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Zorluk: KolayGas Laws and the Ideal Gas Equation

A flexible balloon contains a sample of gas occupying a volume of 3.0 m33.0\text{ m}^3 at a temperature of 27C27^\circ\text{C} under constant pressure. If the gas is heated to 127C127^\circ\text{C} while keeping the pressure constant, what is the new volume of the gas in m3\text{m}^3?

Cevap: 4

Cevap

The new volume of the gas is 4.0 m34.0\text{ m}^3.
According to Charles's Law (V1T1=V2T2 \frac{V_1}{T_1} = \frac{V_2}{T_2}), at constant pressure, volume is directly proportional to absolute temperature in Kelvin. Converting 27C27^\circ\text{C} to 300 K300\text{ K} and 127C127^\circ\text{C} to 400 K400\text{ K} yields a final volume V2=3.0×400300=4.0 m3V_2 = 3.0 \times \frac{400}{300} = 4.0\text{ m}^3.

Adım Adım Çözüm

1
Convert the given initial and final temperatures from Celsius to Kelvin
T1=27+273=300 KT_1 = 27 + 273 = 300\text{ K} and T2=127+273=400 KT_2 = 127 + 273 = 400\text{ K}
Gas law calculations require absolute temperature in Kelvin.
2
Set up Charles's Law equation for constant pressure processes
V1T1=V2T2\frac{V_1}{T_1} = \frac{V_2}{T_2}
At constant pressure, the volume of a given mass of gas is directly proportional to its absolute temperature.
3
Substitute the values into the equation and solve for the final volume V2V_2
V2=3.0×400 K300 K=4.0 m3V_2 = 3.0 \times \frac{400\text{ K}}{300\text{ K}} = 4.0\text{ m}^3
Direct algebraic evaluation yields the final gas volume.

Anahtar Kavram

Charles's Law
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