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Zorluk: OrtaRadioactive Decay Law and Half-life

A radioactive sample has a half-life of 5 days5\text{ days}. If the mass of the sample that has decayed after 20 days20\text{ days} is 45 g45\text{ g}, what was the initial mass of the sample?

  1. 48 g48\text{ g}Cevap
  2. B
    720 g720\text{ g}
  3. C
    60 g60\text{ g}
  4. D
    180 g180\text{ g}

Cevap

The initial mass of the sample was 48 g48\text{ g}.
The elapsed time corresponds to 4 half-lives (20/5=420 / 5 = 4). The remaining mass fraction is (1/2)4=1/16(1/2)^4 = 1/16, which means 15/1615/16 of the original mass has decayed. Setting 15/1615/16 of the initial mass equal to 45 g45\text{ g} gives an initial mass of 48 g48\text{ g}.

Adım Adım Çözüm

1
Calculate the number of half-lives elapsed
n=tT1/2=20 days5 days=4 half-livesn = \frac{t}{T_{1/2}} = \frac{20\text{ days}}{5\text{ days}} = 4\text{ half-lives}
Determining how many half-life cycles occurred within the total elapsed time.
2
Determine the fraction of sample decayed
Fraction remaining = (1/2)4=1/16(1/2)^4 = 1/16; Fraction decayed = 11/16=15/161 - 1/16 = 15/16
The decayed fraction is the complement of the remaining fraction.
3
Calculate the initial mass
Mdecayed=1516M0=45 g    M0=45×1615=48 gM_{\text{decayed}} = \frac{15}{16} M_0 = 45\text{ g} \implies M_0 = 45 \times \frac{16}{15} = 48\text{ g}
Relating the given decayed mass to the total initial mass.

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Radioactive Decay Law and Half-life
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