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Zorluk: KolayThin Lenses, Optical Instruments, and Defects of Vision

A converging lens has a focal length of 25 cm25\text{ cm}. What is the optical power of the lens in dioptres?

  1. +4.0 D+4.0\text{ D}Cevap
  2. B
    4.0 D-4.0\text{ D}
  3. C
    +0.04 D+0.04\text{ D}
  4. D
    +25.0 D+25.0\text{ D}

Cevap

The optical power of the lens is +4.0 D+4.0\text{ D}.
The optical power PP of a lens in dioptres (D\text{D}) is calculated using P=1fP = \frac{1}{f}, where ff is the focal length in metres. Converting 25 cm25\text{ cm} to metres gives 0.25 m0.25\text{ m}. Since the lens is converging, its focal length is positive (+0.25 m+0.25\text{ m}). Thus, P=1+0.25=+4.0 DP = \frac{1}{+0.25} = +4.0\text{ D}.

Adım Adım Çözüm

1
Convert the focal length from centimetres to metres
f=25 cm=0.25 mf = 25\text{ cm} = 0.25\text{ m}
The unit of optical power (dioptre, D\text{D}) requires the focal length to be expressed in metres.
2
Apply the sign convention for a converging lens
f=+0.25 mf = +0.25\text{ m}
A converging (convex) lens has a real principal focus, so its focal length is positive by sign convention.
3
Calculate the optical power using the formula P=1fP = \frac{1}{f}
P=1+0.25=+4.0 DP = \frac{1}{+0.25} = +4.0\text{ D}
Optical power is defined as the inverse of the focal length in metres.

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Power of a Thin Lens
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