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Zorluk: Çok zorLogarithms and Change of Base

If xx and yy are real numbers greater than 11 satisfying the system of equations logxy+logyx=52\log_x y + \log_y x = \frac{5}{2} and xy=64xy = 64 with x>yx > y, find the value of xyx - y.

Cevap: 12

Cevap

The value of xyx - y is 12.
Using the change of base identity logyx=1logxy\log_y x = \frac{1}{\log_x y}, the equation logxy+logyx=52\log_x y + \log_y x = \frac{5}{2} converts to u+1u=52u + \frac{1}{u} = \frac{5}{2} for u=logxyu = \log_x y. Solving the quadratic equation 2u25u+2=02u^2 - 5u + 2 = 0 yields u=12u = \frac{1}{2} or u=2u = 2. Because x>y>1x > y > 1, we must have logxy<1\log_x y < 1, selecting u=12    x=y2u = \frac{1}{2} \implies x = y^2. Substituting into xy=64xy = 64 gives y3=64    y=4y^3 = 64 \implies y = 4 and x=16x = 16. Therefore, xy=164=12x - y = 16 - 4 = 12.

Adım Adım Çözüm

1
Apply the reciprocal change of base identity
Rewrite logyx\log_y x as 1logxy\frac{1}{\log_x y}, yielding logxy+1logxy=52\log_x y + \frac{1}{\log_x y} = \frac{5}{2}.
According to the change of base formula, logyx=logxxlogxy=1logxy\log_y x = \frac{\log_x x}{\log_x y} = \frac{1}{\log_x y}.
2
Solve the quadratic equation in terms of u=logxyu = \log_x y
Substituting u=logxyu = \log_x y gives u+1u=52    2u25u+2=0u + \frac{1}{u} = \frac{5}{2} \implies 2u^2 - 5u + 2 = 0, which factors into (2u1)(u2)=0(2u - 1)(u - 2) = 0, yielding u=12u = \frac{1}{2} or u=2u = 2.
Multiplying through by 2u2u clears fractions and forms a standard quadratic equation.
3
Select the valid root using given inequality constraints
Since x>y>1x > y > 1, taking the logarithm base xx yields logxx>logxy    1>logxy\log_x x > \log_x y \implies 1 > \log_x y. Thus u=12u = \frac{1}{2}, which means y=x1/2y = x^{1/2} or x=y2x = y^2.
The condition x>yx > y restricts the logarithm of yy base xx to be strictly less than 11.
4
Substitute into the product equation to find xx and yy
Substituting x=y2x = y^2 into xy=64xy = 64 gives y3=64    y=4y^3 = 64 \implies y = 4. Consequently, x=42=16x = 4^2 = 16.
Combining the relation x=y2x = y^2 with xy=64xy = 64 enables single-variable cubic solution.
5
Calculate the required difference xyx - y
164=1216 - 4 = 12.
Direct subtraction of the derived values x=16x = 16 and y=4y = 4.

Anahtar Kavram

Logarithmic Change of Base Reciprocal Property
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