Ultraviolet radiation of fixed frequency , which exceeds the threshold frequency of a zinc emitter plate, causes photoelectron emission. If the intensity of the incident radiation is multiplied by two without altering its frequency, what is the effect on the maximum kinetic energy of the photoelectrons and the emission current?
- The maximum kinetic energy is unchanged, but the emission current is doubled.Cevap
- BThe maximum kinetic energy is doubled, and the emission current is also doubled.
- CThe maximum kinetic energy is doubled, while the emission current remains unchanged.
- DThe maximum kinetic energy and emission current both remain unchanged.
Cevap
The maximum kinetic energy is unchanged, but the emission current is doubled.
In the photoelectric effect, the maximum kinetic energy of emitted electrons () depends only on the frequency of the incident radiation and the work function of the metal. Changing light intensity changes only the number of photons arriving per second, which doubles the rate of photoelectron emission and hence doubles the photoelectric current while leaving maximum kinetic energy unchanged.
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Anahtar Kavram
Independence of photoelectron kinetic energy from light intensity