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Zorluk: OrtaMatrices and Determinants

Given the matrices A=(4x13)A = \begin{pmatrix} 4 & x \\ -1 & 3 \end{pmatrix} and B=(2134)B = \begin{pmatrix} 2 & 1 \\ 3 & 4 \end{pmatrix}, if the determinant of the product matrix ABAB is 9595, what is the value of xx?

Cevap: 7

Cevap

The value of xx is 77.
Using the property det(AB)=det(A)det(B)\det(AB) = \det(A)\det(B), we find det(B)=(2)(4)(1)(3)=5\det(B) = (2)(4) - (1)(3) = 5 and det(A)=(4)(3)(x)(1)=12+x\det(A) = (4)(3) - (x)(-1) = 12 + x. Setting 5(12+x)=955(12 + x) = 95 yields 60+5x=9560 + 5x = 95, which solves to x=7x = 7.

Adım Adım Çözüm

1
Calculate the determinant of matrix BB
det(B)=(2)(4)(1)(3)=5\det(B) = (2)(4) - (1)(3) = 5
The determinant of a 2×22 \times 2 matrix (abcd)\begin{pmatrix} a & b \\ c & d \end{pmatrix} is adbcad - bc.
2
Express the determinant of matrix AA in terms of xx
det(A)=(4)(3)(x)(1)=12+x\det(A) = (4)(3) - (x)(-1) = 12 + x
Applying the determinant formula to matrix AA gives 12(x)=12+x12 - (-x) = 12 + x.
3
Apply the determinant product property det(AB)=det(A)det(B)\det(AB) = \det(A) \cdot \det(B)
5(12+x)=955(12 + x) = 95
The determinant of the product of two square matrices is equal to the product of their individual determinants.
4
Solve the linear equation for xx
60+5x=95    5x=35    x=760 + 5x = 95 \implies 5x = 35 \implies x = 7
Subtract 6060 from both sides and divide by 55 to isolate xx.

Anahtar Kavram

Determinant of Matrix Product Property
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