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Zorluk: Çok zorSurface Area and Volume of 3D Solids

A solid wooden block is shaped as a frustum of a right circular cone with a top base radius of 4 cm4\text{ cm}, a bottom base radius of 12 cm12\text{ cm}, and a vertical height of 15 cm15\text{ cm}. A cylindrical hole of radius 4 cm4\text{ cm} is drilled vertically through the center of the frustum from the top base straight down to the bottom base. What is the volume of the remaining wooden solid in cm3\text{cm}^3?

  1. 800π cm3800\pi\text{ cm}^3Cevap
  2. B
    2880π cm32880\pi\text{ cm}^3
  3. C
    560π cm3560\pi\text{ cm}^3
  4. D
    80π cm380\pi\text{ cm}^3

Cevap

The volume of the remaining wooden solid is 800π cm3800\pi\text{ cm}^3.
The volume of a frustum of a cone with radii R=12 cmR=12\text{ cm}, r=4 cmr=4\text{ cm}, and height h=15 cmh=15\text{ cm} is 13π(15)(122+42+12×4)=1040π cm3\frac{1}{3}\pi(15)(12^2 + 4^2 + 12 \times 4) = 1040\pi\text{ cm}^3. Subtracting the volume of the central cylindrical hole of radius 4 cm4\text{ cm} and height 15 cm15\text{ cm}, which is π(42)(15)=240π cm3\pi(4^2)(15) = 240\pi\text{ cm}^3, yields 1040π240π=800π cm31040\pi - 240\pi = 800\pi\text{ cm}^3.

Adım Adım Çözüm

1
Calculate the total volume of the conical frustum before drilling.
Vfrustum=13πh(R2+r2+Rr)=13π(15)(122+42+12×4)=5π(144+16+48)=1040π cm3V_{\text{frustum}} = \frac{1}{3}\pi h (R^2 + r^2 + R r) = \frac{1}{3}\pi (15)(12^2 + 4^2 + 12 \times 4) = 5\pi(144 + 16 + 48) = 1040\pi\text{ cm}^3.
The total volume of a frustum of a cone is determined by its vertical height and the radii of its top and bottom circular bases.
2
Calculate the volume of the cylindrical hole drilled through the solid.
Vcylinder=πrhole2h=π(42)(15)=240π cm3V_{\text{cylinder}} = \pi r_{\text{hole}}^2 h = \pi (4^2)(15) = 240\pi\text{ cm}^3.
The drilled hole forms a right circular cylinder of radius 4 cm4\text{ cm} and height equal to the full height of the frustum (15 cm15\text{ cm}).
3
Subtract the cylinder's volume from the frustum's volume to find the remaining volume.
Vremaining=VfrustumVcylinder=1040π240π=800π cm3V_{\text{remaining}} = V_{\text{frustum}} - V_{\text{cylinder}} = 1040\pi - 240\pi = 800\pi\text{ cm}^3.
Removing material by drilling decreases the overall volume of the original solid by the exact volume of the cylindrical bore.

Anahtar Kavram

Volume of Composite Solids and Conical Frustums
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