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Zorluk: ZorRatio, Proportion, and Rate

A vessel contains a mixture of two liquids, AA and BB, in the ratio 5:35 : 3. If 16 litres16\text{ litres} of the mixture is drawn off and replaced with an equal volume of liquid BB, the ratio of liquid AA to liquid BB in the vessel becomes 1:11 : 1. What was the initial total volume of the mixture in the vessel, in litres?

Cevap: 80 litres

Cevap

The initial total volume of the mixture in the vessel was 80 litres80\text{ litres}.
Let the initial volume of the mixture be VV litres. Liquid AA initially comprises 58V\frac{5}{8}V litres and liquid BB comprises 38V\frac{3}{8}V litres. When 16 litres16\text{ litres} of mixture is removed, the volume of liquid AA removed is 58×16=10 litres\frac{5}{8} \times 16 = 10\text{ litres}, and the volume of liquid BB removed is 38×16=6 litres\frac{3}{8} \times 16 = 6\text{ litres}. After adding 16 litres16\text{ litres} of pure liquid BB, the new volume of liquid AA is 58V10\frac{5}{8}V - 10 and the new volume of liquid BB is 38V6+16=38V+10\frac{3}{8}V - 6 + 16 = \frac{3}{8}V + 10. Since the new ratio is 1:11 : 1, setting 58V10=38V+10\frac{5}{8}V - 10 = \frac{3}{8}V + 10 gives 28V=20\frac{2}{8}V = 20, which simplifies to V=80 litresV = 80\text{ litres}.

Adım Adım Çözüm

1
Define total initial volume as VV and express the initial quantities of liquids AA and BB.
Liquid A=58VA = \frac{5}{8}V litres, Liquid B=38VB = \frac{3}{8}V litres.
The total ratio parts equal 5+3=85 + 3 = 8.
2
Calculate the volume of each liquid removed in 16 litres16\text{ litres} of mixture.
Volume of AA removed =10= 10 litres; Volume of BB removed =6= 6 litres.
The drawn-off mixture retains the original 5:35 : 3 ratio of liquids.
3
Formulate expressions for the quantities of AA and BB after adding 16 litres16\text{ litres} of pure liquid BB.
New amount of A=58V10A = \frac{5}{8}V - 10; New amount of B=38V+10B = \frac{3}{8}V + 10.
1616 litres of liquid BB is added to the remaining quantity of BB, which was 38V6\frac{3}{8}V - 6.
4
Equate the new quantities of AA and BB since the final ratio is 1:11 : 1.
58V10=38V+10    28V=20    V=80\frac{5}{8}V - 10 = \frac{3}{8}V + 10 \implies \frac{2}{8}V = 20 \implies V = 80.
A final ratio of 1:11 : 1 implies equal quantities of both liquids.

Anahtar Kavram

Ratio modification through mixture removal and replacement
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