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Zorluk: OrtaGravitational Field and Orbits

Two point masses, each of mass 125 kg125\text{ kg}, are fixed at positions (3.0 m,0)(-3.0\text{ m}, 0) and (3.0 m,0)(3.0\text{ m}, 0) in the xyxy-plane. What is the magnitude of the net gravitational field strength at a point PP located at (0,4.0 m)(0, 4.0\text{ m}), in terms of the universal gravitational constant GG?

  1. 8.0G N/kg8.0G\text{ N/kg}Cevap
  2. B
    10.0G N/kg10.0G\text{ N/kg}
  3. C
    6.0G N/kg6.0G\text{ N/kg}
  4. D
    4.0G N/kg4.0G\text{ N/kg}

Cevap

The magnitude of the net gravitational field strength at point PP is 8.0G N/kg8.0G\text{ N/kg}.
The distance from each mass to the target point is 5.0 m, yielding an individual field magnitude of 5.0G N/kg. Resolving vectors shows that horizontal components cancel out while vertical components add to give 2 × (5.0G × 4/5) = 8.0G N/kg.

Adım Adım Çözüm

1
Calculate the distance rr from each mass to point P(0,4.0 m)P(0, 4.0\text{ m}).
r=(3.00)2+(04.0)2=9+16=5.0 mr = \sqrt{(-3.0 - 0)^2 + (0 - 4.0)^2} = \sqrt{9 + 16} = 5.0\text{ m}.
The distance formula in two dimensions gives the hypotenuse of the right triangle formed by the coordinates.
2
Determine the magnitude of the gravitational field EE created by each individual mass at point PP.
E=GMr2=G×1255.02=125G25=5.0G N/kgE = \frac{G M}{r^2} = \frac{G \times 125}{5.0^2} = \frac{125G}{25} = 5.0G\text{ N/kg}.
Newton's law of universal gravitation defines field strength as E=GMr2E = \frac{GM}{r^2}.
3
Resolve the field vectors into horizontal and vertical components.
By symmetry, the horizontal components Ex=EsinθE_x = E \sin\theta are equal in magnitude and opposite in direction, so Ex,net=0E_{x,\text{net}} = 0. The vertical components Ey=EcosθE_y = E \cos\theta point downwards towards the origin.
Gravitational field is a vector quantity, so opposite components cancel while aligned components add together.
4
Calculate the total vertical component of the net gravitational field.
cosθ=4.05.0=0.8\cos\theta = \frac{4.0}{5.0} = 0.8. Thus, Enet=2×Ey=2×(5.0G×0.8)=8.0G N/kgE_{\text{net}} = 2 \times E_y = 2 \times (5.0G \times 0.8) = 8.0G\text{ N/kg}.
Summing the vertical contributions from both identical masses gives the net magnitude.

Anahtar Kavram

Vector Addition of Gravitational Field Strengths
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