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Zorluk: KolayCombinations

A committee of 33 members is to be selected from a group of 77 people. In how many different ways can this committee be formed?

Cevap: 35 ways

Cevap

35
Selecting a committee of 33 members from 77 people requires calculating the number of combinations, given by 7C3=7!3!4!=35^7C_3 = \frac{7!}{3!4!} = 35.

Adım Adım Çözüm

1
Identify total elements and group size
n=7n = 7 and r=3r = 3
Since the arrangement or order of members in the committee does not matter, this is a selection problem (combinations).
2
Apply the combinations formula nCr=n!r!(nr)!^nC_r = \frac{n!}{r!(n-r)!}
7C3=7!3!4!^7C_3 = \frac{7!}{3!4!}
This formula counts the distinct subsets of size rr that can be chosen from nn items.
3
Evaluate the factorial expression
7C3=7×6×53×2×1=35^7C_3 = \frac{7 \times 6 \times 5}{3 \times 2 \times 1} = 35
Expanding 7!7! as 7×6×5×4!7 \times 6 \times 5 \times 4! allows cancelling 4!4!, leaving 2106=35\frac{210}{6} = 35.

Anahtar Kavram

Combinations formula nCr=n!r!(nr)!^nC_r = \frac{n!}{r!(n-r)!}
Tahmini Süre:45s
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