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Zorluk: OrtaBasic Trigonometric Ratios, Special Angles, and Identities

If θ\theta is an acute angle such that sinθ=513\sin \theta = \frac{5}{13}, what is the exact numerical value of 169(sin2θcos2θ)169(\sin^2 \theta - \cos^2 \theta)?

Cevap: -119

Cevap

The exact numerical value of the expression is 119-119.
Using the Pythagorean identity sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1, we find cos2θ=125169=144169\cos^2 \theta = 1 - \frac{25}{169} = \frac{144}{169}. Then sin2θcos2θ=25144169=119169\sin^2 \theta - \cos^2 \theta = \frac{25 - 144}{169} = -\frac{119}{169}. Multiplying by 169169 gives 119-119.

Adım Adım Çözüm

1
Calculate cos2θ\cos^2 \theta using the Pythagorean trigonometric identity.
cos2θ=144169\cos^2 \theta = \frac{144}{169}
Since sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1, subtracting sin2θ=25169\sin^2 \theta = \frac{25}{169} from 11 yields 144169\frac{144}{169}.
2
Compute the difference sin2θcos2θ\sin^2 \theta - \cos^2 \theta.
sin2θcos2θ=119169\sin^2 \theta - \cos^2 \theta = -\frac{119}{169}
Subtracting 144169\frac{144}{169} from 25169\frac{25}{169} gives 119169-\frac{119}{169}.
3
Scale the difference by 169169.
169×(119169)=119169 \times \left(-\frac{119}{169}\right) = -119
Multiplying 119169-\frac{119}{169} by 169169 cancels the denominator, leaving 119-119.

Anahtar Kavram

Pythagorean Trigonometric Identity
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