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Zorluk: OrtaMeasures of Dispersion

The masses, in kilograms, of five wooden crates stored in a warehouse are 33, 77, 88, 1010, and 1212. What is the variance of the masses of these crates?

  1. 9.29.2Cevap
  2. B
    2.42.4
  3. C
    11.511.5
  4. D
    46.046.0

Cevap

The variance of the masses is 9.29.2.
The mean of the numbers is 88. The squared deviations are 25,1,0,4,25, 1, 0, 4, and 1616. The sum of these squared deviations is 4646. Dividing by the count of numbers (55) gives 9.29.2.

Adım Adım Çözüm

1
Calculate the mean (xˉ\bar{x}) of the dataset.
xˉ=3+7+8+10+125=405=8\bar{x} = \frac{3 + 7 + 8 + 10 + 12}{5} = \frac{40}{5} = 8
The mean is required to find individual deviations.
2
Compute the deviation of each observation from the mean, (xxˉ)(x - \bar{x}).
38=53 - 8 = -5, 78=17 - 8 = -1, 88=08 - 8 = 0, 108=210 - 8 = 2, 128=412 - 8 = 4
Deviations quantify how far each data point lies from the central mean.
3
Square each deviation, (xxˉ)2(x - \bar{x})^2.
(5)2=25(-5)^2 = 25, (1)2=1(-1)^2 = 1, 02=00^2 = 0, 22=42^2 = 4, 42=164^2 = 16
Squaring eliminates negative signs and weights larger deviations.
4
Sum the squared deviations and divide by the total number of observations N=5N = 5.
Variance σ2=25+1+0+4+165=465=9.2\sigma^2 = \frac{25 + 1 + 0 + 4 + 16}{5} = \frac{46}{5} = 9.2
Variance is defined as the mean of the squared deviations.

Anahtar Kavram

Variance of Ungrouped Data
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