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Zorluk: OrtaModular Arithmetic

Find the smallest non-negative integer xx that satisfies the linear modular congruence 3x8(mod11)3x \equiv 8 \pmod{11}.

Cevap: 10

Cevap

The smallest non-negative integer xx is 10.
Evaluating 3x8(mod11)3x \equiv 8 \pmod{11} by testing multiples of 1111 added to 88 gives 3030, which divided by 33 yields x=10x = 10. Since 10[0,10]10 \in [0, 10], it is the canonical solution.

Adım Adım Çözüm

1
Convert the modular congruence into an algebraic equation
3x=8+11k3x = 8 + 11k for an integer kk
By definition of congruence modulo 1111, 3x83x - 8 must be a multiple of 1111.
2
Find the smallest integer k0k \ge 0 such that 8+11k8 + 11k is divisible by 3
When k=2k = 2, 8+11(2)=308 + 11(2) = 30
3030 is divisible by 33 (30/3=1030 / 3 = 10).
3
Divide by 3 to isolate xx
x=10x = 10
3(10)=308(mod11)3(10) = 30 \equiv 8 \pmod{11}.

Anahtar Kavram

Linear Modular Congruence
Tahmini Süre:1m 15s
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