A bat emitting an ultrasonic sound pulse towards a flat vertical wall receives the reflect… — JAMB UTME

A bat emitting an ultrasonic sound pulse towards a flat vertical wall receives the reflected echo $0.12\text{ s}$ after emission. If the speed of sound in air is $340\text{ m/s}$ , what is the distance between the bat and the wall at the moment of emission?

$20.4\text{ m}$ Cevap
B
$40.8\text{ m}$
C
$81.6\text{ m}$
D
$10.2\text{ m}$

Cevap

The distance between the bat and the wall is

20.4\text{ m}

The distance to the wall is

20.4\text{ m}

because sound undergoes a two-way journey (from source to reflector and back). Multiplying the speed of sound (

340\text{ m/s}

) by the total time (

0.12\text{ s}

) yields the round-trip distance of

40.8\text{ m}

. Dividing this value by

2

gives the one-way distance of

20.4\text{ m}

Adım Adım Çözüm

Calculate the total distance traveled by the sound wave during the round trip.

d_{\text{total}} = v \times t = 340\text{ m/s} \times 0.12\text{ s} = 40.8\text{ m}

The sound wave travels from the bat to the obstacle and reflects back to the bat.

Divide the total round-trip distance by

2

to determine the one-way distance to the wall.

d = \frac{d_{\text{total}}}{2} = \frac{40.8\text{ m}}{2} = 20.4\text{ m}

An echo involves a two-way path, so the one-way distance is half the total distance covered by the wave.

Anahtar Kavram

Echo and Two-Way Distance Calculation

Tahmini Süre:1m 30s

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