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Zorluk: OrtaIndefinite Integration of Polynomial and Trigonometric Functions

The rate of change of a function f(x)f(x) with respect to xx is defined by f(x)=3x24x+6sin(3x)f'(x) = 3x^2 - 4x + 6\sin(3x). If f(0)=7f(0) = 7, determine the value of the constant of integration, CC.

Cevap: 9

Cevap

The constant of integration CC is equal to 9.
Integrating f(x)=3x24x+6sin(3x)f'(x) = 3x^2 - 4x + 6\sin(3x) gives f(x)=x32x22cos(3x)+Cf(x) = x^3 - 2x^2 - 2\cos(3x) + C. Substituting x=0x = 0 and f(0)=7f(0) = 7 leads to 7=002(1)+C7 = 0 - 0 - 2(1) + C, which simplifies to C=9C = 9.

Adım Adım Çözüm

1
Integrate the rate of change function f(x)=3x24x+6sin(3x)f'(x) = 3x^2 - 4x + 6\sin(3x) with respect to xx.
f(x)=x32x22cos(3x)+Cf(x) = x^3 - 2x^2 - 2\cos(3x) + C
Using the power rule xndx=xn+1n+1\int x^n dx = \frac{x^{n+1}}{n+1} and trigonometric integration rule sin(kx)dx=1kcos(kx)\int \sin(kx) dx = -\frac{1}{k}\cos(kx).
2
Substitute the initial condition x=0x = 0 and f(0)=7f(0) = 7 into the expression for f(x)f(x).
7=(0)32(0)22cos(30)+C7 = (0)^3 - 2(0)^2 - 2\cos(3 \cdot 0) + C
The curve passes through x=0x = 0 with value y=7y = 7.
3
Evaluate the trigonometric term at zero and solve for CC.
7=2(1)+C    C=97 = -2(1) + C \implies C = 9
Since cos(0)=1\cos(0) = 1, the expression simplifies to 7=2+C7 = -2 + C, yielding C=9C = 9.

Anahtar Kavram

Indefinite Integration of Polynomial and Trigonometric Functions with Boundary Conditions
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