Examkin

Soru

Zorluk: KolayGay-Lussac's Law of Combining Volumes and Avogadro's Law

According to Gay-Lussac's Law of Combining Volumes, what volume of ammonia gas (NH3NH_3) is produced when 20 cm320\text{ cm}^3 of nitrogen gas (N2N_2) reacts completely with excess hydrogen gas (H2H_2) at constant temperature and pressure?

  1. A
    10 cm310\text{ cm}^3
  2. B
    20 cm320\text{ cm}^3
  3. 40 cm340\text{ cm}^3Cevap
  4. D
    60 cm360\text{ cm}^3

Cevap

40 cm340\text{ cm}^3 of ammonia gas (NH3NH_3) is produced.
According to the balanced chemical equation N2(g)+3H2(g)→2NH3(g)N_2(g) + 3H_2(g) \rightarrow 2NH_3(g), 1 mole (or volume) of N2N_2 reacts to form 2 moles (or volumes) of NH3NH_3. Therefore, 20 cm320\text{ cm}^3 of N2N_2 produces 2×20 cm3=40 cm32 \times 20\text{ cm}^3 = 40\text{ cm}^3 of NH3NH_3 gas.

Adım Adım Çözüm

1
Write the balanced chemical equation for the synthesis of ammonia
N2(g)+3H2(g)→2NH3(g)N_2(g) + 3H_2(g) \rightarrow 2NH_3(g)
Stoichiometric coefficients determine the combining volume ratios of reacting and product gases under constant temperature and pressure.
2
Determine the volume ratio between N2N_2 and NH3NH_3
1 volume of N2:2 volumes of NH31\text{ volume of } N_2 : 2\text{ volumes of } NH_3
By Gay-Lussac's Law of Combining Volumes, gases react in simple whole-number ratios by volume.
3
Calculate the volume of NH3NH_3 formed from 20 cm320\text{ cm}^3 of N2N_2
\text{Volume of } NH_3 = 20\text{ cm}^3 \times 2 = 40\text{ cm}^3
Directly scaling the volume of N2N_2 by the coefficient ratio (2/1).

Anahtar Kavram

Gay-Lussac's Law of Combining Volumes states that when gases react, they do so in volumes which bear a simple whole-number ratio to one another and to the volume of the product if gaseous, provided temperature and pressure remain constant.
Tahmini Süre:45s
Bu soruyu puanla

Konular

Gay-Lussac's Law of Combining Volumes and Avogadro's Law

Bu konudan daha fazla soru