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Zorluk: ZorEquilibrium Constant Expression and Calculations
Excess solid carbon, C(s)\text{C}(s), is allowed to react with 1.0 mol1.0\text{ mol} of carbon dioxide gas, CO2(g)\text{CO}_2(g), in a sealed 2.0 dm32.0\text{ dm}^3 reaction vessel at a constant high temperature according to the equation:
C(s)+CO2(g)2CO(g)\text{C}(s) + \text{CO}_2(g) \rightleftharpoons 2\text{CO}(g)
If 1.0 mol1.0\text{ mol} of carbon monoxide gas, CO(g)\text{CO}(g), is present at equilibrium, calculate the numerical value of the equilibrium constant, KcK_c, in mol dm3\text{mol dm}^{-3}.

Cevap: 1 mol dm^-3

Cevap

1.0
To find KcK_c, convert initial and equilibrium amounts to molar concentrations by dividing by the volume (2.0 dm32.0\text{ dm}^3). Initial concentration of CO2\text{CO}_2 is 0.50 mol dm30.50\text{ mol dm}^{-3}. At equilibrium, [CO]=1.02.0=0.50 mol dm3[\text{CO}] = \frac{1.0}{2.0} = 0.50\text{ mol dm}^{-3}. From the 1:21:2 stoichiometry, 0.25 mol dm30.25\text{ mol dm}^{-3} of CO2\text{CO}_2 reacted, leaving [CO2]=0.25 mol dm3[\text{CO}_2] = 0.25\text{ mol dm}^{-3}. For a heterogeneous system, solid carbon is excluded from the equilibrium constant expression. Thus, Kc=[CO]2[CO2]=(0.50)20.25=1.0 mol dm3K_c = \frac{[\text{CO}]^2}{[\text{CO}_2]} = \frac{(0.50)^2}{0.25} = 1.0\text{ mol dm}^{-3}.

Adım Adım Çözüm

1
Calculate initial concentrations from the given moles and volume
Initial [CO2]=0.50 mol dm3[\text{CO}_2] = 0.50\text{ mol dm}^{-3}, initial [CO]=0.0 mol dm3[\text{CO}] = 0.0\text{ mol dm}^{-3}
Concentration is calculated using C=nVC = \frac{n}{V} where V=2.0 dm3V = 2.0\text{ dm}^3.
2
Determine equilibrium concentrations using stoichiometric mole ratios
Equilibrium [CO]=0.50 mol dm3[\text{CO}] = 0.50\text{ mol dm}^{-3} and [CO2]=0.25 mol dm3[\text{CO}_2] = 0.25\text{ mol dm}^{-3}
Producing 1.0 mol1.0\text{ mol} of CO\text{CO} consumes 0.50 mol0.50\text{ mol} of CO2\text{CO}_2. Remaining moles of CO2=1.00.50=0.50 mol\text{CO}_2 = 1.0 - 0.50 = 0.50\text{ mol}.
3
Write the equilibrium constant expression for the heterogeneous system
Kc=[CO]2[CO2]K_c = \frac{[\text{CO}]^2}{[\text{CO}_2]}
Pure solids like C(s)\text{C}(s) have constant activity and are omitted from the KcK_c expression.
4
Substitute concentrations into the KcK_c expression and solve
Kc=(0.50)20.25=1.0 mol dm3K_c = \frac{(0.50)^2}{0.25} = 1.0\text{ mol dm}^{-3}
Calculates the numerical value of the equilibrium constant.

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Heterogeneous equilibrium constant expression and ICE calculations
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