A sample of impure limestone () is strongly heated until decomposition is complete. If the loss in mass due to the escape of carbon dioxide () gas is , what is the percentage purity of the limestone sample?
Cevap: 80 %
Cevap
The percentage purity of the limestone sample is 80%.
Thermal decomposition of calcium carbonate yields calcium oxide and carbon dioxide. The mass loss of 1.76 g corresponds to the evolved CO2. From the molar masses (CaCO3 = 100 g/mol, CO2 = 44 g/mol), 44 g of CO2 is released by 100 g of pure CaCO3. Thus, 1.76 g of CO2 is released by 4.00 g of pure CaCO3. Dividing the pure mass (4.00 g) by the original sample mass (5.00 g) and multiplying by 100 yields a percentage purity of 80%.
Adım Adım Çözüm
Anahtar Kavram
Calculating percentage purity using stoichiometry and gravimetric decomposition data.