = \frac{0.7\text{ mol}}{0.1\text{ mol}} = 7.
The coefficient xx is the integer ratio of moles of water of crystallization per mole of anhydrous salt.

Anahtar Kavram

Water of Crystallization Stoichiometry
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