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Zorluk: OrtaElectric Circuits and Measuring Instruments

Two parallel resistors of values 6.0 Ω6.0\text{ }\Omega and 12.0 Ω12.0\text{ }\Omega are connected to a DC power source having an open-circuit voltage of 18.0 V18.0\text{ V} and an internal resistance of 1.0 Ω1.0\text{ }\Omega. What is the terminal potential difference supplied to the circuit?

  1. 14.4 V14.4\text{ V}Cevap
  2. B
    18.0 V18.0\text{ V}
  3. C
    3.6 V3.6\text{ V}
  4. D
    17.0 V17.0\text{ V}

Cevap

The terminal potential difference supplied to the circuit is 14.4 V14.4\text{ V}.
The option stating 14.4 V14.4\text{ V} is correct because the parallel combination of 6.0 Ω6.0\text{ }\Omega and 12.0 Ω12.0\text{ }\Omega gives an external equivalent resistance of 4.0 Ω4.0\text{ }\Omega. With an internal resistance of 1.0 Ω1.0\text{ }\Omega, the total circuit resistance is 5.0 Ω5.0\text{ }\Omega, resulting in a total current of 3.6 A3.6\text{ A}. The terminal voltage across the load is 3.6 A×4.0 Ω=14.4 V3.6\text{ A} \times 4.0\text{ }\Omega = 14.4\text{ V}.

Adım Adım Çözüm

1
Calculate the equivalent resistance (RpR_p) of the parallel resistors.
Rp=6.0×12.06.0+12.0=72.018.0=4.0 ΩR_p = \frac{6.0 \times 12.0}{6.0 + 12.0} = \frac{72.0}{18.0} = 4.0\text{ }\Omega
Resistors connected in parallel combine according to 1Rp=1R1+1R2\frac{1}{R_p} = \frac{1}{R_1} + \frac{1}{R_2}.
2
Determine the total resistance (RtotalR_{\text{total}}) of the entire circuit, including internal resistance.
Rtotal=Rp+r=4.0 Ω+1.0 Ω=5.0 ΩR_{\text{total}} = R_p + r = 4.0\text{ }\Omega + 1.0\text{ }\Omega = 5.0\text{ }\Omega
The internal resistance of the power source is in series with the external parallel load.
3
Calculate the total current (II) drawn from the power source.
I=ERtotal=18.0 V5.0 Ω=3.6 AI = \frac{E}{R_{\text{total}}} = \frac{18.0\text{ V}}{5.0\text{ }\Omega} = 3.6\text{ A}
Ohm's law for a complete circuit relates e.m.f., total resistance, and total current.
4
Calculate the terminal potential difference (VV).
V=IRp=3.6 A×4.0 Ω=14.4 VV = I \cdot R_p = 3.6\text{ A} \times 4.0\text{ }\Omega = 14.4\text{ V} (or V=EIr=18.0 V3.6 V=14.4 VV = E - I r = 18.0\text{ V} - 3.6\text{ V} = 14.4\text{ V})
Terminal voltage is the voltage across the external load or the e.m.f. minus the lost volts inside the cell.

Anahtar Kavram

Terminal Potential Difference and Internal Resistance
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